The Concept of Range and Variance
The Concept of Range and Variance
The Concept of Range and Variance
A. What is the range of this set: {15, 12, 8, 10, 6, 12, 18}?
B. What is the range of this set: {5.2, 3.75, 3.8, 3.8, 8.0, 6.25, 5.2, 8.5}?
D. The ages of the 7 grandchildren of Mrs. Mercado are: 7, 5, 3, 12, 6, 7 and 4 years old.
Compute for the range.
E. Seven students in Statistics class have the following IQ’s: 110, 125, 122, 100, 120, 112
and 127. Determine the range.
F. Let x be a natural number. What is the range of this set: {x, x + 1, x - 2, x + 5, x - 3}?
G. Let x be a natural number. What is the range of this set: {x, x + 1, x + 5, x + 4}?
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H. What is the variance of this set: {x, x + 1, x + 5, x + 2}?
● MEAN
○ {x, x+1, x+2, x+5}
○ (x + x+1 + x+2 + x+5) / 4
○ 4x + 1 + 2 + 5
○ 4x + 8 = x+2
● VARIANCE
○ σ² = [(x - x+2)2 + (x+1 - x+2)2 + (x+2 - x+2)2 +(x+5 - x+2)2] / 4
○ σ² = [(x) + (-x-2)2] + [(x+1) + (-x-2)2] + [(x+2 + (-x-2)2] + [(x+5 + (-x-2)2] / 4
○ σ² = (-22 + -12 + 0 + 32) / 4
○ σ² = (4 + 1 + 0 + 9) / 4
○ σ² = (14) / 4
○ σ² = 3.5
I. What is the standard deviation of this set: {3.75, 3.8, 3.8, 5.2, 8.5}?
● MEAN
○ {3.75, 3.8, 3.8, 5.2, 8.5}
○ (3.75 + 3.8 + 3.8 + 5.2 + 8.5) / 5
○ (25.05) / 5 = 5.01
● VARIANCE
○ σ² = [(3.75 - 5.01)2 + (3.8 - 5.01)2 + (3.8 - 5.01)2 + (5.2 - 5.01)2 + (8.5 - 5.01)2] / 5
○ σ² = (1.59 + 1.46 + 1.46 + 0.04 + 12.18) / 5
○ σ² = 3.35
● STANDARD DEVIATION
○ σ = √3.35
○ σ = 1.83
J. The heights of 5 students are 156 cm, 176 cm, 157 cm, 169 cm and 167 cm. What is the
standard deviation of their heights?
● MEAN
○ {156, 157, 167, 169, 176}
○ (156 + 157 + 167 + 169 + 176) / 5 = 165
● VARIANCE
○ σ² = [(156 - 165)2 + (157 - 165)2 + (167 - 165)2 + (169 - 165)2 + (176 - 165)2] / 5
○ σ² = (81 + 64 + 4 + 16 + 121) / 5
○ σ² = 57.2
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● STANDARD DEVIATION
○ σ = √57.2
○ σ = 7.56cm
K. The ages of the 7 grandchildren of Mrs. Mercado are: 7, 5, 3, 12, 6, 7 and 4 years old.
Compute for the standard deviation.
● MEAN
○ {3, 4, 5, 6, 7, 7, 12}
○ (3 + 4 + 5 + 6 + 7 + 7 + 12) / 7 = 6.29
● VARIANCE
○ σ² = [(3 - 6.29)2 + (4 - 6.29)2 + (5 - 6.29)2 + (6 - 6.29)2 + (7 - 6.29)2 + (7 - 6.29)2 +
(12 - 6.29)2] / 7
○ σ² = (10.82 + 5.24 + 1.66 + 0.08 + 0.50 + 0.50 + 32.60) / 7
○ σ² = 7.34
● STANDARD DEVIATION
○ σ = √7.34
○ σ = 2.71
L. Determine the standard deviation of Paulo’s grades in three quizzes: 88%, 98% and 86%.
● MEAN
○ {86%, 88%, 98%}
○ (0.86 + 0.88 + 0.98) / 3 = 0.91
● VARIANCE
○ σ² = [(0.86 - 0.91)2 + (0.88 - 0.91)2 + (0.98 - 0.91)2] / 3
○ σ² = (0.0025 + 0.0009 + 0.0049) / 3
○ σ² = 0.0028
● STANDARD DEVIATION
○ σ = √0.0028
○ σ = 0.053 or 5.3%
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❏ 6 = (5x + 10) / 5
❏ 30 = 5x + 10
❏ 30 - 10 = 5x
❏ 20 = 5x
❏ x=4
● MEAN
○ [(x + (x+1) + (x+2) + (x+3) + (x+4)] / 5
○ [(4 + (4+1) + (4+2) + (4+3) + (4+4)] / 5
○ (4 + 5 + 6 + 7 + 8) / 5
○ 30 / 5 = 6 (the mean we are given)
● VARIANCE
○ σ² = [(4-6)2 + (5-6)2 + (6-6)2 + (7-6)2 + (8-6)2] / 5
○ σ² = (4 + 1 + 0 + 1 + 4) / 5
○ σ² = 2
● STANDARD DEVIATION
○ σ = √2
○ σ = 1.41
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SUBSTITUTE THE VALUE OF x:
● MEAN
○ [(x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6)] / 7
○ [(7 + (7+1) + (7+2) + (7+3) + (7+4) + (7+5) + (7+6)] / 7
○ (7 + 8 + 9 + 10 + 11 + 12 + 13) / 7
○ 70 / 7 = 10 (the mean we are given)
● VARIANCE
○ σ² = [(7-10)2 + (8-10)2 + (9-10)2 + (10-10)2 + (11-10)2 + (12-10)2 + (13-10)2]
/5
○ σ² = (9 + 4 + 1 + 0 + 1 + 4 + 9) / 7
○ σ² = 4
● STANDARD DEVIATION
○ σ = √4
○ σ=2
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