TMA 01 For Scrib

Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Questio
n
Q1 a)
Q1 b)
A = (Total number of boys and girls in aged group 3 ) 11

A = 19 11
A=8
Therefore number of Girls (A) of age 3 are 8
Percentage of children at the nursery who are aged group 0-2 years are
Total number of children of 02 year aged

33
X 100 =
Totalnumber of childrenat the nursery
60
Q1 c)
Mark
s
Answers
X 100 = 55%
Total number of Children aged three or four = 19 + 8 = 27

1/3rd of these children aged three or four to be boys to hold true the following should be the case
1
3
X 27 = 9
But from the table 1, Total number of Boys aged three or four = 11 + 3 = 14.
Hence the statement that 1/3rd of the children aged three or four are boys is false.
Q1 d)
Total number of children at the nursery = 60

Number of children as a fraction of the total number of children =
Q1 e)
70% of the total number of children =
70
100
8
60
4
30
2
15
x 60 = 42
Therefore, no of children attending on a part time basis is 42.

Q 1f)
Predicted increase in the total number of children = 74 60 = 14

Therefore percentage increase in the number of children would be =
14
total number of children origianlly
=
14
60
x 100
x 100 = 23.33%
Percentage increase in the total number of children for next year would be 23% (nearest whole number)
Q 2 a)
Price of Litre of smoothie is 2.39

Offer 1 is 25% off the normal price
Final price of smoothie after 25% reduction =
(10025)
x 2.39
100
= 0.75 x 2.39
= 1.79
2 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Hence the final price of smoothie under offer 1) is 1.79/-
Q 2bi)
Offer 2 is 25% extra of a litre of smoothie

Therefore Volume of extra smoothie =
(100+25)
x 1.0 litres = 125/100 = 1.25litres
100
Hence total volume of extra smoothie = 1.25 litres

Q 2bii)
Total volume of smoothie under offer 2 = 1.25 litres from Q2 bi)

Assuming full price for smoothie is 2.39
Assuming price per litre is X
1.25Litres - 2.39
1.0 Litres - X
X=
1 x 2.39
1.25
=1.03
X = 1.0 (to 1s.f)

Price per litre of smoothie under offer 2) is 1.0
Q 2ci)
Assuming under offer 3 each cartoon of smoothie is 1.0 litre

Hence for 4 you buy 2 litres
Therefore the price per litre of smoothie is
4 x1
2
= 2.
Hence the price per litre of smoothie is 2.0/Q 2cii)
Usual price per litre of smoothie is 2.39

Under offer 3) price per litre of smoothie is 2.0
Difference in price = 2.39 - 2.0 = 0.39
Percentage decrease in price
0.39
2.39
x 100 = 16.31% = 16% (to the nearest whole percent)
3 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Q 3a)
1cm 80,000cm which is 0.80km

Distance on the map from Gravesend to Sevenoaks is 33.5cm
Assume the actual distance on the ground is X
1cm 80,000cm
33.5cm X
Hence X =
33.5 x 80,000
1
= 2,680,000cms =
2680000
100000
= 26.8Kms
The actual distance on the ground is 26.8kms from Gravesend to Sevenoaks

Q3 bi)
Total distance from Gravesend to Tonbridge via Sevenoaks is 36Kms

Total Journey time is 42minutes
Speed =
Distance
time
36
42
= 0.8571 km/min = 0.8571 x 60 Km/hour = 51.43km/hr ( to 2 d.p)
Hence average speed to the nearest 10Km/hr = 514.3km/hr ( to 1 d.p)

Q3 bii)
Total distance from Gravesend to Tonbridge via Sevenoaks is 36Kms =36 x 1000 = 36,000m
Total Journey time is 42minutes which is 42 x 60 = 2,520 secs
Speed =
Q 3ci)
Distance
time
36,000
2520
= 14.28 m/sec = 14m/sec
Cost of the fuel is 1.45 per litre.

Total distance is 36kms
Car consumption for the 36km is 2.3 litres
1 litre is 1.45
2.3 litre is X
Therefore X = 1.45 x 2.3 = 3.3
The cost of fuel for the entire journey is 3.3
4 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Q 3cii)
The total journey consumes 2.3 litres of fuel

36km 2.3 litres
X 1.0 litres
X=
36
2.3
= 15.6
On a litre of fuel it can travel 16Kms (Nearest whole number)

Q 3di)
Q 3dii)
The scale below is for the pounds

Assume A = for the fuel efficient car cost in pounds
Assume B = for older model
2.1
C 5.2
5 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Q4 i)
Flooring Price p
(/m2)
Costs C () for
22m2
10
15
20
25
30
35
110
220
330
440
550
660
770
Q4 ii)
Question 4 - a-ii
900
800
700
600
500
Costs C ()
Flooring Price p (/m2)
400
300
200
100
0
0
10
15
20
25
30
35
40
Flooring Price p (/m2)
Q4 iii)
Starting at 400 on the Y-Axis, the price per square meter of flooring that would cost me 400 is 18
Q4 bi)
The formula is T = 23.98b + 3.5(b-1) + 18.99

