Cosmology
Cosmology
Cosmology
Compare the life cycle of a I can use the Doppler equation to calculate z shift
massive star to a sun like
I can evaluate using the doppler equation the
star.
Gravity has a value of 9.81 recessional velocities of galaxies and link this to the
structure of the universe.
on Earth. Analyse how life
could be different if the
value suddenly changed
to:
i) Half g ii) Double g
Title: Cosmology Date:
November 25, 2024
Learning objective: To determine what redshift is and the
significance it has on the structure of the universe.
Do Same up until the main sequence (other than
now
Gas+Dust Protostar mass). Then Sun-like stars turn into red giant
Main Sequence Red and then white dwarf as the mass is too small
Super Giant for supernova (no fusion after producing
carbon/oxygen).
Supernova Black Hole
Massive stars fuse up until iron and then
or Neutron Star produce a supernova, then black hole or neutron
Higher ‘g’ star (depending on mass)
Maximum height and weight would be less
Bone density would have to be greater
Muscle strength would have to be greater
Maximum jump would be smaller
Opposite for half ‘g’.
Doppler
and red
shift
Make a note of these equations
What causes the Doppler Effect?
Can you write a few sentences, supported by a diagram, to state what the Doppler
effect is, with respect to sound, and how it happens?
3-5 minutes
Green Pen!
What causes the Doppler Effect?
Can you write a few sentences, supported by a diagram, to state what the Doppler
effect is, with respect to sound, and how it happens?
• An object moving towards you will sound higher-pitched, and object moving away
will sound lower pitched.
• The moving object always emits sound waves at the same speed in all directions,
but because the object is moving, the next sound waves emitted will be from
closer to one wavefront than the other.
• The wavefronts on one side are closer together (higher frequency) and the
wavefronts on the other side are further apart (lower frequency).
3-5 minutes
Green Pen!
Doppler and red shift
Doppler
and red
Notice! Notice!
shift
As Wavelength increases: As Wavelength decreases:
Waves move towards infraRED part of Waves move towards ultraVIOLET part
spectrum of spectrum
They have Lower energy & Low They have high energy & high
Frequency Frequency
Red Shift – moving away from Blue shift- Moving towards observer
obsserver
Doppler Observed with Light
The importance of the Doppler effect is that it is seen with light waves and radio
waves.
This chart compares the IR light intensity at different wavelengths from the Sun and
from Arcturus.
What does it tell us? 3 marks
Doppler Observed with Light
The importance of the Doppler effect is that it is seen with light waves and radio
waves.
This chart compares the IR light intensity at different wavelengths from the Sun and
from Arcturus.
What does it tell us? 3 marks
Our Sun contains helium. We know this because there are black
lines in the spectrum of the light from the Sun where helium has
absorbed light. These lines form the absorption spectrum for
helium.
So how are these useful for us to tell
how a star/galaxy are moving?
Challenge: Who is
Edwin Hubble and what
is his link to the big
bang/red shift?
Equation - Red Shift
For any object that is moving with a speed
much less than that of light, it can be shown
that the change in frequency is given by:
f v
∆f - change in frequency (Hz)
f - original frequency (Hz)
v - speed of object (m/s) f c
c - speed of light (m/s)
for v c only!
Equation – Red Shift
The equation in terms of wavelength is? …
v
c
∆λ - change in wavelength (m)
λ - original wavelength (m)
v - speed of object (m/s)
c - speed of light (m/s) for v c only!
For These Equations
• Objects moving towards the observer have a
positive speed; moving away from the
observer the speed is negative.
Use:
v
c
Substitute into the equation:
0.67 × 10 m ÷ 486.27 × 10 m = -v ÷ 3 × 10 m/s
-9 -9 8
v = -4.1 × 10 m/s
5
Question:
A star is moving away from the Earth at 5000 km/s.
A certain wavelength has been detected in its spectrum
which corresponds to a line of wavelength 350 nm as
measured in a laboratory.
∆λ = 5.83 × 10 m
-9