Modern Physics - Chapter 25
Modern Physics - Chapter 25
Modern Physics - Chapter 25
Note that the electric field, current density, and current are
to the right, while the drift velocity is to the left.
October 17, 2017 Physics for Scientists & Engineers 2, Chapter 25 15
PROBLEM:
You are playing Galactic Destroyer on your video game
console.
Your game controller operates at 12 V and is connected to
the main box with an 18-gauge copper wire of length 1.5 m.
One mole of copper has a mass of 63.5 g and contains
6.021023 atoms.
As you fly your spaceship into battle, you hold the joystick
in the forward position for 5.3 s, sending a current of 0.78
mA to the console.
How far have the electrons in the wire moved during those
few seconds, while on the screen your spaceship crossed
half of a star system?
16
Drift Velocity of Electrons in a Copper Wire
SOLUTION:
Think
To find out how far electrons in a wire move during a given
time interval, we need to calculate their drift velocity.
To determine the drift velocity for electrons in a copper
wire carrying a current, we need to find the density of
charge-carrying electrons in copper.
Then, we can apply the definition of the charge density to
calculate the drift velocity.
Sketch
Calculate
Putting in the numerical values, we get:
x=
( 0.78 10-3 A (5.3 s ) ) = 3.69318 10-7 m
( )(
8.49 1028 m -3 1.602 10-19 C 0.823 mm 2 )( )
Double-check
Our result for the the drift velocity is stunningly small.
Typical drift velocities are on the order of 104 m/s.
Since the current is proportional to the drift velocity, a
small current implies a small drift velocity.
An 18-gauge wire can carry a current of several amperes,
so the current specified in the problem statement is less
than 1% of the maximum current.
The fact that our calculated drift velocity is less than 1% of
104 m/s, a typical drift velocity for high currents, is
reasonable.
October 17, 2017 Physics for Scientists & Engineers 2, Chapter 25 20
Resistivity and Resistance
Some materials conduct electricity better than others.
If we apply a given voltage across a conductor, we get a
large current.
If we apply the same voltage across an insulator, we get
very little current.
The property of a material that describes its ability to
conduct electric currents is called the resistivity, .
The property of a particular device or object that describes
its ability to conduct electric currents is called the
resistance, R.
Resistivity is a property of the material.
Resistance is a property of a particular object made from
that material.
October 17, 2017 Physics for Scientists & Engineers 2, Chapter 25 21
Resistance
If we apply an electric potential difference V across a
conductor and measure the resulting current i in the
conductor, we define the resistance R of that conductor as:
Color Tolerance
Brown 1%
Red 2%
Gold 5%
Silver 10%
None 20%
October 17, 2017 Physics for Scientists & Engineers 2, Chapter 25 27
Resistor Color Codes
where
is the resistivity at temperature T.
0 is the resistivity at temperature T0.
is the temperature coefficient of electric resistivity.
The total current in the circuit must equal the sum of these
currents:
Here we have:
So we can write:
Permission required for reproduction of display.
Or
Yikes!
October 17, 2017 Physics for Scientists & Engineers 2, Chapter 25 63
Concept Check
As more identical resistors R are added to the parallel circuit
shown here, the total resistance between points A and B
A) increases.
B) remains the same.
C) decreases.
SOLUTION:
The power when lighted is:
This means that the losses decrease with the square of the
potential difference used to transmit the power.
Normally power transmission is done using alternating
current, but alternating currents have the inherent
disadvantage of high power losses.
High-voltage direct current (HVDC) transmission lines do
not have this problem.
The largest HVDC power line carries power from the Itaipu
Dam 800 km to Sao Paulo, Brazil:
6300 MW power at V = 1200 kV .
Round
Double-check
To double-check our result, lets calculate the resistance of
this transmission line:
Using our calculated value for the diameter, we can find the
cross-sectional area and the resistance: