1. Introduction
The notion of a Hom-Lie algebra was introduced by Hartwig, Larsson, and Silvestrov in [
1] as part of a study of deformations of the Witt and the Virasoro algebras. In a Hom-Lie algebra, the Jacobi identity is twisted by a linear map, called the Hom-Jacobi identity. The set of
-derivations of an associative algebra and some
q-deformations of the Witt and the Virasoro algebras have the structure of a Hom-Lie algebra [
1,
2,
3]. Because of the close relation to discrete and deformed vector fields and differential calculus [
1,
4,
5], more people have started paying attention to this algebraic structure. In particular, representations and deformations of Hom-Lie algebras are studied in [
6,
7,
8]; extensions of Hom-Lie algebras are studied in [
4,
9,
10]. Some split regular Hom-structures are studied in [
11,
12].
The notion of a Hom-Lie 2-algebra, which is the categorification of a Hom-Lie algebra, is given in [
13]. The category of Hom-Lie 2-algebras and the category of 2-term
-algebras are equivalent. Skeletal Hom-Lie 2-algebras can be classified by the third cohomology group of a Hom-Lie algebra. Many known Hom-structures, such as Hom-pre-Lie algebras and symplectic Hom-Lie algebras, lead to skeletal or strict Hom-Lie 2-algebras. In [
14], we give the notion of a derivation of a regular Hom-Lie algebra
. The set of derivations
is a Hom-Lie subalgebra of the regular Hom-Lie algebra
, which is given in [
15]. We constructed the derivation Hom-Lie 2-algebra
, by which we characterize non-abelian extensions of regular Hom-Lie algebras as Hom-Lie 2-algebra morphisms. More precisely, we characterize a diagonal non-abelian extension of a regular Hom-Lie algebra
by a regular Hom-Lie algebra
using a Hom-Lie 2-algebra morphism from
to the derivation Hom-Lie 2-algebra
. Associated to a non-abelian extension of a regular Hom-Lie algebra
by a regular Hom-Lie algebra
, there is a Hom-Lie algebra morphism from
to
naturally. However, given an arbitrary Hom-Lie algebra morphism from
to
, whether there is a non-abelian extension of
by
that induces the given Hom-Lie algebra morphism and what the obstruction is are not known yet.
The aim of this paper is to solve the above problem. It turns out that the result is not totally parallel to the case of Lie algebras [
16,
17,
18,
19,
20,
21]. We need to add some conditions on the short exact sequence related to derivations of Hom-Lie algebras. Under these conditions, first we show that under the assumption of the center of
being zero, there is a one-to-one correspondence between diagonal non-abelian extensions of
by
and Hom-Lie algebra morphisms from
to
. Then for the general case, we show that the obstruction of the existence of a non-abelian extension is given by an element in the third cohomology group.
The paper is organized as follows. In
Section 2, we recall some basic notions of Hom-Lie algebras, representations of Hom-Lie algebras, their cohomologies and derivations of Hom-Lie algebras. In
Section 3, we study non-abelian extensions of
by
in the case that the center of
is zero. We show that if the center of
is zero and the short exact sequence related to derivations of Hom-Lie algebras is also diagonal, then diagonal non-abelian extensions of
by
correspond bijectively to Hom-Lie algebra morphisms from
to
(Theorem 2). In
Section 4, we give a cohomology characterization of the existence of general non-abelian extensions of
by
. We show that the obstruction of the existence of a diagonal non-abelian extension of
by
that induces a given Hom-Lie algebra morphism from
to
is given by a cohomology class in
(Theorem 3). Moreover, isomorphism classes of diagonal non-abelian extensions of
by
are parameterized by
(Theorem 4). In
Section 5, we give a conclusion of the paper.
2. Preliminaries
In this paper, we work over an algebraically closed field of characteristic 0, and all the vector spaces are over . We only work on finite-dimensional vector spaces.
2.1. Representations, Cohomologies and Derivations of Hom-Lie Algebras
Definition 1. - (i)
A (multiplicative) Hom-Lie algebra is a triple consisting of a vector space , a skew-symmetric bilinear map (bracket) and a linear map preserving the bracket, such that the following Hom-Jacobi identity with respect to is satisfied: - (ii)
A Hom-Lie algebra is called a regular Hom-Lie algebra if is an algebra automorphism.
