Drilling and Blasting-MM 321.notes
Drilling and Blasting-MM 321.notes
Drilling and Blasting-MM 321.notes
Ms Dhelda Mfanga
Room Q 204
Part One- Blasting
Topic 1- EXPLOSIVES
INTRODUCTION
The use of explosives in mining and construction applications dates back to
1627
From 1627 through 1865, the explosive used was black powder.
In 1865, Nobel invented nitroglycerin dynamite in Sweden. He invented also
gelatin dynamites in 1866.These new products were more energetic than
black powder.
In the mid-1950's' a new product appeared which was called ANFO,
ammonium nitrate and fuel oil. This explosive was more economical to use
than dynamite.
Since then, ANFO has become the workhorse of the industry and
approximately 80% of all explosives used in the world.
Other new explosive products appeared on the scene in the 1960's and
1970's. such as slurries or water gels.
In the late 1970's' a modification of the water gels called emulsions appeared
on the scene.
Therefore, commercial explosives fall into three major generic categories,
dynamites, dry blasting agents and wet blasting agents (slurries or water gels
or emulsions).
What is Explosive?
There are three distinct zones: (a) the undisturbed medium ahead of the
shock wave; (b) reaction zone and (c) zone of expanding gases. This
condition for stability exists at hypothetical X, which is commonly referred to
as the Chapman-Jouquet (C-J) plane
C-J Plane
The process of explosive detonation is illustrated on figure below as idealized
shock wave propagation through a cylindrical explosive
The steady-state chemical reaction takes place behind the shock front within
the reaction zone.
At the end of this zone, a nonsteady-state region exists.
The C-J plane is seen as the boundary between the steady and non-steady
state, where the reactions are considered complete.
This is also the plane where all the thermodynamic properties are calculated.
These are: pressure, velocity, temperature, internal energy or heat of
formation and density
THEORY OF EXPLOSIVES IN BREAKING THE ROCK
LD = π [D/2]2 ρ, kg/m
2) Water Resistance
An explosive's water resistance is a measure of its ability to withstand
exposure to water without deteriorating or losing sensitivity.
Explosives vary widely in water resistance – ANFO - no water resistance,
emulsions, water gels - good water resistance.
Higher-density explosives have fair to excellent water resistance, whereas
low-density explosives and blasting agents have little or none.
Brown-orange nitrogen oxide fumes from blast indicate inefficient detonation
which might have been caused by wet explosives.
3) Shelf life
Explosives deteriorate and shelf life is particularly affected by both
climate and magazine conditions.
For most explosives products, a shelf life of one year is
recommended, although satisfactory performance can be expected
from most products two, three, and even four years later.
Explosive manufacturers specify the storage properties or shelf life
of their products, based on normal magazine conditions (ICI 1997).
4) Fume class
Characterizes the noxious gases (NO, CO, H2S, SO2), etc,
generated from the disintegration of explosive. Consideration of
fume class is important in the selection of the type of explosive.
For open work, fumes are not usually an important factor, In
confined spaces(underground mine), however, the fume rating of an
explosive is important. In any case, the blaster should ensure that
everyone stays away from fumes generated in a shot.
Factors increasing toxic fume generation: improper priming, lack of
confinement, water, improper explosive composition, improper
timing, improper loading techniques and adverse reaction with rock
Figure 2. Excessive fume production
5) Sensitivity
Measure of the ease of initiation of explosive. Also it is the
resistance of explosive to accidental detonation.
It is established through the “Cap sensitivity test” involving measure
of the minimum energy required to detonate the explosive.
Explosives are classified as cap sensitive or non sensitive based on
the No. 8 standard cap. Example: high explosive (1.1D) - sensitive to
a No. 8 strength blasting cap and blasting agent (1.5D) - not
sensitive to a No.8 strength blasting cap - requires booster
6) Strength
It is a measure of the ability of explosive to break rock /performance
potential.
It is determined by the detonation velocity and density of explosive,
the volume of the gaseous products of explosion and the heat of
explosive reaction
Explosive strength is measured as the absolute bulk strength (ABS)
in Joules/m3 or the absolute weight strength (AWS) in Joules/kg or
Relative bulk strength (RBS)
7) Critical Diameter
It is the minimum borehole diameter (Dmin) in which a particular
explosive compound will detonate reliably.
At diameters below the critical diameter, explosive reactions are
incomplete and energies lower than the available capacities are
liberated.
Above the critical diameter, the detonation of explosive travels at the
maximum- steady state velocity and all thermodynamic parameters
are at their maximum values.
EXPLOSIVE DETONATION
11) Oxygen Balance (OB)
OB is the explosive content of excess or deficit oxygen compared to the
content just sufficient for the complete oxidation of fuel elements within the
explosive.
The basic elements or ingredients which directly produce work in blasting are
those elements which form gases when they react, such as carbon,
hydrogen, oxygen, and nitrogen.
If only the ideal reactions occur from the carbon, hydrogen, oxygen, and
nitrogen, there is no oxygen left over or any additional oxygen needed. The
explosive is oxygen balanced and produces the maximum amount of energy.
If two ingredients are mixed together, such as ammonium nitrate and fuel oil,
and an excess amount of fuel oil is put into the mixture, the explosive
reaction is said to be oxygen negative.
If too little fuel is added to a mixture of ammonium nitrate and fuel oil, then
the mixture has excess oxygen which cannot react with carbon or hydrogen.
This is called an oxygen positive reaction.
The maximum detonation energy is obtained from explosives formulated with
zero oxygen balance, whose explosion products are vaporous H2O, CO2
and N2.
The energy is reduced because other ideal gases liberate heat when they
form, nitrogen oxides absorb heat in order for them to form.
Carbon-Oxygen Ideal Reaction Nitrogen-Nitrogen Ideal Reaction
VI. Fuels
Fuel oil, carbon, granular or powdery aluminium, TNT,
black powder or any carbonaceous material which
produces heat. Many of them are also sensitizers and
absorbents.
VII. Stabilizers
Flame retardants, gelatins, densifiers, emulsifying agents
and thickeners;
VIII. Sensitizer
Provides the heat source (‘hot spot’) to drive the
chemical reaction. Sensitizers are generally small air
bubbles or pockets within the explosive
VIII. Antifreeze
Antifreeze is used to lower the freezing point of the
explosive
THE COMPONENTS OF COMMERCIAL EXPLOSIVES
CATEGORIES OF COMMERCIAL EXPLOSIVES
Properties of NG
Not soluble in water, Poisonous, Liquid and dangerous to handle.
