Industrial Electronics N2
Industrial Electronics N2
Industrial Electronics N2
Module 1:
Atom theory .................................................................................................................... 6
1.1 Introduction................................................................................................................................. 6
1.2 Matter ................................................................................................................................................ 6
1.2.1 Elements ........................................................................................................................................ 7
1.2.2 Compounds ................................................................................................................................. 7
1.2.3 Molecules ...................................................................................................................................... 7
1.3 The atom .......................................................................................................................................... 7
1.4 Covalent bonds.............................................................................................................................. 8
1.5 Electrical current flow ................................................................................................................... 9
Module 2:
Direct Current Theory ................................................................................................... 11
2.1 Introduction............................................................................................................................... 11
2.2 Electromotive force (emf) ......................................................................................................... 11
2.3 Definition of the ampere............................................................................................................ 11
2.4 Voltage ........................................................................................................................................... 12
2.4.1 Definition of the volt ................................................................................................................. 12
2.5 Resistance ...................................................................................................................................... 12
2.6 Ohm’s Law ..................................................................................................................................... 13
2.7 Power ............................................................................................................................................... 13
2.8 Resistor circuits .............................................................................................................................. 14
2.8.1 Resistors in series ........................................................................................................................ 14
2.8.2 Resistors in parallel .................................................................................................................... 14
2.8.3 Series-parallel combinations.................................................................................................. 15
2.9 Kirchoff’s laws ................................................................................................................................ 16
2.9.1 Current law (first law) ............................................................................................................... 16
2.9.2 Voltage law (second law) ..................................................................................................... 17
Module 3:
Alternating Current Theory.......................................................................................... 20
3.1 Introduction............................................................................................................................... 21
3.2 The cycle ........................................................................................................................................ 21
3.3 Frequency (f) ................................................................................................................................. 21
3.4 Period (t) ......................................................................................................................................... 21
3.5 Instantaneous value .................................................................................................................... 22
3.6 Average and rootmean (RMS) square values of a sinusoidal wave ............................ 24
3.6.1 Mid-ordinate rule method ...................................................................................................... 24
Module 8:
Syncro systems ............................................................................................................. 72
8.1 Introduction............................................................................................................................... 72
8.2 Lenz’s law ....................................................................................................................................... 72
8.2.1 Applications ............................................................................................................................... 72
8.3 Advantages of synchro systems over mechanical systems ............................................ 73
8.3.1 Acceptable symbols ................................................................................................................ 73
8.3.2 Operation.................................................................................................................................... 73
8.4 Wiring diagrams ............................................................................................................................ 73
Module 9:
The decibel ................................................................................................................... 76
9.1 Introduction............................................................................................................................... 76
9.2 Formula ........................................................................................................................................... 76
Checklist Practical
Example Safety
Theoretical – questions,
In the workplace
reports, case studies, etc.
Module 1 00
Learning Outcomes
When you have completed this module, as a learner you will be able to:
1.1 Introduction
1.2 Matter
Matter is anything that has weight and takes up space. Matter cannot be
created or destroyed.
Matter exists in four different states, solid, liquid, gas and plasma. The earth and
anything on it is classified as matter.
Examples thereof:
Solid matter are wood and stone
Liquid matter are water and oil
Gas matter are oxygen and helium
Plasma consists of ionised particles such as lightning
Matter can change its state from one form to another. If ice is heated it will
become water and then steam. A solid has changed into a liquid form and then
into a gas.
1.2.1 Elements
Elements are used to construct matter. Examples of elements are gold, copper,
iron and silicon.
1.2.2 Compounds
A compound consists of two or more different types of elements. A compound
is formed when one or more elements react in a chemical way. For instance,
water is a compound that is made up of the elements oxygen and hydrogen.
1.2.3 Molecules
A molecule is the smallest part of a compound that still retains the characteristics
of the original compound without breaking up into individual atoms. A water
molecule is formed when two hydrogen atoms combine with one oxygen atom.
Figure 1.2
The electrons in the orbits have a negative charge and they are attracted by
the protons in the nucleus, which have a positive charge. Each orbit can take
up only a certain number or electrons. The number of electrons in an orbit
determined by the formula 2n².
If the outermost orbit is incomplete (not completely filled with electrons), then
that orbit is called the valency band. The electrons inside the valency band are
called the valency electrons. The number of valency electrons in an atom is
called the valency number of the atom.
The protons in the nucleus have a positive charge, while the neutrons have no
charge at all. The number of electrons and protons in a neutral atom are the
same. The negative charge of electrons has the same amount of charge as the
positive charge of the protons. The atom will thus be electrically neutral.
The atomic number always indicates the number of protons or electrons in the
atom.
If the valency electrons are easily removed from the atom then the element to
which these atoms belong is called a conductor. Electrons which have left an
atom are called free electrons.
When electrons are removed from an atom, the atom becomes positively
charged. This positively charged atom is called a positive ion or a cation. When
electrons are added to an atom, it becomes negatively charged and is called
a negative ion.
When two such atoms combine, a covalent bond is formed. In a covalent bond,
the two atoms involved each have one electron in the bond and they share
these two electrons with each other. Covalent bonds are very strong and
cannot easily be broken up.
Figure 1.3
This causes an electrical current to flow from the negative terminal of the cell to
the positive terminal. This type of current flow is referred to as electron current
flow. When referring to current flow as being from positive to negative, it is called
conventional current flow.
