JPH09167642A - Electric cable joining device by explosion of explosive compound - Google Patents

Abstract

PROBLEM TO BE SOLVED: To reduce an explosion sound, to prevent an explosion gas and scattered objects from inflicting on persons and installations standing in the vicinity, and to execute work safely even in an urban district, on a steel tower, or in an underground disposed passage, when power transmission cables, power distribution cables, or the like are joined together by means of the explosion of an explosive compound. SOLUTION: This is a small sized and light weight device to be used in the event that electric cables 3 are joined together by exploding an explosive compound 1, wherein the explosive compound 1 and a joint part of the electric wires 3 are housed therein a quasi-sealed state and its strength is established according to the kind and quantity of the explosive compound 1 to be used, and a high pressure gas and an explosion sound produced by an explosion are exhausted and propagated, through passages through which the wires 3 are led out from a container to the exterior, as the pressure being reduced and the sound being eliminated, and therefore no danger exists in the proximity, the sound being sufficiently reduced, and explosion-involving work, which was heretofore extremely difficult to be executed in an urban district, on a steel tower for laying electric cables, or in an underground disposed passage, can be executed safely and easily without producing noise pollution.

Description

Detailed Description of the Invention

[0001]

BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to the so-called explosive pressure welding of electric wires, in which the ends of two electric wires are joined by utilizing the explosive pressure of explosives therein, and more broadly, the explosive processing of metals and ceramics. In order to ensure safety and avoid noise pollution, work that could only be done in remote remote areas of the mountains, safely, and with extremely low explosion noise, can be performed in urban areas. Of equipment.

[0002]

2. Description of the Related Art Conventionally, for carrying out explosive pressure welding and explosive processing (hereinafter, explosive pressure welding, etc.), materials for explosive pressure welding and explosives are placed on the ground, or "development silencer", "pressure technology" It is usually carried out in a large stationary explosion-muffling device as described on page 37, March 1988. By transporting the device to an arbitrary point and using it, the safety of work can be improved. I was not able to receive the convenience of avoiding pollution caused by noise.

[0003]

SUMMARY OF THE INVENTION In order to avoid expansion of high-pressure gas caused by explosion of explosives, generation of scattered matter, loud noise, etc., mainly an explosion chamber made of steel, an explosion silencer or an explosion container, etc. It has been performed to explode explosives in a device, which is called a device (hereinafter referred to as a device), which is shielded from the surroundings in a sealed or semi-sealed state. Here, the state referred to as a closed state is a state in which the gas and the like in the device is blocked from the surroundings by the device, and is almost closed from the semi-closed state, but a passage through which a specific slight amount of gas can pass is set. State. According to the conventional technology, the wall of the device is made sturdy in order to solve the problem that the explosive explosive exerts extremely large stress on the device, sometimes projects high-speed solid debris to the surroundings, and produces a loud sound. , And as far as possible from the explosion source,
It was inevitable that it would become large. Therefore, it has been difficult to carry the device to a place where an electric wire erection work is required to connect the electric wires and enjoy the convenience. In order to solve this problem and control a variety of phenomena associated with the above explosion while being lightweight and small in size, and developing a portable and safe device, there are the following problems.

1) In order to suppress the loud sound caused by the explosion, the explosive sound can be suppressed almost completely by enclosing the explosive in a strong metal container to explode it, and only a faint sound is emitted outside. Although not transmitted, if such an airtight container is used, the explosive gas generated by the explosion will be trapped inside the container, and when the container is opened, it will suddenly open due to the internal pressure and the gas will blow out, which may be dangerous to the operator. In addition, it is difficult to introduce a part of a wire having fine irregularities on its surface like an electric wire and to seal it.

2) When joining electric wires, it is necessary to connect long electric wires to each other. Therefore, it is necessary to carry out the work with both ends of the electric wires protruding from the container, and to divide the container after taking out the work. In such a case, a portion connecting the divided containers serves as a singular point, so that it is necessary to have sufficient strength, which causes a weight increase. That is, conventionally, in a device for joining electric wires by explosive explosion,
As a means for connecting the divided devices, most of them are connected by bolting so that the tensile strength of the bolt and the strength of the flange to which the bolt is attached can withstand the explosion impact and the pressure of the explosion gas. By taking such measures, it is possible to obtain a device that can withstand explosive shock and the pressure of explosive gas if the consideration for stress is appropriate, but the bolts and flanges for withstanding the great stress are the factors that increase the weight. Also, the trouble of tightening and loosening the bolt every time the work hinders the work efficiency.

