Chapter 2: The Straight Line and Applications: Figure 2.6, Slide 5
Chapter 2: The Straight Line and Applications: Figure 2.6, Slide 5
Chapter 2: The Straight Line and Applications: Figure 2.6, Slide 5
Measure Slope and Intercept Figures 2.4. Slide 2,4 Different lines with (i) same slopes, (ii) same intercept. Slide 3. How to draw a line, given slope and intercept. Worked Example 2.1 Figure 2.6, Slide 5 What is the equation of a line ? Illustrated by Figure 2.9. Slides nos. 6 - 16 Write down the equation of a line, given its slope and intercept, Worked Example 2.2, Figure 2.9 OR given the equation, write down the slope and intercept Slides no. 17, 18, 19 Plot a line by joining the intercepts. Slide no.20, 21, 22 Equations of horizontal and vertical lines, Figure 2.11: Slide no. 23
The point at which a line crosses the vertical axis is referred as the Intercept
4 3
-4
change in height
y x
intercept = 2 intercept = 0
-4 -3 -2 -1
0 -3 -2 -1 -1 -2 -3 -4 0 1 2 3 4
2
1
0
-1 -2
4
-5 -6
-3
intercept = - 3
-4 -5
Line AB slope =
2 4
Line CD slope =
6 5
Figure 2.6
Lines with same intercept but different slopes are different lines
6 5 4
Lines with same slope but different intercepts are different lines
4 3 2 1
3
-4 -3 -2 -1
0 0 -1 -2 1 2 3 4
2 1
-3
0 -1 -1 -2 0 1 2 3 4 5 6
-4 -5
Intercept, c = 2
slope, m = 1
2 1
0 -1 0 1 2 3 4
(b) vertically upwards by one unit 3. Extend this line indefinitely in either direction, as required
-1
( 1, 3)
2
(0, 2)
1
0 0 1 2 3 4
Consider the equation y = x From the equation, calculate the values of y for x = 0, 1, 2, 3, 4, 5, 6. The points are given in the following table. x 0 1 2 3 4 y 0 1 2 3 4 Plot the points as follows
5 5
6 6
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
1 (0, 0) 0 1 2 3 4 5 6 x
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
3 y 2 (1, 1) 1 (0, 0) 0 1 2 3 4 5 6 x 0
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
4 (3, 3)
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
10
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
5 (4, 4)
4 (3, 3)
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
11
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
5 (4, 4)
4 (3, 3)
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
12
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
5 (4, 4)
4 (3, 3)
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
13
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
4 (3, 3)
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
14
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
5 (4, 4)
4 (3, 3)
3 y (2, 2)
2 (1, 1)
1 (0, 0) 0 1
15
x y
0 0
1 1
2 2
3 3
4 4
5 5
6 6
5 (4, 4)
4 (3, 3)
3 y (2, 2)
2 (1, 1)
0 0
(0, 0) 1 2 3 4 5 6 x
16
(2, 4)
( 1, 3)
2
(0, 2)
1
0 -1 0 1 2 3 4
Figure 2.6
17
y
5
(2, 4)
( 1, 3)
2
(0, 2)
1
0 0 1 2 3 4
Figure 2.6
18
= mx + c
Putting it another way: the equation of a line may be described as the formula that allows you to calculate the y co-ordinate for any point on the line, when given the value of the x co-ordinate. 19
Calculate the horizontal intercept for the line: y = mx + c The horizontal intercept is the point where the line crosses the x -axis Use the fact that the y co-ordinate is zero at every point on the x-axis. Therefore, substitute y = 0 into the equation of the line 0 = mx + c and solve for x: 0 = mx + c: therefore, x = -c/m This is the value of horizontal intercept
Intercept = c Slope = m
20
Determine the slope and intercepts for a line when the equation is given in the form: ax + by +d = 0
Example:4x + 2y - 8 = 0
4x 2 y 8 0 2 y 8 4x y 4 2x
Slope =
d : intercept = b
d Horizontal intercept = a
21
Plot the line 4x+2y - 8 = 0 by calculating the horizontal and vertical intercepts:
4x+2y
-8=0
y
6 5 4 3 2 1 0 -1 -1 -2 0 1 2
Rearrange the equation into the form y = mx + c vertical intercept y = -2x + 4 Vertical intercept at y = 4 Horizontal intercept at x = 2 (see previous slide) Plot these points: see Figure 2.13 Draw the line thro the points
(0, 4)
y = - 2x + 4
(1, 2)
(2, 0)
3 4
Figure 2.13
22
The equation of a horizontal is given by the point of intersection with the y-axis The equation of a vertical line is given by the point of intersection with the x -axis
y
6 5 4 3
y=4
x = - 1.5
2 1 0
x=2
-4
-3
-2
-1 -1 -2
y=-2
-3 -4
Figure 2.11 23