- STRAIGHT DYNAMITE
- GRANULAR
- HIGH DENSITY EXTRA DYNAMITE
DYNAMITE
- LOW DENSITY EXTRA DYNAMITE
DYNAMITE
- GELATIN - STRAIGHT GELATIN DYNAMITE
DYNAMITE - AMMONIA GELATIN DYNAMITE
- SEMIGELATIN DYNAMITE
STRAIGHT DYNAMITE
NG, NaNO3, carbonaceous fuels, sulfur and antacids;
Absorbents + Combustibles: wood pulp + flour;
Strength: (40, 50, 60) % NG;
Characteristics: High detonation velocity & brisance, low flame temperature,
good water resistance & shock sensitivity, poor fume qualities.
EXTRA DYNAMITE
Granular mix of NG and AN +SN;
AN – dynamite varieties: high density and detonation velocity, (20 – 60) %
NG;
Characteristics: Poor water resistance, low explosion temperature and
density, with high or low detonation velocity;
Strength: 65 % NG.
GELATIN DYNAMITE
Straight gelatin or AN (extra) gelatin, basically blasting gels
Gelatins are used as boosters and primers;
Characteristics: High water resistance and least fumes liberation.
SEMIGELATINS
Same as AMMONIA GELATIN except that more of the nitroglycerin,
nitrocellulose mixture and sodium nitrate is replaced by ammonium nitrate.
Strength: 65 %NG;
Characteristics: Higher water resistance than AN dynamites but not as strong
as gelatin dynamites;
Used as primers and boosters.
DBA- BULK ANFO
A dry agent is a granular, free-running mix of a solid oxidizer (usually
AN),prilled into porous pellets onto which a liquid fuel oil or propellant is
absorbed.
Bulk ANFO (Ammonium Nitrate and Fuel Oil) is by far the most commonly
used explosive
Improper mixes produce lower explosive energy and noxious gases
The proper mix is oxygen balanced and occurs with a mix of 94.3% AN and
5.7% FO by weight
The properties of dry blasting agents vary significantly with borehole
diameter, density, confinement, particle size, water conditions, and size of
primer used for initiation.
Density: 0.75 – 0.95;
Detonation velocity > 4500 m/s in holes of diameter > 381 mm;
Critical diameter varies from 51 – 102 mm.
Inexpensive, simple to manufacture
Not waterproof
Can include various amounts of aluminum for extra energy
VOD vs. borehole diameter for selected industrial explosives
Bulk ANFO truck
EMULSIONS
Consists of oxidizers dissolved in water surrounded by a fuel - fine
particle size
Relatively expensive compared to ANFO
Very water resistant in full concentration
Plant or truck mixed
Typical density range of 1.15 to 1.45 g/cc
Typically high detonation velocity and bulk strength
Bagged ANFO
PRIMERS AND BOOSTERS
A primer charge is an explosive ignited by an initiator, which, in turn, initiates
a noncap-sensitive explosive or blasting agent.
A primer contains cap-sensitive high explosive ingredients.
Often cartridges of dynamites, highly sensitized slurries, or emulsions are
used with blasting caps or detonating cord.
Density (g/cc)
Type Density
Granular Dynamite 0.8 to 1.4
Gelatin Dynamite 1.0 to 1.7
Cartridged Water Gel 1.1 to 1.3
Bulk Water Gel 1.1 to 1.6
Air-emplaced ANFO 0.8 to 1.0
Poured ANFO 0.8 to 0.9
Packaged ANFO 0.8 to 1.2
Cartridged Emulsion 1.1 to 1.33
Sensitivity
Type Hazard Performance
Sensitivity Sensitivity
Granular Dynamite Moderate to High Excellent
Gelatin Dynamite Moderate Excellent
Cartridged Water Gel Low Good to Very Good
Bulk Water Gel Low Good to Very Good
Air-emplaced ANFO Low Poor to Good
Poured ANFO Low Poor to Good
Packaged ANFO Low Good to Very Good
Cartridge Emulsion Low Good to Very Good
Packaged Binary Low to Moderate Very Good
Water resistance
Type Resistance
Granular Dynamite Poor to Good
Gelatin Dynamite Good to Excellent
Cartridged Water Gel Very Good
Bulk Water Gel Very Good
Air-emplaced ANFO Poor
Poured ANFO Poor
Packaged ANFO Very Good
(if package is not
broken or torn)
Cartridge Emulsion Very Good
Packaged Binary Poor to Good
Borehole Diameter
Type 2" or less 2" to 4" 4"+
Granulate Dynamite USE N/A N/A
Gelatin Dynamite USE N/A N/A
Cartridge Water Gel USE USE N/A
Bulk Water Gel N/A USE N/A
Air-emplaced ANFO NR USE USE
Poured ANFO NR USE USE
Packaged ANFO N/A USE USE
Cartridged Emulsion USE USE N/A
Packaged Binary USE USE N/A
Topic 2 –INITIATORS AND INITIATION SYSTEMS
INITIATORS
Devices with high energy explosive, which, upon receiving
mechanical or electrical impulse, do produce detonation or
deflagration action that starts up the detonation of main explosive.
INITIATION SYSTEMS
Initiation systems are initiators plus other devices which are used to
start up blasting rounds.
The systems are: Safety fuse; Normal detonating cord; Low power
detonating cord plus electric detonator; Non electric (NONEL);
Electric blasting system, shock tube system, etc.
EXPLOSIVE INITIATION SYSTEMS
Explosive Initiation Systems comprise the followings
1. initial energy sources; includes blasting machine-electric
system, shot shell primer -shock tube system, fuse lighter-cap
and fuse.
2. energy distribution network-distributes energy to blastholes:
wire - electric system, tube – shock tube system, fuse - cap and
fuse
3. blasthole initiators relay energy down blasthole
4. booster - unit of cap sensitive explosive that detonates the
main explosive charge
Some of the explosive initiation systems are:
a. Safety fuse (cap and fuse) system
b. Normal detonating cord system
c. Non electric (NONEL) or ( shock tube) system
d. Electric system
e. Electronic detonators system
f. Low power detonating cord plus electric detonator system, etc.
