Organic Chemistry Notes
Organic Chemistry Notes
Organic Chemistry Notes
of an aton or
Substituted reactions: involves replacement or substitution
of atoms
group of atoms in an organic molecule by another atom or group
molecule.
without change in the remaining part of the
For example: CH,CI + HCI
CH, + Cl,
CH, + CI
CHs
Nu
CH-Nu
CH;CH,
CH,CH
(R)-2-bromobutane (S)-2-butanol
Start with the (R-2-bromobutane. The SN2 reaction produces only one
enantiomer of the 2-butanol produCt, and it is
configuration of the product is supposed to bepredictable that the
S because of the
configuration inversion.
TS.
CH,Br + OH
CH,OH Br
Reaction coordinate
Eas Ea,
Interrnediate
CH, CHH,
(CH),Brt:OH |+:Br
Reactants 2H H,
(CH).C OH +Br
Product
Reaction co-ordinates
Energy profile diagram of alkaline hydrolysis of t-butyl bromide by SN!
mechanism.
lut The connection between the first two curves represent the
carbocation
intermediate. Generally, the intermediate is the product of one step of a
reaction and the reactant for the next step. The intermediate is at a
relatively lower energy level compared to the transition state (which is at the
peak ofa curve), but the intermediate is also highly reactive and unstable.
B. Sc. II SEMESTER
YCM
carbonium ion (CH-CH-CH), which is more stable than primary
carbonium ion (CH3-CHa'). The reason is, in tertiary carbonium ion three
electron releasing alkyl groups are attached to tertiary carbon atom which
easily neutralizes the positive charge compare to secondary and primary
carbonium ion. The order of reactivity of different alkyl halide is
Slow Fast
H Attack of nuclephilet4 H
from back side ofi l Transition sate
bromine atom
The first step which is slow involves the attack of nucleophile OH at
carbon atom of methy] bromide from back side of bromine atom to from an
intermediate transition state, In transition state carbon atom is partially
bonded to both OH and Br. The bromine atom develops a partial negative
charge since it has partially taken the bond and OH group also carries a
partial negative charge since it starts sharing of electrons in transition state.
The carbon hydrogen bonds are in one plane while c-OH and C-Br bonds
are petpendiçular to the plane and lie on opposite sides. Therefore in
product OH group occupies opposite position to that of bromine atom. This
step is Fate determining step and it depends on the concentration of the
reactants, methyl bromide and-OH. According to law of mass action the rate
is proportional to concentrations of reactant, hence it is second order
outilréaction. Also this step involves two reactant molecules hence it is
bimolecular reaction. In second step, which is final step, the nucleophile
OH form a complete bond with carbon atom and simultaneously bromine
atom detaches to give methyl alcohol.
Since the attack of nucleophile at carbon atom from back side of
bromine atom inversion (Walden) in configuration takes place.
B. Sc. I| SEMESTER 3 YCM
Toimolecular nucleophilic substitution reaction SN
CH; Aqueous KOH CH; A N U
CH;-C-CH,
Br
-- CH;-C-CH, + KBr
OH
Tertiary butyl bromide Tertiary butyl alcohol
Mechanism:
KOH
lonization K+OH
Step 1
CH, lonization
CH-C-CH, CH-CH+Br
Slow
Br
Tertiary butyl bromide Tertiary carbonium ion
First step is ionization of tertiary butyl bromide which is slow and rate
determining step. This step depends on the concentration of the reactant,
tertiaryibutyl bromide and according to law of mass action the rate is
proportional, to concentrations of reactant, hence it is first order reaction.
Also thís 'step involves only one reactant molecule hence it is unimolecular
h, reaction. In second step, which is final step, the nucleophile OH attacks the
tertiary carbonium ion to form tertiary butyl alcohol.
This reaction does not depend on the strength of the nucleopjhile.
Reactivity of alkyl halide in SNI reaction depends upon the stability of
carbonium ion formed as intermediate, Tertiary carboniumn ion (CH3-Q*-CH3)
is more stable than secondary H3