[0006]

[Means for Solving the Problems] It is considered that the above problems can be solved by taking the following measures. Each number corresponds to the above-mentioned problem number. 1) With the container in a semi-sealed state, the only obvious open part is the gap intentionally provided in the part where the electric wire protrudes from the container, and the ratio of the area of the gap to the electric wire is a certain value or less to make the semi-sealed state. By utilizing the fact that the surface of the wire is uneven, when explosive gas is automatically ejected from the device by the internal pressure along the surface of the wire, it passes through a passage that is narrowed and has flow resistance. It was found that the harm caused by the ejected gas can be sufficiently reduced and loud noise can be avoided.

2) Abolishing the connection method using bolts and flanges, which has been widely used in the past, when the containers are combined, the connection parts of the containers enter into each other, and the connection parts are engaged and separated by rotating on top of each other. By adopting a so-called bayonet type coupling structure that cannot be used, it is possible to obtain a lightweight device having a simple structure while having sufficient strength.

[0008]

BEST MODE FOR CARRYING OUT THE INVENTION The present invention will be described below with reference to the drawings. FIG. 1 shows that the electric wire joint and explosive are placed in the center of the apparatus according to the present invention, and the electric wire is guided to the outside of the apparatus through a passage provided at a position of 180 ° on the wall surface of the cylindrical apparatus. 1 is an explosive, 2 is a metal tube for joining electric wires, 3 is an electric wire, 4 is an upper part of the device, 5 is a lower part of the device, and the divided part cannot be seen because it is hidden by the electric wire 3. However, the device is divided into two parts 4 and 5 so that the electric wire 3 after joining can be taken out from the device. In addition, 6 is the passage of the electric wire,
Reference numeral 7 is an electric detonator, and 8 is an electric wire for energizing the electric detonator to detonate. The shape of the device is assumed to be a cylindrical shape, but for example, a container having a polygonal cross section instead of a cylindrical shape and a spherical container as long as they have basic knowledge about material mechanics, the present invention It is possible to easily make an appropriate design by using a textbook of material mechanics and the like.

First, the impact stress applied to the wall surface of the device by the explosion of the explosive 1 and the stress applied to the device by the impact stress are obtained by the following procedure. Generally, the pressure of the shock wave generated by the explosion of explosive is 3
It is known to be inversely proportional to the power and proportional to the amount of explosive.
Therefore, if the concept of equivalent dose is introduced in order to easily obtain the shock wave pressure for any distance and any dose, the equivalent dose Z can be expressed by the following equation. Z = R / W ^1/3 ... 1) where R is the distance from the center of the explosive; m, W is the amount of explosive; k
g.

First, let us consider obtaining the stress in the radial direction of the apparatus body. In this case, first, it is necessary to obtain the kinetic energy applied to the inner wall surface of the body of the device 4 or 5, so R is the distance from the center of the explosive to the device wall, and W is the weight of the explosive to be detonated in the container. Equivalent to. When determining the strength of a container, it is finally required to know its strain or load stress. The load or strain due to static pressure can be obtained by finding a value that balances the static load pressure against the wall surface and the resulting deformation stress of the container, but when impact pressure is applied, it is a transient phenomenon. Therefore, it cannot be determined by static balance. In such a case, the kinetic energy given to the wall surface by the impact pressure and the deformation energy stored in the container when the wall surface is displaced by the kinetic energy are deformed and the deformation energy stored in the container is found. Know the stress. For the procedure, it is first necessary to know the reflected impulse Ir. For a wide range of equivalent dose Z values, US Government published Supressive Shields (HNDM111
0-1-2) Jan. 23, 1978, pages 3-15, 16 and Fig. 3-6, with the equivalent dose Z on the horizontal axis, the reflex impulse divided by the 1/3 power of the dose I _r A graph in which / W ^1/3 is plotted on the vertical axis is shown, and I _r / W ^1/3 can be easily obtained from the calculated equivalent dose Z.

According to the above 1), the equivalent dose Z is calculated, the value obtained by dividing the reflection impulse I _r corresponding to that value by W ^1/3 is obtained, and it is multiplied by W ^1/3 to obtain I _r . You can However, the unit of the graph is equivalent dose Z is ft / l
b ^1/3 , and the unit of the value I _r / W ^1/3 obtained by dividing the reflex impulse by the 1/3 power of the dose is psi · sec / lb ^1/3 , so it is calculated in physical units. Therefore, it is necessary to convert to kg-m system. The unit after conversion is equivalent dose Z is m / kg
^1/3 , and I _r / W ^1/3 is kg · m / m ² · sec ² / k
Although it is g ^1/3 , this level of conversion can be easily performed by those skilled in the art of technical calculation with reference to the present specification.

Furthermore, the kinetic energy KE given to the system can be derived from the reflected impulse I _r and the mass M of the material under pressure by equation 2). KE = I _r ² / 2M ... 2) On the other hand, the deformation energy ΔEi due to the strain ε of the cylindrical portion of the device.
Is expressed by the equation 3). ΔEi = 2σεπRht / 2 = σεπRht (3) where σ: load stress on the cylinder, ε: strain rate of the cylinder, R: inner radius of the cylinder, h: height of the cylinder, t: meat of the cylinder Thickness, π; Circularity This assumes that the cylinder is thin, and
It can be applied when the length of the cylinder is not too long with respect to the diameter, but when it is thick or the length is sufficiently long with respect to the diameter, for example, when the length exceeds three times the diameter. in case of,
It is necessary to use the formula of a thick-walled cylinder, and to correct the portion where the length exceeds 3 times the diameter by changing the distance R from the center of the explosive and changing the pressure load direction. However, those skilled in the art can easily correct this amount by referring to a textbook of material mechanics or the like, and there is no practical problem even if it is simply calculated that vertical stress is applied to the entire surface.

Here, if the kinetic energy KE obtained by the equation 2) and the energy ΔEi stored by the deformation of the container are balanced, then I _r ² / 2M = σεπRht can be set, and further, ε = σ / Ey ···· 4) However, Ey is Young's modulus, in the case of steel, 2.1 × 10 ¹¹ k
Since g · m / sec ² , σ = [I _r ² Ey / 2MπRht] ^1/2 ... 5) is obtained. Here, when obtaining the strain ε of the cylinder, σ
Is given by substituting the value of

The above is the procedure for obtaining the radial stress of the body portion loaded on the inner wall surfaces of the cylindrical devices 4 and 5 or the strain due to the stress. However, this value can be directly applied to a spherical container. Absent. However, in the case of a spherical container, the stress is applied evenly in the X-axis and Y-axis directions of the wall surface, so it is necessary to consider that point, but a person skilled in the art who has a basic knowledge of material mechanics, This is a problem that can be easily applied by referring to textbooks on material mechanics. Next, how to obtain the stress or strain vertically applied to the connecting portion of the upper and lower devices by the kinetic energy applied to the lower part and the upper part of the device will be described. Basically, in the case of a spherical container, the vertical component force of the load on the inner wall surface may be integrated along the inner wall surface, but simply the propagation of the explosion impact at a distance R from the explosive center. It may be treated in the same way as stress is applied to a flat wall placed at right angles to the direction. That is, there is no difference in obtaining the kinetic energy KE from the distance from the center of the explosive and the dose, and the mass of the bottom and the lid. However, since the upper part of the device 4 is integral with the lower part of the device 5 and the cylindrical body and the connecting part of the devices 4 and 5 (not shown in FIG. 1), the upper part of the device 4 and the device 5 are integrated. It may be considered that the lower part is pulled through the joint between the body and the devices 4 and 5. That is, the kinetic energy applied to the upper part of the device 4 and the lower part of the device 5 is converted into the strain energy in the vertical direction of the body and the joint. Kinetic energy KE per unit area applied to the upper part of the device 4 and the lower part of the device 5.
Is obtained from equation (2), and assuming that the masses of the upper part of the device 4 and the lower part of the device 5 are M4 and M5, respectively, and the reflected impulses Ir are the same for the sake of simplicity, the kinetic energies KE4 and KE5 per unit area are , Like this: KE ₄ = Ir2 / 2M ₄・ ・ ・ ・ ・ ・ ・ ・ ・ ・ 6) KE ₅ = Ir2 / 2M ₅・ ・ ・ ・ ・ ・ ・ ・ ・ ・ 7)

