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CE155P-2 Exercise No. 1. Answers

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Mapúa University

School of Civil, Environmental and Geological Engineering


Quantity Surveying
CE155P-2/E02

Exercise No. 1

Instruction: Use only a short bond paper in answering this quiz. Write your name and student number on all
sheets. Give the answers in your own handwriting and box your final answer.

Problem 1. Compute for the total volume of excavation, base course requirement, disposal, and backfill on the
selected footings, footing tie beams and columns.

Structural elements to be measured for earthworks:

1. Footings:
1.1 F5 at GL B/1
F6 at GL D/1
F8 at GL B/4
F12 at GL D/4

2. Footing tie beams


2.1 FTB2 at GL B-D/1
FTB1 at GL B/ 1-4
FTB1 at GL B-D/4
FTB2 at GL D/1-4

3. Columns
3.1 C1C at GL B/1
C1A at GL D/1
C1B at GL B/4
C5 at GL D/4
SOLUTION:

FOOTINGS

D T L W
F5 3000 400 1700 1700
F6 3000 400 1800 1800
F8 3000 400 2100 2100
F12 3000 400 2800 2800

Volume of Excavation: 𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛


= (0.2)(0.4 + 0.3)(2.875)
𝐹5: (1.7𝑥 1.7)(3 + 0.1) = 8.959𝑚3 = 𝟎. 𝟒𝟎𝟐𝟓𝒎𝟑
𝐹6: (1.8𝑥 1.8)(3 + 0.1) = 10.044𝑚3
𝐹8: (2.1𝑥 2.1)(3 + 0.1) = 13.671𝑚3
𝐹12: (2.8𝑥 2.8)(3 + 0.1) = 24.304𝑚3 FTB-2 @GL D/1-4
1.8 2.8
𝑇𝑜𝑡𝑎𝑙 = 𝟓𝟔. 𝟗𝟕𝟖𝒎 𝟑 𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 4.775 − − = 2.475𝑚
2 2
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛
= (0.2)(0.4 + 0.3)(2.475)
FOOTING TIE BEAMS = 𝟎. 𝟑𝟒𝟔𝟓𝒎𝟑

Depth of FTB = Depth from NGL + Height of


𝑇𝑜𝑡𝑎𝑙 = 0.812𝑚3 + 0.714𝑚3 + 0.4025𝑚3
FTB
+ 0.3465𝑚3 = 𝟐. 𝟐𝟕𝟓𝒎𝟑
FTB-2 @GL B-D/1
𝑇𝑜𝑡𝑎𝑙 𝑙𝑒𝑛𝑔𝑡ℎ = 1.1𝑚 + 3.5𝑚 + 2.95𝑚 = 7.55𝑚
1.7 1.8
𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 7.55 − − = 5.8𝑚 COLUMNS – NOT APPLICABLE SINCE
2 2 FOUNDATION PART IS ALREADY EXCAVATED
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛
= (0.2)(0.4 + 0.3)(5.8) = 𝟎. 𝟖𝟏𝟐𝒎𝟑 𝑇𝑜𝑡𝑎𝑙 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛
= 𝐹𝑜𝑜𝑡𝑖𝑛𝑔𝑠 + 𝐹𝑜𝑜𝑡𝑖𝑛𝑔 𝑡𝑖𝑒 𝑏𝑒𝑎𝑚
FTB-1 @GL B-D/4 + 𝐶𝑜𝑙𝑢𝑚𝑛
2.1 2.8 𝑇𝑜𝑡𝑎𝑙 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛
𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 7.55 − − = 5.1𝑚
2 2
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛 = 56.978𝑚3 + 2.275𝑚3 + 0 = 𝟓𝟗. 𝟐𝟓𝟑𝒎𝟑
= (0.2)(0.4 + 0.3)(5.1) = 𝟎. 𝟕𝟏𝟒𝒎𝟑

