Dry Type Power Factor Correction Capacitors: Application Manual
Dry Type Power Factor Correction Capacitors: Application Manual
Dry Type Power Factor Correction Capacitors: Application Manual
L O W V N E T W O R K
O L T A G E Q U A L I T Y
Index
Application and installation ............................................................................................ 20.4 - 20.49 Capacitor installation locations ................................................................................................ 20.46 Extract from NEC, Separate overcurrent protection ................................................................ 20.59 General information...................................................................................................... 20.44 - 20.45 Harmonic phenomena.................................................................................................. 20.50 - 20.52 Sizing capacitors at the motor load ............................................................................. 20.53 - 20.56 Typical recommended ratings of cables & protected devices ..................................... 20.57 - 20.58
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21.41
1SXU000023C0202
General information
Most loads on an electrical distribution system can be categorized into three types: Resistive Inductive Capacitive On modern systems, the most common is the inductive load. Typical examples include transformers, fluorescent lighting and AC induction motors. A common characteristic of these inductive loads is that they utilize a winding in order to operate. This winding produces an electromagnetic field which allows the motor or transformer to function and requires a certain amount of electrical power to maintain this electromagnetic field. All inductive load require two kinds of power to function properly: Active power (kW) Reactive power (kvar) - actually performs the work - sustains the electro magnetic field Apparent Power
A distribution systems operating power is composed of two parts: Active (working) power and reactive (non-working magnetizing) power. The ACTIVE power performs the useful work . . . the REACTIVE power does not. It's only function is to develop magnetic fields required by inductive devices. Generally, power factor decreases (phi increases) with increased motor load. This geometric relationship of apparent power to active power is traditionally expressed by the right triangle relationship of: Cos phi = p.f. = kW/kVA
Motor
Fig. 1
One common example of reactive power can be seen in an unloaded AC motor. When all load is removed from the motor, one might expect the no-load current to drop near zero. In truth, however, the no-load current will generally show a value between 25% and 30% of full load current. This is because of the continuous demand for magnetizing current by any inductive load. Active power is the total power indicated on a wattmeter. Apparent power is the combination of reactive and active power.
200
% Current
-P
150
ower
21
kV A(
ap
pa
ren
tp
ow er)
Facto
r Ang
le
0.6
0.5
Fig. 2 21.42
1SXU000023C0202
Fig. 2
General information
How Power Factor Correction Capacitors Solve the Problem of Low Power Factor
Lower power factor is a problem that can be solved by adding power factor correction capacitors to the plant distribution system. As illustrated in Fig. 4, power factor correction capacitors work as reactive current generators providing needed reactive power (kvar) to the power supply. By supplying their own source of reactive power, the industrial user frees the utility from having to supply it; therefore, the total amount of apparent power (kVA) supplied by the utility will be less.
WITHOUT CAPACITORS Reactive Power Active Power Available Active Power
= 15= .96 2
P.F.
=4
P.F .
Fig. 4
Power factor correction capacitors reduce the total current drawn from the distribution system and subsequently increase system capacity by raising the power factor level.
Fig. 5 The capacitor kvar rating shows how much reactive power the capacitor will supply. Each unit of the capacitors kvar will decrease the inductive reactive power demand (magnetizing demand) by the same amount. EXAMPLE: A low voltage network requires 410 kW active power at full load, and the power factor is measured to be .70. Therefore, the systems full load consumption of apparent power is 579.5 kVA. If 300 kvar of capacitive reactive power is installed, the power factor will rise to .96 and the kVA demand will be reduced from 579.5 to 424.3 kVA. See Fig. 5.
5 =.
424.
70
3 kV A2
57 9. 5 A1 kV
A kV n 2 io 5. uct 15 ed R
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21.43
1SXU000023C0202
PFCC
D Overload Relay
T1 T2 T3
Motor Feed
Fused Safety Switch or Breaker
Contactor
L1 L2 L3
MOTOR
PFCC
PFCC
PFCC
Fig. 6 Option D: As a central compensation source connected to the main distribution bus Advantages: Of the four options, this is the most cost efficient because it uses a few large kvar capacitors rather than many small units. A primary disconnect must be provided for switching and overcurrent protection. As with Option C, a real possibility of overcompensation exists during lightly loaded periods unless some form of automatic control is incorporated. Automatic control can be provided by ABB automatic capacitor banks.
