NSTSE Class 7 Solved Paper 2022
NSTSE Class 7 Solved Paper 2022
NSTSE Class 7 Solved Paper 2022
Class : 7 Mathematics
2 3 1
05. If = , then select the value of x .
3 x 2 x 12
(A) –8 (B) 10 (C) –10 (D) 12
5y 3 1
Test Asse ss A chiev e
R S
x
o
110 T
P Q
35°
R
60°
Q S
(A) 20° (B) 12.5° (C) 72.5° (D) 15°
09. In a ABC, E is the midpoint of AC and G is the centroid
of the triangle. What is BE : BG ?
(A) 1 : 2 (B) 2 : 1 (C) 3 : 1 (D) 3 : 2
10. In KLM and XYZ. KL = YX, L = Y and M = Z. By
which congruence condition are the triangles
congruent ?
(A) R.H.S. (B) A.S.A. (C) S.A.S. (D) S.S.S.
and
7 5
13. Choose two rational numbers lying between
3 4
1 17 7 19
(A) , (B) ,
4 6 5 5
2 1 1 19
(C) , (D) ,
3 8 4 6
1 1 1 1 1
14. Select the value of + + + + .
15 35 63 99 143
5 4 2 7
(A) (B) (C) (D)
39 39 39 39
x x
20. Find the value of x if + = x – 14
4 6
(A) 9 (B) 15 (C) 18 (D) 24
7
(A) a2b2c ab2c ab2c ab2c
1 11 1
10 2 28 8
3
(B) a2b2c ab2c ab2c ab2c
1 11 1
10 2 28 8
3 3abc2 1 2
(C) a2b2c ab2c a bc
1
10 2 28 8
3
(D) a2b2c ab2c abc2 a2bc
1 11 1
10 2 28 8
x+1
3 3 5
Choose the value of ‘x’ if =
2 x+1 7
Class : 7 Physics
P Q R S
Connect the terminals with wires to make a battery of
four cells.
(A) A-Q, C-D, D-P (B) P-B, R-S, Q-C
(C) A-B, Q-R, C-S (D) A-B, Q-R, C-D
27. Given that pendulum P is 1 kg, pendulum Q is 10 kg,
pendulum R is 100 kg and the effect of air resistance is
negligible. Identify a true statement.
(A) They will have the same time period.
(B) Pendulum P will oscillate the fastest.
(C) Pendulum R will oscillate the fastest.
(D) They will all swing at different time periods.
50 km
40 km
30 km
20 km A
10 km
B
10.00 10.30 11.00 11.30 12.00 12.30
Time
Identify the correct statement from the following.
(A) A and B move with the same speed.
(B) B moves with non-uniform speed.
(C) A completes his journey early.
(D) B overtakes A at 11.20 a.m.
Class : 7 Chemistry
Column I Column II
a. Burning of wood 1. Physical change
b. Formation of day and night 2. Slow change
c. Curdling of milk 3. Periodic change
d. Melting of ice 4. Chemical change
(A) a-2, b-3, c-4, d-1 (B) a-4, b-3, c-2, d-1
(C) a-4, b-3, c-1, d-2 (D) a-3, b-4, c-2, d-1
45. The given figure shows a doubling in the volume of air.
Air
particles
Class : 7 Biology
Alcohol
Leaf
Heat
P
Q
R
S
(A) (i), (ii) and (iii) only (B) (i), (iii) and (iv) only
(C) (ii), (iii) and (iv) only (D) (i), (ii), (iii) and (iv)
Y
What are the cells labelled X and Y ?
(A) X - xylem; Y - phloem
(B) X - phloem; Y - xylem
(C) X - spongy mesophyll; Y - palisade mesophyll
(D) X - palisade mesophyll; Y - spongy mesophyll
Z
Y
X
(A) (B)
(C) (D)
B
X
S S
C
(A) (B)
(C) (D)
(A) (B)
(C) (D)
CLASS - 7
Question Paper Code : UN474
KEY
1. C 2. D 3. D 4. A 5. C 6. D 7. C 8. B 9. D 10. B
11. C 12. C 13. C 14. A 15. B 16. A 17. D 18. C 19. B 20. D
21. B 22. C 23. B 24. C 25. B 26. C 27. A 28. C 29. B 30. B
31. C 32. A 33. D 34. C 35. C 36. A 37. C 38. B 39. A 40. A
41. B 42. C 43. C 44. B 45. D 46. A 47. B 48. C 49. A 50. A
51. B 52. D 53. C 54. D 55. D 56. D 57. B 58. C 59. A 60. D
SOLUTIONS
MATHEMATICS
01. (C) Given 3B = 2A + 2B 02. (D) Areas ratio = r12 : r22 : r32
3B – 2B = 2A = r12 : r22 : r32
B = 2A
21 14 7
But A + B + C = 180° m : m : m s
2 2 2
2 2 2
A + 2A + 3B = 180°
7 3 7 3 2 7 2 7 2 2 7 1 7 1 2
3A + 3(2A) = 180° m : m : m
[ B = 2A]
4 4 4
9A = 180° = 9 : 4: 1
180
A 20
9
B = 2A = 40°
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1
RSQ = 60° RQS = 60°
Given A :B : 6 : 6 = 3 : 2
In PQR, 35° + PQS + PSQ = 180°
1 1 1 1
03. (D)
2 3 2 3
=3:2=3×3:2×3=9:6 PQS + PQS
= 180° – 35° = 145° [ PSQ = PQS]
B : C : 3:2 3 2: 2 2 6 : 4
1 1
2 3 2PQS = 145°
145
PQS RSQ
A:B:C=9:6:4
04. (A) No. of students walk to school 2
PSR = PSQ = RSQ
420 180
3
=
7 = 72.5° – 60°
No. of students come to school by bus = 12.5°
= 420 168
2
09. (D) Centrold divides median in the ratio
5
No. of students come to school bicycle 2 : 1 from vertex
= 420 – 180 – 68 = 72 B
49 1
05. (C) = G
6 x 12
5 1
A E C
= BE : BG = BG + EG : BG
6 x 12
5×12
= (2 + 1) : 2
=x =3:2
Given in KLM & XYZ
6
10. (B)
x = –10
5y 3 1
K X
21 y 1 5
06. (D) Given
L M Y Z
L = Y and M = Z then K = X
5(5y – 3) = 21y + 1
25y – 15 = 21y + 1
25y – 21y = 1 + 15 K = X and KL = YX
4y = 16 and L = Y
KLM XYZ [ ASA congruency]
y
4
16
11. (C) SP of first watch (SP1) = `1089
4
Gain = 10%
(100 9)
07. (C) Given x + 90° = 110°
x = 110° – 90° SP1 CP1
100
(100 10)
= 20°
08. (B) In QRS, QR = RS RSQ = RQS `1089 CP1
60° + RSQ + RQS = 180°
100
[ RQS = RSQ]
11
CP1 = ` 990
2RSQ = 120°
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2
Smilarly CP2 `1089 `1210
10 1 1 1 1 1
14. (A) + + + +
9 15 35 63 99 143
Total CP = CP + CP2 1 1 1 1 1
= + + + +
= ` 990 + `1210 = `2200 3× 5 5× 7 7× 9 9 ×11 11×13
2 1 1
Total SP = 2 × ` 1089 = ` 2178
Total Loss = ` 2200 – ` 2178 = ` 22 2 3× 5 5× 7 7 × 9 9 ×11 11×13
1 1 1
= + + + +
1 2 2
Total Loss percentage
1 1 1 1 1 1 1 1 1 1 1
+ + + +
(OR) (Short Cut)
2 3 5 5 7 7 9 9 11 11 13
=
If two SP are same and having same loss
1 1 1 1 13 3
& profit percentage of both watches
2 3 13 2 39
then there is always loss % Loss
= =
percentage
x2 102 100
100 100 100
10 5
= =
=1% 2× 39 39
12. (C) Distance to be covered 15. (B) Inner length = 12cm – 1cm – 1cm = 10cm
10h 420 KM
42 KM Inner breadth = 8cm – 2cm – 2cm = 4cm
1h Perimeter of inner rectangle
Speed of the car = 2(l+b) = 2(10cm + 4cm)
60 KMPH
distance 420km = 28 cm
time 7hours
16. (A) Given a – b = –11
Speed to be increased
Squaring on both sides
(a – b)2 = (–11)2
= 60 KMPH – 42 KMPH = 18KMPH
7 5 a2 – 2ab + b2 = 121
13. (C) = 2.33 & = – 1.25
3 4
a2 – 2(–28) + b2 = 121
1 7 5 a2 + 56 + b2 = 121
= – 0.25 it lies between &
4 3 4
a2 + b2 = 121 – 56 = 65
(–2)–3 =
17 1
= 2.83 it does n’t lie between 17. (D) = – 0.125
6 8
7 5
(–10)–3 0.001
1
1000
&
3 4
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3
3 3 5
19. (B) Let ‘x’ to be subtracted 2 x 1 x 1
5 5
– 2.938 = x
x 14
3 3
x x 2 x 8 x1
20. (D) Given
5 5
4 6
3 x 2 x 12 x
14 2x + 8 = –x – 1
12
2x + x = –1 – 8
–7x = = –14 × 12
14 12
3x = –9
x 9
7 x 3
3
x = 24
25. (B) 461 + 462 + 463 + 464
Area of rectangle 31 m 12 m
1 4
21. (B) = 461(1 + 41 + 42 + 43)
4 5
= 461×(5 + 16 + 64)
25 16
125 64 = 461 × 85
m2
41 51
= 460 × 2 × 2 × 85
= 400 m2 = 460 × 2 × 170
1 2 2 1 = 460 × 2 × 17 × 10
10 is the factor of
22. (C) LHS = a b c – a2b2c
2 5
1 1 1 1
the next cell as shown below.
a2b2c ab2c
2 5 6 3
A B C D
1 1 1
abc2 a2bc
4 7 8
a b c ab c abc2 a2bc
3 2 2 1 2 3 1
10 2 28 8 P Q R S
4
29. (B) The chemical energy stored in two cells CHEMISTRY
is more than that in one. So, the bulb in
the circuit that has one bulb and two 36. (A) When strong winds blow over a weak
cells will glow the brightest. thatched roof, it creates a low pressure
over it and a high pressure inside the
Speed
Distance hut causing the roof to blow off. Opening
30. (B) the doors and windows reduces this
Time
pressure difference and prevents the
Distance roof from being blown off.
Let the distance be x, = Time
37. (C) SO3 on hydrolysis gives H2SO4 which is
a strong acid. SO3 + H2O H2SO4
Speed
t1 + t2 = + = 1,
x x 2 x + 3x
=1 38. (B) Precipitation of rain and snow is only a
3 2 6
change of state and no new substance
5x 6 : x 1.2 km
6 is formed. It is a physical change. Rest
of them are chemical changes.
5
39. (A) Lemon juice is acidic with pH-2 and
31. (C) Conduction occurs only in solids, coffee is also acidic with pH 5. Hence,
convection occurs only in liquids and both are acidic
gases, and radiation requires no medium.
40. (A) When sodium chloride (salt) is added to
32. (A) An electromagnet consists of a core of water, it forms a solution and no new
soft iron wrapped around with a coil of substance is formed. Hence, it is a
insulated copper wire. physical change.
33. (D) Statements (A), (B) and (C) are incorrect 41. (B) Carbon forms two oxides CO and CO2.
CO 2 + H 2O H 2CO 3. CO is neutral.
according to the given graph. A takes CO2 on hydrolysis gives carbonic acid
more time than B. So, their speeds are
different. Next, the slope for A and B is Carbon is the non-metal.
a straight line, hence B moves with 42. (C) A physical change is reversible whereas
uniform speed. Finally, it is B and not A a chemical change is irreversible.
who completes the journey early. B
overtook A at 11.20 a.m. 43. (C) The solutions which do not change the
colour of either red or blue litmus papers
34. (C) When a body is heated, the heat energy are known as neutral solutions.
increases the space between particles
44. (B) The correct matching is a-4, b-3, c-2, d-
in the body that tends to increase the
1 Burning of wood - chemical change
volume of the body when heated. This
results in expansion of bodies. Formation of day and night - periodic
change.
35. (C) The iron nail will move towards
electromagnet A as it has more coils of Curdling of milk - slow change
wire around it than electromagnet B and Melting of ice - physical change
thus, it exerts a stronger magnetic force
45. (D) When the volume of air is doubled the
than electromagnet B.
particles are very far apart with less
collisions with the container walls that
results in lowering of air pressure.
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5
BIOLOGY CRITICAL THINKING
46. (A) The alcohol dissolves the chlorophyll in 56. (D) P7Q3R4S
the boiled leaf, when the leaf is boiled
Q (+)
in alcohol.
(Daughter)
(Father)
47. (B) Saliva contains amylase which breaks
P (–) R (–)
down the starch in bread to maltose, a
disaccharide which tastes sweet. (Mother)
S
48. (C) A row of trees can help conserve soil as
the trees act as a windbreak, reducing
soil erosion caused by blowing wind.
49. (A) The pancreas produces pancreatic juice 57. (B)
(that contains amylase and lipase) and
hormones involved in the regulation of 58. (C) Hyderabad
blood glucose concentrations (insulin
59. (A) Option (A) is not in the given figure.
and glucagon). Pepsin is produced in the
stomach and requires an acidic pH to
function. (D)
50. (A) X and Y form part of a vascular bundle.
The xylem vessels are located on the
upper side of the vascular bundle, while (C)
the phloem vessels are located on the
lower side.
51. (B) The walls of blood capillaries are one-
cell thick to assist in the diffusion of
substances.
52. (D) Seed leaves provide food to the growing
plants. Hence at stages (i), (ii) and (iii)
are not affected if it was placed in a dark
room. (B)
53. (C) Yarn is made by spinning. 60. (D) Number of stars and triangles are
54. (D) The function of the beak of the bird subtracted from 1st and 2nd image, we
shown is to reach small fruits from get 3rd image.
tender branches, regulate heat
distribution and to attract a mate and
reproduce.
55. (D) In the given figure X, Y and Z are RBC,
platelets and WBC respectively. WBC
produces antibodies and its count goes
up when there is any infection in the
body.
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