Chapter 8: Natural Convection: Contents
Chapter 8: Natural Convection: Contents
Chapter 8: Natural Convection: Contents
Contents:
1. Physical consideration, governing equation
2. Analysis of vertical, horizontal & inclined plates
3. Analysis of cylinder, sphere & enclosures
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Chapter 8 : Natural Convection
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Chapter 8 : Natural Convection
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Thermal expansion coefficient / Volume
expansion coefficient: Variation of the density of
a fluid with temperature at constant pressure.
Ideal gas
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Rayleigh Number, Ra=Gr.Pr
• In fluid mechanics, the Rayleigh number for a fluid is a
dimensionless number associated with buoyancy driven flow
(also known as free convection or natural convection).
• When the Rayleigh number is below the critical value for that
fluid, heat transfer is primarily in the form of conduction; when it
exceeds the critical value, heat transfer is primarily in the form of
convection.
• The Rayleigh number is defined as the product of
the Grashof number, which describes the relationship
between buoyancy and viscosity within a fluid, and
the Prandtl number, which describes the relationship
between momentum diffusivity and thermal diffusivity.
• Hence the Rayleigh number itself may also be viewed as the ratio
of buoyancy and viscosity forces times the ratio of momentum
and thermal diffusivities. 6
Forced vs Natural Convection
• When analyzing potentially mixed convection, a parameter
called the Archimedes number(Ar) parametrizes the
relative strength of free and forced convection.
• The Archimedes number is the ratio of Grashof number
and the square of Reynolds number, which represents the
ratio of buoyancy force and inertia force, and which stands
in for the contribution of natural convection.
• When Ar >> 1, natural convection dominates and when Ar
<< 1, forced convection dominates.
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Chapter 8 : Natural Convection
2)
3)
*The smooth and parallel lines in (a) indicate that the flow is
laminar, whereas the eddies and irregularities in (b) indicate
that the flow is turbulent.
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Chapter 8 : Natural Convection
Eq. (9.24)
where,
Laminar 104 RaL 109 C = 0.59 n = 1/4
Turbulent 109 RaL 1013 C = 0.10 n = 1/3
• For wide range and more accurate solution, use correlation Churchill and Chu
Eq. (9.26)
Eq. (9.27)
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Chapter 8 : Natural Convection
• For case of vertical cylinders, the previous Eqs. ( 9.24 to 9.27) are valid if the
condition satisfied where
• at the top and bottom surfaces of cooled and heated inclined plates, respectively,
it is recommended that
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Chapter 8 : Natural Convection
Example:
Consider a 0.6m x 0.6m thin square plate in a room at 30C. One side of the
plate is maintained at a temperature of 90C, while the other side is insulated.
Determine the rate of heat transfer from the plate by natural convection if the
plate is vertical.
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Chapter 8 : Natural Convection
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Chapter 8 : Natural Convection
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Chapter 8 : Natural Convection
Example:
Consider a 0.6m x 0.6m thin square plate in a room at 30C. One side of the plate is
maintained at a temperature of 90C, while the other side is insulated. Determine the rate
of heat transfer from the plate by natural convection if the plate is
i) Vertical
ii) Horizontal with hot surface facing up
iii) Horizontal with hot surface facing down
Which position has the lowest heat transfer rate ? Why ?
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Chapter 8 : Natural Convection
• The boundary layer over a hot horizontal cylinder starts to develop at the bottom,
increasing in thickness along the circumference, and forming a rising plume at the top.
• Therefore, the local Nusselt number is highest at the bottom, and lowest at the top of the
cylinder when the boundary layer flow remains laminar.
• The opposite is true in the case of a cold horizontal cylinder in a warmer medium, and
the boundary layer in this case starts to develop at the top of the cylinder and ending with
a descending plume at the bottom.
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Chapter 8 : Natural Convection
Eq. (9.33)
where,
Eq. (9.34)
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Chapter 8 : Natural Convection
Spheres
• In case of isothermal sphere, general correlations is proposed by Churchill
Eq. (9.35)
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Chapter 8 : Natural Convection
Problem 9.54:
A horizontal uninsulated steam pipe passes through a large room whose walls and ambient
air are at 300K. The pipe of 150 mm diameter has an emissivity of 0.85 and an outer
surface temperature of 400K. Calculate the heat loss per unit length from the pipe.
1. Schematic
2. Assumptions
3. Fluid properties
- Calculate RaD
- Calculate NuD
- Calculate hD *If use Eq. 9.33, hD = 6.15 W/m2K Within 4%
- finally, calculate total heat loss, q’ *If use Eq. 9.34, hD = 6.38 W/m2K
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Chapter 8 : Natural Convection
Enclosures are frequently encountered in practice, and heat transfer through them is of practical interest.
Fluid properties at
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Chapter 8 : Natural Convection
- Flow is characterised by RaD value
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Chapter 8 : Natural Convection
Nu = 1
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Chapter 8 : Natural Convection
Selection will be determined by the value of RaL, Pr and aspect ratio H/L:
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Chapter 8 : Natural Convection
For larger aspect ratios, the following correlations have been proposed:
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Chapter 8 : Natural Convection
Example:
The vertical 0.8m high, 2m wide double pane window consists of two
sheet of glass separated by a 2 cm air gap at atmospheric pressure. If
the glass surface temperatures across the air gap are measured to be
12C and 2C, determine the rate of heat transfer through the window.
1. Schematic
2. Assumptions
3. Fluid properties at Tavg
4. Analysis of heat transfer
- Calculate RaD
- Calculate NuD
- Calculate h
- finally, calculate heat transfer
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Chapter 8 : Natural Convection
FC – forced convection
NC – natural convection
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