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21.44
1SXU000023C0202
Temperature and Ventilation Capacitors should be located in areas where the surrounding ambient temperature does not exceed 40o C and where there is adequate ventilation. As capacitors always operate at full load and generate heat of their own, maximum heat dissipation must be provided to ensure long operating life. Line frequency and operating voltage are factors that can cause capacitor temperature to rise. Line Frequency - Assuming the line frequency of the capacitor matches the frequency of the incoming service, line frequency is not a concern since it is constant in modern power systems. Operating Voltage - Capacitor overheating at a normal operating voltage and with adequate ventilation seldom occurs. However, when the voltage exceeds 110% of the capacitor rating, overheating and resultant damage can happen. When the operating voltage exceeds 110% of the capacitors rated voltage, the line voltage should be reduced or the capacitor taken off line. This overvoltage problem is exactly why, when determining the required kvar capacitance for a distribution system, a person should always undersize a capacitors kvar rating... too much capacitance means overvoltage... too much overvoltage means excessive heat... and excessive heat can be damaging to the capacitor unit!!!
Discharging Time
Power factor capacitors need a minimum of one minute to discharge. Afterwards, it is always recommended that the terminals be shortcircuited to ground before touching. The following guidelines can be used when specifying capacitors. SPECIFICATIONS FOR CAPACITORS 600 Volts and Below Furnish and install where indicated power factor correction capacitors of the size, voltage rating, and enclosure type shown on the drawings. (OPTIONAL) All motors of horsepower and above shall have individual power factor correction capacitors energized with the motor. All capacitors shall be the self healing metallized-film type filled with vermiculite, a dry NONFLAMMABLE filler material; oil-filled capacitors will not be acceptable. Discharge resistors shall be provided to automatically discharge the capacitor to less than 50 volts within one minute after de-energization. An internal ground lug shall be provided. The capacitors shall withstand 135% of rated current continuously, 110% of rated voltage continuously; and an ambient temperature range of -40C to +40C. Losses shall be less than 0.5 watts per kvar. Each element shall be individually protected and the enclosure shall be filled with a dry, nontoxic, nonflammable insulating material. The capacitors shall be UL Listed and CSA approved. Capacitors shall be ABB or equivalent.
Special Applications
Care should be taken when power factor correction capacitors are used in the following applications: Plugging and jogging applications Frequent starts Crane or elevator motors where the load may drive the motor Multi-speed motors Motors involving open transition reduced voltage starting Reversing starters if they reverse more frequently than once per minute
UA26 UA30 UA50 UA75 UA95 UA110 A145 A185 A210 A260 A300 AF400 AF460 AF580 AF750
3.5 7.0 10.5 21.5 25.0 28.5 43 57 66 75 88 119 142 178 214
4.0 8.0 12.5 25.0 29.0 33.0 50 66 77 87 101 137 164 205 247
8.0 16.5 25.0 50.0 58.0 66.0 100 133 153 174 203 274 329 411 495
10.0 20.5 31.0 62.0 72.0 83.0 125 166 192 218 254 343 410 514 618
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21.45
1SXU000023C0202
Application and installation Wiring diagrams for Autotransformer, part-winding, wye-delta, multi-speed
Part-winding
B C
INCOMING LINES
A B C
L1
L1 L1
L2
L2 L2 L3 L3
L3
RUN
RUN 2S 2S 2S
T2 T2 T3 T3 100%
RUN
L1 L2 L3 L1 L2 L3
T1
1M
PFCC
2M
2OL
T2 T3 T1 T2 T3
SAT
65%
SAT
65%
80% 50% 0% L3
1OL
T1
1S
T1
T3
1S
PFCC
T3 T2 T1 T7
PFCC
OL
T1 T2 T3
T1
T8 T9
T2
MOTOR
T3
Wye-delta
INCOMING LINES
A B C
2 Speed, 2 winding
INCOMING LINES
A B C
L1
L2
L3
L1
L2
L3
L1
L2
L3
L1
L2
L3
L1
L2
L3
1M
2M
S
MECH. INTLK.
