OFFSET
1,1
COMMENTS
One could just as well sum from n >= 0, giving a value one higher. - Franklin T. Adams-Watters, Nov 30 2018
Conjecture: this is a transcendental number. - Zhi-Wei Sun, May 24 2023
LINKS
Vaclav Kotesovec, Table of n, a(n) for n = 1..1000
FORMULA
Sum_{n>=1} 1/A000041(n) = 2.510597483886...
EXAMPLE
2.510597483886293953236834727415465451683531944955147681908...
MATHEMATICA
digits = 100; NSum[1/PartitionsP[n], {n, 1, Infinity}, NSumTerms -> 10000, WorkingPrecision -> digits+1] // RealDigits[#, 10, digits]& // First (* Jean-François Alcover, Feb 21 2014 *)
PROG
(PARI)
default(realprecision, 100);
N=10000; x='x+O('x^N);
v=Vec(Ser( 1/eta(x) ) );
s=sum(n=2, #v, 1.0/v[n] )
(PARI) {a(n) = if( n<-1, 0, n++; default( realprecision, n+5); floor( suminf( k=1, 1 / numbpart(k)) * 10^n) % 10)} /* Michael Somos, Feb 05 2011 */
CROSSREFS
KEYWORD
cons,nonn
AUTHOR
Ralf Stephan, Jan 05 2003
EXTENSIONS
Corrected digits from position 32 on by Ralf Stephan, Jan 24 2011
More terms from Jean-François Alcover, Feb 21 2014
STATUS
approved