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Revision History for A024966 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
7 times triangular numbers: 7*n*(n+1)/2.
(history; published version)
#70 by Michel Marcus at Tue Feb 21 02:15:44 EST 2023
STATUS

reviewed

approved

#69 by Joerg Arndt at Tue Feb 21 02:05:36 EST 2023
STATUS

proposed

reviewed

#68 by Amiram Eldar at Tue Feb 21 01:05:03 EST 2023
STATUS

editing

proposed

#67 by Amiram Eldar at Tue Feb 21 00:47:44 EST 2023
FORMULA

From Amiram Eldar, Feb 21 2023: (Start)

Product_{n>=1} (1 - 1/a(n)) = -(7/(2*Pi))*cos(sqrt(15/7)*Pi/2).

Product_{n>=1} (1 + 1/a(n)) = (7/(2*Pi))*cosh(Pi/(2*sqrt(7))). (End)

STATUS

approved

editing

#66 by Michel Marcus at Fri Feb 25 04:26:12 EST 2022
STATUS

reviewed

approved

#65 by Joerg Arndt at Fri Feb 25 04:10:42 EST 2022
STATUS

proposed

reviewed

#64 by Joerg Arndt at Fri Feb 25 04:10:24 EST 2022
STATUS

editing

proposed

#63 by Joerg Arndt at Fri Feb 25 04:10:16 EST 2022
MATHEMATICA

s=0; lst={s}; Do[s+=n++ +7; AppendTo[lst, s], {n, 0, 7!, 7}]; lst (* Vladimir Joseph Stephan Orlovsky, Nov 16 2008 *)

STATUS

proposed

editing

#62 by Michel Marcus at Fri Feb 25 03:32:47 EST 2022
STATUS

editing

proposed

#61 by Michel Marcus at Fri Feb 25 03:32:43 EST 2022
COMMENTS

Sequence provides all integers m such that 56*m + 49 is a square. -_ _Bruno Berselli_, Oct 07 2015

STATUS

proposed

editing