T1 T2 T3
S
SOL
F
FOL
T2 T3 T1 T2 T3
T1
T2
T3
21
PFCC
OL
T1 T2 T3
T1
PFCC
T3 T2 T1 T6 T4 T5
PFCC
T3 T2 T1 T11 T12 T13
WYEDELTA MOTOR
21.46
1SXU000023C0202
OL L3 5 L2 3 L1 1
L1 T3 T3 T2 T2 T1 T1 X1
L2
L3
TD
SOFT STARTER
A MOTOR
PFCC
Soft Starter
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21.47
1SXU000023C0202
Harmonic phenomena
Harmonic Content
Thyristor and SCR converters are usually referred to by the number of DC current pulses they produce each cycle. The most commonly used are 6 pulse and 12 pulse. There are many factors that can influence the harmonic content but typical harmonic currents, shown as a percentage of the fundamental current, are given in the below table. Other harmonics will always be present, to some degree, but for practical reasons they have been ignored.
Order of harmonic
1 5 7 11 13 17 19 23 25
100 20 14 9 8 6 5 4 4
100 9 8 4 4
1st = 60 Hz
5th = 300 Hz
7th = 420 Hz
11th = 660 Hz
Fig. 7
Harmonic Resonance
The circuit or selective resonant frequency is reached when the capacitor reactance and the supply reactance are equal. Whenever power factor correction capacitors are applied to a distribution network, which combines capacitance and inductance, there will always be a frequency at which the capacitors are in parallel resonance with the supply.
X XL
Waveform
Harmonics are sinusoidal waves that are integral multiples of the fundamental 60 Hz waveform (i.e., 1st harmonic = 60 Hz; 5th harmonic = 300 Hz). All complex waveforms can be resolved into a series of sinusoidal waves of various frequencies, therefore any complex waveform is the sum of a number of odd or even harmonics of lesser or greater value. Harmonics are continuous (steady-state) disturbances or distortions on the electrical network and are a completely different subject or problem from line spikes, surges, sags, impulses, etc., which are categorized as transient disturbances. Transient problems are usually solved by installing suppression or isolation devices such as surge capacitors, isolation transformers or M.O.V.s. These devices will help solve the transient problems but will not affect the mitigation of low order harmonics or solve harmonic resonance problems. 21.48
1SXU000023C0202
21
XL + XC fhz
fhz Frequency
XL Supply reactance If this condition occurs on, or close XC Capacitor reactance fo Resonant frequency to, one of the harmonics generated by solid state control equipment, then large harmonic currents can Fig. 8 circulate between the supply network and the capacitor equipment. These currents are limited only by the damping resistance in the circuit. Such currents will add to the
XC
Harmonic phenomena
harmonic voltage disturbance in the network causing an increased voltage distortion. This results in a higher voltage across the capacitor and excessive current through all capacitor components. Resonance can occur on any frequency, but in general, the resonance we are concerned with is on, or close to, the 5th, 7th, 11th and 13th harmonics for 6 pulse systems. See Fig. 8. There are a number of ways to avoid resonance when installing capacitors. In larger systems it may be possible to install them in a part of the system that will not result in a parallel resonance with the supply. Varying the kvar output rating of the capacitor bank will alter the resonant frequency. With capacitor switching there will be a different resonant frequency for each step. Changing the number of switching steps may avoid resonance at each step of switching. See Fig. 9.
Types of Filters
Avoiding Resonance
The effectiveness of any filter design depends on the reactive output of the filter, tuning accuracy and the impedance of the network at the point of connection. 5th 7th 11th Harmonics below the filter tuning frequency will be amplified. The filter design is important to ensure that distortion is not amplified to unacceptable levels. Where there are several harmonics present, a filter may reduce some harmonics while increasing others. A filter for the 7th harmonic creates a parallel resonance in the vicinity of the 5th Shunt Filters harmonic with magnification of Fig. 11 the existing 5th harmonic; therefore, a 7th harmonic filter requires a 5th harmonic filter. See Fig. 11. Consequently, it is often necessary to use a multiple filter design where each filter is tuned to a different frequency. Experience is extremely important in the design of such filters to ensure: (a) the most efficient and cost effective solution is selected; (b) no adverse interaction between the system and the filter.
Motor Loads
Capacitor
Fig. 9
Overcoming Resonance
If resonance cannot be avoided, an alternative solution is required. A reactor must be connected in series with each capacitor such that the capacitor/reactor combination is L2 L3 L1 L1 L2 L3 inductive at the critical frequencies but capacitive at the fundamental frequency. To achieve this, the capacitor and series connected reactor must have a tuning frequency below the lowest critical order of harmonic, which is usually the 5th. This means the tuning frequency is in the range of 175 Hz to 270 Hz, although the actual frequency Delta Wye will depend upon the magnitude and order of the harmonic curDetuned Capacitor/Reactor Systems rents present. The addition of a reactor in the capacitor circuit increases the fundamental voltage across the capacitor. Therefore, care should be taken when adding reactors to existing capacitors. See Fig. 10.
