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    EGR240 D3.1 Op Amps

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    Ernesto Vergara Jr.
    Okay, let's solve this step-by-step: * Given: V1 = 2 V, V2 = 1 V * For the inverting op-amp: Vo/V1 = -R2/R1 * R2 = 2 kΩ, R1 = 1 kΩ * So, Vo/V1 = -2 * Vo = -2V1 = -2(2 V) = -4 V Therefore, the output voltage VO is -4 V.

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    EGR240 D3.1 Op Amps

    Uploaded by

    Ernesto Vergara Jr.
    58 views20 pages
    Okay, let's solve this step-by-step: * Given: V1 = 2 V, V2 = 1 V * For the inverting op-amp: Vo/V1 = -R2/R1 * R2 = 2 kΩ, R1 = 1 kΩ * So, Vo/V1 = -2 * Vo = -2V1 = -2(2 V) = -4 V Therefore, the output voltage VO is -4 V.

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    EGR240 D3.1 Op amps

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    Okay, let's solve this step-by-step: * Given: V1 = 2 V, V2 = 1 V * For the inverting op-amp: Vo/V1 = -R2/R1 * R2 = 2 kΩ, R1 = 1 kΩ * So, Vo/V1 = -2 * Vo = -2V1 = -2(2 V) = -4 V Therefore, the output voltage VO is -4 V.

    Copyright:

    © All Rights Reserved
    Download as PPT, PDF, TXT or read online from Scribd
    Download as ppt, pdf, or txt
    58 views20 pages

    EGR240 D3.1 Op Amps

    Uploaded by

    Ernesto Vergara Jr.
    Okay, let's solve this step-by-step: * Given: V1 = 2 V, V2 = 1 V * For the inverting op-amp: Vo/V1 = -R2/R1 * R2 = 2 kΩ, R1 = 1 kΩ * So, Vo/V1 = -2 * Vo = -2V1 = -2(2 V) = -4 V Therefore, the output voltage VO is -4 V.

    Copyright:

    © All Rights Reserved
    Download as PPT, PDF, TXT or read online from Scribd
    Download as ppt, pdf, or txt
    of 20

    CHAPTER 8

    IDEAL OPERATIONAL
    AMPLIFIER AND OP-AMP
    CIRCUITS
    invertin
    g output
    non-inverting

    Op-amp circuit
    symbol

    Open loop mode


    Vo = Aod ( v2 v1)
    Aod is referred to as
    the open loop gain.
    Notice that is v2 =
    v1, the open loop
    gain equals to
    Final Exam SEM II
    2012/2013
    An ideal op-amp, was measured in a lab experiment in
    open-loop mode. Determine the open loop gain (Aod)
    and complete the table below which shows the results
    of the experiment.

    V1 (1) V2 (2) Vo (3)


    -1mV +1mV 1V
    -0.5V
    -0.506 -3V
    0.99 V V 1V 5V
    Op amp can be configured to be used
    for different type of circuit
    applications:
    Inverting Amplifier
    Non inverting Amplifier
    Summing Amplifier
    Integrator
    Differentiator
    Two main characteristics:
    We want the open loop gain to be equal to which means
    that v2 = v1

    We also want the input resistance to be equal to ,


    hence there is no current going into the op-amp
    Inverting Amplifier

    Op-amp as an inverting amplifier

    Voltage at node 1 (inverting) = voltage at node 2


    (non-inverting ) KCL at node 1:
    (Vi 0) / R1 = (0 Vo) / R2
    Vi / R1 = - Vo / R2

    Vo = - R2
    Vi R1
    Exercise 8.3

    Gain = - (R2 / R1) = -(150/12) =


    -12.5
    Can the voltage gain be calculated using the same
    formula?
    Try and use the same method in deriving Vo/Vi
    Non - Inverting Amplifier
    Voltage at node 1 (inverting) = voltage at node 2
    (non-inverting ) KCL at node 1:
    (0 Vi) / R1 = (Vi Vo) / R2

    -(Vi / R1) = (Vi / R2) (Vo / R2)

    Vo / R2 = (Vi / R2) + (Vi / R1)R= VR


    i 1 + 1
    2 1
    Noninverting amplifier
    Vo / Vi = R2R 1 R+ 1
    2 1
    Voltage Follower / Buffer
    Amplifier

    Vo = V i
    Hence, gain =
    1
    Summing Amplifier
    Similarly,

    i 1 + i 2 + i 3 i4 0 =
    0

    Example 8.2

    Design a summing amplifier as shown in figure to produce a specific


    output signal, such that vo = 1.25 2.5 cos t volt. Assume the input
    signals are vI1 = -1.0 V, vI2 = 0.5 cos t volt. Assume the feedback
    resistance RF = 10 k
    Solution: output voltage
    Other Op-Amp
    Applications
    Integrator

    Integrator circuit
    Differentiator

    Differentiator circuit
    EXAMPLE 8.4
    Calculating Gain and Design Questions

    INVERTIN NON -
    G INVERTING

    Calculating Output and Design Questions


    SUMMING
    AMPLIFIER

    INTEGRATOR AMPLIFIER
    DIFFERENTIATOR
    AMPLIFIER
    V V
    a b

    NON - INVERTING INVERTING INVERTING

    Calculate the input voltage if the final output, V O


    is 10.08 V.

    Finally: Then: Have to work


    Va = (1 + 10/5) V1 Vb = -(5/5) backwards:
    Va Vo = -(100/5) Vb
    0.504 = 3V1
    -0.504 = - Va 10.08 = -20 Vb
    V1 = 0.168 V Vb = -0.504 V
    Va = 0.504 V
    What is the value of Vin1 from the figure above?

    12 = - 24 [ Vin1 / 24 + (-2) / 24 + (-6) /


    24 ]
    12 = - [ Vin126]
    12 = - Vin1 + 2 + 6
    Vin1 = - 4 V
    V
    a

    INVERTING SUMMING

    Calculate the output voltage, VO if V1 = V2 = 700 mV

    Va = -(500/250) Then:
    0.7 Vo = - 500 [ Va / 100 + V2 /
    Va = -1.4 V 50 ]
    Vo = - 500 [ -1.4 / 100 +
    0.7 / 50 ]
    Vo = 0 V
    Calculate the output voltage VO of the operational
    amplifier circuit as shown in the figure.

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