Figure 1.4
Activity 1.1
d. Molecules
e. The atom
f. Nucleus
g. Electrons
h. Conductor
i. Insulator
j. Covalent bond
2. Draw a model of an atom with an atomic number 28.
3. Draw a model of an atom which has 3 valence electrons.
4. Sketch two atoms in a covalent bond.
Self-Check
Module 2
Learning Outcomes
When you have completed this module, as a learner you will be able to
2.1 Introduction
Basic unit Unit for small amounts Unit for large amounts
Pronounced Ampere Milli- Micro- Kilo- Mega-
ampere ampere ampere ampere
Abbreviation A mA 𝜇𝐴 kA MA
Multiplier 1 1 x 10-3 1 x 10-6 1 x 103 1 x 106
Table 2.1
Take Note:
2.4 Voltage
Voltage is a general term for emf and pd, and are measured in volts (V). Voltage
is usually indicated by E or V in a circuit.
Basic unit Unit for small amounts Unit for large amounts
Pronounced Volt Milli-volt Micro-volt Kilo-volt Mega-volt
Abbreviation V mV 𝜇𝑉 kV MV
Multiplier 1 1 x 10-3 1 x 10-6 1 x 103 1 x 106
Table 2.2
2.5 Resistance
The process where an electron travels slowly and with difficulty in a conductor, is
known as resistance. Resistance is expressed by R in a circuit and the unit of
resistance is the ohm (Ω).
Definition: Ohm
One ohm is the electric resistance between two points of a conductor
when a constant potential difference of one volt applied between
these two points, produces a current flow of one ampere, and the
conductor is not the source of any emf.
Basic unit Unit for small amounts Unit for large amounts
Pronounced Ohm Milli-ohm Micro-ohm Kilo-ohm Mega-
ohm
Abbreviation Ω mΩ 𝜇𝛺 kΩ MΩ
Multiplier 1 1 x 10-3 1 x 10-6 1 x 103 1 x 106
Table 2.3
2.7 Power
The amount of work done per second in an electrical circuit. The unit is watts (W),
the symbol is (P).
P VI
P I2 R
V2
P
R
Definition: Watt
One watt is the power which results in the production of energy at a
rate of one joule per second.
Basic unit Unit for small amounts Unit for large amounts
Pronounced Watt Milli-watt Micro-watt Kilo-watt Mega-watt
Abbreviation W mW 𝜇𝑊 kW MW
Multiplier 1 1 x 10-3 1 x 10-6 1 x 103 1 x 106
Table 2.4
Figure 2.1
Worked Example 1
5 4 3
Figure 2.2
Solution:
RT = R1 + R2 + R3
=5 +4 +3
= 12
1 1 1 R1 R 2
OR R T
R T R1 R 2 R1 R 2
R1
R2
Figure 2.3
Worked Example 2
5
10
Figure 2.4
Solution:
1
1 1
10 5
RT =
RT 10 5 10 5
1 50
0,3 OR
RT 15
RT 3,33 RT 3,33
Worked Example 3
Find the total resistance of the circuit shown as well as the current flow through
the circuit. Also calculate the total power as well as the voltaqge and power
through the 3 Ω resistor.
4 5
2
I2
I1
6
3
ITOTAL
10V
Figure 2.5
Series circuit
RS 23
5
RS 45
9
Parallel circuit
9 6
RP
9 6
3,6
RT 3,6 5
8,6
Total current flow
VT
IT
RT
10
8,6
1,16 A
Total power
PT VT I T
10 116
,
11,6 W
or
I T RT
2
PT
116
, 2 8,6
11,6 W
Voltage across 3Ω resistor
V3 I R
116
, 3
3,48 V
Power across 3Ω resistor
P3 I2 R
116
, 23
4,04 W
I1
I2 ITOTAL
I3
Figure 2.6
V1 V2 V3
VTOTAL
Figure 2.7
Vt = V1 + V2 + V3
Activity 2.1
3
5
10V
6 2
4
ITOTAL
Figure 2.8
3. Draw a fully labelled circuit diagram of a direct current power supply using
two diodes, a centre lap transformer and filter capacitor. Clearly show the
output waveforms before and after the filter capacitor.
4. Draw a labelled circuit diagram of a full-wave low voltage DC power supply
by using a step down transformer, four diodes, a filter circuit and a load
resistor. Show the polarities over the load resistor as well as the electron flow.
5. Refer to Question 4 and draw three labelled graphs indicating the
waveforms before the diodes, directly after the diodes and the output over
the load.
6. Refer to Figure 2.9 and determine the following:
6.1 The total resistance of the circuit [4Ω]
6.2 The total current of the complete circuit [3A]
6.3 The current I2 [1A]
6.4 The voltage over R2 [4]
6.5 The power consumed by the whole circuit [36W]
Figure 2.9
Self-Check
Module 3
Learning Outcomes
When you have completed this module, as a learner you will be able to:
3.1 Introduction
Armature
Brushes
Sliprings
Galvano-
meter
Figure 3.1
Formula 1 1
t
f
+V
VP
360o
O
VP-P
-V
t
Figure 3.2
Vp-p = Voltage peak to peak.
t = period.
Vp = Vm = Peak Voltage or Maximum voltage.
= Lamda. Lamda is the length of a cycle and is measured in metre (m).
+ V = Positive voltage
-V = Negative Voltage.
Formula 1 1800
e Em Sin 2 ft
Formula 2 e Em Sin 0
Formula 3 1800 1800
2 ft t
Em = Maximum voltage value
(V).
e = Instantaneous voltage (V).
Formula 4 1800
i Im Sin 2 ft
Formula 5 i Im Sin o
Worked Example 1
Solution:
1.
1800
2 ft
1800
2 4510 103
180 0
2,827
= 1620
2.
i Im Sin o
= 20 Sin 1620
= 6,18A
3.
= 2ft
= 36
= 36 = 0,628 radians
180
t
2f
0,628
=
2 ( 45)
= 0,0022s
= 2,2 ms
4.
i Im Sin o
i = 20 Sin 36
= 11,76A
Figure 3.3
Divide 180 of the sinusoidal wave into equally spaced ordinates as illustrated
and let n be the number of ordinates. Sample the value of the voltage or current
at each ordinate intersection. Table the results.