Fig. 10
Load Alteration
Whenever load expansion is considered, the network is likely to change and existing filter equipment should be evaluated in conjunction with the new load condition. It is not recommended to have two or more filters tuned to the same frequency connected on the same distribution system. Slight tuning differences may cause one filter to take a much larger share of the harmonic distortion. Or, it may cause amplification of the harmonic order which the equipment has been designed to reduce. When there is a need to vary the power factor correction component of a harmonic filter, careful consideration of all load parameters is necessary.
Harmonic Analysis
The first step in solving harmonic related problems is to perform an analysis to determine the specific needs of your electrical distribution system. To determine capacitor and filter requirements, it is necessary to establish the impedance of the supply network and the value of each harmonic current. Capacitor, reactor and filter bank equipment are then specified under very detailed and stringent computer analysis to meet your needs.
Harmonic currents can be significantly reduced in an electrical system by using a harmonic filter. In its basic form, a filter consists of a capacitor connected in series with a reactor tuned to a specific harmonic frequency. In theory, the impedance of the filter is zero at the tuning frequency; therefore, the harmonic current is absorbed by the filter. This, together with the natural resistance of the circuit, means that only a small level of harmonic current will flow in the network.
ABB is the world's largest manufacturer of dry type low voltage capacitors! ABB Control Inc. utilizes this experience in recommending three options to solve the problems associated with applying capacitors to systems having harmonic distortion: 1. Apply the correct amount of capacitance (kvar) to the network to avoid resonance with the source. This may be difficult, especially in automatic systems as the capacitance is always changing. This solution usually means connecting less capacitance to the system than is actually needed for optimum power factor correction. 2. Install reactors in series with capacitors to lower the resonance below critical order harmonics; i.e., 5th, 7th, 11th & 13th. This design tunes the resonant frequency of the system well below the critical harmonic and is called an anti-resonance bank. This solution allows the capacitors to operate in a harmonic environment.
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21.49
1SXU000023C0202
Harmonic phenomena
3. Filters are recommended if a problem exists with harmonic distortion before the application of power factor correction, or if the harmonic distortion is above the limits recommended in IEEE 519, "Guide for Harmonic Control and Reactive Compensation of Static Power Converters". (The recommended limits for voltage distortion in IEEE 519 are presently 5% for general applications.) Tuned filters sized to reduce the harmonic distortion at critical frequencies have the benefits of correcting the power factor and improving the network power quality. With our knowledge of harmonics, ABB provides a complete range of products from individual capacitors, fixed banks and automatic banks, to power filter systems. All these products utilize dry type low voltage ABB power factor correction capacitor elements which are self-healing for internal faults. To maintain stringent quality control standards, most control components found in automatic and anti-resonance filter bank products are also ABB products. These products include contactors, circuit breakers, control relays, disconnect switches, power factor relays and pushbutton devices.
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21.50
1SXU000023C0202
When the determination is made that power factor correction capacitors ARE a good investment for a particular electrical system, you need to know: How many capacitors are needed? What sizes are appropriate? The capacitor provides a local source of reactive current. With respect to inductive motor load, this reactive power is the magnetizing or noload current which the motor requires to operate. A capacitor is properly sized when its full load current rating is 90% of the no-load current of the motor. This 90% rating avoids overcorrection and the accompanying problems such as overvoltages.
If the no load current is not known . . . If the no-load current is unknown, a reasonable estimate for 3-phase motors is to take the full load amps and multiply by 30%. Then take that figure and multiply times the 90% rating figure being used to avoid overcorrection and overvoltages. EXAMPLE: Size a capacitor for a 75hp, 460V 3-phase motor which has a full load current of 92 amps and an unknown no-load current. 1. First, find the no-load current by multiplying the full load current times 30%. 92 (full load amps) X 30% = 28 estimated no-load amps 2. Multiply 28 no-load amps by 90%. 28 no-load amps X 90% = 25 no-load amps 3. Now examine the capacitor pricing and selection chart for 480 volt, 3-phase capacitors. Refer again to Table 1. Here it will be seen that the closest capacitor to 25 amps full load current without going over is a 20 kvar unit, rated at 24.1 amps. 4. The correct selection, then, is 20 kvar!
