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Vsepr Theory, Molecular Shapes, Organic Chem, Molecular Geometry, Ap Chem, Organic Chemistry Study, Inorganic Chemistry, General Chemistry, Study Chemistry
Vsepr Theory
Molecular Shapes
Organic Chem
Molecular Geometry
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Organic Chemistry Study
Inorganic Chemistry
General Chemistry
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What are the steps associated with the process of constructing a hybrid orbital diagram? | Socratic

Here are the steps for constructing a hybrid orbital diagram for ethylene. Step 1. Draw the Lewis structure for the molecule. Step 2. Use VSEPR theory to classify and determine the geometry around each central atom. Each carbon atom is an AX₃ system, so the geometry is trigonal planar. Step 3. Determine the hybridization that corresponds to this geometry. Trigonal planar geometry corresponds to sp² hybridization. Step 4. Draw the two carbon atoms side-by-side with their orbitals, Step 5…

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Hybridization makes all bonds to central atom equivalent to one another. In picture "Electronic Domain" refers to the Electronic Geometry, while "Shape" refers to Molecular Geometry. SP3 orbitals have no unhyb. p orb., 25% S character and 75% P character. SP2 has 1 UHPO, which participates in pi bond, while the 3 SP2 orbitals form sigma bonds, including the one w/ the pi bond. It has 33% S character and 67% P character. SP has 2 UHPOs for two pi bonds and 1 HPO to give 50%/50% S and P character. Bonds In Chemistry, Sigma And Pi Bonds, Hybridization Chemistry Notes, Molecular Orbital Theory Notes, Hybridization Chemistry, Orbital Hybridization, Sp3 Hybridization, Apologia Physical Science, Organic Chemistry Notes
Bonds In Chemistry
Sigma And Pi Bonds
Hybridization Chemistry Notes
Molecular Orbital Theory Notes
Hybridization Chemistry
Orbital Hybridization
Sp3 Hybridization
Apologia Physical Science
Organic Chemistry Notes
Hybridization

Hybridization makes all bonds to central atom equivalent to one another. In picture "Electronic Domain" refers to the Electronic Geometry, while "Shape" refers to Molecular Geometry. SP3 orbitals have no unhyb. p orb., 25% S character and 75% P character. SP2 has 1 UHPO, which participates in pi bond, while the 3 SP2 orbitals form sigma bonds, including the one w/ the pi bond. It has 33% S character and 67% P character. SP has 2 UHPOs for two pi bonds and 1 HPO to give 50%/50% S and P…

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