Worked Example 2
V1 = 45V V4 = 194V
V2 = 120V V5 = 126V
V3 = 190V V6 = 30V
Solution:
From this information V(AVE) and V(RMS) can be calculated.
V1 V2 V3 V4 V5 V6
VAVE
(1) n
45 120 190 194 126 30
6
= 117,5V
V1 V2 V3 V4 V5 V6
2 2 2 2 2 2
V( RMS)
(2) n
Formula 1 I1 I 2 I 3 I 4 I 5 ....... I n
I AVE
n
Formula 2 I1 I 2 I 3 I 4 _ _ _ _ _ I n
2 2 2 2 2
I ( RMS)
n
A wave which has a form factor and crest factor value of less than 1,11 and 1,44
respectively is called a flat wave.
Worked Example 3
Calculate
1. The maximum voltage value.
2. Vp-p
3. Vave
4. Vrms
5. Frequency (f)
6. Period (t)
Answers:
1. Vm = Vp = 120V
3. VAVE VM 0,637
120 0,637
76,44 V
4. VRMS VM 0,707
120 0,707
84,84 V
5.
f
2
311,17
2
50Hz
6. 1
t
f
1
50
0,02
20 ms
Resistor (R)
Current and voltage are in phase. Ohms law will apply in these circuits.
Formula 1 V
R
I
V
R
I 18O 36O
I OO O O
VS
Figure 3.4
Capacitor (C)
In a pure capacitor circuit, the current leads the voltage by 90º.
Formula 1 1
Xc
2fc
C 90O x
I y
V
VS
I
Figure 3.5
Inductor (L)
In a pure inductor circuit, the voltage leads the current by 90º.
Formula 1 XL = 2fL
L
V
I V
0 0 0 0 0
I 0 90 180 270 360
900 I
VS
Figure 3.6
R-L circuits
R L
ITOTAL
VS
Figure 3.7
Formula 1
Z R2 XL
2
Formula 2 Vs
I
Z
Where Z = Impedance (Ω) and Vs = Supply
voltage (V)
Formula 3 VS VR VL
2 2
Formula 4 VL = It x XL
Formula 5 VR = It x R
Formula 6 XL
Tan1
R
R-C circuits
R C
ITOTAL VS
Figure 3.8
Formula 1 Z R2 XC
2
Formula 2 Vs
It
Z
Formula 3 Vc = It x Xc
Formula 4 VS VR VC
2 2
Formula 5 X
Tan1 C
R
R-L-C circuits
C
R L
VS
Figure 3.9
Formula 1 Z R L X L XC
2 2
Formula 2 Vs
It
Z
Formula 3 VS VR VL VC
2 2
Formula 4
Tan1
XL XC
R
3.7 Phasors
Phasor diagrams are used to illustrate the relationships between the voltages,
currents or impedances and reactances in a circuit. There are basically three
types or illustrations or phasors.
XL VL IC
Z
R VR IR
VT
XC IT
VC IL
Figure 3.10
Formula 1 1
fR
2 LC
Resonant frequency (FR) is the frequency where XL=XC. In a series R=Z. Current
will be at maximum value. No phase shift 𝜃 = 0º.
Worked Example 4
20 100F
ITOTAL VS=220V
f=50HZ
Figure 3.11
Solution:
1. 1
XC
2 fc
1
2 (50)(100 106 )
31,83
Z R 2 XC
2
202 31,832
37,59
2. VS
It
Z
220
37,59
5,85 A
3. VR = It x R
= 5,85 x 20
= 117,05V
4. Vc = It x Xc
= 5,85 x 31,83
= 186,21V
5. XC
Tan 1
R
1 31,83
Tan
20
57,86 o
6. 20
R
= 57,86 0
31,83
Z
XC
7. VR=117,05V
= 57,860
VS=220V
VC=186,21V
Worked Example 5
C L R
100mH 20
200F
Ib
VS=220V
f=50Hz
Figure 3.12
Solution:
1. 1
XC
2 fc
1
2 (50)(200 106 )
15,92
2. XL = 2fL
-3
= 2(50) (100 x 10 )
= 31,4
Z R 2 X L X C
3. 2
20 2 31,4 15,92
2
25,29
4. Vs
It
Z
220
25,29
8,7A
5. Vc = It x Xc
= 8,7 x 15,92
= 138,18V
6. VL = It x XL
= 8,7 x 31,4
= 273,18V
7. VR = It x R
= 8,7 x 20
= 174V
8. Tan 1 XL XC
R
Tan 115,48
20
37,740
9. XL
XL-XC=15,48
Z
R
20
XC
Activity 3.1
1.1 Xc [159,15]
1.2 Z [187,96]
1.3 It [1,17A]
1.4 VR [117V]
1.5 Vc [186,21V]
C
R
100
20F
VS=220V
f=50HZ
Figure 3.13
2.1 Vs [28,28V]
2.2 L [23mH]
2.3 C [63,3]
2.4 R [10]
2.5 Z [14,14]
C
R L
IT=2A
V S=
f=100HZ
Figure 3.14
3.1 R [3,75]
3.2 C [1273 F]
3.3 L [15,91mH]
3.4 FR [35,4Hz]
3.5 Draw the XL; XC; R; Z phasor diagram.
C R L
f=50HZ
XL
XL- XC =2,5
Z
R
3,75
XC
Figure 3.15
4.1 Z [161,9]
4.2 IT [O,62A]
4.3 VR [62v]
4.4 VC [78,94v]
4.5 Phase angle [51,85O]
C=25F
R=100
IT
VS=100V
f=50HZ
Figure 3.16
5. Draw and label a sine wave of 720º with a peak value of 141,4 V and a
frequency of 100 Hz.
