2.diagram Interaksi P-M
2.diagram Interaksi P-M
2.diagram Interaksi P-M
Data :
b = 500 mm Tulangan D =
h = 500 mm Luas 1-tul =
fc' = 25 MPa As,total =
fy = 390 MPa As = As' =
β1 = 0.85 =
φ = 0.65
Penyelesaian :
Tetapkan ds = d' = 60 mm
d = 440 mm
cb =
600
⋅d
600+ fy
= 266.67 mm
ab = β 1⋅cb
= 226.67 mm
cb−d '
fs' = ⋅600
cb
= 465.00 MPa
fs' < fy ?
465.00 > 390.00 Digunakan fy !
Ts = As . fy
= 553104 N
Cs = As' . fy
= 553104 N
Cc = 0,85 . fc' . ab . b
= 2408333 N
Pb = Cc + Cs - Ts
Pb = 2408333 N
φ Pb = 1565417 N = 1565.417
Mb = Cc⋅ ( h2 − ab2 )+Cs⋅( h2 −d ' )+Ts⋅( h2 −ds)
Mb = 539318246.0317 Nmm
φMb = 350556859.9206 Nmm = 350.557
Cc = 0 , 85⋅fc '⋅a⋅b
= 546265 N
Cs = As' . fy
= 6839 N
Mn = Cc*(d-a/2) + Cs*(d-d')
= 228912648 Nmm
φMn = 0,9 Mn
= 206021383 Nmm = 206.021
φMn = 0,65 Mn
= 148793221 Nmm = 148.793
P-M
19 mm
283.64 mm2
10 D19
5 D19
1418.2143 mm2
nakan fy !
1565.417 kN
) ( h2 −ds)
−d ' +Ts⋅
350.557 kNm
kN
kN
kN
kN
9031
297825
-51055714
mm
mm
MPa
kNm
kNm
3. Tulangan Geser Kolom Persegi
Data :
Pu = 800 kN
Vu = 180 kN = 180000 N
fy = 240 MPa
fc' = 20 MPa
b = 500 mm
h = 500 mm
φ
β
= 0.6
1
Diambil ds = 55 mm
d = h−ds
= 445 mm
Vn = Vu
φ
= 300000 N
Pu 1
Vc =
( 1+
)( )
⋅ √ fc ' b⋅d
14⋅A gross 6
= 203748 N
φ Vc = 122249 N
Vu > φVc ?
180000 > 122249 Perlu tulangan geser !
Vs = Vn - Vc
= 96252 N
Av⋅fy⋅d
S perlu =
Vs
= 174.364 Dipakai P 10 - 150
Kontrol jarak sengkang :
Vs <
( 13 √ fc ' ) b⋅d ?
Digunakan :
S ma ks
S maks = d / 2
= 222.5 mm
Vs <
( 23 √ fc ' ) b⋅d ?
Digunakan :
S maks = d/4
= 111.25 mm