18.774 M 9201 MM 500 MM 1500 MM 25 MM 12000 MM 3000 MM 225 MM 65 MM 4 No 300 MM 600 MM
18.774 M 9201 MM 500 MM 1500 MM 25 MM 12000 MM 3000 MM 225 MM 65 MM 4 No 300 MM 600 MM
18.774 M 9201 MM 500 MM 1500 MM 25 MM 12000 MM 3000 MM 225 MM 65 MM 4 No 300 MM 600 MM
DATA
1) Span Of The Bridge = 18.774 m Overall Span = 20 m)
2) Width Of Carriageway = 9201 mm Grade Ec
3) Width Of Kerb = 500 mm Slab conc 30 31220
4) Width Of Footpath = 1500 mm Gird conc 30 31220
5) Width Of Expansion Gap = 25 mm m ratio 1.0
6) Total Width OF Bridge = 12000 mm
7) Spacing of girders = 3000 mm
9) Thickness of deck slab = 225 mm
10 ) Thickness of wearing cou. = 65 mm
11 ) No. of girders = 4 no
Width of web at center = 300 mm
Width of web at end = 600 mm 1775 L/D 10.58
depth of girder rec: 1550 mm
DETAIL OF SUPERSTRUCTURE
ELEVATION OF GIRDER
0.9
2.4
7.04025
3L / 8 9.387
L/2
Midspan Supports
Width of top flange 1.000 1.00 m. Span of girder 18.774 m slab 0.0098 0.0098
Width of bot flange 0.600 0.60 m. L/D 10.577 web 0.0087 0.0586
Thk of top flange 0.150 0.15 m. top fl 0.0010 0.0010
Thk of bot flange 0.250 0.25 m. bot fl 0.0024 0.0024
Web thickness 0.300 0.60 m. Taper section profile Ixx = 0.0219 0.0717
Thk of top fl at web 0.225 0.193 m.
Thk of bot fl at web 0.400 0.25 m. 0.9 0.9
Depth of girder 1.550 1.55 m.
Thickness of top slab 0.225 0.225 m.
Beff of top slab 3.000 3 m.
Spacing of girders 3.000
Actual width of slab 3.000
Mid span Supports
SECTION PROPERTIES web top flangebot flange web top flangebot flangeTop Slab
Area 0.35 0.16 0.16 0.69 0.16 0.15 0.68
distance from cg 0.02 0.60 0.76 0.00 0.62 0.74 0.41
Moment 0.04 0.0003 0.0008 0.08 0.00 0.00 0.00
Total Moment 0.19 0.22
PRE-CAST GIRDER mid span Support
Area 0.669 0.999 m2
Area * x 0.567 0.821
cg. Of girder 0.848 0.822 m
Mom of inertia 0.190 0.220 m4
Top cg 0.702 0.728 m
Ztop 0.271 0.302 m3
Zbot 0.224 0.267 m3
Reaction from gird 168.2 KN
Composite girder mid spanSupport
Area 1.344 1.674
Area * x 1.690 1.969 m2
cg. Of girder 1.257 1.176 m
Mom of inertia 0.416 0.676 m4
Top cg 0.518 0.599 m
Ztop 0.803 1.129 m3
Zbot 0.331 0.575 m3
Dead load of Slab on girder is calculated as per the contributing area of the slab on the girder.
The footpath and sidl load is distributed on the basis of moment distr.
For inner girder the effect of footpath and sidl is in the opposite direction as the dead load on it, so not considered
(( ) ))) ) )
Bending moments for girder at different section for DL
outer inner
AT 9.39 m L/2 = 1506.2 KNm 1506.4 KNm
AT 7.04 m 3L/8 = 1413.7 KNm 1413.3 KNm
AT 4.69 m L/4 = 1297.3 KNm 1296.7 KNm
AT 2.35 m L/8 = 923.9 KNm 925.2 KNm
MOMENTS MAX
Section LL Max FPLL MOMENT
m SIDL KNm KNm AT SECTION
9.387 366 1693 0 2060
7.0403 344 1601 0 1945
4.6935 315 1453 0 1768
2.3468 222 1102 0 1324
JOINT DL SIDL WC FPLL 2CLA 3rd CLA CL 70R WCL 70R tr Max LL
11 375.2 116.1 62.7 0.0 321.3 8.9 340.9 263.6 402.9
13 410.7 -35.7 57.7 0.0 313.4 23.0 465.3 426.7 549.9
15 402.1 -36.5 56.1 0.0 121.5 250.5 48.1 47.4 395.6
17 378.6 116.1 63.5 0.0 14.1 158.7 20.4 18.1 190.5
155 378.7 116.1 63.5 0.0 297.1 8.0 339.7 280.7 401.4
157 402.1 -36.5 56.1 0.0 260.6 21.3 460.4 457.9 544.0
159 410.8 -35.7 57.7 0.0 108.4 188.9 44.2 49.3 316.1
161 375.2 116.1 62.7 0.0 13.8 124.5 18.7 17.2 152.3
3000
112.50
1662.50
300
Assuming N.A. lies within the web
Bf X Df X( Xna - Df / 2 )
= m X Ast X( d - Xna )
3000 X 112.5 X( Xna - 112.5 / 2 )
= 10.00 X 16076.8 X( 1510.5 - Xna )
Xna - 56.25 = 0.47635 X( 1510.5 - Xna )
Xna = 525.47 mm
Let scbc be the compressive stress developed in concrete at the top
of the flange.
Let scbc' be the compressive stress developed in concrete at the bottom
of the flange.
scbc scbc'
Xna = Xna - Df
YBAR = 54.00 mm
Lever arm = 1456.50 mm
MR = ( scbc +scbc' ) X Bf X Df X Lever arm
2
4000.82 = 4.39E+08 X scbc
scbc
2 2
= 9.11 N/mm < 13.3 N/mm safe
MR = sst X Ast X lever arm
4000.82 = sst X 23415823
sst = 170.86 N/mm
2
< 240 N/mm2 safe
A E
B F 0.25
h1 0.15 h1
4.0°C -0.7°C
C G
h2 0.25 h2
0.2
h
1.225 0.875
0.2
H h3
h3 0.15
D -0.8°C I h4
J 0.25
2.1°C -6.6°C
CG of Restraint Moments
Lever Arm to the CG of
Temp about CG of Section
Section Area Restraint Section (mm)
Description Diagram (KNm)
2
(mm ) Forces (KN) At
From Top
At Support At Mid At Mid
(mm) Support
Section Contributing A 450000 50.0 1180.67625 548.63 468.17 647.757 552.7524
Section Contributing B 450000 75.0 6.84E+02 523.63 443.17 358.4001 303.3249
Section Contributing C 378750 233.3 288.039375 365.30 284.83 105.2205 82.04301
Section Contributing D 90000 1725.0 35.933625 -1126.37 -1206.83 -40.4745 -43.3659
For Fixed Bearing (Refer Detailed Calculation of horizontal forces in the following sections)
F=Fh-u(Rg+Rq) or Fh/2+u(Rg+Rq) Vehicular LL Normal Seimic case
F= 228 - 0.03 x( 1966.7 + 630 ) = 149.8 kN -40.0 kN
113.85 + 0.05 x( 1966.7 + 630 ) = 243.7 kN 116.0 kN