If no-load current is known . . . The most accurate method of selecting a capacitor is to take the noload current of the motor, and multiply by .90 (90%). Take this resulting figure, turn to the appropriate catalog page, and determine which kvar size is needed, catalog number, enclosure type, and price. EXAMPLE: Size a capacitor for a 100hp, 460V 3-phase motor which has a full load current of 124 amps and a no-load current of 37 amps. 1. Multiply the no-load current figure of 37 amps by 90%. 37 no load amps X 90% = 33 no load amps 2. Turning to the catalog page for 480 volt, 3-phase capacitors, find the closest amp rating to, but NOT OVER 33 amps. See Table 1, sample catalog pricing chart. Per the sample chart the closest amperage is 32.5 amps. The proper capacitor unit, then is 27 kvar and the appropriate catalog number depends on the type enclosure desired. NOTE The formula method corrects power factor to approximately .95
Enclosure
Size
1.8 2.4 3.0 3.6 4.8 21.0 27.1 21.7 22.8 24.1 25.3 26.5 27.1 28.9
8 8 8 8 8 13 13 13 13 13 13 13 13 13
C484G1.5 C484G2 C484G2.58 C444G3 C484D3.5 C484G17.5 C484G18 C484G19 C484G20 C484G21 C484G22 C484G22.5 C484G24 C484G25
C484R1.5 C484R2 C484R2.5 C484R2 C484R3.5 C484R17.5 C484R18 C484R19 C484R20 C484R21 C484R22 C484R22.5 332 337
C484D1.5 C484D2 C484D2.5 C484D3 C444D3.5 C484D17 C484D18 C484D19 C484D20 C484D21 C484D22 C484D22 C484D35 C484R24 C484R25
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1SXU000023C0202
14 14 14 14 12 12 12 11 12 12 12 12 11 10 10 10 11 11 12 10 8 8
23 22 20 18 18 17 17 16 15 15 14 14 14 12 12 11 10 10 8 8 8 9
28 26 21 21 20 19 19 19 19 19 17 15 12 12 12 10 10 12 12 12 10 12
38 31 28 27 24 23 23 22 21 21 20 17 16 14 14 13 13 14 13 13 12 12
40 40 38 36 32 25 25 24 24 24 22 14 15 15 14 13 13 13 13 13 14 13
40 40 45 38 34 30 30 30 30 30 28 19 17 17 17 17 17 17 15 15 15 15
Applies to three-phase, 60Hz motors when switched with capacitors as a single unit.
Another method of selecting the proper capacitor employs the use of only a selection chart shown in Table 2 or 3. These tables take other variables such as motor RPM into consideration in making recommendations for capacitor applications. They are convenient because they only require that the user know the horsepower and RPM of the motor. Both tables estimate the percentage reduction in full load current drawn by the motor as a result of the capacitors installation.
TABLE 3: Suggested Maximum Capacitor Ratings for U-Frame NEMA Class B Motors
NEMA Motor Design A or B Normal Starting Torque Normal Running Current
H.P. Rating 3600 RPM kvar %AR 1800 RPM kvar %AR 1200 RPM 900 RPM 720 RPM 600 RPM kvar %AR kvar %AR kvar %AR kvar %AR
WARNING!
NEVER OVERSIZE CAPACITORS OR EXCEED 1.0 POWER FACTOR OR RESULTING PROBLEMS WITH THE MOTOR CAN OCCUR!! If calculations or a kvar determination chart indicate a kvar rating not found in a pricing and selection chart, always refer to the next lower kvar rating! EXAMPLE: A manufacturer needs to determine the proper capacitors required for a 1200 RPM, 75HP T-Frame NEMA class B motor. 1. First find 75 in the horsepower column of the chart. 2. Locate the 1200 RPM capacitor rating (kvar) column. Note the figure of 25 kvar. 3. Now refer to the appropriate pricing and selection chart Table 1, page 6.11. The appropriate kvar rating is 25 kvar. Depending on the desired enclosure, the price and catalog number can then be easily determined.
21
NOTE Using the above charts for selecting capacitors will correct power to approximately .95.