6. Calculate the following for the sine wave in Question 5:
6.1 Peak to peak value
6.2 The RMS value
6.3 Time (period of one cycle in seconds)
7. The equation for a certain alternating wave is given by the formula 3 =
150sin31,41tV. Use the formula to calculate the following:
7.1 The maximum or peak value for voltage [150V]
7.2 The average and RMS values [95,55V; 106,05]
7.3 The form and crest factors [1,11; 1,414]
7.4 The frequency of the waveform [5 Hz; 28,110 8V]
7.5 The instantaneous value of the voltage 6 and 12 milliseconds after
zero [55,225 5V]
Self-Check
Module 4
Learning Outcomes
On completion of this module, students should be able to:
4.1 Introduction
4.5 Doping
When semiconductor material is mixed with other chemicals to produce P-type
or N-type material. This is known as extrinsic or impure semi-conductor material.
material is positive type material and is known as acceptor atom because it will
accept or attract electrons.
P-TYPE SEMICONDUCTOR
CRYSTAL LATTICE STRUCTURE
Figure 4.2
Definition: Pentavalent
An atom with five valence electrons.
N-type material is negative type material and is known as donor atoms, because
they will donate or give free electrons off to atoms attracting them.
Free electrons are electrons not joined in a atom structure. Free electrons are
free to conduct in current flow.
Free
electron
N-TYPE SEMICONDUCTOR
CRYSTAL LATTICE STRUCTURE
Figure 4.3
Figure 4.4
Electrons (é) have a negative charge and are attracted to the (+) side of a cell.
For every electron leaving the metal above one is give off or is replaced by the
(-) side of the cell.
Figure 4.5
Holes (+) are positions where electrons are housed. These holes (+) will attract
electrons. The hole does not move but electrons leaving a hole and filling
another gives the impression that holes are moved, thus hole flow.
Figure 4.6
When P- and N- type material is joined to form one crystal structure. This PN
junction possesses rectification properties, and is known as a diode.
Figure 4.7
Figure 4.8
Ge Si
Uses
1. Rectification.
2. Polarity reversal protection.
3. Filter circuit.
4. Back emf protection.
Symbol
Figure 4.10
Vz = Zener voltage
-V = Reverse bias area
SR = Safe conduction region
CHARACTERISTIC CURVE
Figure 4.11
Uses or application
Reference voltage or voltage regulation, eg if 9,1V zener diode is reverse biased
9,1V will be measured across the diode at all times.
RS
+
VS=12V
RL VZ=9V=VRL
-
APPLICATION CIRCUIT
Figure 4.12
Symbol
Figure 4.13
Characteristic curve
F
100
-V
Figure 4.14
4.12.1 Properties
This diode is always reversed biased. To vary the reverse biased voltage will vary
the depletion area which will vary the capacitance value between the walls of
the depletion region. The larger the reverse voltage the lower the capacitance
value in (F) farads.
Uses
Tuning circuits such as in a (TV) television set.
Symbol
Figure 4.15
4.13 Photodiode
These diodes are reversed biased. This diode is so constructed that a window
allows incident light to fall on the PN junction. In no light conditions, no current
will flow. When light falls on the junction, the photodiode allows current to flow.
Symbol
A C
Figure 4.16
Application circuit
Figure 4.17
Uses
Light sensitive circuits, eg street lights, darkrooms etc.
Symbol
Figure 4.18
Uses
(1) Indication circuits, e.g. on/off indications.
(2) 7-Segment display.
Application circuit
Figure 4.19
Figure 4.20
Uses
Rectification properties. To convert ac to dc.
Figure 4.21
Figure 4.21
Figure 4.22
Figure 4.23
4.17 Calculations
FORMULA: (1) Halfwave Rectifier.
Vdc = Vp x 0,318
Worked Example 1
Solution:
VDC = Vp x 0,637
= 20 x 0,637
= 12,74 V
Worked Example 2
A halfwave rectifier has a VDC value of 13,5 V. Calculate the Vp over the
secondary side of the transformer.
Solution:
VDC = Vp x 0,318
Vdc
VP
0,318
13,5
0,318
42 ,45V
Activity 4.1
Self-Check
Module 5
Learning Outcomes
By the end of the module you should be able to:
5.1 Introduction
Figure 5.1
The transistor consists of three semiconductor layers. The base (B) and emitter (E)
must always be forward biased and the collector (C) reversed biased. This is for
both NPN and PNP transistors.
Figure 5.2
The water flowing from the supply to the bucket is controlled by the tap.
Figure 5.3
0,7V 5V
Vce
0,6V Vrb
4V
0,5V
Figure 5.4
The value of RB is such that the DC voltage drop across RB is 0,6 V. If a person
speaks into the microphone (M) the microphone will produce a varying loss of
current which can be illustrated by VRB.
This current is applied to the base of the transistor which in turn will vary the flow
of current through the transistor from the emitter to the collector and will
produce a current to flow through loudspeaker illustrated by VCB.
The current produced will effect a sound in the loudspeaker which would be
amplified by the amplifier circuit.
The input signal is small and the output signal large. The amplifier has amplified
the signal.
Figure 5.5
If the switch is closed the VBE is forward biased and the transistor will conduct.
The globe will light up. The transistor is saturated. This means that maximum
current will flow through the transistor.
In an amplifier circuit, the current varies through the transistor, and is not in
saturation.
Figure 5.6
Applications
This circuit is used in voltage amplifier circuits.
Figure 5.7
Applications
This circuit is used in a power amplifier circuit.
Figure 5.8
Applications
This circuit is used as a current amplifier circuit.
Activity 5.1
1. Draw and label the block diagram of a PNP transistor. Label the charge
carriers and explain the equation, IE = IB + IC.
2. Draw and label the circuit diagram of an NPN transistor in a common
collector amplifier circuit.
3. Draw and label a common base amplifier using an NPN transistor, showing
the most essential components.
