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7.4 - Circumference Area Arc Length and Area of A Sector

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Warm up: Solve for x

1.) 124◦ 2.) 70◦


53 145
x
18◦
x

3.) 4.)
260◦
70
80 x 20◦
110◦

x
EOC REVIEW

Question of the Day


Questions over hw?
Skills Check
Circumference,
Arc Length, Area,
and Area of
Sectors
Circumference

The distance
around a circle
Circumference
Twinkle, Twinkle Little Star
Circumference Equals 2 pi r

C  2 r
or

C  d
2 Types of Answers
Rounded Exact
• Type the Pi
• Pi will be in
button on your
calculator your answer
• Toggle your
answer
• Do NOT write Pi
in your answer
Find the EXACT circumference.

1. r = 14 feet C  2 14 
C  28 ft
2. d = 15 miles
C   15 
C  15 m ile s
Ex 3 and 4: Find the circumference.
Round to the nearest tenths.

C  2 14.3  C    33 

C  89.8 m m C  103.7 yd
Arc Length
The distance along the curved line making the
arc (NOT a degree amount)


Arc Length
 measure of arc 
Arc Length     2 r
 360 
Ex 5. Find the Arc Length
Round to the nearest hundredths
 measure of arc 
Arc Length     2 r
 360 

 8m
 70 
Arc Length    2 8  70
 360 

Arc Le n g th = 9.7 7 m
Ex 6. Find the exact Arc Length.
 measure of arc 
Arc Length     2 r
 360 

 120  
Arc Length    2 5 
 360 

10
Arc Le n g th =  in
3
Ex 7. What happens to the arc length if the
radius were to be doubled? Halved?
 measure of arc 
Arc Length     2 r
 360 


20
Do u b le d 
3
5
Ha lve d 
3
Ex 8. Find the perimeter of the region.

30  9 u n its
Area of Circles
The amount of space occupied.


r
A = pr 2
Find the EXACT area.
A    29 
2
8. r = 29 feet
A  841 ft 2

2
9. d = 44 miles  44 
A  
 2 
A  484 m i 2
10 and 11
Find the area. Round to the nearest tenths.

2
 53 
A   7.6 
2
A  
 2 
A  181.5 yd 2
A  2206.2 c m 2
Area of a Sector
the region bounded by two radii of the circle and
their intercepted arc.
Area of a Sector
 measure of arc  2
A    r
 360 
Example 12 Find the area of the sector to the
nearest hundredths.

R
cm  60 
 
2
6 60 A   6
Q
 360 

A  18.85 cm2
Example 13 Find the exact area of the sector.

6 cm

 120 
 7 
7 cm 2
R
A 
Q
 360 
120

49 
A cm 2

3
Example 14 Area of minor segment =
(Area of sector) – (Area of triangle)
  
 mRQ 2   1 
R Area of minor segment = r   b  h
 360   2 
 
 90 2 1 
Q =  (12)    (12)(12) 
12 yd  360  2 

=113.10  72
2
Area of minor segment =41.10 yd
Textbook
p. 411 #2 – 14

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