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    M3 Jismo Maret 2021

    Uploaded by

    Dianar Pauwcu
    The document contains several math word problems and geometry diagrams with calculations. It discusses triangle inequalities, counting numbers in ranges, ratios involving beakers of water and sugar, and solving systems of linear equations for unknown variables like the length of a rope. The final calculated length is 360.

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    © All Rights Reserved
    Download as PPTX, PDF, TXT or read online from Scribd

    M3 Jismo Maret 2021

    Uploaded by

    Dianar Pauwcu
    747 views22 pages
    The document contains several math word problems and geometry diagrams with calculations. It discusses triangle inequalities, counting numbers in ranges, ratios involving beakers of water and sugar, and solving systems of linear equations for unknown variables like the length of a rope. The final calculated length is 360.

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    The document contains several math word problems and geometry diagrams with calculations. It discusses triangle inequalities, counting numbers in ranges, ratios involving beakers of water and sugar, and solving systems of linear equations for unknown variables like the length of a rope. The final calculated length is 360.

    Copyright:

    © All Rights Reserved
    Download as PPTX, PDF, TXT or read online from Scribd
    Download as pptx, pdf, or txt
    747 views22 pages

    M3 Jismo Maret 2021

    Uploaded by

    Dianar Pauwcu
    The document contains several math word problems and geometry diagrams with calculations. It discusses triangle inequalities, counting numbers in ranges, ratios involving beakers of water and sugar, and solving systems of linear equations for unknown variables like the length of a rope. The final calculated length is 360.

    Copyright:

    © All Rights Reserved
    Download as PPTX, PDF, TXT or read online from Scribd
    Download as pptx, pdf, or txt
    of 22

    M4 JISMO

    Tuesday, 26 Oct 2021


    Keliling = 18 + 18 + 12 + 12 + 6 + 5 + 5 + 6 = 82
    b l

    b
    l

    b Keliling = 2 length + 2 breadth = 2 x (length + breadth)


    96 = 2 x (length + breadth)
    l b 48 = length + breadth
    4 length + 4 breadth = 4 x (length + breadth)
    = 4 x 48
    = 192
    Maret = 31 hari
    April = 30 hari
    Mei = 31 hari
    Juni = 30 hari
    Juli = 31 hari
    Agustus = 31 hari
    September = 11 hari

    30 hari 153 hari 11 hari 15 min 1 h 28 min

    1 Maret 31 Maret 31 Agustus 11 Sept 11 Sept 11 Sept


    9.45 9.45 9.45 9.45 10.00 11.28
    +  x = 222
    - x = 210 –
    2x = 12
    X=6
    A B C D E

    +4 x4 +4 x4 +4 x4 +4 x4 +4 x4

    A = 148 x 4 = 592
    B = 592 + 4 = 596
    C = 596 x 4 = 2384
    D = 2384 + 4 = 2388
    E = 2388 x 4 = 9552
    Selisih 9552 – 2388 = 7164
    (A x 20)+18

    (A + 18) x 20 = 600
    (A + 18) = 600 : 20
    (A + 18) = 30
    A = 30 – 18
    = 12
    (A x 20)+18 = (12x20)+18 = 240 + 18 = 258
    Iblis = bohong
    Malaikat = jujur
    12 j + k = 1100
    17 j + k 1500
    5 jeruk = 400
    1 jeruk = 400 : 5 = 80
    12 jeruk = 80 x 12 = 960
    960 + k = 1100
    K = 1100 – 960
    = 140
    48 48

    24 24 24 24
    12 12 24 24
    24

    12 12
    x
    2x
    x
    x 2x
    3x
    20 20

    5x = 20
    X=4
    3x = 3 x 4 = 12
    Panjang = 12 + 20+ 20 =52
    ◦ According to the first triangle inequality theorem, the
    lengths of any two sides of a triangle must add up to
    more than the length of the third side
    ◦ 3 + 6 > 7 (correct)
    ◦ 3 + 6 > 10 (incorrect)
    ◦ 4 + 6 > 7 (correct)
    ◦ 6 + 7 > 10 (correct)
    1-9 = 9 angka
    10-99 = 20 x 9 = 180
    100-200 = 101 x 3 = 303
    201 – 300 = 100 x 3 = 300
    301 – 333 =33 x 3 = 99
    Total = 891
    Kemarin = x
    Hari ini = 3x + 7
    X + 3x + 7 = 87
    4x + 7 = 87
    4x = 87 – 7
    4x = 80
    X = 20
    3 (20) + 7 = 67
    Beaker = 25
    Air = 70
    Gula = 10
    Air 70 g+ gula 10 g + gula 5 g= 85

    Air+gula=105-25=80
    Air + gula 5 g= 85
    X9
    X8
    X7
    X6
    X5
    x3
    800 : 40 = 20
    4 x 20 = 80
    A sejajar dengan 2 = 13-2 = 11
    B sejajar dengan 7 = 13 – 7 = 6
    C sejajar dengan 10 = 13-10=3
    A + B x C = 11 + 6 x 3
    = 11 + 18
    = 29
    2x + 140 = 3x + 30
    140 – 30 = x
    X = 110
    Panjang tali = 3x + 30
    = 3 (110) + 30
    = 360

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