Math 31 Reviewer and Pointers: 1 Topic 1: Mathematics in Nature
Math 31 Reviewer and Pointers: 1 Topic 1: Mathematics in Nature
Math 31 Reviewer and Pointers: 1 Topic 1: Mathematics in Nature
Eric G. Lauron
September 18, 2021
Disclaimer: This material is intended only for our review to enhance our preparedness for
the incoming exam. Please circulate this around our section only. Some items are not answered.
Please be diligent in answering them.
2. x + y
This is not a declarative sentence.
5. What is it?
Definition 2 The truth value of a statement is true (T) if the statement is true and false (F)
if it is false.
Theorem 1 The following are the truth values for the compound statements:
1. The truth value of a negation is the opposite truth value of the original statement.
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3. The disjunction p ∨ q is false only if both p and q are false.
5. The biconditional p ⇐⇒ q is true only if both p and q have the same value.
Suppose p and q are logical statements. The following table is a comprehensive presentation
for the truth value of the compound statements.
p q ¬p p ∧ q p ∨ q p → q p ⇐⇒ q
T T F T T T T
T F F F T F F
F T T F T T F
F F T F F T T
Find the truth value of the following:
1. Cebu city is in region V III and region V III is in the Philippines.
Solution:
Let
p : Cebu city is in region V III;
q : region V III is in the Philippines.
We have p is false and q is true. Therefore, by conjunction, the statement is false.
3. All squares are rhombi if and only if all squares are rectangles.
Definition 4 A truth table is a table that shows the truth value of a statement for all possible
truth values of its components.
Question:
If there are n number of statements, how may possible combination of truth values?
Answer:
Suppose there are n statements. Each statement has two possible values. Hence, we have
2| · 2 · 2 ·{z2 · · · 2 · 2}
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1. Construct a table with 2n +1 rows and n + number of distinct compound statements columns
where n is the number of given statements. Reserve the top row for the statements and the
rest of the 2n rows for the truth values.
2. Write the symbolic form of the statements piece by piece. The first n columns should be the
given statements.
n
3. Distribute the possible truth values. To do this, on the first column, write 22 rows of T and
n
F alternately. On the second column, write alternately T and F on 222 number of rows. On
n
third column would be 223 rows of alternate T and F and so on.
Solution:
There are 3 simple statements, so the number of rows is 2n + 1 = 23 + 1 = 8 + 1 = 9. There
are 3 simple statements and 5 compound statements namely, (p → q), (q → r), (p → r),
[(p → q) ∧ (q → r)] and [(p → q) ∧ (q → r)] → (p → r). Hence, there are 3 + 5 = 8 columns.
This is how it is constructed.
p q r (p → q) (q → r) (p → r) [(p → q) ∧ (q → r)] [(p → q) ∧ (q → r)] → (p → r)
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p q r (p → q) (q → r) (p → r) [(p → q) ∧ (q → r)] [(p → q) ∧ (q → r)] → (p → r)
T T
T T
T F
T F
F T
F T
F F
F F
For the r column, we have
p q r (p → q) (q → r) (p → r) [(p → q) ∧ (q → r)] [(p → q) ∧ (q → r)] → (p → r)
T T T
T T F
T F T
T F F
F T T
F T F
F F T
F F T
Lastly, do the connectives,
p q r (p → q) (q → r) (p → r) [(p → q) ∧ (q → r)] [(p → q) ∧ (q → r)] → (p → r)
T T T T T T T T
T T F T F F F T
T F T F F T F T
T F F F T F F T
F T T T T T T T
F T F T F T F T
F F T T T T T T
F F T T T T T T
2. Verify the truth value of
(p → r) → [(p → q) ∧ (q → r)]
where p, q and r are logical statements.
Definition 5 A tautology is a statement that is always true. A contradiction is a statement
that is always false.
In the case that a statement is true for cases and false on others, then it is called contingency.
Show if the following is a tautology, contradiction or contingency:
1. (p ∧ ¬(q ∧ r)) ∨ (q → r) for logical statements p, q and r.
2. ¬({¬(p ∧ ¬r) ∧ ¬(q ∧ ¬s)} ∧ ¬{¬(p ∨ q) ∨ (r ∨ s)}) for logical statements p, q, r and s.
Definition 6 Two compound statements A and B are logically equivalent if they both have the
same truth value for all possible truth values of their simple statements.
Suppose p and q are statements, show that ¬(p ⇐⇒ q) and [(p ∧ ¬q) ∨ (q ∧ ¬p)] are logically
equivalent.
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2 Reasoning and Problem Solving
Definition 7 Reasoning is the act of thinking about something in a logical and sensible way.
Definition 8 Inductive Reasoning is a type of reasoning that forms a conclusion based on the
examination of specific examples. The conclusion drawn is called a conjecture.
Definition 9 Deductive Reasoning is the process of using facts, rules, definitions, or properties
to reach a valid conclusion.
Construct your conjecture by using inductive reasoning and prove it by using deductive rea-
soning.
1. What is the total amount if there are n number of 5-peso coins on the base.
3. In a square egg tray, an egg can only be place on the top space between the four eggs. If the
dimension of the tray is 1 by 1, we cannot put an egg on top of it. If the dimension is 2 by
2, we can put another egg on the space between the four eggs. The total number of eggs is
5. If the dimension of the tray is 3 by 3, then we can put 4 eggs on the second layer on the
spaces between the eggs and 1 egg on the third layer on the space between the four eggs on
the second layer. The total number of eggs is now 9+4+1=14. What is the total number of
eggs in an n by n egg tray?
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1. All prime numbers are odd.
Solution:
2 is prime, yet 2 is even.
(x+1)(x−1)
2. x+1
= x − 1.
Solution:
For x = −1, the equality does not hold.
2. Devise a plan
0.012345678901234567890123456789....
3. In a survey of 200 people that had just re-turned from a trip to Europe, the following
information was gathered:
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How many went to none of these countries.
Solution:
The best way to solve this is to use a diagram.
Next, input first the intersection of the three, meaning there 20 who visited all the three
countries.
Next is the intersections of each countries. To get this, subtract them to the intersection of
three. Hence, Those who visited England and Italy ONLY is 70-20=50. Those who visited
England and Germany ONLY is 50-20=30. Those who visited Italy and Germany ONLY is
30-20=10. Plugging these in to the diagram, we have
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Finally, we will get the number of those who visited a country only. To get this we have,
we will subtract the figure to the number of those who visited both and all three. Hence,
for England, we have 142-(50+20+30)=42. For Italy, we have 95-(50+10+20)=15. For
Germany, we have 65-(30+20+10)=5. Plugging in, we have
Finally, we take the sum of these and subtract from the 200 people. Hence we have 200-
(42+15+5+50+30+10+21)=200-172=28. Therefore, there are 28 people who went to none
of these three countries.
4. At the end of the day the manager of Blue Baker wanted to know how many pizzas were
sold. The only information he had is listed below. Use the information to determine how
many pizzas were sold.
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6. Counterexample-2pts
I’ll give bonus points(maybe 3 pts) on some personal real life applications of math on the first
lesson.
Because of time constrain, I haven’t reviewed all the details of this material. If there are some
ambiguous parts, please notify me. Just study this diligently. God Bless...