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CN108599167B - Linear power flow calculation method for radial power distribution network - Google Patents

Linear power flow calculation method for radial power distribution network Download PDF

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CN108599167B
CN108599167B CN201810035353.3A CN201810035353A CN108599167B CN 108599167 B CN108599167 B CN 108599167B CN 201810035353 A CN201810035353 A CN 201810035353A CN 108599167 B CN108599167 B CN 108599167B
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CN108599167A (en
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吴文传
高长征
张伯明
常学飞
杨越
刘座铭
高松
王佳蕊
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STATE GRID JILINSHENG ELECTRIC POWER SUPPLY Co ELECTRIC POWER RESEARCH INSTITUTE
Tsinghua University
State Grid Corp of China SGCC
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STATE GRID JILINSHENG ELECTRIC POWER SUPPLY Co ELECTRIC POWER RESEARCH INSTITUTE
Tsinghua University
State Grid Corp of China SGCC
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    • HELECTRICITY
    • H02GENERATION; CONVERSION OR DISTRIBUTION OF ELECTRIC POWER
    • H02JCIRCUIT ARRANGEMENTS OR SYSTEMS FOR SUPPLYING OR DISTRIBUTING ELECTRIC POWER; SYSTEMS FOR STORING ELECTRIC ENERGY
    • H02J3/00Circuit arrangements for AC mains or AC distribution networks
    • H02J3/04Circuit arrangements for AC mains or AC distribution networks for connecting networks of the same frequency but supplied from different sources
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Abstract

本发明涉及一种辐射状配电网的线性化潮流计算方法,属于电力系统运行控制技术领域。本发明在传统的不考虑网损和相间互阻抗的线性方程基础上,将非线性网损项线性展开包括在方程内,建立了线性化的三相支路潮流方程,利用所有节点的有功功率负荷和无功功率负荷,计算所有支路有功功率、无功功率、所有节点电压的近似值,得到该辐射状配电网的潮流计算结果。本发明相比不考虑网损的线性化支路潮流方程大大提高了计算精度,同时不需要迭代求解就能直接得到潮流的近似解,计算迅速,适合应用于配电网的实时在线分析等性能要求苛刻的场景之中。

Figure 201810035353

The invention relates to a linearized power flow calculation method for a radial distribution network, and belongs to the technical field of power system operation control. Based on the traditional linear equation that does not consider the network loss and interphase mutual impedance, the invention includes the linear expansion of the nonlinear network loss term into the equation, and establishes a linearized three-phase branch power flow equation, using the active power of all nodes. Load and reactive power load, calculate the approximate values of all branch active power, reactive power, and all node voltages, and obtain the power flow calculation results of the radial distribution network. Compared with the linearized branch power flow equation that does not consider the network loss, the present invention greatly improves the calculation accuracy, and at the same time, the approximate solution of the power flow can be directly obtained without iterative solution, the calculation is fast, and it is suitable for the real-time online analysis of the distribution network and other performances. in demanding scenarios.

Figure 201810035353

Description

一种辐射状配电网的线性化潮流计算方法A Linearized Power Flow Calculation Method for Radial Distribution Networks

技术领域technical field

本发明涉及一种辐射状配电网的线性化潮流计算方法,属于电力系统运行控制技术领域。The invention relates to a linearized power flow calculation method for a radial distribution network, and belongs to the technical field of power system operation control.

背景技术Background technique

与输电网相比,配电网有以下几个显著特点:Compared with the transmission network, the distribution network has the following salient features:

1.基本以辐射状网络运行,不存在环形回路。1. It basically operates in a radial network, and there is no ring loop.

2.线路三相参数不对称,节点三相负荷不平衡,部分支路以单相或双相状态运行。2. The three-phase parameters of the line are asymmetrical, the three-phase load of the node is unbalanced, and some branches operate in a single-phase or two-phase state.

3.支路电阻和电抗大小相近,不满足PQ解耦条件。3. The branch resistance and reactance are similar in size and do not meet the PQ decoupling conditions.

因此需要考虑以上特点,建立符合配电网运行特点的潮流模型。Therefore, it is necessary to consider the above characteristics and establish a power flow model that conforms to the operation characteristics of the distribution network.

目前已经有不少学者提出了适用于配电网的潮流算法,比如基于三相扩展节点导纳矩阵的高斯迭代法,牛顿拉夫逊法和利用配电网辐射状运行特点的前代回代法。虽然前代回代法求解配电网潮流的计算效率相当高,但是它仍然需要迭代求解,而在最优潮流等问题中,潮流方程往往作为非凸的等式约束条件出现在问题中。为了简化问题的求解,需要将精确的潮流方程转化为近似的简化潮流方程。目前已有文献基于配电网的辐射状运行特性提出了单相的支路潮流方程,并略去网损项作为线性方程求解,该方法的缺点是忽略网损导致潮流计算结果精度较差。At present, many scholars have proposed power flow algorithms suitable for distribution networks, such as Gaussian iteration method based on three-phase extended node admittance matrix, Newton-Raphson method and previous generation back-substitution method using the characteristics of radial operation of distribution network . Although the calculation efficiency of the previous generation back-substitution method to solve the power flow of the distribution network is quite high, it still needs to be solved iteratively, and in the optimal power flow and other problems, the power flow equation often appears in the problem as a non-convex equality constraint. In order to simplify the solution of the problem, the exact power flow equation needs to be transformed into an approximate simplified power flow equation. At present, existing literatures have proposed the single-phase branch power flow equation based on the radial operation characteristics of the distribution network, and omitting the network loss term as a linear equation to solve.

