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Arithmetic (Q1W3D1)

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Arithmetic Mean

Quarter I Week 3

GERALD C. MANOLID
Subject Teacher
Answer
Activity 5 Activity 6
1. The relationship between the sum of the
A. terms and the sum of the first and last terms
of an arithmetic sequence is that you can get
1. 18, 30, 42 the sum by multiplying the first and last
terms' sum by half to get the total. This is
2. 55, 42, 29, 16 because finding the sum of the terms is
easier when you start with the first and last
3. -1, 2, 5 terms.
2.
 
4. 1, 3/2
B.1. 0 2. x=6
OBJECTIVES
The learner will be able to:
 determines arithmetic means of an arithmetic sequence.
 solves problems on arithmetic sequence involving
arithmetic means.
 cooperate patiently with the groupmates in doing their
assigned tasks.
DEPARTMENT OF EDUCATION
Who can write the assignment and its answer on
the board?
1. 6 and 54 [ 3 ]
2. 68 and 3 [ 4 ]
Questions:
1. What is arithmetic means?
2. How did you get the 3 arithmetic means
between 6 and 54?
DEPARTMENT OF EDUCATION
Arithmetic Mean
Are the terms between any two nonconsecutive terms of
an arithmetic sequence
Formula: wherein:
𝑎1=1 𝑠𝑡 𝑡𝑒𝑟𝑚 𝑎 𝑛=𝑛𝑡h 𝑡𝑒𝑟𝑚
𝒂 𝒏= 𝒂𝟏 + ( 𝒏 − 𝟏 ) 𝒅 𝑛=𝑛𝑜.𝑜𝑓 𝑡𝑒𝑟𝑚 𝑑=𝑐𝑜𝑚𝑚𝑜𝑛 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒
Steps in solving the arithmetic mean
1. Using the formula of arithmetic sequence solve for
the value of the common difference
2. To get the value of the missing term add the common
difference and the value before the missing term.
Activity: Work in Pair!
1. Insert 6 arithmetic means
between 5 and 61 .
2. Insert 5 arithmetic means
between 66 and -6.
DEPARTMENT OF EDUCATION
Insert six arithmetic means between 5 and 61.
5, ___,
13, ___, 37, ___,
29, ___,
21, ___, 53, 61,
45, ___,
1 2 3 4 5 6 7 8
𝑎 6=𝑎5 + 𝑑
Given: 𝑎 6=37+8
𝑎 1=5 𝑛=8¿ 7 𝑑¿ 56
𝑎 𝑛=61 𝑑= ? 77 𝑎6=45
𝒅 =𝟖 𝑎 7=𝑎 4 +𝑑
Formula:
Arithmetic Mean: 𝑎 7=45+ 8
𝒂 𝒏=𝒂𝟏 + ( 𝒏 − 𝟏 ) 𝒅 𝑎 2=𝑎1 +𝑑 𝑎 4 = 𝐴 3 +𝑑 𝑎 5=53
Solution 𝑎 2=5+ 8 𝑎 4 =21+8
:
61=5 + ( 8 −1 ) 𝑑 𝑎 2=13 𝑎 4 =29
61=5 + ( 7 ) 𝑑 𝑎 3=𝑎2 + 𝑑 𝑎 5= 𝐴 4 + 𝑑
7 𝑑=61− 5 𝑎=13+ 8 𝑎5=29+ 8
𝑎=21 𝑎5=37
Insert five arithmetic means between 66 and -6.
54 ___,
66 ___, 30 ___,
42 ___, 6
18 ___, -6,
1 2 3 4 5 6 7
, 𝑎 6=𝑎5 + 𝑑
Given: 𝑎 6=18− 12
𝑎 1=66 𝑛=¿ 7 ¿
6 𝑑 −72
𝑎 6= 6
𝑎𝑛=− 6 𝑑= ?
𝒅=−𝟏𝟐
Formula:
Arithmetic Mean:
𝒂 𝒏=𝒂𝟏 + ( 𝒏 − 𝟏 ) 𝒅 𝑎 2=𝑎1 +𝑑 𝑎 4 =𝑎 3 +𝑑
Solution 𝑎 2=66 − 12 𝑎 4 =42 − 12
:
−6=66 + ( 7 −1 ) 𝑑 𝑎 2=54 𝑎 4 =30
− 6=66 + ( 6 ) 𝑑 𝑎 3=𝑎2 + 𝑑 𝑎 5=𝑎4 + 𝑑
6 𝑑=−66 − 6 𝑎 3=54 −12 𝑎 5=30 − 12
𝑎 3= 42 𝑎 5=18
Try to solve these problems alone:
1. The arithmetic mean between
two terms in an arithmetic
sequence is 39. If one of these
terms is 32, find the other term.

DEPARTMENT OF EDUCATION
What is your interpretation to
this problem?

How are you going to find the


other term?
DEPARTMENT OF EDUCATION
What is your interpretation to
this problem?
The other term can be found by getting first the common
difference like, 39-32 = 7
since 39 is the arithmetic mean bet.2 terms so 39 is next
to 32 then 39 + 7 = 46.
DEPARTMENT OF EDUCATION
How are you going to find the
other term?
The other term then is 46 and the
sequence is 32, 39, 46,…

DEPARTMENT OF EDUCATION
Arithmetic Mean
Are the terms between any two nonconsecutive terms of
an arithmetic sequence
Formula: wherein:
𝑎1=1 𝑠𝑡 𝑡𝑒𝑟𝑚 𝑎 𝑛=𝑛𝑡h 𝑡𝑒𝑟𝑚
𝒂 𝒏= 𝒂𝟏 + ( 𝒏 − 𝟏 ) 𝒅 𝑛=𝑛𝑜.𝑜𝑓 𝑡𝑒𝑟𝑚 𝑑=𝑐𝑜𝑚𝑚𝑜𝑛 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒
Steps in solving the arithmetic mean
1. Using the formula of arithmetic sequence solve for
the value of the common difference
2. To get the value of the missing term add the common
difference and the value before the missing term.
THANK YOU

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