Evaporation
Evaporation
Evaporation
Evaporation
Why ?
K = a coefficient.
E = KM (ew – ea ) ( I + u9/16 )
• Problem statement:
A reservoir with average surface spread
of 3.3 km2 in December has the water surface
temperature of 22.5 C⁰ and relative humidity of
35% .wind velocity measured at 2.0mabove the
ground at the nearby observatory is 15km/h
.calculate average evaporation loss from the
reservoir in mm/day and the total depth and
volume of evaporation loss for December.
Water balance method
• It balances all the incoming and outgoing of
stored water in a lake or reservoir over a
period of time.
• Eq is in simplest form:
∑ inflow - ∑ outflow = change in storage +
Evaporation loss
∑ I - ∑ O = E + ∆S
Then E = ∑ I - ∑ O ± ∆S
• It can be more generalized by taking all the factors of
inflow and outflow:
∑I = P + Isf + Igf
∑O= T + Osf + Ogf
Where :
P = Precipitation
T = Transpiration loss
Isf=Surface inflow
Igf =Ground water inflow
Osf = Surface water outflow
Ogf = Ground water outflow
∆S = Change in storage
Measurement of all quantities is possible except
Ogf , Igf and T
This equation is fails to give accurate results since ground
water inflow and outflow are very difficult to measure for
a lake or reservoir.
It gives us good results for annually measurements not for
daily estimations.
Energy Balance Method
• Like water balance ,Energy balance for lakes or
reservoirs can be carried out to calculate lake
evaporation.
• Energy of the lake is:
Radiations = Stored energy
Hli + Hsi - Hs - Hlo = Hi + Hif + Hs + He + Hlr + Hgf
Energy Balance Method
• Where:
• Hli = Long wave radiations incident on the
surface
• Hsi = Incident Solar radiations
• Hso = Reflected Solar radiations
• Hlo = Reflected long wave radiations
• Hi = Increased in stored heat energy of water
• Hlf = Energy conducted due to the flow of the water
• Hs = Sensible heat transfer between water and atmosphere
• He = Energy used for evaporation
• Hlr = Long wave radiations emitted from the water
• Hgf = Heat absorbing into ground water
Energy Balance Method
• no water inflow/outflow to lake
• no change in water temperature of lake
• neglects sensible heat transfer to ground and
atmosphere
• neglects heat energy lost with water which
leaves system as vapor
• calculates evaporation on a daily time interval
Energy Balance Method
• Daily calculations are unreliable due to difficulties
in measuring parameters but good estimate can
be obtained if applied to monthly and yearly
values .
• Most difficult value to be measured is Hs ,it can
be measured by Bowen’s ratio:
• β = Hs / He
• Ratio between heat lost by conduction to heat
lost by evaporation.
Energy Balance Method
• Problem statement:
Calculate for the month of august
the solar radiations incident on earth’s surface
and the net outgoing thermal (long wave)
radiations for a place 20⁰ north latitude. Take
no of sunshine hours recorded at the nearby
IMD observatory as 11.5 and mean air
temperature as 25 ⁰C .Take relative humidity
for august as 98%.
Table 4.6
Table 4.7
Mass transfer Method
• Accurate estimation of the amount of water vapour transferred to
atmosphere from a lake surface is still investigated. The equation
proposed by the Thornthwaite and Holzman (1939) takes the following
form:
E = 0.000119 (e1 - e2 )(µ2 - µ1) / Pₓ ln (h2 / h1)
E is in m/sec ,
µ2 and µ1 are the velocities of wind in m/sec at height h 2 and h1 resp.
e1 and e2 are the vapour pressure of air in pascal (pa) at height h 1 and
h2 resp
P is the mean atmospheric pressure in pa between height h 2 and h1 .
h2 is the height taken close to the water surface level(lower height)
and h1 is the upper height.
Mass transfer Method
• Problem statement:
For air temperature of 25⁰ C,
relative humidity of 98%, air pressure of 101.3
× 103 Pa and wind speed of 3m/sec measured
at 2m above the water surface, calculate the
evaporation loss from the water surface .Take
saturation height h1 as 0.03m.
COMPARISON OF METHODS
• Analytical methods can provide good results.
However, they involve parameters that are
difficult to assess.
• Empirical equations can at best give
approximate values of the correct order of
magnitude.
• In view of the above, pan measurements find
wide acceptance in practice.