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Transport Decision

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The document discusses various transport strategy concepts including transport decisions, inventory strategy, location strategy, and freight consolidation. It also provides examples and analyses of transport service selection and vehicle routing problems.

Some of the typical transport decisions discussed include transport service selection, private fleet planning, vehicle routing from multiple points and coincident origin-destination points, and freight consolidation.

The methods discussed for selecting transport services include indirectly through network configuration, directly through channel simulation, and directly through a spreadsheet approach comparing alternatives based on cost types like transportation, in-transit inventory, source inventory, and destination inventory.

Transport Decisions

If you are planning for one year, grow rice. If you are planning for 20 years, grow trees. If you are planning for centuries, grow men. A Chinese proverb

Chapter 7
CR (2004) Prentice Hall, Inc.

7-1

Transport Decisions in Transport Strategy


Inventory Strategy Forecasting Inventory decisions Purchasing and supply Customer scheduling decisions service goals Storage fundamentals The product Storage decisions Logistics service Ord. proc. & info. sys.

Location Strategy Location decisions The network planning process

CR (2004) Prentice Hall, Inc.

CONTROLLING
7-2

ORGANIZING

PLANNING

Transport Strategy Transport fundamentals Transport decisions

Typical Transport Decisions


Transport Service selection Private fleet planning

- Vehicle routing - Routing from multiple points - Routing from coincident origin-destination points - Vehicle routing and scheduling
Freight consolidation
Just a few of the many problems in transportation
CR (2004) Prentice Hall, Inc.

7-3

Transport Service selection


Basic Cost Trade-Off - Balance performance effects on inventory against the cost of transport Methods for selection - Indirectly through network configuration - Directly through channel simulation - Directly through a spreadsheet approach as follows:
Cost types Transportation In-transit inventory Source inventory Destination inventory
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Alternatives Air Truck Rail

7-4

Mode/Service Selection (Contd)


Example Finished goods are to be shipped from a plant inventory to a warehouse inventory some distance away. The expected volume to be shipped in a year is 1,200,000 lb. The product is worth $25 per lb. and the plant and carrying costs are 30% per year.

Other data are:


Transport choice Rail Truck Air
CR (2004) Prentice Hall, Inc.

Rate, $/lb. 0.11 0.20 0.88

Transit time, days 25 13 1

Shipment size, lb. 100,000 40,000 16,000

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Transport Selection Analysis


Cost type Computation Rail .11(1,200,000) = $132,000 Truck .20(1,200,000) = $240,000 Air .88(1,200,000) = $1,056,000 TransRD portation In-transit ICDT inventory 365

[.30(25) [.30(25) [.30(25) 1,200,000(25)]/365 1,200,000(13)]/365 1,200,000(1)]/365 = $616,438 = $320,548 = $24,658 [.30(25) 100,000]/2 = $375,000 [.30(25.11) 100,000]/2 = $376,650 $1,500,088 [.30(25) 40,000]/2 = $150,000 [.30(25.20) 40,000]/2 = $151,200 $ 861,748 [.30(25) 16,000]/2 = $60,000 [.30(25.88) 16,000]/2 = $62,112 $1,706,770
7-6

ICQ Plant inventory 2


IC' Q Whse inventory 2
Include transport rate

Totals
CR (2004) Prentice Hall, Inc.

Improved service

Carrier Routing
Determine the best path between origin and destination points over a
network of routes

Shortest route method is efficient for finding the minimal cost route Consider a time network between Amarillo and Fort Worth. Find the
minimum travel time.

The procedure can be paraphrased as:


- Find the closest unsolved node to a solved node - Calculate the cost to the unsolved node by adding the accumulated cost to the solved node to the cost from the solved node to the unsolved node. - Select the unsolved node with the minimum time as the new solved node. Identify the link.
-

When the destination node is solved, the computations stop. The solution is found by backtracking through the connections made.
7-7

CR (2004) Prentice Hall, Inc.

