A Finite Element For Reinforced Concrete Shells: Kitjapat Phuvoravan
A Finite Element For Reinforced Concrete Shells: Kitjapat Phuvoravan
A Finite Element For Reinforced Concrete Shells: Kitjapat Phuvoravan
Kitjapat Phuvoravan1
ABSTRACT: Two techniques, discrete and layered modeling, exist for modeling reinforced concrete shells. In the
discrete modeling, concrete is modeled by three-dimensional solid elements while the reinforcing steel is modeled by
truss elements. The drawback of the discrete modeling is that a large number of degrees of freedom are required. In the
layered modeling, concrete is divided into a set of layers, while the reinforcing steel is smeared into a layer between
concrete layers. Layered modeling of RC shells is simple, but provides an unrealistic representation of the reinforcing
steel. This paper presents a new finite element for the analysis of reinforced concrete (RC) shells. The element
combines a four-node Kirchhoff shell element for concrete with two-node Euler beam elements for the steel
reinforcement bars. The connectivity between reinforcement beam elements and concrete shell element is achieved by
means of rigid links. By using the transformation method for rigid links, beam nodes are eliminated from the final
mesh of the structure. The stiffness from the reinforcement is implicitly included in the new element. In this manner,
this finite element is able to take into account the location of the reinforcement bars. This is in contrast to the smeared
method, which is often adopted in the layered modeling of RC shells. The new finite element is verified with
experimental results. The effect of different reinforcement spacing with the same reinforcement ratio is also evaluated.
KEYWORDS: Finite elements, Reinforced concrete, Shell structures, Slabs, Layered approach
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reinforced by a beam [4]. The nodes of the beam and the Rigid Link
nodes of the plate do not coincide. The beam helps the
plate resist the external load due to the connection 4* J 3*
between the plate and the beam. 6*
I z
b 1* 2*
2.2 RC Shell Element
The proposed RC shell element is formulated using the 5* y
x
concept of layered shell element for concrete combined Rigid Link
with the beam element for the reinforcement bar by System 1
means of rigid links. The reinforcement beam nodes
disappear in the combined element, however they
implicitly help resist external load through the shell 4
element. 3
To illustrate the proposed method, consider the
problem shown in Figure 4 where a single steel 1 2
reinforcement is placed in a concrete shell. In this figure,
the two systems used to derive the RC shell element are
System 2
shown. In the first system, all degrees of freedom from
the beam and the shell appear in the element. In the Figure 4 Proposed reinforced concrete shell element.
second system, only the degrees of freedom associated
with the shell are presented in the element. First, Given that point I and point J are on the mid-surface
consider nodes 5* and 6*, and points I and J only. The of the shell element, their displacements can be obtained
relationship between these nodes is given by: in terms of shell nodal displacements as:
{ }
u * = [T22 x10 ]⋅ {u IJ } (2) {u IJ } = [N IJ ]⋅ {u} (3)
Where, Where, {u} is shell displacement vector (20x1) at node 1,
[I ] [T ] 0 ⎤ , 2, 3, and 4, and [NIJ] is the matrix (10x20) of shell shape
[T22 x10 ] = ⎡⎢ 12 ⎤⎥ , [T12 x10 ] = ⎡⎢ 6 x5 functions at point I and point J.
⎣[T12 x10 ]⎦ ⎣ 0 [T6 x5 ]⎥⎦ From equation (2) and equation (3), the vector {u*}
⎡1 0 0 0 z ⎤ can be expressed in terms of the shell nodal displacement
⎢0 1 0 − z 0 ⎥ vector {u} as:
⎢
⎢0 0 1 0 0 ⎥
⎥ { }
u * = [T22 x10 ] ⋅ [N IJ ] ⋅ {u} (4)
[T6 x 5 ] = ⎢ ⎥, Next consider the whole shell and beam elements.
⎢0 0 0 1 0 ⎥ The relationship between degrees of freedom at nodes 1*,
⎢0 0 0 0 1 ⎥ 2*, 3*, 4*, 5*, and 6* of System 1 and degrees of freedom
⎢ ⎥ at nodes 1, 2, 3, and 4 of System 2 is given as:
⎣0 0 0 0 0 ⎦
[I12] is a 12x12 identity matrix, z is the z-coordinate from {u′} = [T32 x 20 ]⋅ {u} (6)
the reference mid-shell surface, Where,
{u } = {{u } {u } {u } {u }} [I ]
[T32 x 20 ] = ⎡⎢ 20 ⎤⎥ , [T12 x 20 ] = [T12 x10 ]⋅ [N IJ ] ,
* T * * * *
is displacement vector
⎣[T12 x 20 ]⎦
I J 5 6
(L/t = 36)
fc’ = 286 ksc Center point of slab 1800 mm.
fsy = 3831 ksc (4 meshes)
fsu = 4955 ksc
Spacing varies Ø Varies z
6 @150 mm. = 900 mm.
y
975 mm.
x
y
x
z
75 50
125 mm.
(b)
(a)
Reinforcement Ratio (ρ) = 0.218 %
Symmetry
7 @129 mm. = 900 mm. 75 mm. Figure 6 Problem Description Used to Evaluation the
975 mm.
Effect of Reinforcement Spacing; (a) Slab Configuration,
(b) Reinforcement Detail.
4.8 mm. @ 62.5 mm.
z Figure 7 shows the stiffness contribution of
reinforcement. The comparison is made among the
x
analyses using different reinforcement diameter and
y
50 mm. spacing but same reinforcement ratio. Contrary to the
smear method for reinforcement model, it can be seen
4.8 mm. (b)
4.8 mm.
that the proposed RC shell element can capture the effect
4.8 mm. of the reinforcement spacing and the effect of the
reinforcement diameter. The analysis results show that
Figure 5 Test of Pressure Load on Simply Supported RC the usage of larger reinforcement size and larger spacing
Slab by Taylor [3]; (a) Slab Configuration, (b) yields slightly weaker system. As the reinforcement size
Reinforcement Detail. and its spacing is decreased, the behavior of the slab
becomes closer to the analysis using smear reinforcement
The slab is analyzed using the proposed finite model. Figure 8 shows the effect of reinforcement
element. Due to its symmetry, a quarter of the slab is spacing to the stiffness of the RC slab. It can be seen that
modeled using an 8 by 7 mesh. The proposed RC shell the stiffness of the system decreases as the reinforcement
element is verified by comparing the result from finite spacing increases.
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REFERENCES
[1] Hand, F.R., Pecknold, D.A., and Schnobrich, W.C.
2 Smear Reinforment
(1973), “Nonlinear layered analysis of RC plates and
Contribution of reinforcement
1.55
1.50
1.45
1.40
0 100 200 300 400 500
Spacing (in)
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