NATIONAL

SENIOR CERTIFICATE

GRADE 12

PHYSICAL SCIENCES
CONTROL TEST MARKING GUIDELINES
13 MARCH 2024

MARKS: 100

THIS MARKING GUIDELINE CONSISTS OF 11 PAGES

PHYSICAL SCIENCE GR. 12/TERM 1 2 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

QUESTION 1
1.1 C  (2)
1.2 B  (2)
1.3 B  (2)
1.4 C  (2)
1.5 D  (2)
1.6 B  (2)
1.7 A  (2)
1.8 B  (2)
1.9 D  (2)
1.10 B  (2)
[20]
QUESTION 2

2.1 A body will remain in its state of rest or motion at a constant velocity unless a (2)
non-zero resultant/net force acts on it. 

2.2 OPTION 1: OPTION 2:

Acceptable labels
F Fapplied/Force applied/FA 
Fg w/Fw/weight/mg/gravitational force 
N Normal (force)/Fnormal/FN 
f Friction/Ff/fk 
T FT/Tension 
(5)
Notes:
 Mark awarded for label and arrow.

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PHYSICAL SCIENCE GR. 12/TERM 1 3 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

 Do not penalise for length of arrow since drawing is not to scale.

 Any other additional force(s): 4/5
 If force(s) does/do not make contact with body: 4/5

2.3 OPTION 1 OPTION 2: SYSTEM APPROACH

For Q: 𝐅𝒏𝒆𝒕 = 𝒎𝒂
𝐅𝒏𝒆𝒕 = 𝒎𝒂 𝐅𝒏𝒆𝒕 = 𝟎 Any one 
𝐅𝒏𝒆𝒕 = 𝟎 Any one  𝐅𝒙 − 𝒇𝒌𝑸 − 𝒇𝒌𝑷 = 𝟎
𝑻 − 𝒇𝒌 = 𝟎 𝐅 𝐜𝐨𝐬 𝟑𝟎𝐨 − 𝟏 − 𝟐, 𝟓 = 𝟎 
𝑻 − 𝟏 = 𝟎 ∴ 𝐅 = 𝟒, 𝟎𝟒 𝐍 
𝑻=𝟏𝐍

NB: Maximum marks: 3/6

For P:
𝐅𝒏𝒆𝒕 = 𝒎𝒂
𝐅𝒏𝒆𝒕 = 𝟎
𝐅𝒙 − 𝑻 − 𝒇𝒌 = 𝟎
𝐅 𝐜𝐨𝐬 𝟑𝟎𝐨  − 𝟏 − 𝟐, 𝟓 = 𝟎
∴ 𝐅 = 𝟒, 𝟎𝟒 𝐍 
(6)

2.4 LEFT 
- The only force acting on the object is frictional force. 
- According to Newton’s Second Law, the body will accelerate in the
direction of the (net) force.  (3)
2.5 Increases 
(1)

[17]

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PHYSICAL SCIENCE GR. 12/TERM 1 4 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

QUESTION 3
3.1.1 The collision during which the total kinetic energy of the objects in
the system is conserved/stays the same.  (2)

3.1.2 K = 𝐾 Any one  (4)

1 1 1 1
𝑚 𝑣 + 𝑚 𝑣 = 𝑚 𝑣 + 𝑚 𝑣
2 2 2 2
1 1 1 1
(1,56)(3) + (𝑚)(0)  = (1,56)(0) + (𝑚)(2) 
2 2 2 2
𝑚 = 3,51 𝑘𝑔
3.2.1 Yes  (1)
3.2.2 No negative marking from QUESTION 3.2.1
 Crumple zones increase the collision time/contact time (∆t) 
∆
 According to 𝐹 = ∆ , for constant ∆p, 𝐹 ∝ ∆ 
 If ∆t increases then Fnet decreases, hence less damage  (3)