发明内容SUMMARY OF THE INVENTION

本发明的目的是为克服已有技术的不足之处,提出了一种辐射状配电网的线性化潮流计算方法。该方法选定一个电网的已知潮流状态作为参考点,利用参考点的功率,电压等参数对潮流方程中的非线性项进行近似,得到线性的三相潮流方程,通过求解线性方程快速得到近似的潮流解。本发明的优点是计算速度快,结果精度高,适合应用于配电网的实时在线分析等性能要求苛刻的场景之中。The purpose of the present invention is to provide a linearized power flow calculation method for a radial distribution network in order to overcome the shortcomings of the prior art. This method selects a known power flow state of a power grid as a reference point, uses parameters such as power and voltage at the reference point to approximate the nonlinear terms in the power flow equation, and obtains a linear three-phase power flow equation, which can be quickly approximated by solving the linear equation. trend solution. The invention has the advantages of fast calculation speed and high result accuracy, and is suitable for use in scenarios with demanding performance requirements such as real-time online analysis of distribution networks.

本发明提出的一种辐射状配电网的线性化潮流计算方法,其特征在于,该方法包括以下步骤:A linearized power flow calculation method for a radial distribution network proposed by the present invention is characterized in that the method includes the following steps:

1)假设待进行潮流计算的辐射状配电网有N+1个节点,其中,根节点编号为0,从根节点出发,依次将每条支路的末端节点按从1到N进行编号,则该配电网支路的数目为N;1) Suppose there are N+1 nodes in the radial distribution network to be calculated for power flow. The root node is numbered 0. Starting from the root node, the end nodes of each branch are numbered from 1 to N in turn. Then the number of branches of the distribution network is N;

2)从编号为1至N的节点中任意选取一个节点记为k,该节点与其上游节点i构成的支路记为ik,计算节点k和支路ik的三相支路潮流方程;具体步骤如下:2) arbitrarily select a node from the nodes numbered 1 to N and denote k, the branch formed by this node and its upstream node i is denoted as ik, and calculate the three-phase branch power flow equation of node k and branch ik; Concrete steps as follows:

2-1)计算支路ik上的电压降:2-1) Calculate the voltage drop on branch ik:

Figure BDA0001547782400000021
Figure BDA0001547782400000021

其中,

Figure BDA0001547782400000022
表示点除,v,I和s都是三维的列向量形式,分别代表三相的电压、电流和功率,下标i代表支路ik的首端节点编号,下标k代表支路ik的末端节点编号,*代表复数的共轭;vk和vi分别表示节点k和节点i的电压,Iik表示支路ik的电流,sik表示支路ik的功率;zik是支路ik的三相阻抗矩阵,为3×3的对称复矩阵:in,
Figure BDA0001547782400000022
Represents point division, v, I and s are all three-dimensional column vectors, representing the three-phase voltage, current and power respectively, the subscript i represents the head node number of the branch ik, and the subscript k represents the end of the branch ik Node number, * represents the conjugate of complex number; v k and vi represent the voltage of node k and node i respectively, I ik represents the current of branch ik, s ik represents the power of branch ik; z ik is the power of branch ik The three-phase impedance matrix is a 3×3 symmetric complex matrix:

Figure BDA0001547782400000023
Figure BDA0001547782400000023

其中,zik的对角线元素表示a、b、c三相的自阻抗,非对角线元素表示相间互阻抗;Among them, the diagonal elements of zik represent the self-impedance of the three phases a, b, and c, and the off-diagonal elements represent the mutual impedance between phases;

将式(1)等号两边取共轭并与式(1)点乘,得到:Taking the conjugate of both sides of the equation (1) and multiplying it with the equation (1), we get:

Figure BDA0001547782400000024
Figure BDA0001547782400000024

2-2)考虑节点功率平衡,得到:2-2) Considering the node power balance, we get:

Figure BDA0001547782400000025
Figure BDA0001547782400000025

其中,等式左侧为节点k的流入功率,等式右侧为节点k的流出功率的总和,

Figure BDA0001547782400000026
是节点k的负荷;where the left side of the equation is the inflow power of node k, and the right side of the equation is the sum of the outgoing power of node k,
Figure BDA0001547782400000026
is the load of node k;

将式(1)代入式(4),得到:Substituting equation (1) into equation (4), we get:

Figure BDA0001547782400000027
Figure BDA0001547782400000027

式(1)和(5)组成了节点k和支路ik的三相支路潮流方程;Equations (1) and (5) form the three-phase branch power flow equation of node k and branch ik;

3)对步骤2)得到的三相支路潮流方程进行线性化近似;具体步骤如下:3) Linearize and approximate the three-phase branch power flow equation obtained in step 2); the specific steps are as follows:

3-1)选定一个参考状态,其中

Figure BDA00015477824000000214
代表节点i参考状态的电压,
Figure BDA0001547782400000028
Figure BDA0001547782400000029
分别代表支路ik参考状态的有功功率和参考状态的无功功率;3-1) Select a reference state, where
Figure BDA00015477824000000214
voltage representing the reference state of node i,
Figure BDA0001547782400000028
and
Figure BDA0001547782400000029
respectively represent the active power of the reference state of the branch ik and the reactive power of the reference state;

3-2)用节点i参考状态的电压

Figure BDA00015477824000000210
近似
Figure BDA00015477824000000211
对式(1)进行近似:3-2) Use node i to refer to the voltage of the state
Figure BDA00015477824000000210
approximate
Figure BDA00015477824000000211
Approximate equation (1):