4. Draw and label a single-stage NPN-transistor amplifier in a common emitter
configuration. A microphone and a loudspeaker must be connected to the
input and output terminals.
Self-Check
Module 6
Learning Outcomes
By the end of the module you should be able to:
6.1 Introduction
Figure 6.1
The value under test is passed through the coil which interrupts the magnetic
flux of the magnet, which forces the pointer to a different position. The scale is
calibrated to read off the correct value.
A shunt resistor (RSH) will be placed in parallel to the coil winding to prevent
damage to the meter if a large current (IT) is to be measured. The shunt resistor
is usually composed of a few resistors placed on parallel and is selectable so as
to vary the range of the ampere meter.
Formula
IM RM
(1) RSH Rsh = Shunt resistor
ISH
Im = Current through the meter
(2) Ish = It - Im
Rm = Internal resistance of the meter
IM RM
(3) RSH Ish= Current through Rsh
IT IM
It = Current being measured
Figure 6.2 An ampere meter is always connected in series with the circuit.
Worked Example 1
Solution:
It = 7A
Rm = 2
Im = 10mA = 10 x 10-3
10 103 2
7 10 103
0,02
6,99
2 ,86m
I1 I2 I3 I4 Im
nA A
Figure 6.3
This resistor is called a multiplier and is used to make the meter Multi-rangeable.
The multiplier can be calculated as follows.
Formula
VT
(1) R S RM RS = Multiplier
IM
Figure 6.4
Worked Example 2
Solution:
VT
RS RM
IM
50
5
15 103
3333,33 5
3328,3
3,328k
V Rs1
mV Rs2
S1
+ Rs3 Im
V
Figure 6.5
Figure 6.6
V
R1
S1
mV
R2
V V
R3
S1
A
A
R4 R5 R6
x7
S4 R7
Rv M
B
x10
+ S3 R8 A mA A
S2
x100
R9
_
Figure 6.7
Uses
Current meter
Volts meter
Ohms meter
Continuity tester
Diode tester
Test (HFE) current gain of transistors
Scales
Auto-ranging = automatically selects a suitable range.
Advantages
Advantages of the digital multi-meter over a analogue multi-meter.
Activity 6.1
+ Im=15mA
Rs=14,52 k
Vt=220V V
Rm=150
Figure 6.8
+ It
Im=20mA
Rsh Rm=150
Figure 6.9
Self-Check
Module 7
Learning Outcomes
By the end of the module you should be able to:
7.1 Introduction
The resistance value of a LDR varies with the amount of light that falls on it. A
LDR is a light dependant resistor.
It is used for external lighting systems that are only activated at night, camera
light meters, etc.
The LDR has a ‘window’ under which lies a grid of material that is sensitive to
light.
R
Light intensity
Figure 7.2 Characteristic curve
APPLICATION CIRCUIT
Figure 7.4 When light falls on the (LDR) its resistance decreases, causing the
transistor to conduct, the relay operates and the high current light will switch on.
This simple circuit is used in street lighting, or to switch on a light when the sun
goes down.
7.3 Thermocouples
A temperature sensitive transducer. This transducer consists of two different
metals such as nickel- chrome and nickel- aluminium. If the two metals are
joined together, as illustrated and the two junctions are at different
temperatures, a potential difference exists between two metals.
CHARACTERISTIC CURVE
Figure 7.6
Construction
Figure 7.7
Uses
A simple circuit can be build using the bi-metallic strip to close an alarm circuit
when a fire breaks out.
7.5 Thermistor
A temperature sensitive resistor. This components resistance varies with a charge
of temperature. The component is either (NTC) negative temperature
coefficient, resistance decreases if temperature increases, or (PTC) positive
temperature coefficient, resistance increases with a increase in temperature.
Application
In this application the thermistor is mounted to the heat-sink of the transistor and
prevents thermal runaway of the amplifier and causes distortion.
Figure 7.10
Activity 7.1
1. Define a transducer.
2. Describe each of the following transducers:
2.1 bimetal strip
2.2 thermistor
2.3 LDR
2.4 thermocoule
3. Draw, label and explain application circuits of the transducers in Question 2.
4. Describe briefly, by using labelled sketches, the difference between a
bimetallic strip and a thermocouple transducer.
5. Draw labelled circuit diagram symbols of the LDR and the photo diode.
Briefly describe the main differences between them and the working
principle of each.
Self-Check
Module 8
Learning Outcomes
By the end of the module you should be able to:
8.1 Introduction
If the rotor in the transmitter is moved, the magnetic field on the rotor is affected
and in turn transmits an error signal to the receiver which forces the rotor of the
receiver to the desired position.
8.2.1 Applications
Remote controlled model aeroplane.
Control of dam sluice gate.
Control of ships rudder.
Control of space ships.
Remote control of microwave dishes.
Figure 8.1
8.3.2 Operation
Control between the transmitter and receiver is done by means of a magnetic
field. If the rotor of the transmitter is moved, a magnetic field forces the receiver
to move. The direction of the resultant movement by the receiver will depend on
the wiring of the rotor (R) and the stators (S).
If the transmitter is turned 45º clockwise the receiver will follow and also turn 45º
clockwise.
If S1 and S3 are connected between the transmitter and receiver this will give
an opposite direction displacement. When the transmitter is turned 45º
clockwise, the receiver will turn 45º anticlockwise.
Tx Tx
Activity 8.1
Self-Check
Module 9
Learning Outcomes
By the end of the module you should be able to:
9.1 Introduction
The unit (dB) decibel is 1/10 of a Bel. This unit is used to express the
ratio between two signals, output and input signal. If the output
signal is larger than the input signal, the signal has been amplified. If
the output signal is smaller than the input signal, the signal has been
attenuated.