3.2.3 The total linear momentum of an isolated system remains constant (is
conserved)  (2 or 0) (2)

3.2.4 OPTION 1: EAST AS POSITIVE (4)

𝑝 = 𝑝 
Any one 
𝑚 𝑣 +𝑚 𝑣 =𝑚 𝑣 +𝑚 𝑣

(1350)(20) + (1500)(−10) = (1350)(−5) + (1500)𝑣 

𝑣 = −12,50 𝑚 ∙ 𝑠
= 12,50 𝑚 ∙ 𝑠 eastwards 
OPTION 2: WEST AS POSITIVE

𝑝 = 𝑝 
𝑚 𝑣 +𝑚 𝑣 =𝑚 𝑣 +𝑚 𝑣

(1350)(−20) + (1500)(10) = (1350)(5) + (1500)𝑣 

𝑣 = −12,50 𝑚 ∙ 𝑠 
𝑣 = 12,50 𝑚 ∙ 𝑠  eastwards
[16]

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PHYSICAL SCIENCE GR. 12/TERM 1 5 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

QUESTION 4

4.1 An object which has been given an initial velocity and on which the only force (2)
acting is the gravitational force. 

4.2 OPTION 1 OPTION 2 (4)

Upward positive Downward positive
𝒗𝒇 = 𝒗𝒊 + 𝒂∆𝒕 𝒗𝒇 = 𝒗𝒊 + 𝒂∆𝒕 

−𝟐𝟒, 𝟓 = 𝟐𝟒, 𝟓  + (−𝟗, 𝟖)∆𝒕 𝟐𝟒, 𝟓 = −𝟐𝟒, 𝟓 + (𝟗, 𝟖)∆𝒕

∆𝒕 = 𝟓 𝒔  ∆𝒕 = 𝟓 𝒔 
OPTION 3 OPTION 4
Upward positive Downward positive
𝒗𝒇 = 𝒗𝒊 + 𝒂∆𝒕  𝒗𝒇 = 𝒗𝒊 + 𝒂∆𝒕

𝟎 = 𝟐𝟒, 𝟓  + (−𝟗, 𝟖)∆𝒕 𝟎 = −𝟐𝟒, 𝟓  + (𝟗, 𝟖)∆𝒕

∆𝒕 = 𝟐, 𝟓 𝒔 ∆𝒕 = 𝟐, 𝟓 𝒔
Total time = 2,5 + 2,5 Total time = 2,5 + 2,5
=5s =5s
OPTION 5 OPTION 6
Upward positive Down positive
𝟏 𝟏
∆𝒙 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐  ∆𝒙 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐 𝟐
𝟏 𝟏
𝟎 = 𝟐𝟒, 𝟓∆𝒕 + (−𝟗, 𝟖)∆𝒕𝟐  𝟎 = −𝟐𝟒, 𝟓∆𝒕 + (𝟗, 𝟖)∆𝒕𝟐 
𝟐 𝟐
∆𝒕 = 𝟓 𝒔  ∆𝒕 = 𝟓 𝒔 
4.3 POSITIVE MARKING FROM QUESTION 4.3 (4)
OPTION 1
Upward positive
𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
∆𝒚𝒍𝒂𝒔𝒕 = ∆𝒚(𝟓) − ∆𝒚(𝟒)
𝟏 𝟏
= 𝟐𝟒, 𝟓(𝟓) + (−𝟗, 𝟖)(𝟓)𝟐  − 𝟐𝟒, 𝟓(𝟒) + (−𝟗, 𝟖)(𝟒)𝟐 
𝟐 𝟐
∆𝒚𝒍𝒂𝒔𝒕 = −𝟏𝟗, 𝟔 𝒎
Distance = |∆𝒚| = 𝟏𝟗, 𝟔 𝒎 
(4)

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PHYSICAL SCIENCE GR. 12/TERM 1 6 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