FTB-1 @GL B/1-4


𝑇𝑜𝑡𝑎𝑙 𝑙𝑒𝑛𝑔𝑡ℎ = 0.6𝑚 + 0.5𝑚 + 1.675𝑚
= 4.775𝑚
1.7 2.1
𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 4.775 − − = 2.875𝑚
2 2
Volume of Disposal:
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐵𝑎𝑠𝑒 𝑐𝑜𝑢𝑟𝑠𝑒
= [(1.7)2 + (1.8)2 + (2.1)2 + (2.8)2 ](0.1) Disposal for Column
= 𝟏. 𝟖𝟑𝟖𝒎𝟑 D-t = H of column
𝐶1𝐶 = (0.2 𝑥 0.4)(3 − 0.4) = 0.208
𝐶1𝐴 = (0.2 𝑥 0.4)(3 − 0.4) = 0.208
Disposal for Footing: 𝐶1𝐵 = (0.2 𝑥 0.4)(3 − 0.4) = 0.208
𝐹5: (1.7𝑥 1.7)(0.4) = 1.156𝑚3 𝐶5 = (0.25 𝑥 0.8)(3 − 0.6) = 0.48
𝑇𝑜𝑡𝑎𝑙 = 𝟏. 𝟏𝟎𝟒 𝒎𝟑
𝐹6: (1.8𝑥 1.8)(0.4) = 1.296𝑚3
𝐹8: (2.1𝑥 2.1)(0.4) = 1.764𝑚3
𝑇𝑜𝑡𝑎𝑙 𝐷𝑖𝑠𝑝𝑜𝑠𝑎𝑙
𝐹12: (2.8𝑥 2.8)(0.6) = 4.704𝑚3
= 1.838𝑚3 + 8.92𝑚3 + 1.744𝑚3
𝑇𝑜𝑡𝑎𝑙 = 𝟖. 𝟗𝟐𝒎𝟑 + 1.104𝑚3 = 𝟏𝟑. 𝟔𝟎𝟔𝒎𝟑

BACKFILLING
Disposal for Footing Tie Beam:
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐵𝑎𝑐𝑘𝑓𝑖𝑙𝑙𝑖𝑛𝑔
FTB-2 @GL B-D/1 = 𝑉𝑜𝑙. 𝐸𝑥𝑐𝑎𝑣𝑎𝑡𝑖𝑜𝑛 − 𝑉𝑜𝑙. 𝐷𝑖𝑠𝑝𝑜𝑠𝑎𝑙
𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 7.55 − 0.4 − 0.4 = 6.75𝑚 = 59.253𝑚3 − 13.606𝑚3
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐷𝑖𝑠𝑝𝑜𝑠𝑎𝑙 = 𝟒𝟓. 𝟔𝟒𝟕𝒎𝟑
= (0.2)(0.4)(6.75) = 𝟎. 𝟓𝟒𝒎𝟑

FTB-1 @GL B-D/4


𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 7.55 − 0.2 − 0.25 = 7.1𝑚
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐷𝑖𝑠𝑝𝑜𝑠𝑎𝑙
= (0.2)(0.4)(7.1) = 𝟎. 𝟓𝟔𝟖𝒎𝟑

FTB-1 @GL B/1-4


𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 4.755 − 0.2 − 0.4 = 4.175𝑚
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐷𝑖𝑠𝑝𝑜𝑠𝑎𝑙
= (0.2)(0.4)(4.175) = 𝟎. 𝟑𝟑𝟒𝒎𝟑

FTB-2 @GL D/1-4


𝐶𝑙𝑒𝑎𝑟 𝑙𝑒𝑛𝑔𝑡ℎ = 4.775 − 0.8 − 0.2 = 3.775𝑚
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝐷𝑖𝑠𝑝𝑜𝑠𝑎𝑙
= (0.2)(0.4)(3.775) = 𝟎. 𝟑𝟎𝟐𝒎𝟑

𝑇𝑜𝑡𝑎𝑙 = 0.54𝑚3 + 0.568𝑚3 + 0.334𝑚3


+ 0.302𝑚3 = 𝟏. 𝟕𝟒𝟒𝒎𝟑

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