PI N PO N = Amplifier or attenuater
P = Power
9.2 Formula
PO
N 10 log
Pi
Worked Example 1
An electronic network has a output power of 60mW and a input power of 16mW.
Calculate the gain or loss of the network.
PO
N 10 log
Pi
60 10 -3
10 log
16 10 -3
= 10 log 3,75
= 5,74 dB
Worked Example 2
An electronic network has a output voltage of 2,5V and a input voltage of 12V.
The input and output impedance is 600.
Calculate:
(a) Po
(b) Pi
(c) Io
(d) Ii
(e) The gain or loss of the amplifier in (dB)
(b)
2
V1
Pi
R1
12 2
600
= 0,24W
= 240mW
(c)
V0
I0
R0
2,5
600
= 4,167mA
(d)
V1
I1
R1
12
600
= 20mA
(e)
PO
N 10 log
Pi
10mW
10 log
240mW
= (-) 13,80 dB
The electronic network is a attenuator, (dB) is a ratio and is never express as (-).
Worked Example 3
A electronic network has a gain of 26 dB. The input power (Pi) = 27mW.
Calculate the output power (Po).
P
N 10 log O
Pi
PO
26dB 10 log
27 mW
26 PO
log
10 2,7 10 3
PO
anti log 2,6
2,7 10 3
PO
398,11
2,7 10 3
PO 398,11 2,7 10 3
1,07W
Activity 9.1
Self-Check
Table of C
Past Examination Papers
APRIL 2012
NATIONAL CERTIFICATE
INDUSTRIAL ELECTRONICS N2
(8080602)
28 March (X-Paper)
09:00 – 12:00
This question paper consists of 5 pages, a 1-page diagram sheet and a 3-page
formula sheet.
TIME: 3 HOURS
MARKS: 100
__________________________________________________________________
3. Number the answers according to the numbering system used in this question
paper.
6. Use ONLY IEC symbols and units when answering the question paper.
7. ALL sketches must be neat and labelled, using a pencil and a ruler (NOT
freehand sketches).
9. 22
Use 𝜋 as 3,142 and NOT as
7
QUESTION 1
1. Define the following terms:
[10]
QUESTION 2
2. Refer to FIGURE 1 (on the attached DIAGRAM SHEET) and calculate the
following:
[10]
QUESTION 3
3 Refer to FIGURE 2 (on the attached DIAGRAM SHEET) and calculate the
following:
[14]
QUESTION 4
4.2 The equation for a certain alternating wave is given by the formula:
e = 150 sin 3,41 tV. Use the formula to calculate the following:
The instantaneous value of the voltage 6 and 12 milliseconds after zero. (6)
[12]
QUESTION 5
5.1 Draw the symbols of the following diodes and give ONE use of each:
5.2 Draw and label the expected Input and output waveforms of the rectifier in
FIGURE 3 (attached DIAGRAM SHEET). The transformer is connected to
220 V/50 Hz. (6)
[10]
QUESTION 6
6.1 An ammeter can measure 500 mA full scales. The meter movement requires
a current of 1 mA to show a full-scale deflection. The internal resistance of
the meter is 500 Ω.
6.1.1 Calculate the shunt resistance (up to THREE decimal points). (3)
6.1.2 Draw and label the circuit of the ammeter described in QUESTION 6.1.
(5)
6.2 State THREE precautions which must be taken when measuring current with
an ammeter. (3)
[11]
QUESTION 7
7.1 Draw a labelled circuit symbol for an NPN and a PNP transistor. (6)
[9]
QUESTION 8
[12]
QUESTION 9
9.2 Make a neat labelled sketch of a synchro system showing the connections
for the transmitter and receiver to turn in the same direction. (6)
9.3 State THREE advantages of a synchro system over a mechanical system. (3)
[12]
TOTAL: 100
DIAGRAM SHEET
INDUSTRIAL ELECTRONICS N2
FORMULA SHEET
Marking Guidelines
APRIL 2013
NATIONAL CERTIFICATE
INDUSTRIAL ELECTRONICS N2
(8080602)
QUESTION 1
1.1 Matter is anything that has weight and takes up space and cannot be created (2)
or destroyed. √√
1.4 When XL= X. In a series circuit R = Z and the current will be at its maximum (2)
value. √√
[10]
QUESTION 2
2.1 𝑉 12 (2)
𝑅1 = = 1,2 = 10 𝛺 √√
𝐼
2.3 12
𝑅2 = 0,6 = 20 𝛺 √
𝑉5 = 𝑉𝑡− (𝑉3 + 𝑉4 ) = 12 − (1,2 + 3,6) = 7,2 𝑉 √
7,2
𝑅5 = 0,6 = 12 𝛺 √
6
𝑅 = 2 + 12 + 20 = 10 𝛺 √
𝑅𝑡 = 10//10 = 5𝛺 √√ (6)
NOTE: double ticks at the end of the ANSWER imply a tick for the preceding step. [10]
QUESTION 3
3.1 1
𝑋𝑐 =
2𝜋𝑓𝑐
1
63,662 = 2𝜋 𝑥 50 𝑥 𝐶 √
(2)
𝐶 = 50 𝜇𝐹 √
3.3 2 (3)
𝑍𝑇 = √102 + (63,662 − 15,708) = 48,985 𝛺 √√√
[14]
QUESTION 4
4.2 180
𝑒6𝑚𝑠 = 150 sin 31,41 𝑥 6 𝑥 10−3 𝑥 = 28,08 𝑉 √√
𝜋
180
𝑒12𝑚𝑠 = 150 sin 31,41 𝑥 12 𝑥 10−3 𝑥 = 55,12 𝑉 √√ (6)
𝜋
[12]
QUESTION 5
5.1.1
(2)
5.1.2
(2)
5.2
(6)
[10]
QUESTION 6
6.1.1 (3)
6.1.2
(5)
[11]
QUESTION 7
7.1
(6)
[9]
QUESTION 8
8.1 A device that converts one form of energy into another. √√ (2)
8.2.2 When heating two different types of metal which are fastened on top of each
other, the combined metal strip will bend because of the change in
temperature. √√ (2)
[12]
QUESTION 9
9.1 Whenever a magnetic field cuts through a coil and induces a voltage in the
coil, causing a current to flow, that current will in turn generate its own
magnetic field which will oppose the original induced magnetic field. (3)
9.2
(6)
