1.5 - Solving More Complex Quadratic Equations
1.5 - Solving More Complex Quadratic Equations
1.5 - Solving More Complex Quadratic Equations
Let
Substitute for
𝟒 𝒚 𝟐 −𝟑𝟕 𝒚 +𝟗=𝟎
Factorise
(𝟒 𝒚 −𝟏)( 𝒚 − 𝟗)=𝟎
𝟏
𝒚=
𝟒
𝒚=𝟗
𝟐 𝟏 𝟐
𝒙 =
𝟒
𝒙 =𝟗
𝟏
𝒙=± 𝒙=± 𝟑
𝟐
Example 2
Solve the equation:
Let
Substitute for
𝟐 𝒚 − 𝟒 𝒚 −𝟏𝟐=𝟎 Factorise
( 𝒚 − 𝟔)( 𝒚+𝟐)=𝟎
𝒚=𝟔 𝒚=− 𝟐
√ 𝒙=𝟔 √ 𝒙=−𝟐
𝒙=𝟑𝟔
𝒙=𝟒
Example 3
Solve the equation:
𝟏
𝒚= 𝒚=𝟗
𝟑
𝒙 𝟏 −𝟏𝟏
𝟑 = 𝒙
𝟑 =𝟗 𝟑 = 𝟐
𝟑 =𝟗
𝟑 𝟑
𝒙=−𝟏
𝒙=𝟐
Coursebook Page 16
Exercise 1E
Questions 1 – 5