CH 08
CH 08
CH 08
Mechanisms
ISSUES TO ADDRESS...
• How are dislocations involved in the plastic deformation
of materials?
• Does the crystal structure of a material affect its mechanical
characteristics? If so, how and why?
• How are mechanical properties affected by
dislocation mobilities?
• What techniques are used to increase the
strength/hardness of metals/alloys?
• How are mechanical characteristics of deformed
metal specimens altered by heat treatments?
Chapter 8 - 1
Plastic Deformation by Dislocation
Motion
• Plastic deformation occurs by motion of dislocations
(edge, screw, mixed) – process called slip
• Applied shear stress can cause extra half-plane of atoms
[and edge dislocation line ( )] to move as follows: Fig. 8.1, Callister &
Rethwisch 5e.
Chapter 8 - 3
Motion of Edge and Screw Dislocations
• Direction of edge disl. line ( ) motion—in direction of
applied shear stress .
Edge dislocation
Screw dislocation
+ + + + + + + +
+ + + + + + + +
+ + + + + + + +
electron cloud ion cores
• Metals:
- Examples: copper, aluminum, iron
- Dislocation motion—relatively easy
- Metallic bonding—non-directional
- Close-packed planes and directions for slip
Chapter 8 - 5
Dislocation Characteristics
Ceramics
• Ceramics—Covalently Bonded
- Examples: silicon, diamond
- Dislocation motion—relatively
difficult
- Covalent bonding—directional
• Ceramics—Ionically Bonded
+ - + - + - +
- Examples: NaCl, MgO
- Dislocation motion—relatively - + - + - + -
difficult + - + - + - +
- Few slip systems
motion of nearby ions of like
charge (+ and -) restricted by
electrostatic repulsive forces
Chapter 8 - 6
Slip Systems
Slip System—Combination of slip plane and slip direction
– Slip Plane
• Crystallographic plane on which slip occurs most
easily
• Plane with high planar density
– Slip Direction
• Crystallographic direction along which slip occurs
most easily
• Direction with high linear density
Chapter 8 - 7
Slip Systems (cont.)
• For FCC crystal structure – slip system is
– Dislocation motion on planes
– Dislocation motion in directions
– A total of 12 independent slip systems for FCC
direction
Fig. 8.6, Callister &
Rethwisch 5e.
plane
Chapter 8 - 8
Slip in Single Crystals
Resolved Shear Stress
• Applied tensile stress—shear stress component
when slip plane oriented neither perpendicular nor
parallel to stress direction ϕ
-- From figure, resolved shear stress, τR λ
Chapter 8 - 9
Slip in Single Crystals
Resolved Shear Stress (cont.)
Chapter 8 - 10
Slip in Single Crystals:
Critical Resolved Shear Stress
• Dislocation motion—on specific slip system—when R reaches
critical value:
-- “Critical resolved shear stress”, CRSS
-- Slip occurs when R > CRSS
-- Typically 0.1 MPa < CRSS < 10 MPa
• In a single crystal there are
-- multiple slip systems
-- a variety of orientations
• One slip system for which R is highest: R(max) > ⌠ (cos cosϕ
)max
-- Most
• Yield favorably
strength oriented
of single ⌠y, when
slip system
crystal,
Chapter 8 - 11
Single Crystals
Slip—Macroscopic Scale
• Parallel slip steps form on
surface of single crystal
Chapter 8 - 12
Deformation of Single Crystals
Example Problem
A single crystal of some metal has a crss of 20.7 MPa and is
exposed to a tensile stress of 45 MPa.
(a) Will yielding occur when ϕ = 60° and = 35°?
(b) If not, what stress is necessary?
Solution:
(a) First calculate τR
Chapter 8 - 13
Deformation of Single Crystals
Example Problem (cont.)
(b) To calculate the required tensile stress to
cause yielding use the equation:
Chapter 8 - 14
Slip in Polycrystalline Materials
σ
• Polycrystalline materials—
many grains, often random
crystallographic orientations
- with largest τR
- when τR > τcrss
• In photomicrograph—note slip
lines in grains have different
orientations. 300 μm
σ
Chapter 8 - 15
Slip in Polycrystalline Materials (cont.)
• Grains change shape (become distorted)—during plastic
deformation—due to slip
• Manner of grain distortion similar to gross plastic deformation
- Grain structures before and after deformation (from rolling)
- Before rolling—grains equiaxed & randomly oriented
Properties isotropic
- After rolling (deformation)—grains elongated in rolling direction
Also preferred crystallographic orientation of grains
Properties become somewhat anisotropic
- before rolling
- after rolling Adapted from Fig. 8.11,
Callister & Rethwisch 5e.
