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1978 Australian Open – Women's doubles

From Wikipedia, the free encyclopedia
Women's doubles
1978 Australian Open
Final
ChampionsUnited States Betsy Nagelsen
Czechoslovakia Renáta Tomanová
Runners-upJapan Naoko Sato
Australia Pam Whytcross
Score7–5, 6–2
Events
Singles men women boys girls
Doubles men women mixed boys girls
WC Singles men women quad
WC Doubles men women quad
Legends men women mixed
← 1977 · Australian Open · 1979 →

Evonne Cawley, Helen Gourlay-Cawley, Mona Guerrant and Kerry Reid were the reigning champions. None of them competed.

Seeds

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Draw

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Key

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First round Quarterfinals Semifinals Final
1 United States B Nagelsen
Czechoslovakia R Tomanová
6 7
United States R Blount
Australia D Evers
2 5 1 United States B Nagelsen
Czechoslovakia R Tomanová
7 4 6
New Zealand C Newton
Australia M Robinson
7 3 0 United States P Bostrom
United States B Norton
5 6 0
United States P Bostrom
United States B Norton
6 6 6 1 United States B Nagelsen
Czechoslovakia R Tomanová
6 6
4 New Zealand J Chaloner
Australia P Gregg
6 2 4 Australia C O'Neil
Austria U Ulrich
2 2
Australia C O'Neil
Austria U Ulrich
2 6 6 Australia C O'Neil
Austria U Ulrich
6 6
Australia C Draper
Australia K Pratt
2 4 Australia L Harrison
Australia A Tobin
2 4
Australia L Harrison
Australia A Tobin
6 6 1 United States B Nagelsen
Czechoslovakia R Tomanová
7 6
Australia S Saliba
Australia M Sawyer
4 6 6 Japan N Sato
Australia P Whytcross
5 2
Australia J Dalton
Australia W Gilchrist
6 1 1 Australia S Saliba
Australia M Sawyer
7 6 3
Japan N Sato
Australia P Whytcross
5 6 6 Japan N Sato
Australia P Whytcross
6 7 6
3 United Kingdom S Barker
West Germany H Eisterlehner
7 2 3 Japan N Sato
Australia P Whytcross
6 3 6
Australia C Matison
Italy S Simmonds
6 6 Australia C Matison
Italy S Simmonds
2 6 2
Australia N Gregory
Australia K Hallam
2 2 Australia C Matison
Italy S Simmonds
6 5 6
Denmark D Ekner
Denmark B Hermansen
3 2 2 Australia C Doerner
Australia K Ruddell
4 7 3
2 Australia C Doerner
Australia K Ruddell
6 6
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