School Work">
Ejemplos Tema 1.. Fisica 3
Ejemplos Tema 1.. Fisica 3
Ejemplos Tema 1.. Fisica 3
= ; 0 =
0
De donde =
= 245 /
1
1
(4)9.8 2
0.16
= 2245 /2
= 0.28
Solucin
1
(a) = = 0.25
(b) 0 =
= 4
0 =
(c) = cos (0 + )
= 0 (0 + )
Para = 0, 0 = 0.37, 0 = 0
0 =
0 = 0
Entonces, para = 0, 0 = 0
(d) = cos (0 + )
= 0.37 cos 2
()
= 0.37
(e) = 0 (0 + ) = 25 (0.37) 2
= 0.58 2
(f) = 0 = 2 1 (0.37)
(g) = 02 = 2 1 (0.37)
= 0.58
= 0.91
= 0.58
Solucin
(a) =
= 16 2 + 3
= 32 cos 2 + 3
Para = 2
= 16 + 3 = 16 3
= 13.68
16 = 16 2 + 3
2 + 3 =
1 3
= 2 2 3 = 2 2 3 =
= 1.83
2 + 3 = 1
7
12
32 = 32 cos 2 + 3
2 + 3 =
1
cos 2 + 3 = 1
= 2 3 = 3
= 1.05
igual a + . Calcule, (a) la masa del bloque, (b) el perodo del movimiento y
(c) la aceleracin mxima del bloque.
Solucin
(a) De la conservacin de la energa para este sistema:
1
2
2 = 2 2 + 2 2
2 = (2 2 )
(2 2 ) = 2
6.5 2
0.3
= 2 (2 2 )
[(0.1)2 (0.05)2 ]
= 0.55
0.55
(b) = = 2 = 26.5 /2
0
= 1.82
(c) =
02
= =
= 1.18 / 2
6.5 2 (0.1)
0.55
1
1 2
2 (1 + 2 )
Solucin:
Si el cuerpo se mueve de su posicin de equilibrio una distancia al aplicarse una
fuerza , sobre cada alambre se producir una fuerza de restitucin que se opone a la fuerza
aplicada, la cual se trasmite uniformemente a todo el alambre, produciendo en cada uno de
ellos desplazamientos 1 y 2 , respectivamente, cuya suma ser igual al desplazamiento .
As se tiene
1 = 1 1
2 = 2 2
Y = 1 + 2 (A). De esta manera se obtiene
=
=
1 1
2
2 =
=
2 2
1 =
= +
1
= + =
1
1 +2
1 2
0
2
1 2
0 =
(1 + 2 )
= 2 (
1 2
1 +2 )
eje de rotacin es =
= 2
= 0.15
= 6 103 .
Solucin
= = =
2
+ = 0
2
2
+ 02 = 0
2
2
2
2
+ =0
2
0 =
2(2)(15)2 104
= 2 = 2
2
0
5(6103 ) 2
= 10.88
= ( + )
Si = 0, 2 y
Si = 0
1 = 6 cos(2)
2 = 8cos (2)
= 1 + 2 = (6 + 8) cos(2)
= 14cos (2)
Si =
1 = 6 cos 2
= 1 + 2 = cos(2 + )
= (12 + 22 + 21 2 )1/2 ;
=
= (12 + 22 )2
= 1 2 = 6 = 0.93 = 53.13
1
La amplitud de la oscilacin es
1
= (12 + 22 )2
= (36 + 64)2 = 10
1 = 6 cos 2
= 1 + 2 = 6 cos 2 8 cos 2
= 2 cos 2 = 2cos (2 + )
Solucin
1 = =
=
=
2
2
+
+ =0
2
+
2
+ 02 = 0
2
0 =
() = 0 cos(1 + )
=
= 0
= 20
----- 1.5%
La amplitud 0 es:
= (0.0262 )
= (0.0349 )
= 0
=
0
1
0.0262
= ln =
ln
0
20
0.0349
= 0.014 1