Figure BDA00015477824000000212
Figure BDA00015477824000000212

对式(6)等号右边前两项,定义

Figure BDA00015477824000000213
得到:For the first two terms on the right side of the equal sign of Equation (6), define
Figure BDA00015477824000000213
get:

Figure BDA0001547782400000031
Figure BDA0001547782400000031

其中,pik,qik分别代表支路ik的有功功率和无功功率,

Figure BDA0001547782400000032
是计算得到的辅助变量;Among them, p ik , q ik represent the active power and reactive power of branch ik, respectively,
Figure BDA0001547782400000032
is the calculated auxiliary variable;

对式(6)等式右边第三项,定义

Figure BDA0001547782400000033
diag表示将向量转化为对角矩阵,
Figure BDA0001547782400000034
都是计算得到的辅助变量,得到:For the third term on the right-hand side of equation (6), define
Figure BDA0001547782400000033
diag means to convert the vector into a diagonal matrix,
Figure BDA0001547782400000034
are calculated auxiliary variables, and get:

Figure BDA0001547782400000035
Figure BDA0001547782400000035

式(8)右侧是关于pik和qik的二次函数,在

Figure BDA0001547782400000036
处进行一阶Taylor泰勒展开,转化为线性函数:The right side of equation (8) is the quadratic function about p ik and q ik , in
Figure BDA0001547782400000036
Perform a first-order Taylor expansion at , and convert it to a linear function:

Figure BDA0001547782400000037
Figure BDA0001547782400000037

进一步写成以下形式:It is further written in the following form:

Figure BDA0001547782400000038
Figure BDA0001547782400000038

其中,Rik,Xik是3×3的矩阵,

Figure BDA0001547782400000039
是3×1的向量,取值如下式所示:where R ik , Xi ik are 3×3 matrices,
Figure BDA0001547782400000039
is a 3×1 vector with the following values:

Figure BDA00015477824000000310
Figure BDA00015477824000000310

3-3)用节点i参考状态的电压

Figure BDA0001547782400000041
近似
Figure BDA0001547782400000042
对式(5)进行近似:3-3) Use node i to refer to the voltage of the state
Figure BDA0001547782400000041
approximate
Figure BDA0001547782400000042
Approximate equation (5):

Figure BDA0001547782400000043
Figure BDA0001547782400000043

式(12)左边第二项写成:The second term on the left side of equation (12) is written as:

Figure BDA0001547782400000044
Figure BDA0001547782400000044

Figure BDA0001547782400000045
都是计算得到的辅助变量,得到:make
Figure BDA0001547782400000045
are calculated auxiliary variables, and get:

Figure BDA0001547782400000046
Figure BDA0001547782400000046

将实部与虚部分开写成有功功率和无功功率的形式:Separate the real and imaginary parts in the form of active power and reactive power:

Figure BDA0001547782400000047
Figure BDA0001547782400000047

式(15)中,第一个等式代表节点k有功功率的平衡,第二个等式代表节点k的无功功率的平衡,pik、pkm分别是支路ik和km的有功功率,qik、qkm分别是支路ik和km的无功功率,节点m是节点k的下游节点;

Figure BDA0001547782400000048
是节点k的有功负荷,
Figure BDA0001547782400000049
是节点k的无功负荷;fp(pik,qik)和fq(pik,qik)的计算表达式分别如下:In equation (15), the first equation represents the balance of active power at node k, the second equation represents the balance of reactive power at node k, p ik , p km are the active powers of branch ik and km, respectively, q ik and q km are the reactive powers of branches ik and km respectively, and node m is the downstream node of node k;
Figure BDA0001547782400000048
is the active load of node k,
Figure BDA0001547782400000049
is the reactive load of node k; the calculation expressions of f p (p ik , q ik ) and f q (p ik , q ik ) are as follows:

Figure BDA00015477824000000410
Figure BDA00015477824000000410

Figure BDA00015477824000000411
Figure BDA00015477824000000411

fp(pik,qik)和fq(pik,qik)都是关于pik和qik的二次函数,将其在

Figure BDA00015477824000000412
处进行一阶Taylor展开,转化为线性函数:Both f p (p ik , q ik ) and f q (p ik , q ik ) are quadratic functions of p ik and q ik , which can be expressed in
Figure BDA00015477824000000412
Perform a first-order Taylor expansion at and convert to a linear function:

Figure BDA00015477824000000413
Figure BDA00015477824000000413

Figure BDA0001547782400000051
Figure BDA0001547782400000051

将式(15)写成以下的形式:Write equation (15) in the following form:

Figure BDA0001547782400000052
Figure BDA0001547782400000052

其中Bik,Gik,Hik,Kik是3×3的矩阵,

Figure BDA0001547782400000053
是3×1的向量,取值如下式所示:where Bik , Gik , Hik , Kik are 3×3 matrices,
Figure BDA0001547782400000053
is a 3×1 vector with the following values:

Figure BDA0001547782400000054
Figure BDA0001547782400000054

转化后,式(10)和(20)组成了节点k和支路ik的线性化的三相支路潮流方程;After transformation, equations (10) and (20) form the linearized three-phase branch power flow equation of node k and branch ik;

4)重复步骤2)至步骤3),得到除根节点外配电网所有节点及以该节点为末端节点的对应支路的线性化的三相支路潮流方程;4) Repeat step 2) to step 3) to obtain the linearized three-phase branch power flow equation of all nodes of the distribution network except the root node and the corresponding branch with this node as the end node;

