SCH3U Unit 1 Parctice Test For Onstudy 2020
SCH3U Unit 1 Parctice Test For Onstudy 2020
SCH3U Unit 1 Parctice Test For Onstudy 2020
39
4. Which statements are true about the atom of element
19
X ?
I. The element is yttrium
II. The element has 39 protons
III. The element has 20 neutrons
IV. The element has 19 electrons
6. Using the table below, determine the average atomic mass of magnesium.
Isotope Atomic mass ( Natural abundance (%)
Mg - 24 23.99 79%
Mg - 25 24.99 10%
Mg - 26 25.98 11%
a. 23. 99 d. 25.98
b. 24.31 e. 74.96
c. 24.98
a. two protons.
b. two lone pairs of electrons.
c. two paired valence electrons.
d. two bonding pairs of electrons.
e. two unpaired valence electrons
CHEMICAL
FORMULA CHEMICAL NAME
Molecular Compounds
Diphosphorus pentoxide
CCl4
rubidium selenide
GaI3
FeS
ammonium hydroxide
Li2SO4
magnesium phosphate
potassium chlorite
Onstudy SCH3U Unit 1 Practice Test
Acids
hydrobromic acid
H2CO3
pernitric acid
*you’ll have to think about the ion here
😊
17. Match the term on the left with the most appropriate definition on the right. (C,
8 marks)
i. Polar Covalent A The energy that is needed to remove an electron
Bond from a neutral atom.
ii. Isotopes B A chemical bond in which two electrons are
shared by two atoms.
iii. Electron Affinity C An arrangement of eight electrons in the valence
shell of an atom.
iv. Ionization Energy D A covalent bond between atoms that have
significantly different electronegativities. This
results in the electron pair being shared
unevenly.
v. Atomic Radius E The energy absorbed or released when an
electron is added to a neutral atom.
vi. Stable Octet G The distance from the nucleus of an atom to the
approximate outer boundary of the cloud-like
region of its electrons.
vii. Covalent Bond H Atoms of an element that are chemically similar
but have different numbers of neutrons and
thus, different mass numbers.
Onstudy SCH3U Unit 1 Practice Test
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Onstudy SCH3U Unit 1 Practice Test
22. The differences in the properties of compounds often reflect the type of
chemical bonding in the compound and its polarity. This is especially true for
molecular compounds that are composed of similar molecules but have
different properties (i.e. different boiling and melting points). Examine the
data for the compounds CH3Cl and CH4 shown in the table below
Compound Melting point (ºC) Boling point (ºC)
CH3Cl -97.7 -24.2
CH4 -182.5 -161.5
ANSWER KEY
1. a, 2. d, 3. b, 4. c, 5. a, 6. b, 7. c,
8. c, 9. e, 10. e, 11. d, 12. a, 13. b, 14. D
15.a
16. P2O5, carbon tetrachloride, Rb2Se, gallium iodide, Au2O3, iron (II) sulfide,
CoBr2, NH4OH, lithium sulfate, Mg3(PO4)2, KClO2, HBr, carbonic acid, HNO4.
17. i – D; ii – H; iii- E; iv – A; v – G; vi – C; vii – B; viii – J
18. A compound made up of non-metals, held together by covalent bonds.
19. First Ionization Energy increases across a period (from left to right)
b. For C – H bond, EN = 2.6 – 2.1 = 0.5 ∴ C-H bond is Polar Covalent (PC). However, the
bond dipoles cancel each other making the molecule of methane Non-Polar (NP). In other words,
the share of valence electrons is EVEN ∴ molecule is Non-Polar
For C-Cl bond , EN = 3.2 – 2.6 = 0.6 ∴ C-Cl bond is Polar Covalent(PC). The bond dipoles do
not cancel out, making the molecule of chloromethane Polar (P). In other words, the share of
valence electrons is UNEVEN ∴ molecule is Polar.
c. In Chloromethane, a polar molecule, London dispersion forces (weakest) and hydrogen bonding
are the intermolecular forces whereas in methane only London dispersion forces occur. This
stronger forces in chloromethane are responsible for the higher melting and boiling points
compared to those of methane.