9780 - Week 2 - Sound Waves
9780 - Week 2 - Sound Waves
9780 - Week 2 - Sound Waves
Class: SS 2
Subject: Physics.
Noise and music: Sound can be classified into noise and musical notes. Noise is due to
vibrations of irregular frequency such as the rattling of a wheel on a rough road.
Pitch of a note is its position on the musical scale. It is the degree of highness or lowness of
sound as perceived by the listener. Pitch depends on frequency.
Loudness is the magnitude of the sensation resulting from a sound reaching the ear. It
depends on the amplitude of vibration of the body.
Intensity is the rate of flow of sound energy per unit area perpendicular to the direction of
propagation of the sound waves.
Echoes : echo is a sound heard after the reflection of sound waves from a plane surface.
Reverberation is the perseverance of the sound after the source ceases. It is due to
multiple reflection or echo of the original sound.
Example: A man standing 510m away from a wall sounds a whistle, the echo from the
wall reaches him 3seconds later. Calculate the velocity of sound in air. (NECO 2000)
Solution:
Distance x= 510m
echo t =3s,
velocity v =?
vt =2x,
v =2x÷t = 2× 510÷3
=1020÷3
=340m/s.
Forced vibrations : vibrations that result from an external periodic force acting on a system
and setting vibrating at the same frequency as the external periodic force.
Harmonics : are whole number multiples of the fundamental frequency fo is the first
harmonic, 2fo,3fo etc are the second and third harmonics.
Overtones: are the next higher frequencies produced after the fundamental frequency by a
vibrating body overtone may or may not be harmonics of the fundamental. Stationary waves
are produced when two waves with the same frequency and amplitude travelling in opposite
directions are superposed. Nodes are points on a stationary waves which are at rest.
Antinodes are points where the amplitude of vibration is maximum.
fo = v÷2L
Example : find the frequency of the first harmonic of a piano string of length 1.5m. If the
velocity is 120m/s
Solution:
wavelength =2×L
= 120÷2×1.5
=120÷3
=40Hz .