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    Week 345 Motions in Two Dimensions and Projectile Launched in An Angle

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    Week 345 Motions in Two Dimensions and Projectile Launched in An Angle

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    sandiexiea
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    Original Title

    Week 345 Motions in Two Dimensions and Projectile Launched in an Angle (1)

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    5 views32 pages

    Week 345 Motions in Two Dimensions and Projectile Launched in An Angle

    Uploaded by

    sandiexiea

    Copyright:

    © All Rights Reserved
    Download as PPTX, PDF, TXT or read online from Scribd
    Download as pptx, pdf, or txt
    of 32

    Fourth Quarter

    Physics
    Forces, Motion and
    Energy
    Motion in Two Dimensions
     Have you seen a soccer player
    kick a ball?
     Or a basketball player shoots a

    ball into the ring?


     What have you noticed with the

    path the balls travel?


     If you noticed, the balls travel a

    curve path.
     The curve naturally happens
    when an object, called a
    projectile, moves in two
    dimensions – having both
    horizontal and vertical motion
    components, acted by gravity
    only.
     In physics, this is called

    projectile motion.
    Projectile
    motion can
    happen in two
    situations – projectiles
    launched horizontally
    and projectiles
    launched at an angle.
    Projectiles Launched Horizontally
    A projectile launched
    horizontally has no initial
    vertical velocity (vix = 0).
     Thus, its vertical motion is

    similar to that of a dropped


    object.
     Projectilesare only acted upon
    by gravity. Therefore
    projectiles launched
    horizontally only have
    downward acceleration (ay),
    which is equivalent to -9.8
    m/s2 and has no horizontal
    acceleration (ax = 0).
    Projectiles have
    horizontal (x) and
    vertical (y)
    components that are
    independent of each
    other.
    Sample problem 1
    A marble is thrown horizontally
    from a table top with a velocity of
    1.50 m/s. The marble falls 0.70
    m away from the table’s edge.
    A) How high is the lab table?
    B) What is the marble’s velocity
    just before it hits the floor?
    Given:
    Horizontal (x) Vertical (y)
    component component
    v ix = 1.50 m/s a y = -9.8 m/s 2

    x = 0.70 m y=?
    v fy = ?
    t=?
     You can solve for time using
    equations from Horizontal or
    Vertical Component depending on
    the given.
     In this problem, we cannot solve for

    time using the Y component since


    the variables are lacking.
     If you look at the X Component, Vix

    and X are given; therefore, we can


    use these variables in solving for
    time.
     Solve
    for time using this
    formula:
    X =vixt
    X= vixt
    0.70 m = (1.50 m/s) t
    t = 0.70 m
    1.50 m/s
    = 0.47 s
    Sample problem 2
     A cannonball is launched horizontally from
    the top of a mountain with a velocity of 3.5
    m/s. The cannonball falls 50 m away from the
    edge of the mountain.
    a) How high is the mountain?
    b) What is the cannonball’s velocity just
    before it hits the ground?
    Projectile Motion Launched at an Angle
    (height and range of a projectile)
     There are two coordinates usually
    used to describe projectile
    motion: horizontal and vertical
    axes.
     The horizontal distance traveled

    by the projectile is called the


    range.
     While the vertical distance, that

    is, the distance from where it was


    launched to the topmost point of
    its path, is called its height.
    Sample Problem
    A golfer hits a golf ball at an angle of
    250 above the horizontal at an initial
    velocity of 20 m/s.
    a. How long does it take the golf ball to
    reach its maximum height?
    b. What is the golf ball’s maximum
    height?
    c. How far does the golf ball go?

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