THE SAFETY FUSE SYSTEM
It is detonating cord which is loaded with LE (black powder);
It is a thermal cord which is initiated by fire ignition.
Main Elements
Safety fuse cord;
Safety fuse detonator
Primer (booster or dynamite stick);
Ignition cord;
Fuse lighter.
System Assembly
1. Fuse cord is measured to the desired length, cut off squarely with a
sharp knife, inserted to the open end of detonator fuse and the union
crimped;
2. The primer is made by making a hole in the dynamite stick and the
detonator (which is connected with safety fuse) inserted in it;
3. The end of safety fuse with primer is dropped into the blast-hole;
4. Charging of the blast-hole with main charge is completed and once
ready for firing, the other end of safety fuse protruding on the surface is
ignited with a lighter;
5. The blaster walks/drives to the demarcated safe hiding position.
Firing several rounds of holes is carried out as follows:
1. If it is required to blast holes on delayed sequence, holes to be blasted
first are given shorter and the ones to be fired late are given longer safety
fuse lengths;
2. If holes are closely positioned, safety fuse ends protruding on the surface
from individual holes could all be inserted into the one end of ignition
cartridge (containing ignition material at its other end).
3. If boreholes are positioned far-way from one another, the ends of safety
fuses from separate boreholes are attached on an igniter cord with the
help of special metal connectors.
The final stage of preparations for firing a package of explosive charges.
ELECTRIC BLASTING SYSTEM
Hole for detonator is made in the priming stick of dynamite with the pointed handle
of detonator crimper, wooden stick or copper needle;
Electric computations are carried out based on ohm’s law for ac power source.
Types of Electric Shot Firing Circuits
The methods of connecting electric detonators to the power source are the series,
parallel, series in parallel and parallel in series.
OHMMETER – GALVANOMETER
- Used for measuring resistance of an electric blasting circuit;
- The instrument is connected in the circuit and adjusted until a point of balance is
reached on the galvanometer;
- The resistance of the circuit is then read on the calibrated scale;
- Using it one should be at safe distance from the explosive charge.
-
Borehole Stemming Materials
- Stemming materials must have the following characteristics:
- High coefficient of friction, heavy and good strength;
- Increasing large fractions in stemming materials densely compacted will raise the
coefficient of friction but also the leakage of the gaseous products of hole charge
explosion.
Explosives trucks bring in explosives to load the holes
Same vehicle for explosives and detonator? (may be permitted)
• Blasters are required to have a state issued blasters certification
• Before loading begins all unnecessary personnel and equipment
are removed from the blast site, the site secured and warning
signs posted
Loading a booster+ detonator + cord down to the hole
Only workers thoroughly experienced in handling explosives shall be
permitted to supervise, handle, haul, or detonate explosives.
Loading of explosives –Tamping stick
The loaders fill the holes with the amount of explosives that has been
determined –Pneumatic loading
Blaster-in-Charge
Blasting Shelter
After the holes have been drilled, explosives are loaded in them and they are
joined. Once connected to the blasting maching, the holes can be shot with a
push of a button.
The blasting machine or the firing key should be securely kept by the blaster
during the entire process of loading and hook up to prevent any unintentional
detonation.
THE THEORIES AND GENERAL PRINCIPLES OF ROCK BLASTING
3e
OB = d 2a n
b
100,
2 2
m
Where: n - the atomic weight of oxygen, (n = 16); m - the molecular weight of
explosive.
The Oxygen Balance (OB) of explosive could be as follows:
- Positive if d > 2a + b/2 + (3/2) e;
- Zero if d = 2a + b/2 + (3/2) e;
- Negative if d < 2a + b/2 + (3/2) e.
Zero OB generates the maximum quantity of energy and minimum quantity of
noxious gases
(-) OB generates either the poisonous carbon monoxide (with less heat
generation), or pure carbon in the form of soot, acutely reducing the formation of
gases.
(+) OB, heat generation drops, since that the poisonous nitrogen oxide is formed,
accompanied with the suppression of heat in the reaction.
EXAMPLE ONE
Calculate the OB of TNT (C7 H5 (NO2)3) whose molecular weight is 227
Solution
C7H5 (NO2)3 ~ C7H5N3O6
a = 7, b = 5, c = 3, d = 6
OB = 16 x 100 [6 – (2x 7+ 5/2)]/ 227 = -74 %
EXAMPLE TWO
Calculate the OB of Grammonit 30/70. Grammonit 30/70 consists 30%
AN - ammonium Nitrate (NH4NO3) of molecular weight of 80 and 70%
TNT.
Solution
The oxygen balance of NH4NO3:
NH4 NO3 → N2H4O3
= 16 x 100 [3 – (0 +4/2)/ 80 = + 20 %
The oxygen balance of Grammonit 30/70:
0.3 X (+20) + 0.7 X (- 74) = - 45.8 %
Formulation of Commercial Explosives-ZERO OB
Commercial explosives are prepared to ensure they have zero OB.
Cartridge explosives, they are given a small positive OB for the
oxidation of their packaging material.
For underground works explosives shouldn’t liberate noxious gases
higher than 40 liters of carbon monoxide equivalent from the explosive
reaction of 1 kg of explosive.
For surface mining their oxygen balance are not so strict.
EXAMPLE THREE
Establish the formulation of ANFO whose oxygen balance is zero, based
on Ammonium Nitrate (OB = + 20 %) and Diesel fuel DF (OB = -320% )
Solution:
The quantity of weight parts of AN requirement for oxidation of 1 weight
part of diesel fuel equals to:
n = OB Dies / OB AN = 320/ 20 = 16
The content of DF in ANFO is:
X = 100/ [1 + n] = 100/ [1 + 16] = 5.9%
Respectively, content of AN in ANFO is:
100 – X = 100 – 5.9 = 94.1 %
Therefore, the formula of ANFO is: 94.1 % AN + 5.9 % DF
EXAMPLE FOUR
Establish the formulation of explosive with zero OB, based on the AN and
TNT (C7 H 5 (NO 2) 3. The oxygen balance of TNT is -74 % and the molecular
weight is 227. The oxygen balance of AN explosive is + 20 % and its
molecular weight is 80. Establish also its molecular formula.