(from W.G. Moffatt, G.W. Pearsall,
and J. Wulff, The Structure and
Properties of Materials, Vol. I,
Structure, p. 140, John Wiley and
Sons, New York, 1964.)
• 3 mechanisms discussed
-- Grain size reduction
-- Solid solution strengthening
-- Strain hardening (cold working)
Chapter 8 - 17
Strengthening Mechanisms for Metals
Mechanism I – Reduce Grain Size
• Grain boundaries act as barriers
to dislocation motion
• At boundary
— Slip planes change directions
(note in illustration)
— Discontinuity of slip planes
• Reduce grain size
— increase grain boundary area Fig. 8.14, Callister & Rethwisch 5e.
(From L. H. Van Vlack, A Textbook of Materials
— more barriers to dislocation motion Technology, Addison-Wesley Publishing Co., 1973.
Reproduced with the permission of the Estate of
— increase yield strength, tensile Lawrence H. Van Vlack.)
Chapter 8 - 19
Solid Solution Strengthening (cont.)
• Lattice strain interactions with strains introduced by impurity atoms
• Small substitutional impurities introduce tensile strains
• When located above slip line for edge dislocation as shown:
– partial cancellation of impurity (tensile) and disl. (compressive) strains
– higher shear stress required to cause disl. motion
Chapter 8 - 21
VMSE Solid-Solution Strengthening Tutorial
Chapter 8 - 22
Solid Solution Strengthening (cont.)
• Alloying Cu with Ni increases σy and TS.
• Tensile strength & yield strength increase with wt% Ni.
Tensile strength (MPa)
180
200 60
0 10 20 30 40 50 0 10 20 30 40 50
wt.% Ni, (Concentration C) wt.%Ni, (Concentration C)
• Empirically,
Chapter 8 - 23
Strengthening Mechanisms for Metals
Mechanism III – Strain Hardening
• Plastically deforming most metals at room temp. makes
them harder and stronger
• Phenomenon called "Strain hardening (or cold working)”
• Deformation—often reduction in cross-sectional area.
-Rolling
roll
Ad
Ao
roll
Chapter 8 - 24
Strain Hardening (cont.)
As %CW increases
• Yield strength (σy) increases.
• Tensile strength (TS) increases.
• Ductility (%EL or %AR) decreases.
Chapter 8 - 25
Strain Hardening (cont.)
Lattice strain interactions between dislocations
Chapter 8 - 26
Strain Hardening (cont.)
Dislocation Density and Cold Working
Chapter 8 - 27
Strain Hardening (cont.)
Mechanism of Strain Hardening
• Dislocation structure in Ti after cold working.
• Dislocation density increases
with deformation (cold work) by
formation of new dislocations
• As dislocation density
increases, distance between
dislocations decreases
• On average, disl.-disl. strain
interactions are repulsive
• Dislocation motion hindered by
presence of other dislocations
Copper
Cold
Work
Do = 15.2 mm Dd = 12.2 mm
Chapter 8 - 29
Example Problem (cont.)
• Solution:
Chapter 8 - 30
Example Problem (cont.)
• Yield and tensile strength, and ductility (%EL) are
determined graphically as shown below for %CW = 35.6%
60
700 800
ductility (%EL)
40
500 600
300 MPa Cu
300 Cu 400 340 MPa 20
Cu 7%
100 200 00
0 20 40 60 0 20 40 60 20 40 60
% Cold Work % Cold Work % Cold Work
tensile strength
500°C)
ductility (%EL)
50
500
3. Grain Growth (> 500°C)
40
Fig. 8.22, Callister & Rethwisch 5e.
(Adapted from G. Sachs and K. R. Van Horn,
400 30 Practical Metallurgy, Applied Metallurgy
and the Industrial Processing of Ferrous and
Nonferrous Metals and Alloys, 1940.
ductility 20 Reproduced by permission of ASM
International, Materials Park, OH.)
300
100 200 300 400 500 600 700
annealing temperature (°C) Chapter 8 - 32
Recovery
During recovery – reduction in disl. density – annihilation of disl.
• Scenario 1 extra half-plane
of atoms
Dislocation
atoms annihilation-
diffuse half-planes
to regions come together
of tension
extra half-plane
of atoms
• Scenario 2
3. “Climbed” disl. can now
move on new slip plane
2. grey atoms leave by
4. dislocations of opposite
vacancy diffusion
sign meet and annihilate
allowing disl. to “climb”
1. dislocation blocked; Obstacle dislocation
can’t move to the right
Chapter 8 - 33
Recrystallization
• New grains form that:
-- have low dislocation densities
-- are small in size
-- consume and replace parent cold-worked grains.
