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Electrostatics II

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Paper 102

Electrostatics-II
Electric Potential Energy
 When a particle moves between points a
and b under the influence of a force F the
difference in potential energy DU is equal
to the negative of the work done Wab by the
force, i.e.
U  Wab

 But, remember that this equation is


applicable only when the force is
conservative
Electric Potential Energy
 Now a question is
 What is a conservative force?
 The work done under the influence of such
a force is independent of the path taken by
the particle, it depends only on the initial
and final position
 In other words, work done on a closed path
under the influence of such a force is zero
Electric Potential Energy
 Examples of such forces are: gravitational
force and electrostatic force
 The equation for difference in the potential
energy under the influence of such a
conservative force can also be written as
b  
U  U a  U b    F  dl
a
Electric Potential Energy
𝞓U > 0
Homework

EXAMPLE

Hint: Apply conservation of energy


(KE + PE) Before = (KE + PE) After

Ans. 240 m/s


The electric potential energy of a system of
fixed point
charges at rest is equal to the work that
must be done by an external agent to
assemble the system, bringing each charge
in from an infinite distance where it is also
at rest.
Potential difference
Electric Potential
 This equation for electric potential (V) at
point P at a distance r from the charge Q
Q
VP 
4 o r

indicates that the potential due to positive


charge is positive, that due to negative
charge is negative
Electric Potential
 Electric potential at point P due to system
of n number of charges is given by
1 qi
V  V1  V2  V3  ... 
4 o
i r
i
Electric Potential
 Note that the sum here is an algebraic sum
and not a vector sum
1 qi
V  V1  V2  V3  ... 
4 o
i r
i
Potential due to an Electric Dipole
 We have already discussed about electric
dipole
 Two equal and opposite charges (q)
separated by a finite distance (2a)
constitute an electric dipole
 Each dipole has a dipole moment (p), given
 
by p  q2a 
 It’s a vector, directed from negative charge
to positive charge
Potential due to an Electric Dipole
 An electric dipole is
arranged on Y- axis as
shown in the figure
 An expression for electric
potential at a point P,
having coordinates (r, q)
due to this dipole

1 p cos 
V
4 o r 2
Potential due to an Electric Dipole
 It is clear that at every
point on the perpendicular
bisector of the dipole (X-
axis), q = 90o
 Therefore, cos q = 0
 And hence, the potential is
also zero there
1 p cos 
V
4 o r 2
Potential due to an Electric Dipole
 This means that the electric
field of the dipole does no
work when a test charge
moves from infinity along
a line in the mid-plane of
the dipole

1 p cos 
V
4 o r 2
Potential due to an Electric Dipole
 For a given value of r, the
potential is maximum
positive when q = 0o and it
is maximum negative when
q = 180o

1 p cos 
V
4 o r 2
Potential due to an Electric Dipole
 One more important point
to be noted
 The potential due to an
electric dipole varies as
1/r2 and not as 1/r as in the
case of a point charge

1 p cos 
V
4 o r 2
Same charges Opposite Charges
Circuit with two resistances
Circuit with Internal resistance
Solution of the
equation
Solution of the
equation

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