5)将步骤4)得到的所有线性化三相支路潮流方程转化成矩阵形式,得到配电网潮流计算结果;5) Convert all the linearized three-phase branch power flow equations obtained in step 4) into matrix form to obtain the power flow calculation result of the distribution network;

矩阵形式的线性化三相支路潮流方程表达式如下:The linearized three-phase branch power flow equation in matrix form is expressed as follows:

Figure BDA0001547782400000055
Figure BDA0001547782400000055

Figure BDA0001547782400000056
Figure BDA0001547782400000056

Figure BDA0001547782400000057
Figure BDA0001547782400000057

对式(22)至(24)组成的线性方程组求解,得到支路有功功率pb、无功功率qb、支路电压差ub和节点电压un的表达式如下,其中,下标b代表所有支路集合,下标n代表所有节点集合;Solving the linear equations composed of equations (22) to (24), the expressions of branch active power p b , reactive power q b , branch voltage difference ub and node voltage u n are obtained as follows, where the subscript b represents the set of all branches, and the subscript n represents the set of all nodes;

Figure BDA0001547782400000061
Figure BDA0001547782400000061

Figure BDA0001547782400000062
Figure BDA0001547782400000062

其中,M为三相扩展节点支路关联矩阵,Np表示网络关联矩阵,Rb,Xb,Bb,Gb,Hb,Kb分别表示将每条支路对应的Rik,Xik,Bik,Gik,Hik,Kik按照支路末端节点编号顺序沿矩阵主对角线排布的扩展形式,都是3N×3N的矩阵;

Figure BDA0001547782400000063
分别表示将每条支路对应的
Figure BDA0001547782400000064
按照支路末端编号顺序排布的扩展形式,都是3N×1的向量;Among them, M is the three-phase expansion node branch correlation matrix, N p represents the network correlation matrix, R b , X b , B b , G b , H b , K b represent the R ik , X corresponding to each branch, respectively ik ,B ik ,G ik ,H ik ,K ik are the extended forms arranged along the main diagonal of the matrix according to the number sequence of the branch end nodes, which are all 3N×3N matrices;
Figure BDA0001547782400000063
Respectively represent the corresponding
Figure BDA0001547782400000064
The extended forms arranged in the order of branch end numbers are all 3N×1 vectors;

利用式(25),输入所有节点的有功功率负荷pL和无功功率负荷qL,计算所有支路有功功率pb、无功功率qb、所有节点电压un的近似值,得到该辐射状配电网的潮流计算结果。Using equation (25), input the active power load p L and reactive power load q L of all nodes, calculate the approximate values of all branches active power p b , reactive power q b , and all node voltage u n , and obtain the radial pattern The result of the power flow calculation of the distribution network.

本发明方法的特点及有益效果在于:The characteristics and beneficial effects of the method of the present invention are:

为了提高线性化三相潮流方程的精确性,本发明提出了一种新的线性化近似方法,在传统的不考虑网损和相间互阻抗的线性方程基础上,将非线性网损项线性展开包括在方程内。只要选取合适的参考潮流状态,本方法就能对网损做出相当精确的估计,计算结果的精度明显高于简单线性方程,并且保持了线性模型的优势,不需要迭代求解,计算速度很快。In order to improve the accuracy of the linearized three-phase power flow equation, the present invention proposes a new linearization approximation method, which linearly expands the nonlinear network loss term on the basis of the traditional linear equation that does not consider the network loss and interphase mutual impedance. included in the equation. As long as an appropriate reference power flow state is selected, this method can make a fairly accurate estimation of the network loss. The accuracy of the calculation result is obviously higher than that of the simple linear equation, and the advantages of the linear model are maintained. Iterative solution is not required, and the calculation speed is very fast. .

本方法从精确支路潮流方程出发,将方程中的电压用参考状态的电压代替,将二次功率项在参考点功率处进行一阶Taylor展开线性化,并无其他近似或者去掉某项。因此,该潮流方程的准确性只依赖于基准点的选取,并不受三相不平衡程度的影响。经过在实际配电网算例中的应用表明,本方法给出的结果精度很高,而且精度与选择的参考状态有关,当选择精确潮流解作为参考状态时,得到的就是精确解,即便选择非精确潮流解作为参考状态,误差也要远小于不考虑网损的线性化支路潮流方程。同时本方法不需要迭代求解,计算迅速,适合应用于配电网的实时在线分析等性能要求苛刻的场景之中。This method starts from the accurate branch power flow equation, replaces the voltage in the equation with the voltage of the reference state, and linearizes the secondary power term at the reference point power by first-order Taylor expansion, and there is no other approximation or a certain term is removed. Therefore, the accuracy of the power flow equation only depends on the selection of the reference point, and is not affected by the degree of three-phase unbalance. The application in the actual distribution network example shows that the accuracy of the results given by this method is very high, and the accuracy is related to the selected reference state. When the precise power flow solution is selected as the reference state, the exact solution is obtained. The inaccurate power flow solution is used as the reference state, and the error is also much smaller than the linearized branch power flow equation without considering the network loss. At the same time, the method does not need iterative solution, and the calculation is fast, which is suitable for real-time online analysis of distribution network and other scenarios with demanding performance requirements.

附图说明Description of drawings

图1是本发明方法的整体流程框图。Fig. 1 is an overall flow chart of the method of the present invention.

图2是本发明实施例的辐射状配电网潮流示意图。FIG. 2 is a schematic diagram of the power flow of a radial distribution network according to an embodiment of the present invention.