- (iii)
The center of a regular Hom-Lie algebra is defined by
Remark 1. The center of a Hom-Lie algebra (not necessarily regular) is usually defined by Equation (
2)
; see [9] (Definition 2.13). However, for , may not be in . This is a conflict with the definition of a subalgebra of a Hom-Lie algebra, for which one requires that the subspace is closed with respect to both and . We note that for a regular Hom-Lie algebra, if is such that for all , then also satisfies this property. This follows fromThus, we suggest that for a general Hom-Lie algebra, one should define its center by In the sequel, we always assume that is an algebra automorphism. That is, in this paper, all the Hom-Lie algebras are assumed to be regular Hom-Lie algebras despite that some results also hold for general Hom-Lie algebras.
Example 1. Let V be a vector space and . Define a skew-symmetric bilinear bracket operation by Denote by the adjoint action on , that is, Then is a regular Hom-Lie algebra. See [15] for more details. Definition 2. A morphism of Hom-Lie algebras is a linear map such that Definition 3. A representation of a Hom-Lie algebra on a vector space V with respect to is a linear map such that for all , the following equalities are satisfied: We denote a representation by .
Theorem 1 ([
15], (Theorem 4.2)).
Let be a Hom-Lie algebra, V be a vector space, and . Then is a representation of on V with respect to β if and only if is a morphism of Hom-Lie algebras. For all
, we define
by
Then is a representation of the Hom-Lie algebra on with respect to , which is called the adjoint representation.
Let
be a representation. We define the set of
k-Hom-cochains by
For
, we define the coboundary operator
by
where
is proved in [
8]. Denote by
and
the sets of
k-cocycles and
k-coboundaries, respectively. We define the
kth cohomology group
to be
. See also [
6] for more details about such cochain and coboundary setups.
Definition 4 ([
14], (Definition 3.1)).
A linear map is called a derivation of a Hom-Lie algebra if Denote by the set of derivations of the Hom-Lie algebra . Then we obtain that is a Hom-Lie algebra, which is a subalgebra of the Hom-Lie algebra .
Remark 2. The above definition of a derivation of a Hom-Lie algebra is more general than that given in [8]. Under the condition , the above definition is the same as the α-derivation given in [8]. See Remark 3.2 in [14] for more details. For all
,
is a derivation of the Hom-Lie algebra
, which we call an
inner derivation. See [
14] for more details. Denote by
the set of inner derivations of the Hom-Lie algebra
, that is,
Lemma 1 ([
14], (Lemma 3.6)).
Let be a Hom-Lie algebra. For all and , we haveTherefore, is an ideal of the Hom-Lie algebra . Denote by
the set of out derivations of the Hom-Lie algebra
, that is,
We use to denote the quotient map from to .
2.2. Non-Abelian Extensions of Hom-Lie Algebras
Definition 5. A non-abelian extension of a Hom-Lie algebra by a Hom-Lie algebra is a commutative diagram with rows being short exact sequences of Hom-Lie algebra morphisms:where is a Hom-Lie algebra. We can regard as a subspace of and . Thus, is an invariant subspace of . We say that an extension is diagonal if has an invariant subspace X of such that . In general, does not always have an invariant subspace X of such that . For example, the matrix representation of is a Jordan block. We only study diagonal non-abelian extensions in the sequel.
Definition 6. Two extensions of by , and are said to be isomorphic if there exists a Hom-Lie algebra morphism such that we have the following commutative diagram: Lemma 2 ([
14], (Lemma 4.4)).
A Hom-Lie algebra is a diagonal non-abelian extension of a Hom-Lie algebra by a Hom-Lie algebra if and only if there is a section such that and . This section is called diagonal.
Let
be a diagonal extension of a Hom-Lie algebra
by a Hom-Lie algebra
and
be a diagonal section. Define linear maps
and
respectively by
Clearly,
is isomorphic to
as vector spaces. Transferring the Hom-Lie algebra structure on
to that on
, we obtain a Hom-Lie algebra
, where
and
are given by
The following proposition gives the conditions on and such that is a Hom-Lie algebra.
Proposition 1 ([
14], (Proposition 4.5)).
With the above notations, is a Hom-Lie algebra if and only if ρ and ω satisfy the following equalities:where c.p. is the cyclic permutation of . For any diagonal non-abelian extension, by choosing a diagonal section, it is isomorphic to . Therefore, we only consider diagonal non-abelian extensions of the form in the sequel.