OPTION 2
Downward positive
𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
∆𝒚𝒍𝒂𝒔𝒕 = ∆𝒚(𝟓) − ∆𝒚(𝟒)
𝟏 𝟏
= −𝟐𝟒. 𝟓(𝟓) + (𝟗, 𝟖)(𝟓)𝟐  − −𝟐𝟒, 𝟓(𝟒) + (𝟗. 𝟖)(𝟒)𝟐 
𝟐 𝟐
∆𝒚𝒍𝒂𝒔𝒕 = 𝟏𝟗, 𝟔 𝒎
Distance =|∆𝒚| = 𝟏𝟗, 𝟔 𝒎 
OPTION 3
Upward positive
𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
𝟏
= (𝟐𝟒, 𝟓(𝟒) + (−𝟗, 𝟖)(𝟒)𝟐 
𝟐
= 𝟏𝟗, 𝟔 𝒎
Distance =|∆𝒚| = 𝟏𝟗, 𝟔 𝒎 
OPTION 4
Downward positive
𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
𝟏
= (−𝟐𝟒, 𝟓(𝟒) + (𝟗, 𝟖)(𝟒)𝟐 
𝟐
= 𝟏𝟗, 𝟔 𝒎
Distance =|∆𝒚| = 𝟏𝟗, 𝟔 𝒎 
OPTION 5
Upward positive
𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
𝟏
∆𝒚 = 𝟐𝟒, 𝟓(𝟏) + (−𝟗, 𝟖)(𝟏)𝟐 
𝟐
= 𝟏𝟗, 𝟔 𝒎
Distance = |∆𝒚| = 𝟏𝟗, 𝟔 𝒎 

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PHYSICAL SCIENCE GR. 12/TERM 1 7 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

OPTION 6
Downward positive
𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝟐 𝒂∆𝒕𝟐 
𝟏
∆𝒚 = −𝟐𝟒, 𝟓(𝟏) + (𝟗, 𝟖)(𝟏)𝟐 
𝟐
= −𝟏𝟗, 𝟔 𝒎
Distance = |∆𝒚| = 𝟏𝟗, 𝟔 𝒎 
OPTION 7
Upward positive
𝒗𝒇 = 𝒗𝒊 + 𝒈∆𝒕
= 𝟐𝟒, 𝟓 + (−𝟗, 𝟖)(𝟒)
= −𝟏𝟒, 𝟕 𝒎 ∙ 𝒔 𝟏

𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
𝟏
= −𝟏𝟒, 𝟕(𝟏) + (−𝟗, 𝟖)(𝟏)𝟐 
𝟐
= −𝟏𝟗, 𝟔 𝒎 
OPTION 8
Downward positive
𝒗𝒇 = 𝒗𝒊 + 𝒈∆𝒕
= −𝟐𝟒, 𝟓 + 𝟗, 𝟖(𝟒)
= 𝟏𝟒, 𝟕 𝒎 ∙ 𝒔 𝟏

𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐
𝟏
= 𝟏𝟒, 𝟕(𝟏) + (𝟗, 𝟖)(𝟏)𝟐 
𝟐
= 𝟏𝟗, 𝟔 𝒎 

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PHYSICAL SCIENCE GR. 12/TERM 1 8 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

4.4.1 POSITIVE MARKING FROM QUESTION 4.2 (3)

OPTION 1 OPTION 2
𝟏 𝟏
∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐  ∆𝒚 = 𝒗𝒊 ∆𝒕 + 𝒂∆𝒕𝟐 
𝟐 𝟐
𝟏 𝟏
−𝟓𝟔 = 𝒗𝒊 (𝟒) + (−𝟗, 𝟖)(𝟒)𝟐  𝟓𝟔 = 𝒗𝒊 (𝟒) + (𝟗, 𝟖)(𝟒)𝟐 
𝟐 𝟐
𝟏
𝒗𝒊 = 𝟓, 𝟔 𝒎 ∙ 𝒔 𝟏
 𝒗𝒊 = −𝟓, 𝟔 𝒎 ∙ 𝒔
𝒗𝒊 = 𝟓, 𝟔 𝒎 ∙ 𝒔 𝟏

4.4.2 POSITIVE MARKING FROM QUESTION 4.4.1 (3)
OPTION 1 OPTION 2
Upward positive Downward positive
𝒗𝒇 = 𝒗𝒊 + 𝒂∆𝒕  𝒗𝒇 = 𝒗𝒊 + 𝒂∆𝒕 

