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    Bolt Capacity Calculations

    Uploaded by

    kalpanaadhi
    The document discusses determining the shear, bearing, and tensile capacities of a 20mm bolt that is property class 8.8. It provides the relevant material properties and dimensions. For shear capacity, it calculates the nominal capacity based on the bolt area and applies strength and load factors. For bearing capacity, it calculates the nominal capacity based on the bolt diameter, plate thickness, and material strengths using codal provisions for end/pitch distances and applies factors. For tensile capacity, it calculates the nominal capacity based on the net tensile bolt area and material strength and applies factors.

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    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd

    Bolt Capacity Calculations

    Uploaded by

    kalpanaadhi
    347 views4 pages
    The document discusses determining the shear, bearing, and tensile capacities of a 20mm bolt that is property class 8.8. It provides the relevant material properties and dimensions. For shear capacity, it calculates the nominal capacity based on the bolt area and applies strength and load factors. For bearing capacity, it calculates the nominal capacity based on the bolt diameter, plate thickness, and material strengths using codal provisions for end/pitch distances and applies factors. For tensile capacity, it calculates the nominal capacity based on the net tensile bolt area and material strength and applies factors.

    Original Description:

    Bolt Capacity Calculations as per IS 800-2007

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    © © All Rights Reserved

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    The document discusses determining the shear, bearing, and tensile capacities of a 20mm bolt that is property class 8.8. It provides the relevant material properties and dimensions. For shear capacity, it calculates the nominal capacity based on the bolt area and applies strength and load factors. For bearing capacity, it calculates the nominal capacity based on the bolt diameter, plate thickness, and material strengths using codal provisions for end/pitch distances and applies factors. For tensile capacity, it calculates the nominal capacity based on the net tensile bolt area and material strength and applies factors.

    Copyright:

    © All Rights Reserved
    Download as PDF, TXT or read online from Scribd
    Download as pdf or txt
    347 views4 pages

    Bolt Capacity Calculations

    Uploaded by

    kalpanaadhi
    The document discusses determining the shear, bearing, and tensile capacities of a 20mm bolt that is property class 8.8. It provides the relevant material properties and dimensions. For shear capacity, it calculates the nominal capacity based on the bolt area and applies strength and load factors. For bearing capacity, it calculates the nominal capacity based on the bolt diameter, plate thickness, and material strengths using codal provisions for end/pitch distances and applies factors. For tensile capacity, it calculates the nominal capacity based on the net tensile bolt area and material strength and applies factors.

    Copyright:

    © All Rights Reserved
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    of 4

    Design Shear Capacity of bearing type bolts

    Remarks/
    Determine shear capacity of a 20mm bolt of property class 8.8 could safely carry
    Codal
    if it connects plates of 10 mm thick and in single shear (Shear plane cuts the
    Provisions
    shank)
    M20 Bolt- Property Class 8.8: Bearing type bolt
    Asb = Shank area of bolt = 314 mm2
    Anb = Net tensile area at threads = 245 mm2
    fub = 800 MPa
    fy = 640 MPa
    Solution:

    Bolt in single shear

    10mm
    10mm

    Bolt in single shear


    Shear capacity of the bolt:

    Vdsb = Vnsb / γmb


    where
    Clause
    Vnsb = nominal shear capacity of a bolt, calculated as follows:
    10.3.3
    f
    Vnsb = u (n n A nb + n s A sb )
    3
    where
    fu = ultimate tensile strength of a bolt.
    nn = number of shear planes with threads intercepting the shear plane
    ns = number of shear planes without threads intercepting the shear plane
    Asb = nominal plain shank area of the bolt
    Anb = net tensile area at threads

    Assume the threads are not intercepting the shear plane


    ∴nn = 0 ; ns = 1.

