CH-9 Super 30
CH-9 Super 30
CH-9 Super 30
Questions
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GYAANI KEEDA bhattdeepak454 https://t.me/gyannikeedamaths
Super 30 Questions
Some Application of Trigonometry
1. The length of the shadow of a tower on the plane ground is √3 times the height of
the tower. The angle of elevation of sun is:
(A) 45° (B) 30° (C) 60° (D) 90°
2. The tops of the poles of height 16 m and 10 m are connected by a wire of length l
metres. If the wire makes an angle of 30° with the horizontal, then 𝑙 =
(A) 26 𝑚 (B) 16 𝑚 (C) 12 𝑚 (D) 10 𝑚
3. A ladder leaning against a wall makes an angle of 60° with the horizontal. If the
foot of the ladder is 2.5 m away from the wall, then the length of the ladder is
(A) 3 𝑚 (B) 4 𝑚 (C) 5 𝑚 (D) 6 𝑚
4. If a tower is 30 m high, casts a shadow 10√3𝑚 long on the ground, then the angle
of elevation of the sun is
(A) 30° (B) 45° (C) 60° (D) 90°
5. A tower is 50 m high. When the sun’s altitude is 45° then what will be the length of
its shadow?
50
6. The length of shadow of a pole 50 m high is 𝑚 find the sun’s altitude.
√3
28. A vertical tower stands on a horizontal plane and is surmounted by a vertical flag
staff of height ℎ. At a point on the plane, the angles of elevation of the bottom and
the top of the flag staff are α and β, respectively. Prove that the height of the tower
ℎ tan 𝛼
is ( ).
tan 𝛽−tan 𝛼
29. A window of a house is h metres above the ground. From the window, the angles
of elevation and depression of the top and the bottom of another house situated on
the opposite side of the lane are found to be α and β, respectively. Prove that the
height of the other house is h ( 1 + tan α cot β ) metres.
30. The lower window of a house is at a height of 2 m above the ground and its upper
window is 4 m vertically above the lower window. At certain instant the angles of
elevation of a balloon from these windows are observed to be 60o and 30o,
respectively. Find the height of the balloon above the ground.
ANSWER’S
Q1. B Q15. 1268 m
Q2. C Q16. 7(√3) + 1 m
Q3. C Q17. 10√3𝑚, 40 𝑚
Q4. C Q19. 864 km/hr
Q5. 50 m Q20. 29.28 m
Q6. 60° Q21. 6 𝑚
Q7. 130 𝑚 Q22. 115.46 m
Q8. 25 m Q23. 58√3
Q9. 13.65 𝑚 Q24. ℎ𝑒𝑖𝑔ℎ𝑡 = 64.95 𝑚,
Q10. 315.46 m Q25. 1902 𝑚/ℎ (Approx)
Q11. 94.64 m 1
Q26. (i) tan 𝜃 =
Q12. 25√3 m √3
2
Q13. 100 m (ii) sec 𝜃 + 𝑐𝑜𝑠𝑒𝑐 𝜃 = +2
√3
Q14. 54 𝑚 Q30. 8 m