具体实施方式Detailed ways

本发明提出的一种辐射状配电网的线性化潮流计算方法,下面结合附图和具体实施例进一步详细说明如下。A linearized power flow calculation method for a radial distribution network proposed by the present invention is further described in detail below with reference to the accompanying drawings and specific embodiments.

本发明提出的一种辐射状配电网的线性化潮流计算方法,针对配电网辐射状运行以及三相不平衡的网络特性,整体流程如图1所示,包括以下步骤:A linearized power flow calculation method for a radial distribution network proposed by the present invention, aiming at the radial operation of the distribution network and the network characteristics of three-phase unbalance, the overall process is shown in Figure 1, including the following steps:

1)假设待进行潮流计算的辐射状配电网有N+1个节点,其中,根节点编号为0,从根节点出发,依次将每条支路的末端节点按从1到N进行编号,则该配电网支路的数目为N;1) Suppose there are N+1 nodes in the radial distribution network to be calculated for power flow. The root node is numbered 0. Starting from the root node, the end nodes of each branch are numbered from 1 to N in turn. Then the number of branches of the distribution network is N;

2)从编号为1至N的节点中任意选取一个节点记为k,该节点与其上游节点i构成的支路记为ik,计算节点k和支路ik的三相支路潮流方程;2) arbitrarily select a node from the nodes numbered 1 to N and denote k, the branch formed by this node and its upstream node i is denoted as ik, and calculate the three-phase branch power flow equation of node k and branch ik;

以如图2所示的节点k和支路ik的潮流为例,节点i是节点k的上游节点(即节点i比节点k更接近根节点,且辐射状电网中每个节点有且只有一个上游节点,(如果所选节点编号为1.那么上游节点是根结点,也采取同样方法计算),节点m是节点k的一个下游节点(每个节点的下游节点可能不止一个,此处取出任意一个下游节点m作为示意)。Taking the power flow of node k and branch ik as shown in Figure 2 as an example, node i is the upstream node of node k (that is, node i is closer to the root node than node k, and each node in the radial grid has one and only one Upstream node, (if the selected node number is 1. Then the upstream node is the root node, and the same method is used to calculate), node m is a downstream node of node k (each node may have more than one downstream node, take it out here Any downstream node m is used as an illustration).

具体步骤如下:Specific steps are as follows:

2-1)计算支路ik上的电压降:2-1) Calculate the voltage drop on branch ik:

Figure BDA0001547782400000071
Figure BDA0001547782400000071

其中,

Figure BDA0001547782400000072
表示点除,v,I和s都是三维的列向量形式,分别代表三相的电压、电流和功率,下标i代表支路ik的首端节点编号,下标k代表支路ik的末端节点编号,*代表复数的共轭。vk和vi分别表示节点k和节点i的电压,Iik表示支路ik的电流,sik表示支路ik的功率。zik是支路ik的三相阻抗矩阵,为3×3的对称复矩阵:in,
Figure BDA0001547782400000072
Represents point division, v, I and s are all three-dimensional column vectors, representing the three-phase voltage, current and power respectively, the subscript i represents the head node number of the branch ik, and the subscript k represents the end of the branch ik Node number, * represents the conjugate of a complex number. v k and vi represent the voltage of node k and node i respectively, I ik represents the current of branch ik, and s ik represents the power of branch ik. z ik is the three-phase impedance matrix of branch ik, which is a 3×3 symmetric complex matrix:

Figure BDA0001547782400000073
Figure BDA0001547782400000073

其中,zik的对角线元素表示a、b、c三相的自阻抗,非对角线元素表示相间互阻抗。Among them, the diagonal elements of zik represent the self-impedance of the three phases a, b, and c, and the off-diagonal elements represent the mutual impedance between phases.

将式(1)等号两边取共轭并与式(1)点乘,得到:Taking the conjugate of both sides of the equation (1) and multiplying it with the equation (1), we get:

Figure BDA0001547782400000074
Figure BDA0001547782400000074

2-2)考虑节点功率平衡,得到:2-2) Considering the node power balance, we get:

Figure BDA0001547782400000075
Figure BDA0001547782400000075

其中,等式左侧为节点k的流入功率,等式右侧为节点k的流出功率的总和,

Figure BDA0001547782400000076
是节点k的负荷。where the left side of the equation is the inflow power of node k, and the right side of the equation is the sum of the outgoing power of node k,
Figure BDA0001547782400000076
is the load of node k.

将式(1)代入式(4),得到:Substituting equation (1) into equation (4), we get:

Figure BDA0001547782400000081
Figure BDA0001547782400000081

式(1)和(5)组成了节点k和支路ik的三相支路潮流方程。与单相支路潮流方程相比,由于存在相间耦合,三相支路潮流方程的数学形式要更为复杂。Equations (1) and (5) form the three-phase branch power flow equation for node k and branch ik. Compared with the single-phase branch power flow equation, the mathematical form of the three-phase branch power flow equation is more complicated due to the existence of phase-to-phase coupling.