9.3 Transmitter and receiver can be far apart. Very little electrical energy is used.
Contact between the two systems can be by means of radio, telemetering or
wires. Quantity can be controlled. Large values can be transmitted when it is
combined with a server system. √√√ (Any THREE) (3)
[12]
TOTAL: 100
Past Examination
Table of C Papers
NOVEMBER 2012
NATIONAL CERTIFICATE
INDUSTRIAL ELECTRONICS N2
(8080602)
9 November (X-Paper)
09:00 – 12:00
This question paper consists of 5 pages, a 1-page diagram sheet and a 3-page formula
sheet.
TIME: 3 HOURS
MARKS: 100
__________________________________________________________________
3. Number the answers according to the numbering system used in this question
paper.
6. Use ONLY IEC symbols and units when answering the question paper.
7. ALL sketches must be neat, using a PENCIL and a ruler. NOT freehand.
9. 22
Use 𝜋 as 3,142 and NOT as 7
QUESTION 1
1. Define the following:
[10]
QUESTION 2
2 Refer to FIGURE 1 (on the attached DIAGRAM SHEET) and calculate the
following:
[13]
QUESTION 3
3.5 The phase angle between the voltage and current (2)
[10]
QUESTION 4
4.1 Draw and label a sine wave of 720° with an RMS value of 220 V with a
frequency of 50 Hz. (4)
4.2 Calculate the following for the sine wave in QUESTION 4.1:
[12]
QUESTION 5
5.2 With the aid of neat labelled circuit diagrams, explain the following as
applicable to PN-junction diodes: (4)
Forward bias
5.6 Draw a fully labelled circuit diagram of a half-wave rectifier using a step down
transformer, a diode, capacitor and a load resistor. (6)
[16]
QUESTION 6
6.1 State FOUR advantages of the digital meter as compared to the analog
meter. (4)
6.2 State THREE precautions which must be taken when measuring voltage with
a multimeter. (3)
[7]
QUESTION 7
7.1 Draw and label a single-stage NPN transistor amplifier in a common emitter
configuration. A microphone and a loudspeaker must be connected to the
input and output terminals. (6)
[9]
QUESTION 8
8.2 Describe the difference between a light dependent resistor and a thermistor. (4)
8.3 The input power to a system is 100 mW and the power it delivers at the output (6)
is 10 mW. Calculate the system's power loss.
[13]
QUESTION 9
9.1 Draw the TABLE in FIGURE 2 on the attached DIAGRAM SHEET A in the
ANSWER BOOK and show the coupling between the transmitter and receiver
for a 240° phase shift. (6)
[10]
TOTAL: 100
DIAGRAM SHEET A
INDUSTRIAL ELECTRONICS N2
FORMULA SHEET
Marking Guidelines
NOVEMBER 2012
NATIONAL CERTIFICATE
INDUSTRIAL ELECTRONICS N2
(8080602)
QUESTION 1
1.1 Impedance is the total resistance offered to a circuit by the inductor, capacitor
and resistor. √√ (2)
1.2 Photodiodes are diodes which offer a high resistance in the dark, but when
incident, light falls onto the pn-junction, the diodes resistance decreases. √√ (2)
1.4 The forward bias voltage required to overcome the depletion region of the
diode for silicon diodes its 0, 6. √√ (2)
1.5 Covalent bonds is the sharing of valency electrons by two atoms. √√ (2)
[10]
QUESTION 2
2.1 15 𝑥 10
𝑅// = = 6𝛺 √
15+10
20 𝑥 20
𝑅// = = 10𝛺 √
20+20
10 𝑥 6
𝑅// = 10+6 = 3,75 𝛺 √
𝑅𝑇 // = 3,75 + 2 = 5,75 𝛺 √
12
𝐼𝑇 = 5,75 = 2,08 𝐴 √ (5)
[13]
QUESTION 3
3.2 1 (2)
𝑋𝐶 = = 16,08 √√
2 𝑥 3,141 𝑥 50 𝑥 198 𝑥 10−6
2
3.3 𝑍𝑇 = √102 + (16,08 − 3,14 = 167,557 𝛺 √√ (2)
3.4 𝐼𝑇 =
𝑉𝑡
𝑍𝑡
=
50
167,557
= 0,298 𝐴 √√ (2)
3.5 𝑅 10 (2)
𝜑 = cos−1 = cos−1 = 86,57 √√
𝑧 167,557
[10]
QUESTION 4
4.1
(4)
4.2.4 𝐼 𝐼 (2)
𝑡= = = 0,02 𝑠𝑒𝑐𝑜𝑛𝑑𝑠 √√
𝑓 50
[12]
QUESTION 5
5.1.1 (2)
5.1.2 (2)
5.1.3 (2)
5.3
(6)
[16]
QUESTION 6
[7]
QUESTION 7
7.1
(6)
QUESTION 8
8.1 A loudspeaker
A microphone
A solar cell (3)
8.2 LDR – This is a light sensitive resistor. The resistance varies with change in
light intensity. √√
8.3 𝑃0
𝑁 = 10 𝐿𝑜𝑔
𝑃1
10 𝑚𝑊
= 10𝐿𝑜𝑔 100 𝑚𝑊 √√
(6)
= −10 𝑑𝐵(𝑙𝑜𝑠𝑠 𝑜𝑟 𝑛𝑒𝑔𝑎𝑡𝑖𝑣𝑒 𝑔𝑎𝑖𝑛) √√√√
[13]
QUESTION 9
9.1
5 marks for each correct coupling. 1 extra mark if all correct – 6 marks (6)
[10]
TOTAL: 100
Table of C
Past Examination Papers
APRIL 2012
NATIONAL CERTIFICATE
INDUSTRIAL ELECTRONICS N2
(8080602)
22 March (X-Paper)
09:00 – 12:00
This question paper consists of 5 pages, 1 diagram sheet and a 3-page formula
sheet.