21.52
1SXU000023C0202
14 12 11 10 9 9 6 5 8 7 6 7 8 6 6 6 5 5
1.5 2 2.5 3 4 5 5 5 10 10 10 15 20 25 30 40 45 50
15 13 13 11 10 10 8 8 8 8 8 8 8 7 7 7 6 6
20 17 15 14 13 11 11 11 10 9 10 9 9 9 9 8 9 9
27 25 22 21 18 18 13 15 16 12 11 11 11 10 10 11 10 9
35 32 30 27 23 20 20 22 18 15 15 15 14 14 17 12 12 12
41 37 34 31 27 25 21 25 20 22 20 20 18 17 17 17 17 17
Applies to three-phase, 60Hz motors when switched with capacitors as a single unit.
80
0.982 .937 .893 .850 .809 .769 .730 .692 .655 .618 .584 .549 .515 .483 .450 .419 .368 .358 .329 .299 .270 .242 .213 .186 .159 .132 .105 .079 .053 .026 .000 -
81
1.008 .962 .919 .876 .835 .795 .756 .718 .681 .644 .610 .575 .541 .509 .476 .445 .414 .384 .355 .325 .296 .268 .239 .212 .185 .158 .131 .105 .079 .052 .026 .000 -
82
1.034 .989 .945 .902 .861 .821 .782 .744 .707 .670 .636 .601 .567 .535 .502 .471 .440 .410 .381 .351 .322 .294 .265 .238 .211 .184 .157 .131 .105 .078 .052 .026 .000 -
83
1.060 1.015 .971 .928 .887 .847 .808 .770 .733 .696 .662 .627 .593 .561 .528 .497 .466 .436 .407 .377 .348 .320 .291 .264 .237 .210 .183 .157 .131 .104 .078 .052 .026 .000 -
84
1.086 1.041 .997 .954 .913 .873 .834 .796 .759 .722 .688 .653 .619 .587 .554 .523 .492 .462 .433 .403 .374 .346 .317 .290 .263 .236 .209 .183 .157 .130 .104 .078 .052 .026 .000 -
85
1.112 1.067 1.023 .980 .939 .899 .860 .822 .785 .748 .714 .679 .645 .613 .580 .549 .518 .488 .459 .429 .400 .372 .343 .316 .289 .262 .235 .209 .183 .156 .130 .104 .078 .052 .026 .000 -
86
1.139 1.094 1.050 1.007 .966 .926 .887 .849 .812 .775 .741 .706 .672 .640 .607 .576 .545 .515 .486 .456 .427 .399 .370 .343 .316 .289 .262 .236 .210 .183 .157 .131 .105 .079 .053 .027 .000 -
87
1.120 1.076 1.033 .992 .952 .913 .875 .838 .801 .767 .732 .698 .666 .633 .602 .571 .541 .512 .482 .453 .425 .396 .369 .342 .315 .288 .262 .236 .209 .183 .157 .131 .105 .079 .053 .026 .000 -
88
1.147 1.103 1.060 1.019 .979 .940 .902 .865 .828 .794 .759 .725 .693 .660 .629 .598 .568 .539 .509 .480 .452 .423 .396 .369 .342 .315 .289 .263 .236 .210 .184 .158 .132 .106 .080 .053 .027 .000 -
89
1.220 1.175 1.131 1.088 1.047 1.007 .968 .930 .893 .856 .822 .787 .753 .721 .688 .657 .626 .596 .567 .537 .508 .480 .451 .424 .397 .370 .343 .317 .291 .264 .238 .212 .186 .160 .134 .108 .081 .055 .028 .000 -
90
1.248 1.203 1.159 1.116 1.075 1.035 .996 .958 .921 .884 .850 .815 .781 .749 .716 .685 .654 .624 .595 .565 .536 .508 .479 .452 .425 .398 .371 .345 .319 .292 .266 .240 .214 .188 .162 .136 .109 .082 .056 .028 .000 -
91
1.276 1.231 1.187 1.144 1.103 1.063 1.024 .986 .949 .912 .878 .843 .809 .777 .744 .713 .682 .652 .623 .593 .564 .536 .507 .480 .453 .426 .399 .373 .347 .320 .294 .268 .242 .216 .190 .164 .137 .111 .084 .056 .028 .000 -
92
1.306 1.261 1.217 1.174 1.133 1.090 1.051 1.013 .976 .939 .907 .870 .836 .804 .771 .740 .709 .679 .650 .620 .591 .563 .538 .507 .480 .453 .426 .400 .374 .347 .321 .295 .269 .243 .217 .191 .167 .141 .114 .086 .058 .030 .000 -
93
1.337 1.292 1.248 1.205 1.164 1.124 1.085 1.047 1.010 .973 .939 .907 .870 .838 .805 .774 .743 .713 .684 .654 .625 .597 .568 .541 .514 .487 .460 .434 .408 .381 .355 .329 .303 .277 .251 .225 .198 .172 .145 .117 .089 .061 .031 .000 -
94
1.369 1.324 1.280 1.237 1.196 1.156 1.117 1.079 1.042 1.005 .971 .936 .902 .870 .837 .806 .775 .745 .716 .686 .657 .629 .600 .573 .546 .519 .492 .466 .440 .413 .387 .361 .335 .309 .283 .257 .230 .204 .177 .149 .121 .093 .063 .032 .000 -
95