= 𝟓, 𝟔 + (−𝟗, 𝟖)(𝟒) = −𝟓, 𝟔 + (𝟗, 𝟖)(𝟒)

𝟏
= −𝟑𝟑, 𝟔 𝒎 ∙ 𝒔 = 𝟑𝟑, 𝟔 𝒎 ∙ 𝒔 𝟏

= 𝟑𝟑, 𝟔 𝒎 ∙ 𝒔 𝟏

4.5 POSITIVE MARKING FROM QUESTION 4.2 AND 4.3
OPTION 1 Marking criteria
Upward positive Correct shape of A 
Correct shape of graph B parallel 
to A below A.
Time at which both A and B reach 
the ground 5 s
Time for A to reach the maximum 
height 2,5 s.

OPTION 2 Marking criteria

Downward positive Correct shape of A 

Correct shape of graph B parallel to 
A above A.
Time at which both A and B reach 
the ground 5 s
Time for A to reach the maximum 
height 2,5 s.
(4)
[20]

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PHYSICAL SCIENCE GR. 12/TERM 1 9 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

QUESTION 5
5.1.1 Ketone (s)  (1)
5.1.2 Pentanal (2)
ACCEPT:
Marking criteria
2,2-dimethylpropanal
2-methylbutanal  Correct func onal group, i.e. – al 
 Whole name correct 
3-methylbutanal

5.2.1 5-bromo-2,3-dimethylhexane
Marking criteria
 Correct stem i.e. hexane 
 All substituents (bromo and dimethyl) correctly identified 
 IUPAC name completely correct including numbering, sequence,
(3)
hyphens and commas. 

5.2.2
Marking criteria
 Whole structure correct. 2/2
 Only functional group correct ½
If:
 Molecular formula 0/2
 Condensed structural formula ½ (2)

5.3.1 The C atom bonded to the hydroxyl group is bonded to only one other (2)
C-atom.  (2 or 0)
OR
The hydroxyl group/-OH is bonded to a C atom which is bonded to two
hydrogen atoms.  (2 or 0)
OR
The hydroxyl group/functional group/-OH is bonded to a primary
C atom/ the first C atom.  (2 or 0)
OR

The functional group is bonded to only one other C-atom. 

(2 or 0)

5.3.2 Esterification/condensation  (1)

5.3.3 Butanoic acid  (1)
[12]

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PHYSICAL SCIENCE GR. 12/TERM 1 10 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

QUESTION 6
6.1.1 Liquid  (1)
6.1.2 Solid  (1)
6.2.1 Marking criteria (2)
If any one of the underlined key phrases in the correct context is
omitted, deduct 1 mark.
The temperature at which the vapour pressure equals the atmospheric
(external) pressure. 

6.2.2 Lower than  (1)

6.2.3 Marking criteria (3)
 Compare structures 
 Compare the strength of intermolecular forces 
 Compare the energy required to overcome intermolecular forces

2,2-dimethylbutane
Structure:
 More branched/more compact/more spherical/smaller surface area
(over which intermolecular forces act). 

Intermolecular forces:
 Weaker/less intermolecular forces/Van der Waals forces/London
forces/Dispersion forces. 

Energy:
 Less energy needed to overcome or break intermolecular forces/Van
der Waals forces. 
OR
Hexane
Structure:
 Longer chain length/unbranched/less compact/less spherical/larger
surface area (over which intermolecular forces act) 

Intermolecular forces
 Stronger/more intermolecular forces/Van der Waals force/London
force/dispersion forces. 

Energy
 More energy needed to overcome or break intermolecular
forces/Van der Waals forces. 
[08]

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PHYSICAL SCIENCE GR. 12/TERM 1 11 LIMPOPO/MARCH 2024
NSC – MARKING GUIDELINES

QUESTION 7
7.7.1 Addition/hydration  (1)
7.1.2 Addition/halogenation/bromination  (1)
7.2.1 Water/H2O  (1)
7.2.2 (Dilute) sulphuric acid/H2SO4 OR (Dilute) phosphoric acid/H3PO4  (1)
7.3

(3)
NOTE: Do not penalise HBr
[07]

TOTAL: 100 MARKS

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