3)对步骤2)得到的三相支路潮流方程进行线性化近似;具体步骤如下:3) Linearize and approximate the three-phase branch power flow equation obtained in step 2); the specific steps are as follows:

3-1)为了进行线性化近似,需要选定一个参考状态,该参考状态包括支路功率和节点电压的数值,通常可以选择状态估计的结果作为参考状态,在下面的推导中用上标0表示参考状态的值,包括:

Figure BDA0001547782400000082
代表节点i参考状态的电压,
Figure BDA0001547782400000083
Figure BDA0001547782400000084
分别代表支路ik参考状态的有功功率和参考状态的无功功率;3-1) In order to perform the linearization approximation, it is necessary to select a reference state, which includes the values of branch power and node voltage. Usually, the result of state estimation can be selected as the reference state, and the superscript 0 is used in the following derivation Values representing reference states, including:
Figure BDA0001547782400000082
voltage representing the reference state of node i,
Figure BDA0001547782400000083
and
Figure BDA0001547782400000084
respectively represent the active power of the reference state of the branch ik and the reactive power of the reference state;

3-2)对式(1)进行近似,实际电网的电压标幺值都在1左右,因此用节点i参考状态的电压

Figure BDA0001547782400000085
近似
Figure BDA0001547782400000086
3-2) Approximate Equation (1), the voltage per unit value of the actual power grid is all around 1, so the voltage of node i is used as a reference state
Figure BDA0001547782400000085
approximate
Figure BDA0001547782400000086

Figure BDA0001547782400000087
Figure BDA0001547782400000087

对式(6)等号右边前两项,定义

Figure BDA0001547782400000088
得到:For the first two terms on the right side of the equal sign of Equation (6), define
Figure BDA0001547782400000088
get:

Figure BDA0001547782400000089
Figure BDA0001547782400000089

其中,pik,qik分别代表支路ik的有功功率和无功功率,

Figure BDA00015477824000000810
都是计算得到的辅助变量。Among them, p ik , q ik represent the active power and reactive power of branch ik, respectively,
Figure BDA00015477824000000810
are calculated auxiliary variables.

对式(6)等式右边第三项,定义

Figure BDA00015477824000000811
diag表示将向量转化为对角矩阵,
Figure BDA00015477824000000812
都是计算得到的辅助变量,得到:For the third term on the right-hand side of equation (6), define
Figure BDA00015477824000000811
diag means to convert the vector into a diagonal matrix,
Figure BDA00015477824000000812
are calculated auxiliary variables, and get:

Figure BDA00015477824000000813
Figure BDA00015477824000000813

其中

Figure BDA00015477824000000814
分别代表支路ik参考状态的有功功率和无功功率。in
Figure BDA00015477824000000814
represent the active power and reactive power of the branch ik reference state, respectively.

式(8)右侧是关于pik和qik的二次函数,在

Figure BDA00015477824000000815
处进行一阶Taylor泰勒展开,转化为线性函数:The right side of equation (8) is the quadratic function about p ik and q ik , in
Figure BDA00015477824000000815
Perform a first-order Taylor expansion at , and convert it to a linear function:

Figure BDA0001547782400000091
Figure BDA0001547782400000091

进一步写成以下形式:It is further written in the following form:

Figure BDA0001547782400000092
Figure BDA0001547782400000092

其中,Rik,Xik是3×3的矩阵,

Figure BDA0001547782400000093
是3×1的向量,取值如下式所示:where R ik , Xi ik are 3×3 matrices,
Figure BDA0001547782400000093
is a 3×1 vector with the following values:

Figure BDA0001547782400000094
Figure BDA0001547782400000094

3-3)用节点i参考状态的电压

Figure BDA0001547782400000095
近似
Figure BDA0001547782400000096
对式(5)进行近似:3-3) Use node i to refer to the voltage of the state
Figure BDA0001547782400000095
approximate
Figure BDA0001547782400000096
Approximate equation (5):

Figure BDA0001547782400000097
Figure BDA0001547782400000097

式(12)左边第二项写成:The second term on the left side of equation (12) is written as:

Figure BDA0001547782400000098
Figure BDA0001547782400000098

Figure BDA0001547782400000099
Figure BDA00015477824000000910
都是计算得到的辅助变量,得到:make
Figure BDA0001547782400000099
Figure BDA00015477824000000910
are calculated auxiliary variables, and get:

Figure BDA00015477824000000911
Figure BDA00015477824000000911

将实部与虚部分开写成有功功率和无功功率的形式:Separate the real and imaginary parts in the form of active power and reactive power:

Figure BDA0001547782400000101
Figure BDA0001547782400000101

式(15)中,第一个等式代表节点k有功功率的平衡,第二个等式代表节点k的无功功率的平衡,pik、pkm分别是支路ik和km的有功功率,qik、qkm分别是支路ik和km的无功功率,节点m是节点k的下游节点;

Figure BDA0001547782400000102
是节点k的有功负荷,
Figure BDA0001547782400000103
是节点k的无功负荷。fp(pik,qik)和fq(pik,qik)的计算表达式分别如下:In equation (15), the first equation represents the balance of active power at node k, the second equation represents the balance of reactive power at node k, p ik , p km are the active powers of branch ik and km, respectively, q ik and q km are the reactive powers of branches ik and km respectively, and node m is the downstream node of node k;
Figure BDA0001547782400000102
is the active load of node k,
Figure BDA0001547782400000103
is the reactive load of node k. The calculation expressions of f p (p ik , q ik ) and f q (p ik , q ik ) are respectively as follows:

Figure BDA0001547782400000104
Figure BDA0001547782400000104

Figure BDA0001547782400000105
Figure BDA0001547782400000105

fp(pik,qik)和fq(pik,qik)都是关于pik和qik的二次函数,将其在

Figure BDA0001547782400000106
处进行一阶Taylor展开,转化为线性函数:Both f p (p ik , q ik ) and f q (p ik , q ik ) are quadratic functions of p ik and q ik , which can be expressed in
Figure BDA0001547782400000106
Perform a first-order Taylor expansion at and convert to a linear function:

Figure BDA0001547782400000107
Figure BDA0001547782400000107

Figure BDA0001547782400000108
Figure BDA0001547782400000108

经过整理,将式(15)写成以下的形式:After finishing, formula (15) can be written in the following form:

Figure BDA0001547782400000109
Figure BDA0001547782400000109

其中Bik,Gik,Hik,Kik是3×3的矩阵,

Figure BDA00015477824000001010
是3×1的向量,取值如下式所示:where Bik , Gik , Hik , Kik are 3×3 matrices,
Figure BDA00015477824000001010
is a 3×1 vector with the following values:

Figure BDA0001547782400000111
Figure BDA0001547782400000111

转化后,式(10)和(20)组成了节点k和支路ik的线性化的三相支路潮流方程。After transformation, equations (10) and (20) form a linearized three-phase branch power flow equation for node k and branch ik.