Further, since the radii of the pressure receiving portions of the upper portion of the device 4 and the lower portion of the device 5 are equal to the radius of the body portion, both the pressure receiving areas are πR ² . Therefore, multiplying it by KE4 and KE5 gives each kinetic energy. Thus the kinetic energy KE _T the _{^{total, KE T = πR 2 I r}} 2 (M 4 + M 5) / (2M 4 M 5) ···· 8) is established, and support it in the deformation energy of the cylindrical container Therefore, assuming that the cross-sectional area perpendicular to the vertical axis of the body is A, the length is L, and the connection is based on the bayonet structure at several places, and the bayonet part is treated as if it does not deform, the deformation energy of the container is all above the container. It can be treated as the deformation energy of the vertical wall surfaces of 4 and the lower part 5. The total cross-sectional area of the container wall is A ',
If the length is L ', the respective strains are ε and ε', and the common stress in the vertical direction is σV, the deformation energy ΔEi is ΔEi = E _y Σε _n ² A _n L _n ... ......... 9). Similar to the calculation of the radial load on the torso, kinetic energy and strain energy are set equal,
By introducing 4), the stress σ _V in the vertical direction between the body and the joint can be obtained.

The problem here is that radial stress and cylindrical axial stress are simultaneously applied to the body. That is, the load is in a triaxial stress state. It is known that when triaxial stress is applied and the impact load condition which is a problem in the present invention, the material easily undergoes brittle fracture.
However, empirically, the load stress is 5% of the tensile strength of the material used.
It is less than 0%, preferably less than 30%, and if the design is appropriate, it can be used within a life range of about 10 4 times unless a flaw that causes stress concentration during use is created. Also,
Since the intersection of the upper and lower planes and the cylinder becomes dangerous due to stress concentration, it is necessary to prevent the brittle fracture by giving a sufficient curvature to the joint or by devising a method for relaxing the stress concentration. As for how much curvature is required and how the stress concentration can be relaxed, it depends on the shape of the container, the degree of load, the required life, the material used, etc. It is difficult to specify in a general way, but if you have basic knowledge about material mechanics, you can design appropriately by referring to the specification of the present invention and textbooks of material mechanics. . However, with any suitable design, it is possible that the container may be damaged by imperfect flaws in use or latent defects in the material. As a safety measure against such accidents, it is necessary to consider, for example, in a sturdy cover so as not to injure the human body or equipment even if the container is broken and scattered. .

The method for obtaining the stress applied to the device by the shock wave generated when the explosive explodes in the closed or semi-closed device has been described above. receive. The static internal pressure PS is obtained by the equation 10). _{P S = f · W / V} ··················· 10) Here, P _S; generating internal pressure, f; explosive force, W, dose, V;
Container volume By knowing the internal pressure P _S applied to the container by this, the strain or stress of the container to which the internal pressure is applied can be obtained by referring to the textbook of material mechanics and the examples of the present specification. It is possible to easily know whether the container strength is suitable or not. However, in most cases, the strain or stress of the container due to the internal pressure P _S applied to the container is a. It is smaller than that due to the impact discussed in, and does not need to be a problem. When it becomes a problem, in a container with a relatively large volume, the impact pressure is low,
In the case of detonating explosive with a large amount of gas, such as ANFO, the static stress on the container may exceed the dynamic stress. In such a case, the design should be made to deal with static stress, but in the case of the device according to the present invention, it is not necessary to make it a target, and therefore a description by a concrete example is avoided here, but it is necessary. In this case, a person skilled in the art can easily calculate and design by referring to the above description, the reference book on appropriate explosive and the specification of the present invention.