1.403 1.358 1.314 1.271 1.230 1.190 1.151 1.113 1.076 1.039 1.005 .970 .936 .904 .871 .840 .809 .779 .750 .720 .691 .663 .634 .607 .580 .553 .526 .500 .474 .447 .421 .395 .369 .343 .317 .291 .265 .238 .211 .183 .155 .127 .097 .066 .034 .000 -
96
1.442 1.395 1.351 1.308 1.267 1.228 1.189 1.151 1.114 1.077 1.043 1.008 .974 .942 .909 .878 .847 .817 .788 .758 .729 .701 .672 .645 .616 .591 .564 .538 .512 .485 .459 .433 .407 .381 .355 .329 .301 .275 .248 .220 .192 .164 .134 .103 .071 .037 .000 -
97
1.481 1.436 1.392 1.349 1.308 1.268 1.229 1.191 1.154 1.117 1.083 1.048 1.014 .982 .949 .918 .887 .857 .828 .798 .769 .741 .712 .685 .658 .631 .604 .578 .552 .525 .499 .473 .447 .421 .395 .369 .343 .317 .290 .262 .234 .206 .176 .145 .113 .079 .042 .000 -
98
1.529 1.484 1.440 1.397 1.356 1.316 1.277 1.239 1.202 1.165 1.131 1.096 1.062 1.030 .997 .966 .935 .905 .876 .840 .811 .783 .754 .727 .700 .673 .652 .620 .594 .567 .541 .515 .489 .463 .437 .417 .390 .364 .337 .309 .281 .253 .223 .192 .160 .126 .089 .047 .000 -
99
1.590 1.544 1.500 1.457 1.416 1.377 1.338 1.300 1.263 1.226 1.192 1.157 1.123 1.091 1.058 1.027 .996 .966 .937 .907 .878 .850 .821 .794 .767 .740 .713 .687 .661 .634 .608 .582 .556 .530 .504 .478 .451 .425 .398 .370 .342 .314 .284 .253 .221 .87 .150 .108 .061 .000
100
1.732 1.687 1.643 1.600 1.669 1.519 1.480 1.442 1.405 1.368 1.334 1.299 1.265 1.233 1.200 1.169 1.138 1.108 1.079 1.049 1.020 .992 .963 .936 .909 .882 .855 .829 .803 .776 .750 .724 .698 .672 .645 .620 .593 .567 .540 .512 .484 .456 .426 .395 .363 .328 .292 .251 .203 .142
1.165 1.192
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How is the Power Factor Correction Chart Used if Existing Power Factor Level is Unknown?
1. First, power factor has to be calculated. Power factor is equal to active power (kW) divided by apparent power (kVA). kW will be known because it is the total amount of power consumed over a given period of time and is the amount shown on a utility bill. Therefore: pf = kW / kVA 2. Using the above example, 500kW divided by 670kVA equals a present power factor (pf) of .746. 500kW / 670kVA = .746 pf 3. When DETERMINING power factor, always round off to the next higher rating. Therefore, the .746 power factor figure is rounded off to .75. NOTE: Dont confuse rounding UP a power factor figure that is manually calculated with the warning on page 46 that tells you to round DOWN when using a catalog selection chart! 4. Now that present power factor is known, the above problem can be solved as before. FINAL EXAMPLE: A manufacturer has a 480 volt, 3-phase metered demand of 460kW. An ammeter on the system shows total current draw of 770 amps. Existing power factor and apparent power (kVA) are unknown. What is the existing system power factor and how much capacitance is required to correct to .92? 1. First, solve for kVA. 480 VOLTS x 770 AMPS x 3 1000 = 640kVA 2. Next, solve for Power Factor. 460kW / 640kVA = .72 POWER FACTOR 3. To correct the power factor from .72 to .92 refer to the Power Factor
Correction Chart on page 47. A factor of .534 will be determined. 4. The final step is to multiply the 460kW figure by the correction factor of .534. 460kW X .534 = 245 kvar This system would require the installation of 245 kvar of capacitance to improve the power factor to .92. Refer to the appropriate automatic or fixed bank catalog pages, select the proper voltage and phase, then identify the proper catalog number.