Carrier Routing (Contd)


Origin Amarillo A 90 minutes 138 C 348 156 B 84 E 84

Oklahoma City I

66 90

120

132 126

60 H 126 132 48 J Destination Fort Worth

Can be a weighted index of time and distance


48 D Note : All link times are in minutes

150 G

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7-8

1 2

174

BE *

228

CF

258

EI*

288

FH

294

CD

384

IJ*

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Shortest Route Method


7-9

Step

Solved Nodes Directly Connected to Unsolved Nodes A A B A B C A C E A C E F A C F I A C F H I H I

Its Closest Connected Unsolved Node B C C D E F D F I D D I H D D H J D D G G J J J

Total Cost Involved 90 138 90+66=156 348 90+84=174 138+90=228 348 138+90=228 174+84=258 348 138+156=294 174+84=258 228+60=288 348 138+156=294 228+60= 288 258+126=384 348 138+156=294 288+132=360 288+48=336 258+126=384 288+126=414 258+126=384

nth Nearest Node B C

Its Minimu m Cost 90 138

Its Last Connection a AB * AC

MAPQUEST SOLUTION

Mapquest at www.mapquest.com
CR (2004) Prentice Hall, Inc.

7-10

Routing from Multiple Points


This problem is solved by the traditional transportation method of linear programming
4a Supplier A Supply 400 6 5 5 Supplier B Supply 700 5 9 5 8 Supplier C Supply 500
a

Plant 1 Requirements = 600

Plant 2 Requirements = 500

Plant 3 Requirements = 300

CR (2004) Prentice Hall, Inc.

. The transportation rate in $ per ton for an optimal routing between supplier A and plant 1 7-11

TRANLP problem setup

Solution

CR (2004) Prentice Hall, Inc.

7-12

Routing with a Coincident Origin/Destination Point


Typical of many single truck routing problems from a single depot. Mathematically, a complex problem to solve efficiently. However, good routes can be found by forming a route pattern where the paths do not cross a "tear drop" pattern.

D
Depot (a) Poor routing-paths cross

D
Depot (b) Good routing-no paths cross

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7-13

Single Route Developed by ROUTESEQ in LOGWARE


Y coordinates 8 8 Y coordinates 9 10 13 16 19 7 6 4

7
6 5 42

9
10 6 8 5

13 16
19 15 18 20

6
8

15
18 D 12

20 5
42 3 2 3

3
2 3

17

12

17

1
01 0

7 1 2

11 14

1 7
01 8 0 1 2

11 14 6 7 8

3 4 5 X coordinates

3 4 5 X coordinates

(a) Location of beverage accounts and distribution center (D) with grid overlay
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(b) Suggested routing pattern


7-14

Multi-Vehicle Routing and Scheduling


A problem similar to the single-vehicle routing
problem except that a number of restrictions are placed on the problem. Chief among these are: A mixture of vehicles with different capacities Time windows on the stops Pickups combined with deliveries Total travel time for a vehicle

CR (2004) Prentice Hall, Inc.

7-15

Practical Guidelines for Good Routing and Scheduling


1. Load trucks with stop volumes that are in closest proximity to each other

Stops

D Depot (a) Weak clustering CR (2004) Prentice Hall, Inc.

D Depot (b) Better clustering

7-16

Guidelines (Contd)
2. Stops on different days should be arranged to produce tight clusters
F F F F Stop F T T T T F F T F T T F F T T F F F F T T T T T

May need to (a) Weak clustering-- coordinate with routes cross sales to achieve clusters
CR (2004) Prentice Hall, Inc.

D Depot

D Depot (b) Better clustering

7-17

Guidelines (Contd)
3. Build routes beginning with the farthest stop from the depot 4. The stop sequence on a route should form a teardrop pattern (without time windows) 5. The most efficient routes are built using the largest vehicles available first

6. Pickups should be mixed into delivery routes rather than assigned to the end of the routes
7. A stop that is greatly removed from a route cluster is a good candidate for an alternate means of delivery 8. Narrow stop time window restrictions should be avoided (relaxed)
7-18

Application of Guidelines to Casket Distribution

Warehouse Funeral home


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Typical weekly demand and pickups

7-19

Application of Guidelines to Casket Distribution (Contd)


Territories of equal size to minimize number of trucks

Warehouse Funeral home


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Division of sales territories into days of the week

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Application of Guidelines to Casket Distribution (Contd)

Warehouse Funeral home


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Route design within territories

7-21

Sweep Method for VRP


Example A trucking company has 10,000-unit vans for merchandise pickup to be consolidated into larger loads for moving over long distances. A days pickups are shown in the figure below. How should the routes be designed for minimal total travel distance?