TIME: 3 HOURS
MARKS: 100
__________________________________________________________________
3. Number the answers according to the numbering system used in this question
paper.
7. ALL sketches must be neat, using a pencil and a ruler NOT freehand.
9. 22
Use 𝜋 as 3,142 and NOT as
7
QUESTION 1
1. Indicate whether the following statements are TRUE or FALSE. Choose the
answer and write only 'true' or 'false' next to the question number (1.1 - 1.10)
in the ANSWER BOOK.
1.3 The voltmeter must always be connected in parallel with the load. (1)
1.5 The common emitter amplifier has a 180° phase shift. (1)
1.6 The mid-ordinate rule is used to calculate the RMS values of sinusoidal wave
forms. (1)
1.7 The sum of the currents flowing towards a point is equal to the sum of the
currents flowing away from the same point. (1)
1.8 Electrons on the outer energy level are called valence electrons. (1)
1.9 Varactor diodes are most commonly used in FM and TV receiver circuits. (1)
[10]
QUESTION 2
[14]
QUESTION 3
3.4 The voltage drop across the inductor and the capacitor (4)
[14]
QUESTION 4
4.1 Draw neat, labelled characteristic curves of the silicon and germanium diodes
on the same axis. (6)
4.2 Draw a fully labelled circuit diagram of a direct current power supply using
FOUR diodes, step down transformer and filter capacitor. (5)
[11]
QUESTION 5
5. Refer to the table below and make use of the mid-ordinate rule to determine
the following:
(The above values are ordinates and not the mid-ordinate values)
[13]
QUESTION 6
6.2 State THREE advantages of digital meters over analogue meters. (3)
[10]
QUESTION 7
7. Answer the following questions with reference to transistor theory. Write only
the answer next to the question number (7 .1 - 7.3) in the ANSWER BOOK.
7.1 Draw and label a circuit symbol of a PNP silicon transistor. (3)
7.3 Draw a labelled circuit diagram of a common BASE amplifier circuit which
uses an NPN transistor. (3)
[9]
QUESTION 8
5.2 Calculate the gain or loss of an amplifier with an input of 1 W and an output
of 100 mW. (4)
[10]
QUESTION 9
[9]
TOTAL: 100
DIAGRAM SHEET
INDUSTRIAL ELECTRONICS N2
FORMULA SHEET
Marking Guidelines
APRIL 2012
NATIONAL CERTIFICATE
INDUSTRIAL ELECTRONICS N2
(8080602)
QUESTION 1
1.1 True (1)
[10]
QUESTION 2
2.1 20 𝑥 5
𝑅// = 20 ÷5 = 4𝛺 √
𝑅𝑆 = 4 𝛺 + 60 𝛺 + 36 𝛺 = 100 𝛺 √
𝑅// = (100 𝑥 100)/200 = 50𝛺 √
𝑅𝑡 = 50 𝛺 + 50 𝛺 = 100 𝛺 √√
𝐼𝑇 = 50/100 = 0,5 𝐴 (4)
[14]
QUESTION 3
3.3 1 (4)
𝑓𝑜 = = 1/0,01997 = 50𝐻𝑧 𝑋𝐶 = 𝑋𝐿
2𝜋√𝐿𝐶
3.4 𝑉𝑡 (4)
𝐼𝑇 = = 200/100 = 2𝐴 √√
𝑍𝑡
𝑉𝐿 = 2𝑥10 = 20𝑉 √
𝑉𝑐 = 2𝑥10 = 20𝑉 √
[14]
QUESTION 4
4.1
(6)
4.2
(5)
[11]
QUESTION 5
5.2 𝑣𝑅𝑀𝑆/𝐺𝐸𝑀 = 11,25 + 50 + 112,5 + 122,5 + 72,5 + 25/6 = 65,625 𝑉 √√√ (3)
5.3 𝑣 +𝑣 +𝑉 1 2 2 (3)
𝑉𝑊𝐺𝐾 = √ 2 𝑛2 2 = 77,642 𝑉 √√√
[13]
QUESTION 6
6.1 The ammeter must be connected in series with the load. Always start with the
highest scale. Switch of the power before measuring. (2)
6.2 More sensitive. More robust. No parallax error. No guessing. Overload (3)
indication.
[10]
QUESTION 7
7.1
(3)
7.3
(3)
[9]
QUESTION 8
8.1 The thermo couple is a temperature device consisting of two metals joined at
the ends. When one end is heated a potential difference is set up across the
two ends. This potential difference is proportional to the difference in
8.2 The bi-metal strip instead of generating a voltage it indicates only a change (3)
in temperature. The two Metals have different expansion coefficients
therefore it will bend when it is heated. √√√
8.3 𝑃0 (4)
𝑁 = 10 𝐿𝑜𝑔 = 10𝐿𝑜𝑔 100 𝑚𝑤 = −10 𝑑𝐵 √√√√
𝑃1
[10]
QUESTION 9
9.1 When a magnetic field cuts through a coil it induces a current to flow which
will generate a magnetic field. This magnetic field will oppose the original
field. (5)
9.2
(3)
9.3 Receiver and transmitter can be far apart. Contact can be by means of radio,
telemetering or wires. Very little energy is used. (3)
[9]
TOTAL: 100