Next, as a measure against the leakage of the explosion sound and the ejection of the explosion gas in the problem 1), the semi-closed type is adopted in order to avoid the danger caused by the closed type. Specifically, the passage of the electric wire of the device shall be able to pass some gas,
It was decided to explode the explosive gas along the irregularities on the surface of the electric wire automatically from the device due to the internal pressure, thereby relaxing the internal pressure and allowing some acoustic leakage. When using such means, the cross-sectional area of the passage through which the electric wire passes is 2 times the cross-sectional area of the electric wire.
It has been found that if it is less than 00%, there is almost no problem with explosion sound leakage and explosion gas ejection. The cross-sectional area of the electric wire mentioned here is a value obtained by multiplying the square of the radius of the electric wire by the pi, and is not the actual cross-sectional area obtained by adding the cross-sectional areas of the individual twisted wires of the twisted wire. The cross-sectional area of the passage is
It is the maximum part of the area of the passage of the electric wire and is the area of the surface perpendicular to the longitudinal axis of the electric wire.

FIG. 2 is a plan view of the lower part 5'of the device for explaining the structure and strength of the device connecting part of the problem 2). 9 protruding to the inside of the device is one side of the bayonet for connecting, and B is the device. It is a recess for inserting the bayonet provided in the upper portion 5 during assembly. 3 is a cross-sectional view taken along the line AA of FIG. 2, and 9'shows the lower surface of 9 of FIG. 2, to which the bayonet provided in the upper part 5 of the apparatus is meshed and coupled. It is the part that FIG. 4 is a top view 4 ′ of the device for explaining the structure and strength of the device coupling part.
In the plan view of FIG. 9, 9 "is inserted into the part B of FIG.
By rotating by a degree, it is engaged with and coupled with 9'of FIG. FIG. 5 is a view showing a cross section taken along the line CC shown in FIG. 4, and 9 "'indicates the lower surface of 9" of FIG. 4, and that portion is provided on the lower part 5 "of the apparatus of FIG. Bottom of bayonet 9 '
Are engaged and joined.

FIG. 6 is a view showing a state in which the lower part 5 "of FIG. 3 and the upper part 4" of FIG. Hereinafter, the present invention will be described in more detail with reference to Examples and will be compared with Comparative Examples.

<Example 1> An explosive 100 g of an explosive was detonated inside to produce an electric wire explosion joining device for joining an electric wire made of a stranded aluminum wire having a diameter of 18.2 mm.
The upper part 4 of the device body has an outer diameter of 230 mm and an inner diameter of 200.
mm, height 100 mm tensile strength is 100 kgf / mm ²
A high-tensile steel cylinder was prepared, and the opening on one side of the cylinder was closed with a steel material of the same material with a thickness of 15 mm to form the ceiling of the device. Inner radius 20 mm, outer radius 35
It is designed to be connected by an arc of mm. As a result, the distance from the end of the cylindrical opening on the opposite side of the ceiling to the inside of the apparatus on the ceiling was 120 mm. 20m wide on the edge of the cylindrical opening
A groove having a depth of 25 mm and a depth of 25 mm and a semicircular shape having a lower end with a radius of 10 mm was provided at two symmetrical positions to form a wire passage. The cross-sectional area of the passage according to this dimension corresponds to 176% of the cross-sectional area of the wire.

As a bayonet for connecting the upper part 4 and the lower part 5 of the device, the height of the joint part 4 to the inner wall surface is on the lower part side.
0mm, width 50mm, four bayonets with a projection of 15mm from the inner wall surface are provided symmetrically in four places, and a height of 60mm, a width of 50mm, a projection of 25mm, and a catching dimension of 50mm on the lower bayonet are fitted on the upper part. × 10m
m bayonet was set up.

Three aluminum wires having an outer diameter of 18.2 mm and a diameter of 2.6 mm are twisted around seven steel wires having a diameter of 2.6 mm, and two wires having a length of 0.6 m are prepared. Each end was inserted into an aluminum tube having an outer diameter of 25 mm, an inner diameter of 19 mm, and a length of 100 mm, and the abutted portion was positioned at the center of the tube, and the ends of the tube were fixed with an adhesive tape of vinyl chloride. . Furthermore, in the center of the aluminum pipe, the outer diameter is 49 mm, the inner diameter is 25 mm, and the length is 60 mm.
mm 95mm black carlit explosive, 0.2m outside
It was put in a paper cylinder of m and attached, and the No. 6 electric detonator was also fixed with tape at one end. Combined in that way,
Install the electric wire and the aluminum tube, explosive, and electric detonator in the lower part of the device so that the electric wire passes through the device passage 6 and the explosive is located in the center of the device. In addition, it was led from the passage 6 to the outside of the apparatus. The upper part of the device was inserted into the lower part of the device and rotated by 45 ° to engage and fix the bayonet.

