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Informasi Data: Analisis Momen Crack Tangga

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The document provides an analysis of a reinforced concrete beam based on ACI 318 code provisions.

The beam being analyzed is a singly reinforced rectangular beam.

The input data provided includes properties of the concrete, beam dimensions, reinforcement amounts and locations, and working moment.

ANALISIS MOMEN CRACK TANGGA

ANALISIS LENTUR
ACI 318 - 99

Informasi Data
P/
2

P/2
A's

h=16.67 mm
As

40 cm

40

40 cm
b=39.11 mm

Data Penampang
b=
39.11 cm
h=

16.67

cm

d=

14.02

cm

d' =

2.5

cm

Data Bahan
Panjang Mod.
(L) =
Elastis (E)
=

A's =
As =

0.39 kN m
0.9

Ma=

dia (cm)
1.3
1.3

15

Luas

1.05

Es =
fy =

y=

0.981
Mcr (kN m) =
Mcr (ton m) =

0.39 kN m
15,098 cm4
### mm4

Inersia (I) =

2.65
mm2
2.65
mm2
dia (cm) jarak (cm)

Sengkang

tjd

Data Tulangan
n
2
2

21,640 N/mm2
0.1 ton

Beban (P/2) =

M
Tulangan
Tul. Tekan
Tul. Tarik

1,200 mm

200,000 N/mm2
240 N/mm2
0.0012

cm2

Data Masukan ke Perhitungan


Reinforcing Yield Strength, fy
Concrete Comp. Strength, f 'c
Beam Width, b
Depth to Tension Reinforcing, d
Total Beam Depth, h
Tension Reinforcing, As
No. of Tension Bars in Beam, Nb
Tension Reinf. Bar Spacing, s1
Clear Cover to Tension Reinf., Cc
Depth to Compression Reinf., d'
Tulangan Tekan, A's
Momen kerja, Ma
Momen Ultimit, Mu
Gaya Geser Ultimit, Vu
Total Stirrup Area, Av(stirrup)
Tie/Stirrup Spacing, s2

Kesimpulan
Momen Crack penampang
Beban P/2

atau dengan kata lain P =


Momen TERJADI
Konstruksi Tangg #NAME?

=
240
M Pa
=
21.2
M Pa
=
39.11
cm
=
14.02
cm
=
16.67
cm
=
2.65
cm2
=
2
=
35.11
cm
=
2
cm
=
2.5
cm
=
2.65
cm2
=
0.39
kNm
=
0.39
kNm
=
0
kN
= 1.0471976 cm2
=
15
cm

0.52
0.1
0.2
0.39

Konversi mutu beton ke K


K - 250.372

ton-m
ton
ton
ton-m

5.19
0.52

ANALISIS BALOK BETON BERTULANG PENAMPANG PERSEGI


Lentur, Geser, Kontrol Retak dan Penampang Inersia
ACI 318

Data
b

Beam or Slab Section?


Exterior atau Interior?
Reinforcing Yield Strength, fy =
Concrete Comp. Strength, f 'c =
Beam Width, b =
Depth to Tension Reinforcing, d =
Total Beam Depth, h =
Tension Reinforcing, As =
No. of Tension Bars in Beam, Nb =
Tension Reinf. Bar Spacing, s1 =
Clear Cover to Tension Reinf., Cc =
Depth to Compression Reinf., d' =
Tulangan Tekan, A's =
Momen kerja, Ma =
Momen Ultimit, Mu =
Gaya Geser Ultimit, Vu =
Total Stirrup Area, Av(stirrup) =
Tie/Stirrup Spacing, s2 =

Beam
Exterior
34.8
3.074
15.40
5.52
6.56
0.411
2.000
13.823
0.787
0.984
0.411
0.29
0.29
0.00
0.162
5.9055

ksi
ksi

in.
in.

As

in.
in.^2
in.

Penampang bertulangan tunggal


d'=0.98''

b=15.40''

in.
in.
in.^2
ft-kips

A's
=0.411
h=6.56''

d=5.52''

ft-kips
kips

As=0.411

in.^2
in.

Penampang bertulangan rangkap

Hasil
Cek Kapasitas Momen untuk Beam-Type Section:
1 =
0.85
c = 0.419 in.
a = 0.356 in.
b = 0.04559
(prov) = 0.00484
(min) = 0.00575
As(min) = 0.488 in.^2 > As = 0.41 in.^2, N.G.
(temp) =
N.A.
(total for section)
As(temp) =
N.A.
in.^2/face
(max) = 0.03903
As(max) = 3.317 in.^2 >= As = 0.41 in.^2, O.K.
f 's =
N.A.
ksi (A's does not yield)
Mn =
5.74
ft-k >= Mu = 0.29 ft-k, O.K.

Kontrol Crack/ Retak


Per ACI 318 Code:
Es = 29000 ksi
Ec =
3160
ksi
n=
9.18
n = Es/Ec
fs =
1.67
ksi
fs(used) =
1.67
ksi
s1(max) = 258.30 in. >= s1 = 13.82 in., O.K.

Cek Kapasitas Geser untuk Beam-Type Section:


Vc =
8.01
kips
Vs =
4.49
kips
Vn = Vc+Vs = 12.50 kips >= Vu = 0 kips, O.K.
Vs(max) = 32.04 kips >= Vu-(phi)Vc = 0 kips, O.K.
Av(prov) = 0.162 in.^2 = Av(stirrup)
Av(req'd) = 0.000 in.^2 <= Av(prov) = 0.16 in.^2, O.K.
Av(min) = 0.000 in.^2 <= Av(prov) = 0.16 in.^2, O.K.
s2(max) =
N.A.
in.
Keterangan

Moment Inersia untuk Lendutan:


fr =
0.416 ksi
kd = 1.3672 in.
Ig = 362.73 in.^4
Mcr =
3.83
ft-k
Icr = 78.72 in.^4
Ie = 362.73 in.^4 (for deflection)

Per ACI 318 Code:


dc = 1.0433
z=
4.28
z(allow) = 145.00

in.
k/in.
k/in. >= z = 4.28 k/in.,
O.K.

ANALISIS MOMEN CRACK TANGGA


ANALISIS LENTUR
Per ACI 318-99 Code
fr =
Es =
Ec =
n=
r=
B=
kd =
Ig =

Input Data:
Reinforcing Yield Strength, fy =
Concrete Comp. Strength, f 'c =
Beam/Section Width, b =
Depth to Tension Reinforcing, d =
Beam/Section Total Depth, h =
Tension Reinforcing, As =
Depth to Compression Reinf., d' =
Compression Reinforcing, A's =
Working Stress Moment, Ma =

34.8
3.074
15.398
5.520
6.563
0.411
0.984
0.411
0.29

ksi
ksi
in.
in.

in.

Icr =
Ig/Icr =

in.^2
in.

As

in.^2
ft-kips

Results:

Singly Reinforced Section

d'=0.9842

fr =
Es =
Ec =
n=
kd =
Ig =
Mcr =
Icr =
Ig/Icr =
Ie =

0.416
29000
3160
9.18
1.3672
362.73
3.83
78.72
4.608
362.73

b=15.40''

A's
=0.411
h=6.56299212598425''

ksi
ksi
ksi
in.

As=0.411

in.^4

Doubly Reinforced Section

ft-k
in.^4
in.^4

Note: Use effective moment of inertia, 'Ie', in deflection calculations.


Comments:

Mcr =

5.193
0.52

d=5.52''

kNm
ton m

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