Solution:
The composition of the explosive mixture should fulfill condition:
X (-74 %) + (100 – X) 20 % = 0,
Where, X – the content of TNT in the mixture, %.
Solving the above equation indicates that:
X ≈ 21 % And
(100 – X) = 79 %.
Such composition of the explosive mixture corresponds to grammonit 79/21
and Ammonit standard explosives.
Let’s express the number AN moles through y, and the number of TNT moles
through z.
Then from the relationship: [80 Y]/ [227 z] = 79/21,
We obtain: y = 79 x 227z / [21 x 80] = 10.7z
and letting z = 1, gives: y = 10.7
Consequently, the molecular formula of Grammonit is:
Z + 10.7 y = C7H5 (NO2)3 + 10.7 NH4NO3
EXAMPLE FIVE
Establish the molecular formula of Granulit AC-8, which has the
following composition: 89 % AN (NH4NO3); 3% straw oil (C16H34) of
molecular weight is 226; 8 % Aluminium powder (Al) whose
molecular weight is 27.
Solution
Let’s express the number of straw oil moles through x, AN moles
through y, Aluminium powder moles through z.
Then, we could write the chemical formula as: Y
yNH4NO3 + x C16H34 + z Al
In correspondence to weight compositions we could write the
following relationship:
[80 y]/ [226 x] = 89/3; [27 z]/ [226 x] = 8/3.
From there we obtain:
Y = 83.9 x; z = 22.4 x
If we express x = 1, the molecular formula of Granulit AC – 8 will be
as follows:
83.9 NH4NO3 + C16H34 + 22.4 Al
Homeworks
i) Establish the oxygen balance of “TEN” explosive whose chemical formula is
C (CH2O.NO2)4 and molecular weight is 316;
vi) Establish the percentage contents of Al and TNT required to make their
explosive mixture of zero oxygen balance.
Topic 4: EXPLOSIVE THERMOCHEMISTRY
The Heat, volume, temperature and pressure of the gaseous products of
explosion are determined by their composition and quantity.
The Oxygen Balance of commercial explosives determines the composition of
their products explosion and the conversion reactions of explosive disintegration.
The reaction structures of the conversion reactions of commercial explosives are
categorized into 3 groups:
GROUP ONE:
Explosive with oxygen content that is sufficient for the complete oxidation of its
content of fuel elements. Explosives in this group have zero or positive oxygen
balance.
Example: The decomposition reaction of Nitroglycerin:
2C3H5 (ONO2)3 → 6 CO2 + 5 H2O + 3 N 2 + 0.5 O2
GROUP TWO:
The group includes explosives with oxygen content which is sufficient for the
complete formation of gases.
The oxygen contained in the explosive, first oxidizes hydrogen into water, carbon
into carbon monoxide, and remaining portion of oxygen combining with CO
forming CO2.
a a 2 4Qv b
t=
2b
Depending on temperature, the heat capacities of certain gases are
determined from the following equations:
For gases made of two atoms:
Cv = 20.1 + 18.8 x 10-4t J/ (mole.0C)
For gases made of four atoms:
Cv = 41.9 + 18.8 x 10-4t J/ (mole.0C)
For water vapour:
Cv = 16.76 + 90 x 10-4t J/ (mole.0C)
For carbon dioxide:
Cv = 37.7 + 24.3 x 10-4t J/ (mole.0C)
For solids:
Cv = 26.8 J/ (mole.0C)
The heat capacity of a gaseous mixture we consider the partial contributions
of each of the components by summing per element to determine the sums
of a, and b in accordance to formula:
t= a a 4 b Q.1000
2
2 b
EXAMPLE SEVEN
Establish the temperature of explosion of nitroglycerin. The heat of
explosion of nitroglycerin is 1443kJ/ mole.
Solution
Heat capacities of all explosion products (EXAMPLE SIX), based on
the above formulas are:
For 3 CO2: 3 (37.7 + 24.3 x 10-4 t) = 113 + 72.9 x 10-4 t;
For 2.5 H2O: 2.5 (16.76 + 90 x 10-4 t) = 41.9 + 225 x 10-4 t;
Total: CV = 154.9 + 297.9 x 10-4 t;
Therefore, ∑a = 154.9; ∑b = 297.9 x 10-4
Using the obtained values on the formula for t, we will obtain:
t = [-154 +√ [23994 + 4 x 297.9 x 10-4 x 1443 x 103]]/ [2 x 297.9 x 10-4]
= 4780, 0C
THE VOLUME OF EXPLOSION GASES
The volume of explosion gases is established based on the
Avogadro Law which says: “The volume occupied by one gram
molecule of various gases at 00C and pressure 1.01 X 105 Pa is
22.42 X 10-3 m3”.
The volume of gases (m3/ kg), generated from the explosion 1 kg of
explosive:
Vo = 22.42n1 n2 ... nk
m1M 1 m2 M 2 ... mn M n
EXAMPLE EIGHT
Calculate the volume of the gaseous products from the explosion of
1 kg of nitroglycerin.
Solution:
The volume of gases:
For the vaporous state of water,
V0 = 22.42 (3 + 2.5 + 1.5 + 0.25) = 0.616 m3/ kg
1 X 227
For the liquid state of water,
V0 = 22.42 (3 + 1.5 + 0.25) = 0.469 m3/ kg
(1 X 227)
THE PRESSURE OF EXPLOSION GASES
The pressure of gases (Pa) resulting from explosion is calculated
based on the Law of Boiler – Marriott and Gay- Lusaka’s as follows:
P= q oVo T ( applicable for ideal gases)
273V
Where: qo - The gaseous atmospheric pressure which equals 1.01 x
105 Pa;
Vo - volume of explosion gases (m3)
T - The temperature of explosion, read from absolute zero, K;
V - The volume of charge chamber, m3.