The apparatus was placed on the ground, a parallel vinyl-coated electric wire was attached to a conductor of an electric detonator, and electricity was supplied to detonate the electric detonator to explode the explosive. As a result, a small, low explosion sound was heard, and a rubbing sound of explosive gas blown out from the gap between the electric wire and the electric wire passage was heard for about 1 second. The acoustic level measured at a distance of 20 m was 76 phon in A characteristics. It was
In addition, since the gas was blown out for about 1 second, it is estimated that the pressure of the explosion gas was sufficiently reduced at the outlet of the electric wire passage, which is the outlet, which is the electric wire passage and the expansion chamber. It was judged that the passage 6, which doubles as a muffling room, has achieved its purpose. Rotating the upper part 4 and the lower part 5 of the device relative to each other by 45 ° and taking them out, the electric wire was taken out.
The electric wire of the book was clamped and joined by an aluminum tube. Although such an experiment was repeated by changing the amount of explosive in the range of 100 g to 60 g, the explosion sound was always the same, the device was not damaged at all, and it was judged to be sufficiently practical. It was

Here, the load applied to the device by this experiment is obtained. First, the equivalent dose Z was obtained from the formula 1). However, the same table is based on the TNT explosive, in the case of black Carlit explosives, since explosive shock may be considered to 0.6 times the TNT, T from dose W _BC black Carlit explosive
To obtain the NT equivalent equivalent dose W _TNT , it is necessary to multiply by that multiple. For replacing various explosives with a dosage based on TNT, see the TNT of the explosive energy of the explosive.
It is only necessary to multiply the explosive energy by the ratio of the explosive energy to the explosive energy, and the explosive energy values of various explosives can be easily known from a handbook or reference books on explosives. W _TNT = 0.6W _BC = 0.6 × 95g = 57g Since the distance R from the center of the explosive to the device wall is 0.1m, Z = R / W ^1/3 = 0.1m / (0.057kg) ^1/3 = 0.
2598m / kg ^{1/3 If} this value is converted into feet-pounds, Z = 0.65
52 ft / lb ^1/3 , and the corresponding I _r / W ^1/3 is 0.4 psi · sec / l from the table of the above-mentioned US government publication.
It turns out that it is b ^1/3 . Converting this to m-kg units, it is 3.59 × 10 ³ kg · m / m ² · sec ² / kg ^1/3
It is. To obtain the reflected impulse I _r from this, W ^1/3
I _r = 3.59 × 10 ³ kg · m / m ² · sec ² / kg ^1/3 × (0.057 kg) ^1/3 = 1.38 × 10 ³ kg · m / m ²・ Sec

Assuming that the thickness of the wall is 15 mm and the height of each of the upper half and the lower half is 100 mm, and for simplicity, the upper and lower parts of the device are integrated, the area S of the inner wall of the cylindrical body of the device is , 0.126 m ² , and the weight of the body including the flange is about 28 kg. Therefore, the impact I _r0 received by the inner wall of the cylindrical body of the device is I _r0 = I _r × S = 1.38 × 10 ³ kg · m · sec / sec ² · m ² × 0.126 m ² = 1.74 × It is 10 ² kg · m · sec / sec ² , and the kinetic energy KE is calculated from the equation 3) as follows: KE = I _r0 ² /2M=(1.74×10 ² kg · m / sec) ² / (2 × 28 kg) = 5.40 × 10 ² J For simplicity, consider the structure as a thin cylinder, and from Equations 3) and 4), ΔEi = σεπRht ε = σ / Ey σ = (ΔEiEy / πRht) ^1/2 , and ΔEi = KE, R is the average of the inner and outer diameters of the cylinder, and R = 0.108 m, t = 0.015 m, h
= 0.2 m, σ = [5.4 × 10 ² kg · m ² · sec × 2.1 × 10 ¹¹ kg · m / m ² · sec ² / (π × 0.108 m × 0.015 m × 0 .2 m)] ^1/2 = 3.34 × 10 ⁸ kg · m / m · sec ² = 334 MPa = 34.0 kgf / mm ²

That is, the stress applied to the body of the apparatus is 334MP.
a = 34.0 kgf / mm ² , tensile strength is 100 kgf
Since steel of / mm ² was used, it can be seen that it can withstand it sufficiently.

