TOS Table of Specifications G6 Math SY 2023 2024 Summative Final
TOS Table of Specifications G6 Math SY 2023 2024 Summative Final
TOS Table of Specifications G6 Math SY 2023 2024 Summative Final
Department of Education
REGION I
PANGASINAN SCHOOLS DIVISION OFFICE II
2
routine problems involving
multiplication of decimals
and mixed decimals Ie-113.2 =1.14
including money using =1
appropriate problem-
solving strategies.
solves multi-step problems
involving multiplication and
addition or subtraction of
M6NS (3/132)*50
decimals, mixed decimals
If-113.3 3 =1.14 32 32 32
and whole numbers =1
including money using
appropriate problem-
solving strategies and tools.
divides:
a. whole numbers by
(2/132)*50
decimals up to 2 decimal
2 =.76 41 41 41
places and vice versa =1
b. decimals/mixed decimals
up to 2 decimal places
divides decimals:
a. up to 4 decimal places by (1/132)*50
0.1, 0.01, and 0.001 1 =.38
b. up to 2 decimal places by =0
10, 100, and 1 000 mentally
differentiates terminating
(2/132)*50
from repeating, non- M6NS
2 =.76 33 33 33
terminating decimal Ii-119 =1
quotients
solves routine and non- M6NS 2 (2/132)*50 46 46 46
routine problems involving Ii-120.2 =.76
=1
division of decimals, mixed
decimals, and whole
numbers including
3
money using appropriate
problem-solving strategies
and tools.
solves multi-step routine
and non-routine problems
involving division and any
of the other operations of M6NS (3/132)*50
decimals, mixed Ij-120.3 3 =1.14 47 47 47
decimals, and whole =1
numbers including money
using appropriate problem-
solving strategies and tools
MATH 6 SECOND QUARTER EXAM (TABLE OF SPECIFICATIONS)
Express one value as a (1/132)*50
fraction of another given their M6NS-IIa- 1 =.38
ratio and vice versa(M6NS- 129 =0
IIa129)
Defines and illustrates the
meaning of ratio and (1/132)*50
M6NS-IIb- 1 =.38
proportion using concrete or
131 =0
pictorial models (M6NS-IIb-
131)
Finds a missing term in a (5/132)*50
M6NS-IIb- 34. 34.
proportion (direct, inverse, 5 =1.89 34 48
133 48. 48.
and partitive (M6NS-IIb-133) =2
Solves problems involving
direct proportion, partitive
proportion, and inverse (4/132)*50
proportion in different M6NS-IIc- 4 =1.52 6 6 6
context such as distance, rate, 134 (2-1) =1
and time using appropriate
strategies and tools (M6NS-
IIc134)
Finds the percentage or rate (3/132)*50
M6NS-IId- 3 =1.14 7 7 7
or percent in a given problem
142 =1
(M6NS-IId-142)
Solves routine and non- M6NS-IId- 2 (2/132)*50 8 8 8
4
routine problems involving
finding the percentage,rate =.76
and base using appropriate 143 =1
strategies and tools (M6NS-
Iid-143)
Solves percent problems such
as percent of
increase/decrease, (discounts, (4/132)*50
original price, rate of M6NS-IIe- 9. 9.
4 =1.52 9 42
discount, sale price, marked- 144 42. 42.
=2
up price), commission, sales,
tax and simple interest
(M6NS-IIe-144)
Describes the exponent and
base in a number expressed in M6NS-IIf-
exponential notation(M6NS- 146 (1/132)*50
IIf-146) 1 =.38
Gives the value of numbers =0
M6NS-IIf-
expressed in exponential
147
notation (M6NS-IIf-147)
Interprets and explains the
Grouping, Exponent, (1/132)*50
M6NS-IIf- 1 =.38
Multiplication, Division,
148 =0
addition, ,Subtraction
(GEMDAS) rule (M6NS-IIf-148)
Performs two or more
different operations on whole (2/132)*50
M6NS-IIf- 2 =.76 10 10. 10
numbers with or without
149 =1
exponents and grouping
symbols(M6NS-IIf-149)
(1/132)*50
Describes the set of M6NS-IIg- 1 =.38
integers(M6NS-IIg-151) 151 =0
Compares integers with other
numbers such as whole M6NS-IIg- (1/132)*50
1
numbers, fractions, and 152 =.38
decimals(M6NS-IIg-152) =0
Compare and arranges M6NS-IIh-
integers(M6NS-IIh-154) 154
5
Describes and interprets the
basic operations on integers (2/132)*50
M6NS-IIh- 2 =.76 43 43. 43
using materials such as
155 =1
algebra tiles, counters, chips,
and cards(M6NS-IIh-155)
(2/132)*50
Performs the basic operations M6NS-IIi- 2 =.76 35 35. 35.
