Chapter-Five: Basic Operations in Surveying
Chapter-Five: Basic Operations in Surveying
Chapter-Five: Basic Operations in Surveying
A H
5.2. Tape Measurements and methods
Tape Measurements/Chain Surveying
Chain surveying is a method of land surveying where only lin
ear measurement are made.
Instruments used
Chain: - widely used method for measuring distance.
It was 100 ft steel ribbon type.
Tapes: - made in a variety of materials, lengths and weigh
ts.
Steel tapes, some times called the engineers or surveyor’s tape
more commonly used by surveyors and for engineering meas
urements.
The woven metallic and non-metallic tapes.
Woven metallic tape: - is a ribbon of water proofed fabric in
to which are woven small brass or bronze wires to prevent it
s stretching. It is 10,20,30 or 50m long,
Cont….
.
nted with characteristic red and white bands, which are usually 0.5m long, a
nd tipped with a pointed steel shoe to enable them to be driven into the gro
und. They are used in the measurement of lines with the tapes, and for marki
ng any points that need to be seen. In hard or paved ground a tripod is used t
Taping Pins: - are also called chaining pins are commonly employed to mark
the ends of the tape during the process of taping between two points more th
Hand level: - can be used to keep the two ends of the tape at the same elev
Indirect Ranging
When the end stations between which a straight line is to be
laid, are not inter-visible, indirect method of ranging is bein
g adopted.
Figure below shows the field operations involved in reciprocal
ranging. Let A and B are the two end points whose distance is
required to be found and are not inter visible. To fix the inter
mediate points in a straight line between these points, two mo
re points say C and D are chosen in such a way that D & B ar
e visible from C and C & A from D. Then, direct ranging is b
eing carried out alternatively along DCA and CDB for a num
ber of times so that ACDB lie in a straight line
2.3.2. Miscellaneous Taping and Ranging opera
tions.
1. Angle measurement:
When angle-measuring instruments like transit or theodolite are not available tapes
can be used to determine the angle between two lines within 5 to 10 minutes of arc.
A Pond C D
B
Cont…..
Taping around the obstruction is possible
During measurement of distance, various obstacles may be
encountered in the field.
5.3. Systematic errors in taping
Sources of errors
The principal systematic errors in linear measurement
s made with a tape are:
1.Incorrect length of tape
2.Tape not horizontal;
3.Variation in temperature;
4.Incorrect tension or pull;
5.Sag in tape;
6.Incorrect a alignment of tape and;
Cont…..
Example
A distance is measured with a 50m steel tape and is fo
und to be 1357.40m. Later the tape is standardized an
d is found to have an actual length of 49.96m. What is
the correct distance measured?
Solution: Ca=true length-nominal length
= 49.96-50=-0.04/ tape length
Corrected distance=1357.40+ (1357.40*-0.04)
50
= 1357.40-1.08592=1356.3141m
Cont…..
2.Malalignment of Tape
If the tape is assumed to be on a survey line, it may be
misaligned out of survey line and an error is introduce
d. This malalignment may be at the end of the tape or
at the middle of the tape
If the end of the tape is out of line by an amount h in a
length L, the error will be
h
L
e=h2/2L and the correction C = - h 2/2L
The distance that is measured along the slope is
always greater than the horizontal distance. This
makes the correction to be subtractive.
Cont…..
3.Change in Temperature:
When a taping instrument is made, it is standardized for diffe
rent conditions, temperature, pull and support. When the fiel
d temperature differs considerably from the standard, a meas
urement made with a take will also vary considerably because
of the thermal expansion of the material to which the tape is
made. So, possible corrections are necessary for the variation
in length of the tape by the equation.
Ct=L (T-Ts)
Where Ct =temperature correction (m)
= Coefficient of thermal expansion (for steel
=11.5*10-6/C0)
L = Length of tape actually used
T = Temperature at which measurement is made (0C)
Ts= Temperature at which tape was standardized (0C)
Cont.…..
Example
A traverse line is 152.4 m long. If the tape used in the field
is 50.0m when standardized at 170c, what correction mu
st be applied if the temperature at the time of measurem
ent is 230c? ( =11.2*10-6/0c)
Solution: Ct=L (T-Ts)
= 50*11.2x10-6(23-17)
= 3.36 x10-3 m/length
Total correction = 152.4* 3.36 x10-3 =+0.010m
50
Corrected Distance=152.4+0.010=152.41m
Cont.…..
4. Correction for tension (CT)
If a tape is used in the field under a tension different from the standard t
ension used in calibration, the tape will change its length a slight amoun
t according to the relation ship between stress and strain. The amount of
correction to be added or subtracted for the measured length is a functio
n of the measured length, tension during taping, the standard tension, cr
oss sectional area of the tape, and the modulus of elasticity of which the
tape is made.
Correction for pull (incorrect tension)
CP= (P-Ps)L
AE
Where Cp is the correction per tape length (m)
P is the tension applied (kg)
Ps standard tension (kg)
L the length (m)
A is the cross-sectional area of tape (cm2)
E is the modulus of elasticity of the steel tape
Modules of Elasticity of steel is 2,100,000kg/cm2
Cont.…..
Example
A 30m tape weighing 0.90kg has cross-sectional area of 0.04
85 cm2. The tape measures 29.94m when it is pulled under a t
ension of 45kg. The tape was standardized under a tension of
10kg and modulus of elasticity of the tape is 2.1x106 kg/cm2.
Determine the correct distance measured.
Solution: Using the above equn (correction for pull)
CP= (P-Ps)L
AE
Cp= (45-10)30 =0.010m
0.0485* 2.1x106
The correct distance =29.94+0.010= 29.95m
Cont.…..
5. Correction for sag:
A tape supported only at the ends will sag in the center b
y an amount that is related to its weight and the pull (ten
sion). If the tape is standardized for a flat a negative corr
ection is required for sag because the chord distance is al
ways less than the curved distance along the sag which is
given by:-
Cg = - w2 L3 , Where Cg = Correction for sag
24P2 L = Length of the tape b/n supports
w = Weight of the tape per unit length (N/M)
P = Pull applied in the field.
If the total weight of the tape (W) is used, the formula will be.
Cs = - W2L
24P2
Where Cs= Correction between points of support, m
W=weight of tape, kg/m
L= distance between support, m
P= applied tension, kg
Cont.…..
Example
Calculate the sag correction for a 30m steel tape un
der a pull of 100N if the weight of the tape was 0.
17 N/m.
Example
A distance measured with a hundred meter steel tape along an uneve
n ground and found to be 238. 40m. if the elevation difference b/n
the end pts is 2.75m (or ,the slope angle is 0 0 39’39”) what’s the res
pective measured horizontal distance.
Given – S-238.40m V= 2.75m (ፀ= 00 39’39”)
Refld - H distance
Slop – (1) Cs = V2 = ( 2.75)2 = 0.02
2S (2x238.40)
Or
(2) Cs = S(1 – Cos 00 39’39”) = 238.40 (1.00 39’39”)
= 0.02M
H distance = S - Cs = 238.40 – 0.02
= 238.38m
5.4. Electromagnetic distance measurement
method. These are carried out with the help of optical wedge
attachments.
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