Grade 8 Logical Reasoning in
Grade 8 Logical Reasoning in
Grade 8 Logical Reasoning in
Class 8
Logical Reasoning
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1 1 1 1
(1) (99999 + ) (99999 + ) − (99999 − ) (99999 − )= ?
33333 33333 33333 33333
a. 6 b. 3
c. 12 d. 33333
(2) How many more squares need to be shaded to cover 75% of the total area?
a. 6 b. 42
c. 24 d. 48
3
(3) P (x) is a polynomial such that P (x + ) = P (x). If P (9) = 344, find the value of P (21).
2
a. 344 b. 348
3 1
c. 344 d. 344
2 2
(4) What is the missing number in the series: 1, 2, 4, 3, 9, 4, 16, __25, 6, 36, 7 ?
a. 5 b. 4
c. 25 d. 6
(5) Tina introduces Rajesh as the son of the brother of her mother. How is Tina related to Rajesh?
a. Cousin b. Nephew
c. Aunt d. Daughter
(8) If N = 111112, find the 5th digit in the expansion of N from the right.
(9) During a day, the hour hand and the minute hand of a clock form a right angle, at multiple times.
For example, the two hands form a right angle at 9 am. How many times during a day (24 hours)
will the two hands form a right angle?
(10) Ashish likes 144 but not 134, 1600 but not 1700, and 5625 but not 5610. Which of the following
four numbers would he like: 629, 618, 625 or 622?
Solutions
(1) c. 12
Step 1
1 1 1 1
(99999 + ) (99999 + ) − (99999 − ) (99999 − )
33333 33333 33333 33333
2 2
1 1
(
= 99999 + ) − (99999 − )
33333 33333
Step 2
Using algebraic identities (a + b)2 = a
2
+ b
2
+ 2ab and (a − b)2 = a
2
+ b
2
− 2ab
2 2
1 1
(99999 + ) − (99999 − )
33333 33333
2 2
1 1 1 1
=99999
2
+ ( ) + 2 × 99999 × − [99999 2
+ ( ) − 2 × 99999 × ]
33333 33333 33333 33333
2 2
1 1 1 1
=99999
2
+ ( ) + 2 × 99999 × − 99999
2
− ( ) + 2 × 99999 ×
33333 33333 33333 33333
=2 × 3 + 2 × 3
=12
Step 3
Therefore, the value of
1 1 1 1
(99999 + ) (99999 + ) − (99999 − ) (99999 − ) is 12.
33333 33333 33333 33333
(2) b. 42
Step 1
The total number of squares = number of rows × number of columns
=8×8
= 64
Step 2
Let us now find the required number of shaded squares, which is 75% of the total number of
squares,
or 75% of 64
75
= 64 ×
100
= 48
Step 3
We can see in the picture that 6 squares are already shaded.
Step 4
Therefore, the number of more squares which need to be shaded
= The required number of shaded squares − The number of squares already shaded
= 48 − 6
= 42
Step 5
Hence, 42 more squares need to be shaded to cover 75% of the total area.
(3) a. 344
Step 1
It is given that,
3
P (x + ) = P (x)
2
3
It means that value of polynomial P for any x is same as its value for (x + ).
2
Step 2
3
It also means that if we keep adding to the x, the value will remain unchanged.
2
3
i. e. P (x) = P (x + )
2
3 3 3
⟹ P (x) = P [(x + )+ ] = P (x + 2 × )
2 2 2
3 3 3
⟹ P (x) = P [(x + 2 × )+ ] = P (x + 3 × )
2 2 2
3 3 3
⟹ P (x) = P [(x + 3 × )+ ] = P (x + 4 × )
2 2 2
and so on..
3 3 3
⟹ P (x) = P [(x + 3 × )+ ] = P (x + n × ) … [ Where n is any natural number]
2 2 2
Step 3
Now we can write P (21) in terms of P (9) as following,
P (21) = P (9 + 12)
3
⟹ P (21) = P (9 + 8 × )
2
Step 4
Since P (21) = P (9), value of P (21) = 344
(4) a. 5
Step 1
1, 2, 4, 3, 9, 4, 16, __25, 6, 36, 7
If we look at the given series carefully, we notice that the given series is like:
1, n, n2, (n+1), (n+1)2, (n+2), (n+2)2........
(Where, n = 2, 3, 4.....). So, we can say that the missing number in the series 1, 2, 4, 3, 9, 4,
16, __25, 6, 36, 7 is 5.
Step 2
Hence, option a is the correct answer.
(5) a. Cousin
Step 1
According to the question, Tina introduces Rajesh as the son of the brother of her mother.
Step 2
Or, we can say that the brother of Tina's mother is the maternal uncle of Tina.
Step 3
Or, we can say that Rajesh is the son of Tina's maternal uncle.
Step 4
Or, we can say that Rajesh is the cousin of Tina.
Step 5
Hence, option a is the correct answer.
(6) c. 5
Step 1
It is given that x+ = 1 + 2 + 3 + ... + x
Step 2
According to the question, (15+) - (14+) = (k+)
⇒ (1+2+3+ ... +15) - (1+2+3+ ... +14) = (1+2+3+ ... +k)
Step 3
Let us find the value of k for which sum of first k natural numbers is 15.
Let us start with k = 2
For k = 2, 1 + 2 = 3
For k = 3, 1 + 2 + 3 = 6
For k = 4, 1 + 2 + 3 + 4 = 10
For k = 5, 1 + 2 + 3 + 4 + 5 = 15
Step 4
Therefore, the value of k is 5. Hence, option c is the correct answer.
(7) 6
Step 1
It is given that x+ = 1 + 2 + 3 + ... + x
Step 2
According to the question, (21+) - (20+) = (k+)
⇒ (1+2+3+ ... +21) - (1+2+3+ ... +20) = (1+2+3+ ... +k)
Step 3
Let us find the value of k for which sum of first k natural numbers is 21.
Let us start with k = 2
For k = 2, 1 + 2 = 3
For k = 3, 1 + 2 + 3 = 6
For k = 4, 1 + 2 + 3 + 4 = 10
For k = 5, 1 + 2 + 3 + 4 + 5 = 15
For k = 6, 1 + 2 + 3 + 4 + 5 + 6 = 21
Step 4
Hence, the value of k is 6.
(8) 5
Step 1
The square of 11 is equal to 121.
Step 2
The square of 111 is equal to 12321.
Step 3
We can see that the squares of such numbers follow a pattern. Based on the pattern the
square of 11111 will be 123454321.
Step 4
We can see that the 5th digit in the square of 11111 from the right is 5.
(9) 44
Step 1
Let us look at the clock at 9 am:
We can see that the hour hand and the minute hand are making a right angle.
Step 2
In a clock, while the minute hand moves, the hour hand also moves, although a lot slowly.
It is easy to see that in a 12 hour period, the minute hand make 12 revolutions while, the hour
hand makes one.
Step 3
For each revolution around the hour hand, the minute hand makes a right angle twice with it.
The total number of times we see the two hands making a right angle is 11 × 2 = 22.
Step 4
In 12 hours, the number of times the two hands make a right angle = 22
In 24 hours, the number of times the two hands make a right angle = 22 × 2 = 44
(10) 625
Step 1
If we look at the pattern, we notice that Ashish likes only those numbers which have complete
squares.
144 = 122
1600 = 402
5625 = 752
Step 2
Now, observe the given options and see if there is any number which has complete square.
Among the given options, we notice that 625 = 252.
Hence, 625 has complete square of 25.
Step 3
Therefore, Ashish will like 625.