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1816 Delaware gubernatorial election

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1816 Delaware gubernatorial election

← 1813 October 1, 1816 1819 →
 
Nominee John Clark Manaen Bull
Party Federalist Democratic-Republican
Popular vote 4,008 3,517
Percentage 53.26% 46.74%

Clark:      60–70%
Bull:      60–70%

Governor before election

Daniel Rodney
Federalist

Elected Governor

John Clark
Federalist

The 1816 Delaware gubernatorial election was held on October 1, 1816. Incumbent Federalist Governor Daniel Rodney was unable to seek re-election due to term limits. Former State Representative John Clark ran as the Federalist nominee, and narrowly defeated Democratic-Republican nominee Manaen Bull to hold the office for his party.[1]

General election

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Results

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1816 Delaware gubernatorial election[2]
Party Candidate Votes % ±%
Federalist John Clark 4,008 53.26% −1.94%
Democratic-Republican Manaen Bull 3,517 46.74% +1.94%
Majority 491 6.52% −3.88%
Turnout 7,525 100.00%
Federalist hold

References

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  1. ^ Conrad, Henry C. (1908). History of the State of Delaware: From the Earliest Settlements to the Year 1907. Vol. 1. Lancaster, Pa.: Wickersham Company, Printers and Binders. p. 175.
  2. ^ "Delaware 1816 Governor". A New Nation Votes: American Election Returns 1787-1825. Tufts University. Retrieved June 17, 2021.

Bibliography

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  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.