However, considering that the load is impact stress and it is necessary to endure fatigue due to repeated use, the tensile strength is 1 when a load of this level is applied.
It is suitable to use high-strength steel of 00 kgf / mm ² or more.

Next, the load on the ceiling and bottom of the apparatus and the stress applied to the apparatus by the load will be calculated. Similar to the case where the stress on the body is obtained, first, the equivalent dose Z is calculated. Since the distance R from the center of the explosive to the wall surface of the device is 0.12 m, Z = R / W ^1/3 = 0.12 m / (0.057 kg) ^1/3 =
It is 0.3118 m / kg ^1/3, which is Z = 0.78 when converted to feet-pounds.
It becomes 62 ft / lb ^1/3 , and from the table of US government publications,
It can be seen that the corresponding I _r / W ^1/3 is 0.3 psi · sec / lb ^1/3 . Converting this to m-kg units,
It is 2.69 × 10 ³ kg · m / m ² · sec ² / kg ^1/3 . To obtain the reflected impulse I _r , multiply by W ^1/3 and I _r = 2.69 × 10 ³ kg · m / m ² · sec ² / kg ^1/3 × (0.057 kg) ^1/3 = 1 0.04 × 10 ³ kg ・ m / m ²・ sec

The ceiling and bottom of the device both have a thickness of 15 m.
m, and the inner radius is 100 mm, the areas S ′ of the ceiling and the bottom of the device are 0.031 m ² and the weight is about 3.7, respectively.
kg. Therefore, the impact I on the ceiling and bottom of the device I
_r1 is I _r1 = I _r × S ′ = 1.04 × 10 ³ kg · m · / sec · m ² × 0.031 m ² = 32 kg · m · sec / sec ² , and the kinetic energy KE is given by Equation 3 ), KE = I _r1 ² / 2M = (32 kg · m / sec) ² /(2×3.7 kg) = 1.40 × 10 ² J

This stress or kinetic energy is applied as a stress to the portion from the joint of the upper half of the device to the ceiling to the bayonet and the portion of the lower half of the device to the joint to the bottom of the body, and the load is applied. Will be temporarily stored as deformation energy. Further, since the above-mentioned kinetic energy is applied to either the ceiling or the bottom, the amount of deformation due to the tensile stress of the entire device is doubled above. The cross-sectional area A of the body is 0.01 m ² , the length L is 0.16 m including the upper and lower parts of the device, and the total cross-sectional area A ′ of the bayonet-bearing portion is 0.003 m ² , effective length. L'is 0.0
Since it is 6 m, and the stress applied to the body of the device is equal to the stress applied to the bolt, assuming that each part is made of the same kind of material, the expression 11) is established. E _y ε _n-1 A _{n-1 =} E _y ε _n A _n ... 11) In addition, the cross-sectional area of the body is A ₀ , and the bayonet is broken. Assuming that the area is A ₁ , from the above data, A ₀ / A ₁ = 0.01 m ² /0.003 cm ² = 3.3 11), and ε ₁ = 3.3 ε ₀ ΔE _i = E _y Σε _n ² A _n L _n = E _y [ε ₀ ² A ₀ L ₀ + ε ₁ ² A ₁ L ₁ ] = Ε ₀ ² E _y [A ₀ L ₀ + 10.9A ₁ L ₁ ]