Proposition 2 ([
14], (Theorem 4.9)).
Let and be two diagonal non-abelian extensions of by . The two extensions are equivalent if and only if there is a linear map such that 3. Classification of Diagonal Non-Abelian Extensions of Hom-Lie Algebras: Special Case
In this section, we classify diagonal non-abelian extensions of Hom-Lie algebras for the case that
Theorem 2. Let and be Hom-Lie algebras such that . If the following short exact sequence of Hom-Lie algebra morphisms:is a diagonal non-abelian extension of by , then isomorphism classes of diagonal non-abelian extensions of by correspond bijectively to Hom-Lie algebra homomorphisms: Proof. Let
be a diagonal non-abelian extension of
by
given by Equations (15) and (16). By Equation (18), we have
. Let
be the quotient map. We denote the induced Hom-Lie algebra structure on
by
and
. Hence we can define
By Equation (
17), for all
, we have
By Equation (20), we have
Thus, is a Hom-Lie algebra homomorphism from to .
Let
and
be isomorphic diagonal non-abelian extensions of
by
. By Proposition 2, we have
Thus, we obtain that isomorphic diagonal non-abelian extensions of by correspond to the same Hom-Lie algebra homomorphism from to .
Conversely, let
be a Hom-Lie algebra homomorphism from
to
. Because the short exact sequence of Hom-Lie algebras (Equation (
25)) is a diagonal non-abelian extension of
by
, we can choose a diagonal section
s of
. Moreover, we define
by
We have
. Thus we obtain Equation (18). Because
s is a diagonal section, we have
Thus, we obtain Equation (
17). Because
and
are Hom-Lie algebra homomorphisms, for all
, we have
which implies that
. Because we have the following short exact sequence of Hom-Lie algebra morphisms:
and
, there exists a unique linear map
such that
Furthermore, we claim that
In fact, for all
, we have
which implies that
because
Thus, we obtain Equations (19) and (20). For all
, by
and Equations (
27) and (
28), we have
Because , we have Equation (21). Therefore, we deduce that Equations (17)–(21) hold. By Proposition 1, is a diagonal non-abelian extension of by .
If we choose another section
of
, we obtain another diagonal non-abelian extension
. Clearly, we have
which implies that
. Because
, there is a unique linear map
such that
In fact, for all
, we have
which implies that
because
. Thus, we obtain Equations (22) and (23). By Lemma 1 and Equation (
28), for all
we have
By , we obtain Equation (24). Thus, we have Equations (22)–(24). Therefore, we deduce that and are isomorphic diagonal non-abelian extensions of by . The proof is finished. ☐
4. Obstruction of Existence of Diagonal Non-Abelian Extensions of Hom-Lie Algebras
In this section, we always assume that the following short exact sequences of Hom-Lie algebra morphisms:
are diagonal non-abelian extensions. Given a Hom-Lie algebra morphism
, where
, we consider the obstruction of existence of non-abelian extensions. By choosing a diagonal section
s of
, we can still define
by Equation (
26) such that Equation (
27) holds. Moreover, we can choose a linear map
such that Equations (
28) and (
29) hold. Thus,
is a diagonal non-abelian extension of
by
if and only if
Let
be the formal coboundary operator associated to
. Then we have
Therefore, is a diagonal non-abelian extension of by if and only if
Definition 7. Let be a Hom-Lie algebra morphism. We call an extensible homomorphism if there exists a diagonal section s of and linear map such that Equations (
27), (
28)
and (
33)
hold. For all
, it is clear that
. For
, we have
Thus, we have
. Therefore, we can define
by
By Equations (
27) and (
28), we obtain that
is a Hom-Lie morphism from
to
. By Theorem 1,
is a representation of
on
with respect to
. By Equation (
31), we deduce that different diagonal sections of
give the same representation of
on
with respect to
. In the sequel, we always assume that
is a representation of
on
with respect to
, which is induced by
. By Equation (
30), we have
. Thus, we have
. Moreover, we have the following lemma.
Lemma 3. is a 3-cocycle on with the coefficient in , and the cohomology class does not depend on the choices of the diagonal section s of and ω that we make.
Proof. For all
, by straightforward computations, we have
By the definition of
, we have 60 terms in the right-hand side of the above formula. Fortunately, we can cancel the following terms:
By Equations (
27)–(
29), the above formula reduces to the following:
Because
and
is an algebra morphism, this is rewritten as follows:
Thus, we obtain .