4)重复步骤2)至步骤3),得到除根节点外配电网所有节点及以该节点为末端节点的对应支路的线性化的三相支路潮流方程。4) Repeat steps 2) to 3) to obtain the linearized three-phase branch power flow equations of all nodes of the distribution network except the root node and the corresponding branch with this node as the end node.

5)将步骤4)得到的所有线性化三相支路潮流方程转化成矩阵形式,得到配电网潮流计算结果;5) Convert all the linearized three-phase branch power flow equations obtained in step 4) into matrix form to obtain the power flow calculation result of the distribution network;

矩阵形式的线性化三相支路潮流方程表达式如下:The linearized three-phase branch power flow equation in matrix form is expressed as follows:

Figure BDA0001547782400000112
Figure BDA0001547782400000112

Figure BDA0001547782400000113
Figure BDA0001547782400000113

Figure BDA0001547782400000114
Figure BDA0001547782400000114

对式(22)至(24)组成的线性方程组求解,可以用MATLAB等线性代数软件求解,得到,支路有功功率pb(下标b代表所有支路集合)、无功功率qb、支路电压差ub,节点电压un(下标n代表所有节点集合)的显式表达式如下,可以看出是节点负荷pL和qL的线性形式。To solve the linear equation system composed of equations (22) to (24), it can be solved by linear algebra software such as MATLAB, and it can be obtained that the branch active power p b (subscript b represents the set of all branches), reactive power q b , The explicit expressions of the branch voltage difference ub and the node voltage un (the subscript n represents the set of all nodes) are as follows, and it can be seen that it is the linear form of the node loads p L and q L.

Figure BDA0001547782400000115
Figure BDA0001547782400000115

Figure BDA0001547782400000116
Figure BDA0001547782400000116

其中,M为三相扩展节点支路关联矩阵,Np表示网络关联矩阵(这两个矩阵可以根据电网拓扑直接写出),Rb,Xb,Bb,Gb,Hb,Kb分别表示将每条支路对应的Rik,Xik,Bik,Gik,Hik,Kik按照支路末端节点编号顺序沿矩阵主对角线排布的扩展形式,都是3N×3N的矩阵。

Figure BDA0001547782400000117
分别表示将每条支路对应的
Figure BDA0001547782400000118
按照支路末端编号顺序排布的扩展形式,都是3N×1的向量。Among them, M is the three-phase expansion node branch correlation matrix, N p represents the network correlation matrix (these two matrices can be directly written according to the grid topology), R b , X b , B b , G b , H b , K b Respectively represent the extended form of arranging Rik , Xik , Bik , Gik , Hik , Kik corresponding to each branch along the main diagonal of the matrix according to the number sequence of the end nodes of the branch, all of which are 3N×3N matrix.
Figure BDA0001547782400000117
Respectively represent the corresponding
Figure BDA0001547782400000118
The extended forms arranged in the order of branch end numbers are all 3N×1 vectors.

利用式(25),输入所有节点的有功功率负荷pL和无功功率负荷qL,进行矩阵运算,就能直接求得所有支路有功功率pb、无功功率qb、所有节点电压un的近似值,得到该辐射状配电网的潮流计算结果。Using formula (25), input the active power load p L and reactive power load q L of all nodes, and perform matrix operation, the active power p b of all branches, reactive power q b , and voltage u of all nodes can be directly obtained. The approximate value of n can be used to obtain the calculation result of the power flow of the radial distribution network.

Claims (1)

