Law of Friction: Surface Between Two Bodies Oppose Relative Motion
Law of Friction: Surface Between Two Bodies Oppose Relative Motion
Law of Friction: Surface Between Two Bodies Oppose Relative Motion
Applied
If the block remains at rest,
force FA f = FA
The frictional force to be
overcome before it moves
Frictional is called limiting friction.
force f
2
Limiting friction
FA / N f/N
Applied
0 0
force FA 1 1
2 2
Frictional 3 3
force f
4 3
Limiting friction = 3 N 5 3
3
Limiting friction
Applied f/N
force FA At rest Moving
3
2
Frictional 1
force f
0 1 2 3 4 5 FA / N
Limiting friction = 3 N
Static Kinetic
friction friction
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Limiting friction
f/N
At rest Moving
•Kinetic / Dynamic friction is
3 the frictional force acting on
2 an object when it is moving.
1 •Static friction is the frictional
force when the object is
0 1 2 3 4 5 FA / N stationary.
Static Kinetic
friction friction
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Friction f From experiment, limiting
friction f is slightly greater
Static friction Kinetic friction than kinetic friction f’.
f i.e. f > f’
f’ Suppose f = 3.1 N, f’ = 3N
A force of 3.1 N is required to
make the block move.
Applied force F But once the block is moving,
a force of 3 N only is required
to keep the block moving.
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Law of friction Normal
reaction N
Applied
force FA
Frictional force f
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A block of mass 2 kg starts from rest, sliding down a
rough inclined plane making an angle of 30o with the
horizontal. Length of plane is 8 m. It takes 4 seconds to
reach the bottom. Find the coefficient of kinetic friction.
Solution:
t = 4 s, s = 8 m, u = 0 ms-1 R
f a
By s = ut + ½ at2
8 = 0(4) + ½ a(4)2 8m
a = 1 ms-2
mg sin 30o – f = ma
mg 30o
(2)(10)sin 30o – f = (2)(1)
f=8N
R = mg cos 30o = 17.32 N
By f = mR
8 = m(17.32)
m = 0.462 9
For the following situation, find the least coefficient of
friction between the ground and the ladder.
N = 250 Newton
Take moment about A,
S S x 4 sin 60o = 250 x 2 cos 60o
smooth
S = 72.17 Newton
N f = S = 72.17 Newton
The ladder is about to slip,
60o f = mN
72.17 = m x 250
f A
m = 0.289
250 N
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How to find coefficient of limiting friction? p 22
The coefficient of limiting friction, m, can be found by
placing the block on a surface and tilting the latter to an
angle q at which the block is just about to slip.
N Along the plane:
f = mg sin q --- (1)
Perpendicular to the plane:
N = mg cos q --- (2)
f Since the block is just about to slip,
f = mN --- (3)
q Sub (3) into (1):
mN = mg sin q --- (4)
mg
(4)/(2):
m = tan q
Hence, the coefficient of limiting friction is just tan q.
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