on integers(M6NS-IIi156) 156 =1
Solves routine and non-
routine problems involving (4/132)*50
M6NS-IIj- 4 =1.52 49 49. 49.
basic operations of integers
157 (2-1) =1
using appropriate strategies
and tools(M6NS-IIj-157)
MATH 6 THIRD QUARTER EXAM (TABLE OF SPECIFICATIONS)
visualizes and describes the different
solid figures: cube, prism, pyramid, (2/132)*50
M6GE-IIIa- 2 =.76 11 11. 11
cylinder, cone, and sphere using
27 =1
various concrete and pictorial
models.
differentiates solid figures from (1/132)*50
plane figures. M6GE-IIIa- 1 =.38
28 =0
identifies the faces of a solid figure. (1/132)*50
M6GE-IIIb- 1 =.38
30 =0
formulates the rule in finding the nth
term using different strategies (2/132)*50
(looking for a pattern, guessing and 2 =.76 12 12. 12.
M6AL-IIId-7
checking, working backwards) e.g. =1
4,7,13,16,…n (the nth term is
3n+1)
differentiates expression from (2/132)*50
equation. M6AL-IIId- 2 =.76 13 13. 13.
15 =1
gives the translation of real-life (2/132)*50
verbal expressions and equations M6AL-IIIe- 2 =.76 14 14 14
into letters or symbols and vice 16 =1
versa.
defines a variable in an algebraic (2/132)*50
expression and equation. M7GE-IIId- 2 =.76 15 15 15
e-1 =1
6
represents quantities in real-life (2/132)*50
situations using algebraic M6AL-IIIe- 2 =.76 16 16 16
expressions and equations. 18 =1
solves routine and non-routine
problems involving different types of (4/132)*50
numerical expressions and equations M6AL-IIIf-19 4 =1.52 36 36. 36.
such as 7+ 9 (2-1) =1
=___ + 6.
calculates speed, distance, and time. (2/132)*50
M6ME-IIIg- 2 =.76 17 17 17
17 =1
solves problems involving average (2/132)*50
rate and speed. M6ME-IIIg- 2 =.76 37 37. 37.
18 =1
finds the area of composite figures (2/132)*50
formed by any two or more of the M6ME-IIIh- 2 =.76 18 18 18
following: triangle, square, 89 =1
rectangle, circle, and semi-circle.
solves routine and non-routine
problems involving area of (2/132)*50
composite figures formed by any M6ME-IIIh- 2 =.76 38 38. 38.
two or more of the following: 90 =1
triangle, square, rectangle, circle,
and semi-circle.
visualizes and describes surface area (2/132)*50
and names the unit of measure used M6ME-IIIi- 2 =.76 19 19 19
for measuring the surface area of 91 =1
solid/space figures.
finds the surface area of cubes, (2/132)*50
prisms, pyramids, cylinders, cones, M6ME-IIIi- 2 =.76 20 20 20
and spheres. 93 =1
solves word problems involving (5/132)*50
measurement of surface area. M6ME-IIIj- 5 =1.89 50 50 50
94 (2-1) =1
MATH 6 FOURTH QUARTER EXAM (TABLE OF SPECIFICATIONS)
Determines the relationship of 21 21
the volume between a (2/132)*50
M6ME- 2 =.76 21
rectangular prism and a
IVa-95 =1
pyramid;a cylinder and a cone;
and a cylinder and sphere.
Finds the volume of cylinders, M6ME- 2 (2/132)*50 22 22 22
pyramids, cones, and spheres. IVb-97 =.76
7
=1
(2/132)*50 44 44
Constructs a pie graph based on M6SP-IVe- 2 =.76 44
a given set of data. 2.6 =1
(2/132)*50 26 26
Solves routine and non-routine
=.76
problems using data presented M6SP-IVf-
2 =1 26
in a pie graph. 4.6
Describes the meaning of (2/132)*50 27 27
probability such as 50% chance M6SP-IVg- 2 =.76 27
of rain and one in a million 19 =1
chance of winning.
Performs experiments and (2/132)*50 45 45
records outcomes. M6SP-IVh- 2 =.76 45
21 =1
8
EASY AVERAGE DIFFICULT
Note: TD – Teaching Days TTD – Total Teaching Days TI – Total Items
Prepared by: Checked and Evaluated by: Noted for School Implementation:
Noted for Monitoring and Evaluation: Noted for Monitoring and Evaluation: