b. 2) It defines various terminology related to ellipses such as foci, directrix, vertices, major axis, minor axis, principal axes, centre, diameter, and focal chord. 3) Diagrams are included to illustrate these terms visually."> b. 2) It defines various terminology related to ellipses such as foci, directrix, vertices, major axis, minor axis, principal axes, centre, diameter, and focal chord. 3) Diagrams are included to illustrate these terms visually.">
JEE+Crash+course+ +Phase+I+ +Ellipse+and+Hyperbola+ +vmath
JEE+Crash+course+ +Phase+I+ +Ellipse+and+Hyperbola+ +vmath
JEE+Crash+course+ +Phase+I+ +Ellipse+and+Hyperbola+ +vmath
http://vdnt.in/HARSHPRIYAM
https://t.me/harshpriyam
priyam_harsh
23 Nov Parabola
29 Nov Statistics
30 Nov Probability
Session Link
+
Mock Paper
+
Session PDF
All available at
one place
Link in the description
Q. Let P(a, b) be a point on the parabola
y2 = 8x such that the tangent at P passes
through the centre of the circle
x2 + y2 - 10x - 14y + 65 = 0. Let A be the
product of all possible values of a and B be
the product of all possible values of b. Then
the value of A + B is equal to:
JEE Main 2022 27 July Shift I
A 0 B 25
C 40 D 65
Q. Let P(a, b) be a point on the parabola
y2 = 8x such that the tangent at P passes
through the centre of the circle
x2 + y2 - 10x - 14y + 65 = 0. Let A be the
product of all possible values of a and B be
the product of all possible values of b. Then
the value of A + B is equal to:
Q. Let P(a, b) be a point on the parabola
y2 = 8x such that the tangent at P passes
through the centre of the circle
x2 + y2 - 10x - 14y + 65 = 0. Let A be the
product of all possible values of a and B be
the product of all possible values of b. Then
the value of A + B is equal to:
Solution
Q. Let P(a, b) be a point on the parabola
y2 = 8x such that the tangent at P passes
through the centre of the circle
x2 + y2 - 10x - 14y + 65 = 0. Let A be the
product of all possible values of a and B be
the product of all possible values of b. Then
the value of A + B is equal to:
JEE Main 2022 27 July Shift I
A 0 B 25
C 40 D 65
Ellipse
TWO STANDARD ELLIPSE
axes is
B(0, b)
P(x, y)
M’ M
L1 L
X’ C X
Z’ A’ S’ (ae, 0) S A Z
(-a, 0) (ae, 0) (a, 0)
L1’ L’
B’
(0, -b)
Directrix
Directrix
Y’
Y
GENERAL TERMINOLOGY
B(0, b)
P(x, y)
M’ M
L1 L
C X
Z’ A’ S’ (ae, 0) S A Z
(-a, 0) (ae, 0) (a, 0)
L1’ L’
B’
(0, -b)
Directrix
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
Y
GENERAL TERMINOLOGY
(k) Latus Rectum: The focal chord
perpendicular to the major axis is called the
latus rectum.
B(0, b) (i) Length of latus rectum (LL’)
P(x, y)
M’ M
L1 L
C X
Z’ A’ S’ (ae, 0) S A Z
(-a, 0) (ae, 0) (a, 0)
(ii) Equation of latus rectum: x = 士ae.
L1’ L’ (iii) Ends of the latus rectum are
B’
(0, -b)
Directrix
Directrix
and
Y’
Y
GENERAL TERMINOLOGY
Directrix
Y’
ANOTHER FORM OF ELLIPSE
Z y = b/e ANOTHER FORM OF ELLIPSE
Directrix B(0, b)
(a) AA’ = Minor axis = 2a
A’ (-a, 0) A(a, 0)
(c) a2 = b2(1 - e2)
X’ X
C (0, 0) (d) Latus rectum LL’ = L1L1’ = ,
L1’ L1
S’ (0, -be)
Equation y = 土 be
B’(0, -b)
Z’ y = - b/e
Directrix
Y’
Z y = b/e ANOTHER FORM OF ELLIPSE
Directrix B(0, b)
(e) Ends of the latus rectum are:
S (0, be)
A’ (-a, 0) A(a, 0)
X’ X
C (0, 0)
L1’ L1
S’ (0, -be)
(f) Equation of directrix y = 土 b/e
B’(0, -b)
(g) Eccentricity:
Z’ y = - b/e
Directrix
Y’
SHIFTED ELLIPSE
Point Form
Note
Slope Form
Parametric Form
Note
points 𝝰 & 𝛃 is
NORMAL TO ELLIPSE
Point Form
Slope Form
Parametric Form
A
If P(x1, y1) be any point lies outside the ellipse
Y’
CHORD WITH GIVEN MIDDLE POINT
T = S1 where
Hyperbola
STANDARD EQUATION
S’ A’ C A S
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
L’
GENERAL TERMINOLOGY
y
(b) Equations of directrices :
L
B (0, b) x = (ae, b2/a)
S’ A’ C A S
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
L’
GENERAL TERMINOLOGY
y
(c) Vertices :
L A ≡ (a, 0) & A’ ≡ (-a, 0).
B (0, b) x = (ae, b2/a)
S’ A’ C A S
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
L’
GENERAL TERMINOLOGY
y
(d) Latus rectum :
L (i) Equation : x = ±ae
B (0, b) x = (ae, b2/a) (ii) Length
S’ A’ C A S
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
(iii) Ends :
L’
GENERAL TERMINOLOGY
y
(e) (i) Transverse Axis :
L The line segment A’A of
B (0, b) x = (ae, b2/a) length 2a in which the foci S’
& S both lie is called the
Transverse Axis of the
S’ A’ C A S Hyperbola.
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
L’
GENERAL TERMINOLOGY
y
(e) (ii) Conjugate Axis :
L The line segment B’B
B (0, b) x = (ae, b2/a) between the two points B’≡
(0, -b) & B ≡ (0, b) is called as
the Conjugate Axis of the
S’ A’ C A S Hyperbola.
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
The Transverse Axis & the
Conjugate Axis of the
B’ (0, b) (ae, -b2/a) hyperbola are together called
the Principal axes of the
L’ hyperbola.
GENERAL TERMINOLOGY
y
(f) Focal Property :
L The difference of the focal
B (0, b) x = (ae, b2/a) distances of any point on the
hyperbola is constant and
equal to transverse axis i.e.
S’ A’ C A S ||P S| - |P S’|| = 2a.
x The distance SS’ =
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
focal length.
L’
GENERAL TERMINOLOGY
y
(g) Focal distance :
L Distance of any point P(x, y)
B (0, b) x = (ae, b2/a) on Hyperbola from foci PS =
ex - a & PS’ = ex + a.
S’ A’ C A S
x
(-ae, 0) (-a, 0) (0, 0) (a, 0) ae, 0
L’
CONJUGATE HYPERBOLA
(-a, 0) (a, 0)
Note
Let
The quantity
where θ is a parameter.
TANGENT TO THE HYPERBOLA
Point Form
Slope Form
Parametric Form
Point Form
Slope Form
Parametric Form
or T = 0 at (x1, y1).
PAIR OF TANGENTS
i.e.
CHORD WITH GIVEN MIDDLE POINT
is T = S1
where
RECTANGULAR HYPERBOLA
y
A hyperbola is said to be rectangular hyperbola
A2 y=x if its transverse axis is equal to its conjugate
A1
axis i.e. b = a ⇒ e = .
y = -x
In rectangular hyperbola asymptotes are
perpendicular to each other.
45o
x
For x2 - y2 = a2 its asymptotes are y = 土 x.
RECTANGULAR HYPERBOLA
reduced to or
respectively. In
1000
Vedantu Students
Qualify NEET 2022
JEE Adv. 2022
V are proud of you,
Deevyanshu!
JEE Adv. 2022
V are proud of you,
Chaitanya!
JEE Adv. 2022
V are proud of you,
Krish!
Our JEE Adv. 2022 Achievers
Our JEE Adv. 2022 Achievers
Our JEE Adv. 2022 Achievers
Our JEE Adv. 2022 Achievers
Our JEE Adv. 2022 Achievers
Q. If distance between the foci of an ellipse is
6 and distance between its directrices is 12,
then length of its latus rectum is
JEE Main 2020 7 Jan Shift I
A 4
C 9
D
Q. If distance between the foci of an ellipse is
6 and distance between its directrices is 12,
then length of its latus rectum is
Solution
Q. If distance between the foci of an ellipse is
6 and distance between its directrices is 12,
then length of its latus rectum is
JEE Main 2020 7 Jan Shift I
A 4
C 9
D
Q. The locus of the mid point of the line
segment joining the point (4, 3) and the
points on the ellipse x2 + 2y2 = 4 is an ellipse
with eccentricity:
JEE Main 2022 26 June Shift 2
D
Q. The locus of the mid point of the line
segment joining the point (4, 3) and the
points on the ellipse x2 + 2y2 = 4 is an ellipse
with eccentricity:
Q. The locus of the mid point of the line
segment joining the point (4, 3) and the
points on the ellipse x2 + 2y2 = 4 is an ellipse
with eccentricity:
Solution
Q. The locus of the mid point of the line
segment joining the point (4, 3) and the
points on the ellipse x2 + 2y2 = 4 is an ellipse
with eccentricity:
JEE Main 2022 26 June Shift 2
D
Q. If a hyperbola passes through the point
P(10, 16) and it has vertices (±6, 0), then the
equation of the normal to it at P is:
JEE Main 2020 8 Jan Shift 2
A 2x + 5y = 100
B 2x + 5y = 10
C 2x - 5y = 100
D 5x + 2y = 100
Q. If a hyperbola passes through the point
P(10, 16) and it has vertices (±6, 0), then the
equation of the normal to it at P is:
Q. If a hyperbola passes through the point
P(10, 16) and it has vertices (±6, 0), then the
equation of the normal to it at P is:
Solution
Q. If a hyperbola passes through the point
P(10, 16) and it has vertices (±6, 0), then the
equation of the normal to it at P is:
JEE Main 2020 8 Jan Shift 2
A 2x + 5y = 100
B 2x + 5y = 10
C 2x - 5y = 100
D 5x + 2y = 100
Q. A hyperbola has its centre at the origin,
passes through the point (4, 2) and has
transverse axis of length 4 long the x-axis.
Then, the eccentricity of the hyperbola is:
JEE Main 2019 9 Jan Shift 2
C 2
D
Q. A hyperbola has its centre at the origin,
passes through the point (4, 2) and has
transverse axis of length 4 long the x-axis.
Then, the eccentricity of the hyperbola is:
Q. A hyperbola has its centre at the origin,
passes through the point (4, 2) and has
transverse axis of length 4 long the x-axis.
Then, the eccentricity of the hyperbola is:
Solution
Q. A hyperbola has its centre at the origin,
passes through the point (4, 2) and has
transverse axis of length 4 long the x-axis.
Then, the eccentricity of the hyperbola is:
JEE Main 2019 9 Jan Shift 2
C 2
D
Q. The acute angle between the pair of
tangent drawn to the ellipse 2x2 + 3y2 = 5
from the point (1, 3) is
JEE Main 2022 26 July Shift 2
D
Q. The acute angle between the pair of
tangent drawn to the ellipse 2x2 + 3y2 = 5
from the point (1, 3) is
Q. The acute angle between the pair of
tangent drawn to the ellipse 2x2 + 3y2 = 5
from the point (1, 3) is
Solution
Q. The acute angle between the pair of
tangent drawn to the ellipse 2x2 + 3y2 = 5
from the point (1, 3) is
JEE Main 2022 26 July Shift 2
D
Q. Let e1 and e2 be the eccentricities of the ellipse,
and the hyperbola,
respectively satisfying e1e2 = 1. If 𝛼
and β are the distances between the foci of the
ellipse and the foci of the hyperbola respectively,
then the ordered pair (𝛼, β) is equal to:
A (8, 10)
D (8, 12)
Q. Let e1 and e2 be the eccentricities of the ellipse,
and the hyperbola,
respectively satisfying e1e2 = 1. If 𝛼
and β are the distances between the foci of the
ellipse and the foci of the hyperbola respectively,
then the ordered pair (𝛼, β) is equal to:
Q. Let e1 and e2 be the eccentricities of the ellipse,
and the hyperbola,
respectively satisfying e1e2 = 1. If 𝛼
and β are the distances between the foci of the
ellipse and the foci of the hyperbola respectively,
then the ordered pair (𝛼, β) is equal to:
Solution
Q. Let e1 and e2 be the eccentricities of the ellipse,
and the hyperbola,
respectively satisfying e1e2 = 1. If 𝛼
and β are the distances between the foci of the
ellipse and the foci of the hyperbola respectively,
then the ordered pair (𝛼, β) is equal to:
A (8, 10)
D (8, 12)
Q. If m is the slope of a common tangent to
the curves and x2 + y2 = 12,
then 12m2 is equal to:
A 6
B 9
C 10
D 12
Q. If m is the slope of a common tangent to
the curves and x2 + y2 = 12,
then 12m2 is equal to:
Q. If m is the slope of a common tangent to
the curves and x2 + y2 = 12,
then 12m2 is equal to:
Solution
Q. If m is the slope of a common tangent to
the curves and x2 + y2 = 12,
then 12m2 is equal to:
A 6
B 9
C 10
D 12
Q. if e1 and e2 are eccentricities of the ellipse
and the hyperbola
respectively and if the point (e1, e2) lies on
ellipse 15x2 + 3y2 = k. Then find value of k
A 14
B 15
C 16
D 17
Q. if e1 and e2 are eccentricities of the ellipse
and the hyperbola
respectively and if the point (e1, e2) lies on
ellipse 15x2 + 3y2 = k. Then find value of k
Solution
Q. if e1 and e2 are eccentricities of the ellipse
and the hyperbola
respectively and if the point (e1, e2) lies on
ellipse 15x2 + 3y2 = k. Then find value of k
A 14
B 15
C 16
D 17
Q. If tangents are drawn to the ellipse x2 +
2y2 = 2 at all points on the ellipse other than
its four vertices then the mid points of the
tangents intercepted between the coordinate
axes lie on the curve:
JEE Main 2019 11 Jan Shift I
D
Q. If tangents are drawn to the ellipse x2 +
2y2 = 2 at all points on the ellipse other than
its four vertices then the mid points of the
tangents intercepted between the coordinate
axes lie on the curve:
Q. If tangents are drawn to the ellipse x2 +
2y2 = 2 at all points on the ellipse other than
its four vertices then the mid points of the
tangents intercepted between the coordinate
axes lie on the curve:
Solution
Q. If tangents are drawn to the ellipse x2 +
2y2 = 2 at all points on the ellipse other than
its four vertices then the mid points of the
tangents intercepted between the coordinate
axes lie on the curve:
JEE Main 2019 11 Jan Shift I
D
Q. If the normal at an end of a latus rectum of
an ellipse passes through an extremity of the
minor axis, then the eccentricity e of the
ellipse satisfies:
JEE Main 2020 6 Sep Shift I
A e2 + 2e - 1 = 0
B e2 + e - 1 = 0
C e4 + 2e2 - 1 = 0
D e4 + e2 - 1= 0
Q. If the normal at an end of a latus rectum of
an ellipse passes through an extremity of the
minor axis, then the eccentricity e of the
ellipse satisfies:
Solution
Q. If the normal at an end of a latus rectum of
an ellipse passes through an extremity of the
minor axis, then the eccentricity e of the
ellipse satisfies:
JEE Main 2020 6 Sep Shift I
A e2 + 2e - 1 = 0
B e2 + e - 1 = 0
C e4 + 2e2 - 1 = 0
D e4 + e2 - 1= 0
Q. For the hyperbola H : x2 - y2 = 1 and the
ellipse a > b > 0, let the
(1) Eccentricity of E be reciprocal of the
eccentricity of H, and
(2) The line be a common
tangent of E and H.
Then 4(a2 + b2) is equal to____.
My name is _______________.
I amMy name is _______________.
in _____(11th/12th) grade and I want join
I am in 10th grade and I want join the
the family of ___________ (JEE/NEET).
And family of _________.
I am texting (JEE/NEET)
after watching session of Harsh
Andsir.
priyam I am texting after watching
Abhishek sir's session.