Since the length L _{0 of the} portion of the body on which the tensile stress is applied is 125 mm and the length L _{1 of the} portion of the bayonet on which the tensile stress is applied is 60 mm, ΔEi = 1.40 × 10 ² kg · m ² / sec ² = ε ₀ ² × 2.1 × 10 ¹¹ kg · m / m ² · sec ² [0.01m ² × 0.125m + 11 × 0.003m ² × 0.06 m] = 6.78 × 10 ⁸ ε ₀ ² kg · m ² / sec ² ε ₀ = [1.40 × 10 ² /6.78×10 ⁸ ] ^1/2 = 4.54 × 10 ^-4 ε ₁ = 3.3 ε ₀ = 1.5 × 10 ^-3, and determine the stress sigma ₁ tensile now according to such tensile stress sigma ₀ and bayonet the _{barrel, σ 0 = E y ε 0} = 2.1 × 10 11 kg · m / m 2 · sec 2 × 4.54 × 10 ⁻⁴ = 9.53 × 10 ⁷ kg · m / m ² · sec ² = 95 MPa = 9.7 kgf / mm ² σ ₁ = 3.3 σ ₀ = 314 MPa = 32 A .1kgf / mm ^2, both tensile strength is sufficiently lower than the tensile strength of the high-tensile steel 100 kgf / mm ^2, a withstand stress.

<Comparative Example> A bonding experiment of the same electric wire was carried out without using the apparatus. When the explosive is exploded, the sound at a distance of 20 m exceeds 130 phons, and a combination of electric wires that joins the explosive is placed, height of about 30 cm, diameter of about 2
Sand spattered from the m pile of sand, and the joined electric wire flew 2 m above the ground and dropped about 15 m away. Compared to this situation, the sound of the device is reduced, the ability to reduce the pressure inside the device while lowering the pressure of the high pressure gas generated by the explosion, and the ability to prevent scattering of surrounding objects and electric wires are sufficient. It was decided that there was.

[0034]

INDUSTRIAL APPLICABILITY The explosive joining device for electric wires according to the present invention can reduce the explosion sound of explosives to the extent that noise pollution is not affected in the surroundings, and the explosively joined electric wires and objects around explosives scatter. Since it is a device that is easy to work because it is small, lightweight, and easy to assemble, it can also be used for wire joining work on towers and underground passages, for example, work efficiency of wire joining It has the effect of improving safety and economic efficiency and expanding the usable range of electric wire explosive coupling work.

[Brief description of the drawings]

1 is a schematic cross-sectional view of an apparatus according to the present invention.

FIG. 2 is a plan view of the upper part of the device according to the present invention.

FIG. 3 is a cross-sectional view of the upper part of the device according to the present invention.

FIG. 4 is a plan view of the lower portion of the device according to the present invention.

FIG. 5 is a cross-sectional view of the lower portion of the device according to the present invention.

FIG. 6 is a cross-sectional view of a state in which the device according to the present invention is assembled.

[Explanation of symbols]

1 Explosive 2 Metal tube for joining electric wires 3, Electric wires 4, 4 ', 4 ", 4"' Upper part of device 5, 5 ', 5 ", 5"' Lower part of device 6, 6'Wire passage 7 , Electric detonator 8, Electric detonator conductor 9, 9 ', 9 ", 9"', 9 "", 9 ""'Conductive circuit for detonation

Continued on the front page (72) Inventor Masato Araki 2-31, Iwanamesaicho, Handa-shi, Aichi 31 Starship Co., Ltd.

Claims (1)

[Claims] 1. An explosive device provided with a closed or semi-closed container for detonating explosives therein, which satisfies the following requirements. a. It can be divided into two parts, the upper part and the lower part, at the approximate center of the vertical position of the container, or 2 at the left and right at the approximate center of the horizontal or vertical position.
A splittable device, b. Two passages through which electric wires can be passed through the divided portion, c. The cross-sectional area of the passage does not exceed 200% of the cross-sectional area of the wire, d. The parts other than the passages through which the electric wire can pass are hermetically sealed against the leakage of explosive gas caused by the explosion of explosives and the propagation of explosive sound. E. When assembling a device divided into two parts, the divided device is fitted and then rotated, so that the fasteners of the staggered structure provided for each are engaged with each other, so that the explosive stored in the device is removed. Withstands the shock of explosion and the pressure of explosive gas when exploding, f. Explosive sound and explosive gas pressure are reduced by passing through the gap between the wire and passage and leaking out of the device.