For the actual explosive charging densities (0.5 → 1.0 T/ m3), great
role is played by the volume of the individual molecules (co-
volumes) of the products of explosion, which is taken equal to: α =
0.001Vo
P = Po Vo T
273(V- α)
For explosive densities higher than 1g/ cm3: α = 0.0006 Vo
If the volume of charge chamber V is changed with the loading density
of explosive (Δ =m/V) T/ m3, then for a unit mass (m =1) we will obtain
P = Po Vo T = Po Vo T Δ Pa
273(1/Δ - α) 273(1- α Δ)
EXAMPLE NINE
Calculate the pressure of explosion gases of Nitroglycerine, whose 1 kg
gives 0.716 m3 of gases at the temperature of 5053 K , for loading
densities of Δ = 0.8 g/ cm3 and Δ = 1.2 X 103 Kg/m3
Solution
For loading density of 0.8 g/ cm3
P = 1.01 x 105 x 0.716 x 5053 x 0.8 x 103
273 (1 – 0.716 x 0.001 x 0.8 x 103)
= 2.5 x 109 Pa
ii) Establish the heat, temperature and volume of the gases of nitroglycerin
explosion, whose reaction of explosive disintegration is given as:
C2H4 (ONO2)2 2CO2 + 2H2O + N2
iii) Establish the heat, temperature, the volume of explosion gases and the
pressure of explosion gases of RDX whose borehole loading density is 0.8 T/
m3 and reaction of explosive disintegration given as:
C3H6N6O6 3H2O + 3CO + 3N2
V2
Where: Q – The potential energy (the total heat energy) of explosion, kJ/
Kg;
V1 and V2 – The initial and end unit volumes, m3/Kg; k = Cp/ Cv - adiabatic
index;
Cp and Cv – heat capacities at constant pressure and volume respectively.
Replacing the ratio of unit volumes with the ratio of the initial
explosion pressure P1 to pressure P2, when gases have executed
work A, we could write:
k 1
A=Q 1 P2
k
P1
For explosions conducted in the air (P2 = 105 Pa) and their total
working capability:
k 1
1 10
5
AT = Q
k
Qq
P1
AT/ Q = ηT,
k 1
1 1.01x10
5
k
AT = Q P
1.241
1 1.01x10
5
= 3930
1.24
3.36 x10 9
= 3402kJ/Kg
ii) Calculate the total working capability (strength) and the coefficient of explosion
efficiency of nitroglycerin charge of borehole loading density 1.0 t/ m3.
iii) Calculate the total working capability (strength) and the coefficient of
explosion efficiency of TNT charge of borehole loading density 1.0 t/ m3,
blasted in water at a depth of 100m.
iv) Calculate the total working capability (strength) and the coefficient of
explosion efficiency of ammonal charge of borehole loading density 0.9 t/ m3,
fired in a media of compression strength 3 x 107 Pa,
v) Calculate the total working capability (strength) and the coefficient of explosion
efficiency of RDX charge of borehole loading density 1.0 t/ m3.
vi) Calculate the total working capability (strength) and the coefficient of
explosion efficiency of Dynamite - 62 % charge of borehole loading density
1.1 t/ m3, fired in a media of compression strength 1 x 108 Pa,
vii) Calculate the total working capability (strength) and the coefficient of
explosion efficiency of AN charge of borehole loading density 0.9 t/ m3.
Topic 5: COMPUTATION OF THE DETONATION STATE
PARAMETERS
Theory:
The equation of explosion products state for solid explosives is given as:
PVn = Constant,
Where: P – The pressure of explosive, Pa; V – The volume explosion
products, m3; n – The polytrophic index of explosion products (dependent on
the initial
density of explosive):
n 1.3 1.6 2.2 2.8 3.0 3.2 3.4
ρe, 0.1 0.25 0.5 0.75 1.0 1.25 1.75
t/m3
The pressure of shock wave on the C-J plane is calculated from formula:
PD = ρeD2 , Pa,
(n + 1)
The explosive density on the detonation shock wave:
ρe' = 4 ρe
3
The masses movement velocity of the explosion products (m/s) on the C-J
plane: D
V = n 1
The detonation velocity (D) for gases is given as
D = 31.5 2 n 2 1 Qv gives too high results when applied on solid
explosives
DN = DNf QN
Qref
DN, DNf : the detonation velocity of present explosive and reference
explosive respectively, (m/s);
QN, Q Nf: the explosion heat of present explosive and reference explosive
respectively, (kJ/ kg).
Reference explosive: Ammonit No.6ЖВ or Grammonit 79/20 which have the
following characteristics: Explosion heat: QNf: 4315.7 kJ/ kg; Detonation
velocity DNf: 3600 m/s; Loading density ΔNf: 1.0 t/m3.
For other borehole charge loading densities, detonation velocity is calculated
from the formula: D = DNf + DNf (ρe – 1)
EXAMPLE ELEVEN
Calculate the detonation parameters of aquatol 65/35 of charge loading density
1.45 t/m3 and explosion heat Q = 3854.8 kJ/ kg.
Solution
Let’s calculate the detonation velocity of Ammonite No. 6 reference explosive at
the loading density of 1.45 t/m3 as:
D = DNf + DNf (ρe – 1)
= 3600 + 3600 (1.45 – 1) = 5220m/s
i) Establish the detonation parameters of Alumatol charge of loading density1000 kg/ m3 and
explosion heat 5279 kJ/ kg;
ii) Establish the detonation parameters of Grammonal A-45 charge of loading density 900
kg/ m3 and explosion heat 5720 kJ/ kg;
iV) Establish the detonation parameters of Carbonate Э-6 charge of loading density 1100
kg/ m3 and explosion heat 5720 kJ/ kg;
V) Establish the detonation parameters of Ammonium nitrate charge of loading density 900
kg/ m3 and explosion heat 1425 kJ/ kg;
Topic 6: COMPUTATIONS OF ELECTRIC CHARGE FIRING
CIRCUITS
Theory:
Electric blasting is based on the following detonator
commutation circuits.
- Series;
- Parallel;
- series-parallel;
- parallel- series.
Series
Parallel series-parallel
The main condition for the efficient electric blasting is the
provision of non-failure firing of all detonators which are
connected in a network.
The characteristics of modern detonators are composed of
the following quantities:
i. The resistance of electric detonator:
Composed of the resistance of detonators bridge
and end wires;
varies from 2 to 9 Ω (ohm).
i. The maximum non-failure current:
The upper limit of d.c current, which won’t cause
detonator explosion;
within limits of 0.18A
i. Ignition impulse (A2.s): kB = I2 tB
The lowest quantity of current impulse, which
causes detonator explosion:
Where: I - ignition current, A; tB - the minimum time
of ignition current flow
iv. Sensitivity of electric detonator (A2.S) -1
the inverse of ignition impulse:
iv. Minimum non-failure current:
The lowest current quantity, ultimately causing
detonator explosion;
For direct current: 1.38 A; for alternating current:
1.47 A
iv. Guaranty current quantities for electric detonators.