Recrystallized grains
Chapter 8 - 35
Recrystallization Temperature
TR = recrystallization temperature = temperature
at which recrystallization just reaches
completion in 1 h.
0.3Tm < TR < 0.6Tm
Chapter 8 - 36
Cold Working vs. Hot Working
Chapter 8 - 37
Grain Growth
• Grain growth occurs as heat treatment continues.
-- Average grain size increases
-- Small grains shrink (and ultimately disappear)
-- Large grains continue to grow
Chapter 8 - 39
Grain Growth (cont.)
• Empirical relationship—dependence of average grain
size (d) on heat treating time (t):
material constant
exponent typ. ~ 2 —depends on T
—independent of t
Chapter 8 - 40
Recovery, Recrystallization, & Grain Growth
Summary
TR = recrystallization
temperature
TR annealing time = 1 h
º
Chapter 8 - 41
Design Problem
Description of Diameter Reduction
Procedure
A cylindrical rod of brass originally 10 mm in diameter
is to be cold worked by drawing. The circular cross
section will be maintained during deformation. A cold-
worked tensile strength in excess of 380 MPa and a
ductility of at least 15 %EL are desired. Furthermore,
the final diameter must be 7.5 mm. Explain how this
may be accomplished.
Chapter 8 - 42
Design Problem (cont.)
Solution:
Brass
First compute the %CW. Cold
Work
D o = 10 mm D d = 7.5 mm
Chapter 8 - 43
Design Problem Solution (cont.)
60
800
40
600
540
400 20
6
200 0
0 20 40 60 0 20 40 60
% Cold Work % Cold Work Fig. 8.19, Callister
& Rethwisch 5e.
40
600
400 20
380 15
200 0
0 1220 40 60 0 20 27 40 60
% Cold Work % Cold Work Fig. 8.19, Callister
& Rethwisch 5e.
To meet criteria
—deformation requirement 12 < %CW < 27
Chapter 8 - 45
Design Problem Solution (cont.)
Procedure: Cold work, anneal, then cold work again.
• To meet criteria, for 2nd deformation step: 12 < %CW < 27
– We will deform to 20%CW
• Diameter after first cold work stage (but before 2nd cold work
stage), Di, calculated as follows:
Intermediate diameter =
Chapter 8 - 46
Design Problem Summary
Chapter 8 - 47
Mechanical Properties of Polymers –
Stress-Strain Behavior
brittle polymer
plastic
elastomer
elastic moduli
– less than for metals Adapted from Fig. 7.22,
Callister & Rethwisch 5e.
x plastic failure
Chapter 8 - 49
Mechanisms of Deformation —
Semicrystalline (Plastic) Polymers
σ(MPa) fibrillar
structure
Inset figures along plastic
x brittle failure
response curve adapted from near
Figs. 8.27& 8.28, Callister & onset of
failure
Rethwisch 5e. necking plastic failure
x
unload/reload
e
crystalline
block segments
separate
undeformed
structure amorphous
crystalline
regions
regions align
elongate
Chapter 8 - 50
Predeformation by Drawing
• Drawing…(ex: monofilament fishline)
-- stretches the polymer prior to use
-- aligns chains in the stretching direction
• Results of drawing:
-- increases the elastic modulus (E) in the
stretching direction
-- increases the tensile strength (TS) in the
stretching direction Adapted from Fig. 8.28,
-- decreases ductility (%EL) Callister & Rethwisch 5e.
Chapter 8 - 51
Mechanisms of Deformation—
Elastomers
σ(MPa)
x brittle failure Stress-strain curves
adapted from Fig. 7.22,
Callister & Rethwisch 5e.
Inset figures along
elastomer curve (green)
adapted from Fig. 8.30,
plastic failure
x Callister & Rethwisch 5e.
(Fig. 15.15 adapted from Z. D.
Jastrzebski, The Nature and
x Properties of Engineering
Materials, 3rd edition.
elastomer Copyright © 1987 by John
Wiley & Sons, New York.
final: chains Reprinted by permission of
John Wiley & Sons, Inc.)
ε
are straighter,
still
cross-linked
initial: amorphous chains are deformation
kinked, cross-linked. is reversible (elastic)!
Chapter 8 - 53
Summary (cont.)
Chapter 8 - 54
ANNOUNCEMENTS
Reading:
Core Problems:
Self-help Problems:
Chapter 8 - 55