B = Boxes of vinyl tiles ( 15 boxes)
6 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Q4 bii)
T = 23.98 x 15 + 3.5(15-1) +18.9

= 359.7+ 3.5(14)+18.9
= 359.7+49+8.9
= 417.6
Hence the total cost in pounds for buying 15 boxes is 417.6/- only
The formula is T = 23.98b + 3.5(b-1) + 18.99
It costs 18.99 for the first box which is a constant
Thereafter for subsequent boxes delivery is 3.5(b-1) which excludes the first box and cost 3.5 per box.
Per box cost 23.98 hence for b number of boxes 23.98b
Hence the Formula for the total cost 23.98b + 3.5(b-1) + 18.99
Q 4ci)
Cost of Graham is 5.0 per hour

Cost per visit is 14.0
Graham takes 17hours over 3 visits.
Hence the Cost of Graham fitting the floor would be
=( 5 per hour x 17 hours ) + ( 3 visits x 14 per visit)
= 85 + 42
= 127
Q 4cii)
Graham worked h hours.

Graham had v visits.
Hence the formula would be
= 5h + 3v
7 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
Q 5a i)
Given
A = 36 +
6
B
4B
6
3
4*3
When B=3
A = 36 +
= 36 +2 12
= 26
Q 5a ii)
Given
A = 36 +
6
B
4B
When B=-1.5, Following the BIDMAS rule

A = 36+(
= 36 -
6
1.5 )+ 4*(-1.5)
6
1.5
+6
= 36-4+6
=36+6-4
= 42-4
=38
Q 5b i)
The student should have multiplied as per the BIDMAS rule.
Q 5b ii)
While Solving Equations, Always the rule is to follow BIDMAS.

What happened above is Substraction was carried out before the Multiplication and the -1x -1 gives = 1
Calucations have to be made in the following order
A = 36 +
6
B
4B
When B=-1.5, Following the BIDMAS rule

A = 36+(
= 36 -
6
1.5 )+ 4*(-1.5)
6
1.5
+6
= 36-4+6
=36+6-4
= 42-4
=38
8 of 9
Name: ABC
Module Code: MU123
PI Number: XYZ
TMA - 01
9 of 9

TMA 01 For Scrib

Uploaded by

Copyright:

Available Formats

TMA 01 For Scrib

Uploaded by

Document Information

Original Description:

Original Title

Copyright

Available Formats

Share this document

Share or Embed Document

Sharing Options

Did you find this document useful?

Is this content inappropriate?

Copyright:

Available Formats

TMA 01 For Scrib

Uploaded by

Copyright:

Available Formats

Name: ABC

Module Code: MU123

A = (Total number of boys and girls in aged group 3 ) 11

Total number of children of 02 year aged

Total number of Children aged three or four = 19 + 8 = 27

Total number of children at the nursery = 60

Therefore, no of children attending on a part time basis is 42.

Predicted increase in the total number of children = 74 60 = 14

Price of Litre of smoothie is 2.39

Module Code: MU123

Hence the final price of smoothie under offer 1) is 1.79/-

Offer 2 is 25% extra of a litre of smoothie

Hence total volume of extra smoothie = 1.25 litres

Total volume of smoothie under offer 2 = 1.25 litres from Q2 bi)

X = 1.0 (to 1s.f)

Assuming under offer 3 each cartoon of smoothie is 1.0 litre

Hence the price per litre of smoothie is 2.0/Q 2cii)

Usual price per litre of smoothie is 2.39

x 100 = 16.31% = 16% (to the nearest whole percent)

Module Code: MU123

1cm 80,000cm which is 0.80km

The actual distance on the ground is 26.8kms from Gravesend to Sevenoaks

Total distance from Gravesend to Tonbridge via Sevenoaks is 36Kms

= 0.8571 km/min = 0.8571 x 60 Km/hour = 51.43km/hr ( to 2 d.p)

Hence average speed to the nearest 10Km/hr = 514.3km/hr ( to 1 d.p)

= 14.28 m/sec = 14m/sec

Cost of the fuel is 1.45 per litre.

Module Code: MU123

The total journey consumes 2.3 litres of fuel

On a litre of fuel it can travel 16Kms (Nearest whole number)

The scale below is for the pounds

Module Code: MU123

Flooring Price p (/m2)

Flooring Price p (/m2)

The formula is T = 23.98b + 3.5(b-1) + 18.99

Module Code: MU123

T = 23.98 x 15 + 3.5(15-1) +18.9

Cost of Graham is 5.0 per hour

Graham worked h hours.

Module Code: MU123

When B=-1.5, Following the BIDMAS rule

The student should have multiplied as per the BIDMAS rule.

While Solving Equations, Always the rule is to follow BIDMAS.

When B=-1.5, Following the BIDMAS rule

Module Code: MU123

You might also like