For direct current: 1 to 100 detonators: Ig = 1A;
101 up to 300 detonators: Ig = 1.3A;
For alternating current: Ig = 2.5 A.
COMPUTATIONS OF ELECTRIC CHARGE FIRING CIRCUITS
Determination of the quantity of current which will flow through the
bridge filament of the electric detonators.
Leads to the establishment of the basic assembly scheme of its
elements.
The condition of non-failure firing of the commutation scheme
requires that guaranty current must flow through all detonators within
the scheme.
Carried out in accordance to the following sequence:
1. Compute the resistance of mainline, connection and other
wires on the circuit;
2. Calculate the total resistance of the electric charge firing
circuit;
3. Establish the quantity of current available in circuit branches
and in individual detonators
4. Check the condition of non- failure firing.
A. The resistance of main and connection wires, (ohm):
R = 1.1 ρ 4l
πdW2
ρ – Unit length resistance, ohm. mm2/ m;
For copper wire: ρ = 0.0175 ohm. mm2/m;
For aluminum wire: ρ = 0.028 ohm. mm2/m;
l – The length of wire (for mainline wires, length is doubled),
m;
dW – The diameter of wire, mm.
B. The quantity of current in the firing circuit, (A):
I = E/(R + ro)
E - The electromotive force of current power source, V;
R - The total resistance of the firing circuit, ohm;
r0 - The internal resistance of the power source
THE SERIES SCHEME:
Total resistance in a circuits:
Rs = Rw + nr,
Where: Rw - The resistance of main and connection wires, (ohm);
r - Resistance of individual detonator plus its end wires
(ohm);
n - No. of detonators in the circuit.
The quantity of current in a single detonator:
i = Is = E/ (Rs + r0)
Condition of non-failure charge firing:
i ≥ Ig
n
Rs = Rm + Rc + Ry + nRk + ∑Rd,
1
where: Rm – resistance of main wires, ohm;
Rc – resistance of connection wires, ohm;
Ry – resistance of section wires, ohm;
Rk – resistance of end wires, ohm;
Rd – resistance of a single detonator, ohm.
THE PARALLEL SCHEME:
Total resistance
Rp = Rw + r/ n
Amount of current in the circuit:
Ip = E/ (Rp + r0);
Amount of current in a single detonator:
i = Ip /n
Condition of non - failure charge firing:
i ≥ Ig
The required power source voltage:
E ≥ nIg (Rm + Rc + Ry + (Rd + Rk)/n),
THE SERIES IN PARALLEL SCHEME:
Total resistance:
Rmx = Rm + [Rc + Ry + n1 (Rd + Rk)]/ m,
Where: m – Number of groups which are connected in
parallel;
n – number of detonators which are series
connected in a group.
Amount of current in the circuit:
Imx = E/ Rmx
The quantity of current in a single detonator
i = Imx / m
Condition of non - failure charge firing:
i ≥ Ig
THE PARALLEL IN SERIES SCHEME:
Total resistance :
Rmx = Rw + m1r/n1 = Rm + Rc + (Ry + Rk + Rd) m1/ n1,
Where: m1 – Number of groups which are connected in series;
n1 – number of detonators which are parallel connected in a
group.
Amount of current in the circuit:
Imx = E/ Rmx
The quantity of current in a single detonator
i = Imx / n1
Condition of non - failure charge firing: i ≥ Ig
N.B. The formulas for the computation of mixed circuits given above
are only applicable on the circuits which have the same no. of
detonators in the groups. Contrary to that, computations become a
bit complicated.
EXAMPLE TWELVE
Compute the electric charge firing circuit and establish the possibility
of using d.c. power source of electromotive force E = 120 V for the
development of main cross cut of cross section 16 m2. Number of
boreholes is 50. The resistance of detonator with its end wires is 6
ohm. Distance from crosscut face to the power source location is
200m. Also given that:
a. main line wires : are made of double core copper cable, and the
cross section of each wire core is 2.5 mm2;
b. connection wires: Copper wire of cross-section: 1mm2 and
length: 20m (ρ = 0.0175 ohm. mm2/m).
Solution
Let’s calculate the resistance of mainline wire using formula
RM = ρ 4l x 1.1 = ρ l x 1.1= 0.0175 x 2 x 200 x 1.1 = 3.08 ohm
πdw2 S 2.5
Resistance of connection wires:
Rc = ρ l x 1.1 = 0.0175 x 20 x 1.1 = 0.385 ohm
S
Total resistance of the circuit wires:
RT = RM + Rc = 3.08 + 0.385 ≈ 3.465 ≈ 3.5 ohm
For series connection:
The total resistance of blasting circuit:
Rs = RT + nr = 3.5 + 50 x 6 = 303.5 ohm
The total current flowing in the circuit:
Is = E/ Rs = 120/303.5 = 0.39 A
Is < (Ig = 1 A), this means the series commutation does not have
enough current to blast the detonators
For parallel connection:
Total resistance of blasting circuit
Rp = RT + r/n = 3.5 + 6/50 ≈ 3.6 ohm
Total current in the circuit:
Ip = E = 120 ≈ 33.5 A
Rp 3.6
Current available for a single detonator:
i = Ip/n = 33.5/50 = 0.67 A
Ip < (Ig = 1 A), it implies that parallel commutation also doest have
enough current to blast the detonators.
For parallel in series circuit:
m= 5 series connected groups,
n1 = 10 parallel connected detonators:
Total resistance of blasting circuit
Rmx = RT + m1r/ n1 = 3.5 + 5x6/10 = 6.5 ohm
The amount of current in the circuit:
Imx = E/ Rmx = 120/ 6.5 = 18.5A
In electric detonator:
i = Imx = 18.5 = 1.85A
n1 10
Since (i = 1.85) > (Ig = 1A), it implies that, the circuit should
work.
If the No. of detonators is different in branches, current in the
branches is established from the total conductance of all branches.
Let use four groups of the following no. of detonators per group: 5,
10, 15 and 20.