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21.54
1SXU000023C0202
240 Volt
2.5 3.5 5 7.5 10 15 20 25 30 40 50 60 75 100 125 150 200 250 300 1.5 2 2.5 3 3.5 4 5 6 6.5 7.5 10 15 20 25 30 35 40 45 50 60 70 75 80 90 100 150 200 250 300 350 400 500
6 8.4 12 18 24 36 48 60 72 96 120 144 180 241 301 361 481 601 722 1.8 1.8 3 3.6 4.2 4.8 6 7.2 7.8 9 12 18 24 30 36 42 48 54 60 72 84 90 96 108 120 180 241 301 361 421 481 601
#14 #14 #14 #12 #10 #6 #4 #4 #2 #1 1/0 2/0 250 kcmil 400 kcmil (2) - 4/0 (2) - 250 kcmil (2) - 400 kcmil (3) - 300 kcmil (3) - 400 kcmil #14 #14 #14 #14 #14 #14 #14 #14 #14 #14 #14 #12 #10 #8 #6 #6 #4 #4 #4 #2 #1 #1 #1 1/0 2/0 250 kcmil 400 kcmil (2) - 4/0 (2) - 250 kcmil (2) - 300 kcmil (2) - 400 kcmil (3) - 300 kcmil
10 15 20 30 40 60 80 100 125 175 200 250 300 400 500 600 800 1000 1200 3 3 6 6 10 10 10 15 15 15 20 30 40 50 60 70 80 90 100 125 150 150 175 200 200 300 400 500 600 700 800 1000
30 30 30 30 60 60 100 100 200 200 200 400 400 400 600 600 800 1000 1200 30 30 30 30 30 30 30 30 30 30 30 30 60 60 60 100 100 100 100 200 200 200 200 200 200 400 400 600 600 800 800 1000
15 15 20 30 40 60 80 90 110 150 200 225 300 400 500 600 750 900 1100 15 15 15 15 15 15 15 15 15 15 20 30 40 50 60 70 80 90 90 110 150 150 150 175 200 300 400 500 600 650 750 902
480 Volt
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21.55
1SXU000023C0202
600 Volt
#14 #14 #14 #14 #14 #14 #14 #10 #10 #8 #8 #6 #6 #4 #4 #2 #2 #1 #0 3/0 300 kcmil 400 kcmil (2) - 3/0 (2) - 4/0 (2) - 300 kcmil (2) - 400 kcmil
3 6 6 10 15 20 25 35 40 50 60 70 80 80 100 125 150 150 175 250 350 400 500 600 650 800
30 30 30 30 30 30 30 60 60 60 60 100 100 100 100 200 200 200 200 400 400 400 600 600 800 800
15 15 15 15 15 15 25 30 40 50 60 60 70 80 90 110 125 150 150 225 300 400 450 550 600 750
NOTE: Cable sizes are derived from Article 310, Table 310-16 of 2002 NEC The above table gives recommended ratings of cables, disconnect switches, and/or molded case circuit breakers for use with capacitor loads. For requirements not covered in the table, the following application guidelines may be used for capacitor switching duty: Power Cable Sizing Disconnect Switch Molded Case Circuit Breaker 135% of Capacitor Current 165% of Capacitor Current 135% of Capacitor Current
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NOTE: National Electric Code and NEC are registered trademarks of the National Fire Protection Association, Inc., Quincy, MA 02269
21.56
1SXU000023C0202
Main Feed
Fused Safety Switch or Breaker
PFCC
D Overload Relay
T1
Motor Feed
Fused Safety Switch or Breaker
Contactor
L1 L2 L3
MOTOR
T2 T3
PFCC
PFCC
PFCC
C
Fig. 12
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21.57
1SXU000023C0202
Notes
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21.58
1SXU000023C0202