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1853 Rhode Island gubernatorial election

From Wikipedia, the free encyclopedia

1853 Rhode Island gubernatorial election
← 1852 6 April 1853 1854 →
 
Nominee Philip Allen William W. Hoppin Edward Harris
Party Democratic Whig Free Soil
Popular vote 10,471 8,228 542
Percentage 54.40% 42.75% 2.82%

County results
Allen:      50–60%
Hoppin:      50–60%

Governor before election

Philip Allen
Democratic

Elected Governor

Philip Allen
Democratic

The 1853 Rhode Island gubernatorial election was held on 6 April 1853 in order to elect the governor of Rhode Island. Incumbent Democratic governor Philip Allen won re-election against Whig nominee William W. Hoppin and Free Soil nominee Edward Harris.[1]

General election

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On election day, 6 April 1853, incumbent Democratic governor Philip Allen won re-election by a margin of 2,243 votes against his foremost opponent William W. Hoppin, thereby keeping democratic control over the office of governor. Free Soil nominee Edward Harris also was unable to be elected as governor for the fourth time, after his election losses in the gubernatorial elections of 1849, 1850 and 1851. Allen was sworn in for his third term on 6 May 1853.[2]

Results

[edit]
Rhode Island gubernatorial election, 1853
Party Candidate Votes %
Democratic Philip Allen (incumbent) 10,471 54.40
Whig William W. Hoppin 8,228 42.75
Free Soil Edward Harris 542 2.82
Scattering 7 0.03
Total votes 19,248 100.00
Democratic hold

References

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  1. ^ Capace, Nancy (2001). The Encyclopedia of Rhode Island. North American Book Dist LLC. p. 180. ISBN 9780403096107.
  2. ^ "RI Governor". ourcampaigns.com. June 6, 2005. Retrieved May 10, 2023.