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7-22

Stop Volume and Location


Geographical region 1,000 4,000 3,000 2,000 3,000 3,000 2,000 Pickup points

2,000

1,000

Depot 2,000

2,000 2,000

CR (2004) Prentice Hall, Inc.

7-23

Sweep Method Solution


Sweep direction is arbitrary
Route #1 1,000 10,000 units 4,000 3,000 2,000 3,000 3,000 2,000 Route #3 8,000 units

2,000

1,000 2,000

Depot
2,000 2,000

Route #2 9,000 units


CR (2004) Prentice Hall, Inc.

7-24

The Savings Method for VRP


Stop
dA,0 A d0,A B d0,A 0 Depot dB,0

A dA,B B

0
Depot dB,0

d0,B

Stop (a) Initial routing (b) Combining two stops on a route Route distance = d 0,A +dA,0 +d0,B + dB,0 Route distance = d 0,A +dA,B +dB,0

CR (2004) Prentice Hall, Inc.

Savings is better than Sweep methodhas lower average error

7-25

Savings Method Observation


The points that offer the greatest savings when combined on the same route are those that are farthest from the depot and that are closest to each other.

This is a good principle for constructing multiple-stop routes


CR (2004) Prentice Hall, Inc.

7-26

Route Sequencing in VRP


AM 8 Truck #1 Truck #2 Truck #3 Truck #4 Truck #5 9 10 Route #1 Route #9 Route #5 Route #2 Route #7 Route #3 11 12 1 Route #10 2 PM 3 4 5 Route #6 6

Route #4 Route #8

Minimize number of trucks by maximizing number of routes handled by a single truck


CR (2004) Prentice Hall, Inc.

7-27

Freight Consolidation
Combine small shipments into larger
ones

A problem of balancing cost savings


against customer service reductions

An important area for cost reduction in


many firms

Based on the rate-shipment size


relationship for for-hire carriers
CR (2004) Prentice Hall, Inc.

7-28

Freight Consolidation Analysis


Suppose we have the following orders for the next three days. From: Ft Worth Day 1 To: Topeka 5,000 lb. Kansas City 7,000 Wichita 42,000 Day 2 25,000 lb. 12,000 38,000 Day 3 18,000 lb. 21,000 61,000

Consider shipping these orders each day or consolidating them into one shipment. Suppose that we know the transport rates.
Note: Rates from an interstate tariff
CR (2004) Prentice Hall, Inc.

7-29

Freight Consolidation Analysis (Contd)


Separate shipments Topeka Kansas City Wichita
a

Day 1 Rate x volume = cost 3.42 x 50 = $171.00 3.60 x 70 = 252.00 0.68 x 420 = 285.60 Total $708.60

Day 2 Rate x volume = cost 1.14 x 250 = $285.00 1.44 x 120 = 172.80 a 0.68 x 400 = 272.00 Total $729.80

Ship 380 cwt., as if full truckload of 400 cwt.

Day 3 Rate x volume = cost Topeka Kansas City Wichita 1.36 x 180 = $244.80 1.20 x 210 = 252.00 0.68 x 610 = 414.80

Totals $700.80 676.80 972.40

Total
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$911.60

$2,350.00
7-30

Freight Consolidation Analysis (Contd)


Consolidated shipment

Computing transport cost for one combined, three-day shipment


Day 3 Rate x volume = cost Topeka Kansas City Wichita
a

0.82 x 480 = $393.60 0.86 x 400 = 344.00 0.68 x 1410 = 958.80

Total
480 = 50 + 250 + 180

$1,696.40
Cheaper, but what about the service effects of holding early orders for a longer time to accumulate larger shipment sizes?

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7-31

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