1. A linearization power flow calculation method of a radial distribution network is characterized by comprising the following steps:
1) supposing that a radial distribution network to be subjected to load flow calculation has N +1 nodes, wherein the number of a root node is 0, starting from the root node, numbering the tail end nodes of each branch from 1 to N in sequence, and then, the number of the branches of the distribution network is N;
2) randomly selecting one node from nodes numbered from 1 to N as k, recording a branch formed by the node and an upstream node i as ik, and calculating a three-phase branch load flow equation of the node k and the branch ik; the method comprises the following specific steps:
2-1) calculate the voltage drop over branch ik:
Figure FDA0001547782390000011
wherein,
Figure FDA0001547782390000012
the expression points are divided, v, I and s are all in a three-dimensional column vector form and respectively represent voltage, current and power of three phases, subscript I represents the number of a head node of a branch ik, subscript k represents the number of a tail node of the branch ik, and x represents the conjugate of a complex number; v. ofkAnd viRespectively representing the voltages of node k and node I, IikCurrent, s, representing branch ikikRepresents the power of branch ik; z is a radical ofikIs a three-phase impedance matrix of branch ik, which is a 3 × 3 symmetric complex matrix:
Figure FDA0001547782390000013
wherein z isikThe diagonal elements of (1) represent self-impedance of a, b and c three phases, and the non-diagonal elements represent interphase mutual impedance;
conjugate two sides of the equal sign of the formula (1) and multiply the conjugate with the formula (1) to obtain:
Figure FDA0001547782390000014
2-2) considering node power balance, obtaining:
Figure FDA0001547782390000015
where the left side of the equation is the incoming power of node k, the right side of the equation is the sum of the outgoing powers of node k,
Figure FDA0001547782390000016
is the load of node k;
substituting formula (1) for formula (4) to obtain:
Figure FDA0001547782390000017
the three-phase branch load flow equation of the node k and the branch ik is formed by the formulas (1) and (5);
3) carrying out linear approximation on the three-phase branch load flow equation obtained in the step 2); the method comprises the following specific steps:
3-1) selecting a reference state, wherein
Figure FDA0001547782390000018
The voltage representing the reference state of node i,
Figure FDA0001547782390000019
and
Figure FDA00015477823900000110
respectively representing the active power of the branch ik reference state and the reactive power of the reference state;
3-2) voltage of reference state with node i
Figure FDA00015477823900000111
Approximation
Figure FDA00015477823900000112
Approximation of equation (1):
Figure FDA0001547782390000021
for the first two terms on the right of the equal sign of formula (6), define
Figure FDA0001547782390000022
Obtaining:
Figure FDA0001547782390000023
wherein p isik,qikRespectively representing the active and reactive power of branch ik,
Figure FDA0001547782390000024
is a calculated auxiliary variable;
for the third term on the right of equation (6), define
Figure FDA0001547782390000025
diag denotes the conversion of a vector into a diagonal matrix,
Figure FDA0001547782390000026
are all calculated auxiliary variables, resulting in:
Figure FDA0001547782390000027
to the right of formula (8) is with respect to pikAnd q isikA quadratic function of
Figure FDA0001547782390000028
The first-order Taylor expansion is carried out and converted into a linear function:
Figure FDA0001547782390000029
further written in the form:
Figure FDA00015477823900000210
wherein R isik,XikIs a 3 x 3 matrix of the matrix,
Figure FDA00015477823900000211
is a 3 × 1 vector, and takes the following value:
Figure FDA0001547782390000031
3-3) voltage of reference state with node i
Figure FDA0001547782390000032
Approximation
Figure FDA0001547782390000033
Approximation of equation (5):
Figure FDA0001547782390000034
the second term on the left of equation (12) is written as:
Figure FDA0001547782390000035
order to
Figure FDA0001547782390000036
Figure FDA0001547782390000037
Are all calculated auxiliary variables, resulting in:
Figure FDA0001547782390000038
writing the real part and the imaginary part separately into the forms of active power and reactive power:
Figure FDA0001547782390000039
in equation (15), the first equation represents the active power balance of node k, the second equation represents the reactive power balance of node k, pik、pkmThe active power of the branches ik and km, qik、qkmThe reactive powers of the branches ik and km respectively, and the node m is a downstream node of the node k;
Figure FDA00015477823900000310
is the active load of the node k and,
Figure FDA00015477823900000311
is the reactive load of node k; f. ofp(pik,qik) And fq(pik,qik) Respectively as follows:
Figure FDA00015477823900000312
Figure FDA00015477823900000313
fp(pik,qik) And fq(pik,qik) Are all about pikAnd q isikOf a quadratic function of
Figure FDA0001547782390000041
And (3) performing first-order Taylor expansion, and converting into a linear function:
Figure FDA0001547782390000042
Figure FDA0001547782390000043
equation (15) is written as follows:
Figure FDA0001547782390000044
wherein B isik,Gik,Hik,KikIs a 3 x 3 matrix of the matrix,
Figure FDA0001547782390000045
is a 3 × 1 vector, and takes the following value:
Figure FDA0001547782390000046
after conversion, the equations (10) and (20) form a linearized three-phase branch load flow equation of the node k and the branch ik;
4) repeating the step 2) to the step 3) to obtain a linearized three-phase branch flow equation of all nodes of the power distribution network except the root node and corresponding branches taking the nodes as tail end nodes;
5) converting all the linearized three-phase branch load flow equations obtained in the step 4) into a matrix form to obtain a power distribution network load flow calculation result;
the expression of the linearized three-phase branch load flow equation in the form of a matrix is as follows:
Figure FDA0001547782390000047
Figure FDA0001547782390000048
Figure FDA0001547782390000051
solving a linear equation set composed of the formulas (22) to (24) to obtain the active power p of the branchbReactive power qbBranch voltage difference ubAnd node voltage unWherein subscript b represents all branch sets and subscript n representsThere is a set of nodes;
Figure FDA0001547782390000052
Figure FDA0001547782390000053
wherein M is a three-phase extended node branch incidence matrix, and N ispRepresenting a network incidence matrix, Rb,Xb,Bb,Gb,Hb,KbRespectively representing R corresponding to each branchik,Xik,Bik,Gik,Hik,KikThe extension forms which are arranged along the main diagonal of the matrix according to the serial number sequence of the branch tail end nodes are all 3 Nx3N matrixes;
Figure FDA0001547782390000054
respectively indicating that each branch corresponds to
Figure FDA0001547782390000055
The extension forms arranged according to the serial number sequence of the branch ends are vectors of 3 Nx 1;
inputting the active power load p of all nodes by the equation (25)LAnd reactive power load qLCalculating the active power p of all branchesbReactive power qbAll node voltages unAnd obtaining the load flow calculation result of the radial distribution network.
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