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    Moment Distribution Spread Sheet

    Uploaded by

    Sajid Nazir
    The document describes a moment distribution method for calculating internal forces in a beam with multiple joints (A, B, C, D) and members (AB, BC, CD). It lists the relative stiffness and fixed end moments that need to be input for each member. It then shows the distribution factors and balancing moments that would be calculated at each iteration to distribute moments throughout the beam until the internal forces sum to zero, validating the solution.

    Copyright:

    Attribution Non-Commercial (BY-NC)
    Download as XLS, PDF, TXT or read online from Scribd

    Moment Distribution Spread Sheet

    Uploaded by

    Sajid Nazir
    11K views1 page
    The document describes a moment distribution method for calculating internal forces in a beam with multiple joints (A, B, C, D) and members (AB, BC, CD). It lists the relative stiffness and fixed end moments that need to be input for each member. It then shows the distribution factors and balancing moments that would be calculated at each iteration to distribute moments throughout the beam until the internal forces sum to zero, validating the solution.

    Original Description:

    moment distribution method spread sheet excel

    Original Title

    Moment Distribution spread sheet

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    © Attribution Non-Commercial (BY-NC)

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    The document describes a moment distribution method for calculating internal forces in a beam with multiple joints (A, B, C, D) and members (AB, BC, CD). It lists the relative stiffness and fixed end moments that need to be input for each member. It then shows the distribution factors and balancing moments that would be calculated at each iteration to distribute moments throughout the beam until the internal forces sum to zero, validating the solution.

    Copyright:

    Attribution Non-Commercial (BY-NC)
    Download as XLS, PDF, TXT or read online from Scribd
    Download as xls, pdf, or txt
    11K views1 page

    Moment Distribution Spread Sheet

    Uploaded by

    Sajid Nazir
    The document describes a moment distribution method for calculating internal forces in a beam with multiple joints (A, B, C, D) and members (AB, BC, CD). It lists the relative stiffness and fixed end moments that need to be input for each member. It then shows the distribution factors and balancing moments that would be calculated at each iteration to distribute moments throughout the beam until the internal forces sum to zero, validating the solution.

    Copyright:

    Attribution Non-Commercial (BY-NC)
    Download as XLS, PDF, TXT or read online from Scribd
    Download as xls, pdf, or txt
    of 1

    MOMENT DISTRIBUTION METHOD

    AUTHOR : MUHAMMAD YASIR SALEEM (2K7-CE-02)

    Please Enter Relative Stiffness and Fixed End Moments

    Joint A B C D
    Member 0 AB BA BC CB CD DC 0
    Relative Stiffness (K=I/L) 0.000 Enter Enter Enter 0.000
    Distribution factor 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    1 Fixed end Moment 0.000 Enter Enter Enter Enter Enter Enter 0.000
    Balancing moment 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    2 COM 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    Balancing moment 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    3 COM 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    Balancing moment 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    4 COM 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    Balancing moment 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    5 COM 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    Balancing moment 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    6 COM 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    Balancing moment 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    ∑ 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    CHECKS
    "Change (Near)" 0.000 #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! 0.000
    "-1/2 Change Far" #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE!
    ∑ #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE!
    θ(Rel) = ∑ / -K #VALUE! #VALUE! #VALUE! #VALUE! #VALUE! #VALUE!

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