Transport Decision
Transport Decision
Transport Decision
If you are planning for one year, grow rice. If you are planning for 20 years, grow trees. If you are planning for centuries, grow men. A Chinese proverb
Chapter 7
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CONTROLLING
7-2
ORGANIZING
PLANNING
- Vehicle routing - Routing from multiple points - Routing from coincident origin-destination points - Vehicle routing and scheduling
Freight consolidation
Just a few of the many problems in transportation
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[.30(25) [.30(25) [.30(25) 1,200,000(25)]/365 1,200,000(13)]/365 1,200,000(1)]/365 = $616,438 = $320,548 = $24,658 [.30(25) 100,000]/2 = $375,000 [.30(25.11) 100,000]/2 = $376,650 $1,500,088 [.30(25) 40,000]/2 = $150,000 [.30(25.20) 40,000]/2 = $151,200 $ 861,748 [.30(25) 16,000]/2 = $60,000 [.30(25.88) 16,000]/2 = $62,112 $1,706,770
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Totals
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Improved service
Carrier Routing
Determine the best path between origin and destination points over a
network of routes
Shortest route method is efficient for finding the minimal cost route Consider a time network between Amarillo and Fort Worth. Find the
minimum travel time.
When the destination node is solved, the computations stop. The solution is found by backtracking through the connections made.
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Oklahoma City I
66 90
120
132 126
150 G
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1 2
174
BE *
228
CF
258
EI*
288
FH
294
CD
384
IJ*
Step
Total Cost Involved 90 138 90+66=156 348 90+84=174 138+90=228 348 138+90=228 174+84=258 348 138+156=294 174+84=258 228+60=288 348 138+156=294 228+60= 288 258+126=384 348 138+156=294 288+132=360 288+48=336 258+126=384 288+126=414 258+126=384
MAPQUEST SOLUTION
Mapquest at www.mapquest.com
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. The transportation rate in $ per ton for an optimal routing between supplier A and plant 1 7-11
Solution
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D
Depot (a) Poor routing-paths cross
D
Depot (b) Good routing-no paths cross
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7
6 5 42
9
10 6 8 5
13 16
19 15 18 20
6
8
15
18 D 12
20 5
42 3 2 3
3
2 3
17
12
17
1
01 0
7 1 2
11 14
1 7
01 8 0 1 2
11 14 6 7 8
3 4 5 X coordinates
3 4 5 X coordinates
(a) Location of beverage accounts and distribution center (D) with grid overlay
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Stops
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Guidelines (Contd)
2. Stops on different days should be arranged to produce tight clusters
F F F F Stop F T T T T F F T F T T F F T T F F F F T T T T T
May need to (a) Weak clustering-- coordinate with routes cross sales to achieve clusters
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D Depot
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Guidelines (Contd)
3. Build routes beginning with the farthest stop from the depot 4. The stop sequence on a route should form a teardrop pattern (without time windows) 5. The most efficient routes are built using the largest vehicles available first
6. Pickups should be mixed into delivery routes rather than assigned to the end of the routes
7. A stop that is greatly removed from a route cluster is a good candidate for an alternate means of delivery 8. Narrow stop time window restrictions should be avoided (relaxed)
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2,000
1,000
Depot 2,000
2,000 2,000
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2,000
1,000 2,000
Depot
2,000 2,000
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A dA,B B
0
Depot dB,0
d0,B
Stop (a) Initial routing (b) Combining two stops on a route Route distance = d 0,A +dA,0 +d0,B + dB,0 Route distance = d 0,A +dA,B +dB,0
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Route #4 Route #8
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Freight Consolidation
Combine small shipments into larger
ones
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Consider shipping these orders each day or consolidating them into one shipment. Suppose that we know the transport rates.
Note: Rates from an interstate tariff
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Day 1 Rate x volume = cost 3.42 x 50 = $171.00 3.60 x 70 = 252.00 0.68 x 420 = 285.60 Total $708.60
Day 2 Rate x volume = cost 1.14 x 250 = $285.00 1.44 x 120 = 172.80 a 0.68 x 400 = 272.00 Total $729.80
Day 3 Rate x volume = cost Topeka Kansas City Wichita 1.36 x 180 = $244.80 1.20 x 210 = 252.00 0.68 x 610 = 414.80
Total
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$911.60
$2,350.00
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Total
480 = 50 + 250 + 180
$1,696.40
Cheaper, but what about the service effects of holding early orders for a longer time to accumulate larger shipment sizes?
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