Now we check that the cohomology class
does not depend on the choices of the diagonal section
s of
and
that we make. Let
be another diagonal section of
; we have
and choose
such that Equations (
27) and (
28) hold. We prove that
. Because
s and
are diagonal sections of
, we have a linear map
such that
By straightforward computations, we obtain that Equations (
28) and (
29) hold for
. For all
, we have
where
By Equations (
27) and (
28), we have
. Because
is a derivation, we obtain
. Because
and
are Hom-Lie algebras, we obtain
. Thus, we have
. Because Equations (
28) and (
29) hold for
and
, respectively, we have
Thus, we have
. Moreover, we have
. By Equation (
29), we can define
by
Therefore, we obtain . The proof is finished. ☐
Now we are ready to give the main result in this paper, namely, that the obstruction of a Hom-Lie algebra homomorphism being extensible is given by the cohomology class .
Theorem 3. Let be a Hom-Lie algebra morphism. Then is an extensible homomorphism if and only if Proof. Let
be an extensible Hom-Lie algebra morphism. Then we can choose a diagonal section
s of
and define
by Equation (
26). Moreover, we can choose a linear map
such that Equations (
27) and (
28) hold. Because
is extensible, we have
, which implies that
.
Conversely, if
, then there exists
such that
Thus, we have
Because
, we also have
By Proposition 1, we can construct a Hom-Lie algebra . Therefore, is an extensible morphism. The proof is finished. ☐
The following theorem classifies diagonal non-abelian extensions of by once they exist.
Theorem 4. Let be an extensible morphism. Then isomorphism classes of diagonal non-abelian extensions of by induced by are parameterized by .
Proof. Because
is an extensible morphism, we can choose a diagonal section
s of
and define
by Equation (
26). We choose a linear map
such that Equations (
27) and (
28) hold and
. Thus, the Hom-Lie algebra
defined by Equations (15) and (16) is a diagonal non-abelian extension of
by
, which is induced by
. Let
be another diagonal section of
and define
by Equation (
26). We also choose a linear map
such that Equations (
27) and (
28) hold and
. Because
s and
are diagonal sections of
, there exists a linear map
such that
By the computation in Lemma 3, we have
. Thus, the Hom-Lie algebra
constructed from
is isomorphic to the Hom-Lie algebra
constructed from
. Thus, we only need to study the Hom-Lie algebras constructed from a fixed diagonal section
s. For all
, which satisfy Equations (
28) and (
29) and
, we define
Moreover, we have
which implies that
.
Moreover, let us assume that the Hom-Lie algebra
constructed from
is isomorphic to the Hom-Lie algebra
constructed from
. Then there exists a linear map
that does not change
, that is,
, such that
This is equivalent to Thus, isomorphism classes of diagonal non-abelian extensions of by induced by are parameterized by . ☐
Corollary 1. The isomorphism classes of diagonal non-abelian extensions of a Hom-Lie algebra by a Hom-Lie algebra correspond bijectively to the set of pairs , where is an extensible morphism from to and .
5. Conclusions
In this paper, we use a cohomological approach to study diagonal non-abelian extensions of regular Hom-Lie algebras. First, for the case that , we classify diagonal non-abelian extensions of a regular Hom-Lie algebra by a regular Hom-Lie algebra by Hom-Lie algebra morphisms from to the outer derivation of the Hom-Lie algebra . More precisely, we show that under the condition , isomorphism classes of diagonal non-abelian extensions of a regular Hom-Lie algebra by a regular Hom-Lie algebra one-to-one correspond to Hom-Lie algebra morphisms from to . Then for the general case, isomorphic diagonal non-abelian extensions of a regular Hom-Lie algebra by give rise to the same morphism from to . However, given a morphism from to , there is an obstruction for the existence of a diagonal non-abelian extension of regular Hom-Lie algebras that induces the given morphism. We show that the obstruction is given by a cohomological class in the third cohomology group. More precisely, if the cohomological class is trivial, then there is a diagonal non-abelian extension of regular Hom-Lie algebras inducing the given morphism. In this case, we say that the given morphism is extensible. In particular, if the third cohomology group is trivial, then every Hom-Lie algebra morphism from to is extensible. Moreover, we show that isomorphism classes of diagonal non-abelian extensions of by inducing the given morphism are parameterized by the second cohomology group.