     (800
    Vnsb =  (0 × 245 + 1 × 314) × 1 = 145.0 kN
     3  1000

    145
    Vdsb = = 116.0 kN (See Table 7.1)
    1.25

    Multiplication factor for packing plates (if used)

    527
    Let tpk = 10 mm
    β pk = (1 − 0.0125t pk )
    = (1 − 0.0125 ×10)
    = 0.88

    Multiplication factor for long joints

    Assuming the length of the joint lj = 360 mm


    Diameter of the bolt = 20 mm
    lj/d =360/20 = 18
    lj
    β lj = (1.075 − 0.005 )
    d
    360
    = (1 − 0.005 × )
    20
    = 0.99

    Multiplication factor for large grip lengths

    In the present case the grip length lg = 20 mm. Since it does not exceeds lg=5d ,
    no reduction is needed. However for exemplifying the procedure the following
    calculation is shown
    8
    β lg = ≤ β lj
    lg
    3+
    d
    8
    =
    20
    3+
    20
    = 1.00 (max imum)

    528
    Design bearing Capacity of bearing type bolts
    Determine bearing capacity of a 20mm bolt of property class 8,8 if it connects Remarks/
    plates of 10 mm thick. Assume a pitch of 2.5 d and end distance of 1.5 d0 and Codal
    also kb = 1.0 Provisions
    M20 Bolt- Property Class 8.8: Bearing type bolt
    d = diameter of the bolt =20 mm ; d0 = diameter of hole = 20 + 2 =22mm
    thickness of the plate = 10 mm
    fub = ultimate tensile strength of the bolt = 800 MPa
    fyb = yield strength of the bolt = 640 MPa
    fu = ultimate tensile strength of the plate = 410 MPa Table 19
    Solution:
    (a) Bolt in single shear

    10mm
    10mm

    Bolts in single shear


    Bearing capacity of the bolt:
    Vdpb = Vnpb / γmb where
    Vnpb = nominal shear capacity of a bolt, calculated as follows:
    =2.5 kb d t fu where
    kb is smaller of (i) e/3d0 (ii) (p/3d0) – 0.25 (iii) fub/fu (iv) 1.0 Clause
    10.3.4
    e,p = end and pitch distances of the fastener in the bearing direction
    (i) e/3d0 = 1.5d0/3d0 = 0.5 (ii) (p/3d0) – 0.25 = 50 / (3 x 22) – 0.25 = 0.51
    (iii) fub/fu = 800 /410 = 1.95 (iv) 1.0
    Hence kb = 0.5

    Vnpb = (2.5 × 0.5 × 20 ×10 × 410) ×


    1
    = 102.5 kN
    1000

    if kb = 1.0 then Vnpb = (2.5 ×1.0 × 20 ×10 × 410) ×


    1
    =205 kN
    1000
    102,5 205
    Vdpb = = 82 kN & Vdpb = = 164 kN
    1.25 1.25
    If fub is used for the bearing stress calculation as:

    if kb = 1.0 then Vnpb = (2.5 ×1.0 × 20 ×10 × 800) ×


    1
    =400 kN
    1000
    400
    Vdpb = = 320 kN
    1.25

    529
    Design tensile Capacity of bolts

    Determine the design tensile capacity of 20mm bolt of Property class 8.8. Remarks/
    Codal
    Provisions

    M20 Bolt- Property Class 8.8:


    Bearing type bolt
    Asb = Shank area of bolt = 314 mm2
    Anb = Net tensile area at threads = 245 mm2
    fub = 800 MPa
    fy = 640 MPa
    Solution:

    (a) Bolt in tension

    Bolt in tension

    Tension capacity of the bolt:

    Tdb = Tnb / γmb

    where
    Tnsb = nominal tensile capacity of a bolt, calculated as follows:
    Tnb = 0.9 × f ub × Anb < ( f yb / γ m0 ) × Asb × γ mb Clause
    10.3.5
    Tnb = (0.9 × 800 × 245) ×
    1
    = 176.4 kN < 228.4 kN
    1000
    176.4
    Tdb = = 141.1 kN
    1.25

    530

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