The total conductance of all branches:
1= 1 + 1 + 1 + 1 = 1 + 1 + 1 +1 = 25
RB r n1 r n2 r n3 r n4 6x5 6x10 6x15 6x20 360
• Burdens are normally equal (20 40)dc t (for example the burden
for a 165 mm charge would range from 3.3 to 6.6 m)
• Important factors that should be considered during burden selection
include: bench height, rock hardness, structure, explosive used,
desired displacement and the fragmentation required
Burden dimension should be perpendicular to the desired direction
of displacement
4. Spacing, a
Distance between blastholes perpendicular to the burden
7. Pattern layout
Square or staggered square
Rectangular or staggered rectangular
Slightly rectangular, staggered patterns provide the best explosive
energy distribution (equilateral triangle)
8. Burden stiffness ratio
1. Volume Calculations
Bank cubic metres (bcms) per hole calculation
= burden x spacing x bench height (B x S x BH)
Converting bcms to tonnes
= bcms multiplied by the rock density (g/cc)
2. Charging Calculations
Loading Density (kg of explosive per metre of borehole)
= .000785 x explo. density x (explo.diameter) 2
Parameters
lc - borehole length
lexp - charging length
Hy - bench height
ln - subdrill length
ls - stemming length
W - line of least resistance from the bench toe/ BURDEN
b- burden
a - spacing
c - Distance along the perpendicular line between the upper edge of bench and
the line along boreholes on the first row
The main formulas of blasting rounds charge design in Surface
blasting
1. The weight of rock blasted from one borehole charge : Q = qaWH, kg
Where: q – Powder factor of explosive consumption, kg/m3;
a – spacing, m;
W – Value of the line of least resistance at bench toe, face
burden, m;
H – Bench height, m.
2. Burden at bench toe – W:
W =0.9√(P/mq): inclined or vertical holes (Most common);
W = 2mdc√ (Δe/q): for inclined or vertical holes;
W = 53 krcdc √ Δ/ρ: for inclined holes.
For vertical holes – Often:
W = √(0.25P2 + 4qoPHyLc) – 0.5P:
2qoHy
Where: krc = coefficient accounting for intensity of rock jointing:
for large size blocked rocks: krc = 1;
for fine, small size blocked rocks: krc = 1.2.
3. W is checked for the fulfillment of condition for the safe positioning of the
drilling machine; Wmin ≤ W ≤ Wmax,
Wmin H cot c H cot 3
Δe
Wmax 53k β d c
γ
a = mW, m
7. The Spacing between Borehole Rows
b = (0.85 1.0) a
8. The volume of rock blasted from one borehole charge:
V = aWH, m3
9. The volume of rock blasted from 1 m of borehole length:
B = aWH/Lc,
Where: Lc – borehole length, m.
10. Distance along the perpendicular line between the upper edge of
bench and the line along boreholes on the first row:
C = W - H cot (α),
Where: α - The angle of bench slope inclination, degrees.
Usually: C ≥ 3.
11. Borehole charge holding capacity, kg:
QH = [Lc – ls] P,
Where: ls –stemming length, m: (ls) varies from (20 → 35) dc
Solution:
Due to the small sizes of rock segregations and fine rock jointing,
measurements of their content on massif were not carried out.
Instead, a control blast was conducted with a higher powder factor:
q2 = 0.75 kg/m3
And the output of fines carefully measured, giving: V-H100 = 45%.
Results from mine record and those obtained from experimental blast
could be presented graphically as shown on figure 9.2:
1. Fragmentation
Uniform fragmentation generally requires the production
of new free faces during the detonation process .
Optimum fragmentation in blocky and massive rock
generally occurs when one hole is detonated per delay
and the inter-hole delay is < 1 ms per m of spacing
The delay between rows should be at least 2 to 3 times
the delay between holes in a row (<2.0 ms/m of burden)
In highly jointed or highly bedded rock the delay interval
plays a lesser role in the fragmentation of the rockmass.
2. Vibration Control
Fast inter-hole delay intervals and inter-row delay can
increase ground vibration
Based on the findings of the study, many regulations have
adopted the “8 ms rule” which states that if charges are not
separated by at least 8 ms their charge weight has to be
added together to estimate potential vibrations
What is the maximum number of holes that fire with less than 8 ms of
delay separation?
What is the maximum number of holes that fire with less than 20 ms of
separation?
3. Muckpile displacement
The direction of displacement depends path of
least resistance for the explosive energy to follow
With the proper blast design the delay sequence
can control the direction and degree of
displacement
Typically longer delay intervals (>12 ms/m of
burden) are required between rows to maximize
displacement
The type of excavator will often determine the
degree of displacement required which will
dictate the delay interval between rows of
blastholes
4. Wall control
Too short of delay intervals between holes in a row and between
rows can cause excessive overbreak
If the delay between blastholes in the back row is less than 6 ms/m
the charges can act together to damage the back wall
5. Geology
Short delay times cause higher rock piles closer to the face.
Short delay times cause more backbreak.
Short delay times cause more violence, air blast and ground
vibration.
Short delay times have more potential for flyrock.
Long delay times decrease levels of ground vibration.
Long delay times decrease the amount of backbreak.
Topic 8: UNDERGROUND BLASTING
Introduction
Drilling and blasting in the underground mining is carried out
in the
- Mining development e.g. drifts, crosscuts, shafts, raises
and winzes
- Production mining in blocks
The factors determining the effectiveness of underground
blasting are:
a) Strength of explosive:
- volume of gases produced,
- velocity of detonation,
- the temperature to which the gases are raised at the
time of detonation.
b) Physical properties of explosives
- Water resistance
- Density
- Fume class
- Temperature effect
c) Physical and mechanical characteristics of rock:
- Strength of the rock
- planes of cleavage and fracture
- the size of excavation
Vertical blastholes
The blastholes can be from 32 mm up to 250 mm in diameter,
depending on factors such as quality of rock, fragmentation
requirement, etc.
Horizontal blastholes
Vertical Crater Retreat (VCR)
Vertical or sub-vertical blastholes are drilled downward from the top
level to the bottom level
A cuboid of ore-body can be excavated from the lower level upward
by a number of horizontal slices using the same blastholes
VCR loaded explosive column
Topic 9: CONTROLLED BLASTING
Introduction
Causes:
- Carelessness
- Improper stemming length
- Weak geology, etc.
Inadequate Face Burden
Causes
a. improper blast design
b. over excavating the face
c. weak face caused by overbreak from
previous blast, etc.
