DDCO Module 1
DDCO Module 1
DDCO Module 1
RBT: L1, L2
(x * y) * z = x * (y * z) for all x, y, z, H S
• Commutative law:
A binary operator * on a set S is said to be
commutative whenever
x * y = y * x for all x, y H S
• Identity element:
A set S is said to have an identity element with respect to a binary
operation * on S if there exists an element e belongs to S with the property that
e * x = x * e = x for every x € S
x + 0 = 0 + x = x for any x € I
The set of natural numbers, N, has no identity element, since 0 is excluded from
the set.
• Inverse. A set S having the identity element e
with respect to a binary operator * is said to
have an inverse whenever, for every x € S,
there exists an element y € S such that
x*y=e
Example: In the set of integers, I, and the
operator +, with e = 0, the inverse of an element
a is (-a), since a + (-a) = 0.
Distributive law. If * and # are two binary operators
on a set S, * is said to be distributive over whenever
x * (y . z) = (x * y) .(x * z)
A field is an example of an algebraic structure. A
field is a set of elements, together with two binary
operators, each having properties 1 through 5 and
both operators combining to give property 6. The
set of real numbers, together with the binary
operators + and . , forms the field of real numbers.
The field of real numbers is the basis for arithmetic and ordinary
algebra. The operators and postulates have the following meanings:
• The binary operator + defines addition.
• The additive identity is 0.
• The additive inverse defines subtraction.
• The binary operator . defines multiplication.
• The multiplicative identity is 1.
• For a ≠ 0, the multiplicative inverse of a = 1/a defines division
(i.e., a . 1/a = 1 ).
• The only distributive law applicable is that of # over +:
a . (b + c) = (a .b) + (a . c)
Simplify:
1. x(x + y) = xx + xy = 0 + xy = xy.
2. x + xy = (x + x)(x + y) = 1(x + y) = x + y.
3. (x + y)(x + y) = x + xy + xy + yy = x(1 + y + y) = x.
4. xy + xz + yz = xy + xz + yz(x + x) = xy + xz + xyz + xyz = xy(1 + z) + xz(1 + y) = xy + xz.
5. (x + y)(x + z)(y + z) = (x + y)(x + z), by duality from function 4
Complement of a Function:
The complement of a function F is F and is obtained from an
interchange of 0’s for 1’s and 1’s for 0’s in the value of F. The complement of a
function may be derived algebraically through De Morgan’s theorems
Theorem 5, De Morgan
(a) (x + y) = x y
(b) (b) (xy) = x + y