Nothing Special   »   [go: up one dir, main page]

Transformer Solved Problem

Download as docx, pdf, or txt
Download as docx, pdf, or txt
You are on page 1of 4

ELECTRICAL APPARATUS AND DEVICES/ AC APPARATUS AND DEVICES

EE 322/ EE 421
SEMI FINAL-TERM EXAMINATION
NAME: Palada, Royce M. COURSE & YR: BSEE - 3 ID.#: 18 - 41707

1) The corrected instrument readings obtained from open and short-circuit tests
on 10-kVA, 450/120-V, 50-Hz transformer are :

O.C. test : V1 = 120 V; I1 = 4.2 A; W1 = 80 W; V1, W1 and I1 were read on the low-voltage side.
S.C. test : V1 = 9.65 V; I1 = 22.2 A ; W1 = 120 W − with low-voltage winding short-circuited

Compute :
(i) the equivalent circuit (approximate) constants,
(ii) efficiency and voltage regulation for an 80% lagging p.f. load,
(iii) the efficiency at half full-load and 80% lagging p.f. load.
Given:
From O.C. test reading
on the low-voltage side:
From S.C. test reading with
V1 = 120 V a low-voltage short circuited:
I1 = 4.2 A V1 = 9.65 V
W1o.c. = 80 W
I1 = 22.2 A

Required: W1s.c. = 120 W


a. Ro and Do
b. % regn and efficiency @ Full-load
c. efficiency @ Half-load

Solution:
a. From O.C. Test

Equivalent Circuits:
From S.C. Test

b. Total Transformation Drop as referred to primary

For Full-load:

c. For Half-load:
2) A 20-kVA, 2200/220-V, 50-Hz distribution transformer is tested for efficiency and regulation as
follows :

O.C. test : 220 V 4.2 A, 148 W –l.v side

S.C. test : 86 V 10.5 A, 360 W – l.v. side

Determine:
(i) core loss
(ii) equivalent resistance referred to primary
(iii) equivalent resistance referred to secondary
(iv) equivalent reactance referred to primary
(v) equivalent reactance referredto secondary
(vi) regulation of transformer at 0.8 p.f. lagging current
(vii) efficiency at full-load and half the full-load at 0.8 p.f. lagging current
Given:
From O.C. test reading From S.C. test reading with
on the low-voltage side: a low-voltage short circuited:
V1 = 9.65 V
V1 = 220 V
I1 = 4.2 A I1 = 22.2 A
W1o.c. = 148 W W1s.c. = 120 W

Required:
a. Core loss
b. R01
c. R02
d. X01
e. X02
f. V'1
g. efficiency @ Full-load and efficiency @ Half-load
Solution:

You might also like