Inadequate Timing Between Rows Of
Blastholes
Causes
a. poor timing design
b. improper design implementation
c. inaccurate delays
Excessive Powder Factor
Causes
a. improper design and or implementation
b. too large of charge diameter
c. improper charge density
d. improper stem length
Secondary Blasting
Causes
a. lack of energy confinement
b. overloaded
Adverse Geology
Causes
a. weak geological structures( mud seams and joints) poorly confine
explosive energy
b. voids can cause the hole to be overloaded
c. soft overburdens
Solution of the above causes
1. Good shot design is the primary method for
avoiding flyrock
2. But good design cannot completely eliminate
flyrock due to geological inconsistencies so
expect the worst and plan accordingly.
3. Even with proper precautions, flyrock can still
occur
4. Unusually long throw distances should be
recorded and used for determining the proper
blast area to be cleared.
5. All observers of the blast must have adequate
protection from flyrock.
Part two: DRILLING
Fc
Mrm
The action of forces and the form of hole face in Rotary Drilling
Fc + Fu
Mrm
Operation principles
R-P drilling is composed of percussion impulse (Fu), rotation
torque (Mrm) and significant feed force (Fc),
The piston drill is fixed on top of the drilling steels and the
rotation mechanism.
Areas of favorable application
1. In rocks of hardness (f = 6 ----14)
2. Only suitable for shallow-small diameter drill holes.
Fu+Fc
Mrm
Operation principles
P-R is composed of significant percussion impulse (Fu),
continuous rotation torque (Mrm) and continuous feed force
(Fc)
The rotation mechanism is fixed on the top of hole surface-
drilling steel;
The piston drill is fixed on the bottom end of drilling steels and
in contact with the rock on hole face
Bit cooling and hole cleaning :
Accomplished from compressed air or air-water mixture
supplied in through the drill.
Disadvantage of P-R drills
Since it is difficult to manufacture P-R (DTH) drills of smaller
diameters, these drills are only for deep holes of larger
diameters > 90 mm.
Advantages of P-R/DTH drills over R-P/Top Hammer
Efficiency in hard rocks types
With the hammer in the hole drilling vibrations are reduced
Tend to drill straighter holes at greater depths as compared to
R-P drills
With the increase of hole depth and the consequent of drilling
steel extension, percussion efficiency is retained in P-R drills
and decreased in R-P drills;
Schematic drawing of three types of drilling
A- Top Hammer (R-P) ; B- DTH (P-R) C- Rotary
a - tip, b- bit, c- rod, d- sleeve, e- drill pipe, f- piston, g- cylinder,
h- percussion mechanism,
i- rotation mechanism, j- flushing.
Percussive – turn rock drills (P)
The P is based on indentation- that is, the drill bit is placed in contact
with the rock and the periodic- short lived blows of percussion stress
(Fu) applied by the drilling machine on the drill bit, causing its inserts
or buttons to penetrate the rock through a thickness (h)
Mrm
Fu +Fc
The action of forces and the form of hole face in Percussive-turn rock drilling
Feed force
(Fc)
Rotation
Torque (Mrm)
Percussion
impulse (Fu)
Coefficient of
rock hardness ≤ 10 6 14 8 20 8 20
4. Drill bits:
The two types of drill bits commonly used on percussion drills
are:
1. The brazed bit;
2. The button bit.
Brazed bits
The brazed bit is made up from one, four or six rectangular prisms of
cemented tungsten carbide or hardened steel inserts.
Brazed bits made of 4 prisms of inserts are the most common on
percussive drills and are of two types:
1. The cross bit (+);
2. The x-bit.
The cross bit is made of inserts which are mounted at 900 from each
other.
In the X-bit the angle between inserts is 800 and 1000.
Bits have one hole at the centre and four on the side wall of the bit
for water passage to cool the bit and flush drilled products out of the
hole.
Button bit
THE DRILLING INSTRUMENTS OF ROTARY DRILLS
• Rigs are either truck or track-mounted. Rubber tired rigs can travel
quickly between job sites. However not able to move on rough terrain
• Track or crawler mounts can easily traverse rough terrain.
Rotary Drilling Rigs
Jackleg
Topic 2: FIELD CONTROLS FOR SAFE,
EFFICIENT BLASTING
MAJOR FACTORS INFLUENCING BLAST EFFICIENCY
1. Geological Effects
2. Optimum Explosive Performance
3. Quality control
4. Communication
A. Geological Effects
Blasting results are influenced more by rock properties and structure
than by explosive properties
1. Physical rock properties- e.g. compressive strength, tensile
strength, Young's modulus, density etc.
2. Rock structure-
Rock fragmentation is primarily controlled by the rock structure
(i.e. bedding, jointing and faulting)
5. Water
Presence of water has major influence on the
type of explosive used and overall costs
Mine site dewatering - expensive but can be
justified by overall savings in mine equipment
and explosives used.
B. Optimum Explosive Performance
D. Communication
Safe, optimized blasting requires good
communication between members of each group
and interaction between groups
Efficient blast designs require a group
effort
I. SITE EVALUATION
Site Conditions That Influence Blast Design are
1. Rock type
a. ore / waste
b. block size
c. structural orientation
d. blastability (easy, average, hard)
e. reactive ground
2. Desired fragmentation
a. ideal size distribution for excavation
3. Desired amount and direction of rockmass displacement
a. dilution control
b. excavator efficiency
4. Wall damage control
a. blast location with respect slope
b. slope stability
5. Water conditions
a. water table
b. recharge rate
6. Available explosives
a. density
b. energy
c. water resistance
7. Drilling equipment
a. type available (rotary, hammer)
b. bit diameter
c. angle capacity
d. productivity
8. Labor requirements
a. productivity (holes loaded per day)
9. Bench restrictions
a. free face
b. berm location
c. overbreak from adjacent blasts
II. BLAST DESIGN
Considerations are
1. Performance goal(s)
2. Site conditions
Storage of Explosives
TRANSPORTATION OF EXPLOSIVES
When explosives are transported on the highway, they
should be transported in vehicles in proper working
condition and equipped with federal, state or locally
approved containers for safe transport
Unless the explosives are in the proper approved
containers, caps and explosives should not be carried
on the same vehicle.
The explosive cargo should be gently unloaded and
cases should not be thrown onto the ground.
Transport of Explosives